Previously I have posted a similar question on passing JSON data to drop down menu using PHP. How can i arrange data array from API request into HTML SELECT OPTION LIST?
Right now I would like to INSERT the JSON datat in to MySQL database
Below is my api_redcap.php code for calling the data from other web server:
<?php
$data = array(
'token' => '4B0D42AB9D061C0FADD724D2E908349D',
'content' => 'report',
'format' => 'json',
'report_id' => '71',
'rawOrLabel' => 'label',
'rawOrLabelHeaders' => 'label',
'exportCheckboxLabel' => 'false',
'returnFormat' => 'json');
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://redcap-virtualbox/redcap/api/');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_VERBOSE, 0);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_MAXREDIRS, 10);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'POST');
curl_setopt($ch, CURLOPT_FRESH_CONNECT, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data, '', '&'));
$output = curl_exec($ch);
$json = json_decode($output);
?>
Below is my output from api_redcap.php.:
[{"project_code":"16001","dept":"Orthopaedic Surgery (ORTHO)","group":"","name":"Jameson Lua Yao Chung"},{"project_code":"16002","dept":"Rheumatology Allergy & Immunology (RAI)","group":"","name":"Koh Ee Tzun"},{"project_code":"16003","dept":"Orthopaedic Surgery (ORTHO)","group":"","name":"Ang Wei Luong"},{"project_code":"16004","dept":"Rheumatology Allergy & Immunology (RAI)","group":"","name":"Lim Xin Rong"},{"project_code":"16005","dept":"Physiotherapy (PT)","group":"","name":"Li Kun Man"}]
My table name is called PROJECT_CODE in MySQL database and the attributes are as follow:
Table Name - PROJECT_CODE
Field Name:
PROJECT_code,
DEPARTMENT,
REQUESTOR,
I would like to insert the project_code, dept and name variables from JSON into the MySQL table fields respectively. Please help. Thanks
$json = json_decode($output, true);
foreach($json as $val)
{
$project_code = $val['project_code'];
$dept = $val['dept'];
$name = $val['name'];
/*
* Generate insert query as below
* "INSERT INTO MyGuests (project_code, dept, name) VALUES ($project_code, $dept, $name);";
*/
}
Also, you can insert multiple record in single loop
Please check below reference link
https://www.w3schools.com/php/php_mysql_insert_multiple.asp
In reference link 3 different methods given,so, you can use any one whatever suitable for you
Related
The below PHP code for Onesignal push notification is working fine,
But how do I add Title to the notification along with a defined custom icon instead of the default bell?
//Push Notifications Starts User --------------------------------------------------------------
notify("Alert","Your Order status has been changed to '$order_status'.");
$content = array("en" => "Your Order status has been changed to '$order_status'.");
$fields = array(
'app_id' => "fa0e5f20-xxxxxxxxxxxxxxxxxxxx",
'included_segments' => array('All'),
'contents' => $content,
'data' => array("en" => "bar"),
'large_icon' =>"ic_launcher_round.png",
);
$fields = json_encode($fields);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://onesignal.com/api/v1/notifications");
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json; charset=utf-8',
'Authorization: Basic NTBjNDExxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch, CURLOPT_HEADER, FALSE);
curl_setopt($ch, CURLOPT_POST, TRUE);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
$response = curl_exec($ch);
curl_close($ch);
//Push Notifications Ends --------------------------------------------------------------
Please note that "ic_launcher_round.png" is in my studio sdk inside folders "res->mipmap->ic_launcher_round"
The push is working, but I need the Title on top of the content along with 'ic_launcher_round.png' as a custom icon.
Any help is greatly appreciated.
I'm trying login to a remote site, by having curl to the login form.
I want to redirect to another subdomain and get content.
The code I have doesn't seem to work and only tries to show the main page of the site.
<?php
$username = 'user';
$password = 'pass';
$loginUrl = 'https://site_url';
//init curl
$ch = curl_init();
//Set the URL to work with
curl_setopt($ch, CURLOPT_URL, $loginUrl);
// ENABLE HTTP POST
curl_setopt($ch, CURLOPT_POST, 1);
//Set the post parameters
curl_setopt($ch, CURLOPT_POSTFIELDS, 'user='.$username.'&password='.$password);
//Handle cookies for the login
curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookie.txt');
curl_setopt ($ch, CURLOPT_COOKIEFILE, 'cookie.txt');
//Setting CURLOPT_RETURNTRANSFER variable to 1 will force cURL
//not to print out the results of its query.
//Instead, it will return the results as a string return value
//from curl_exec() instead of the usual true/false.
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
//execute the request (the login)
$store = curl_exec($ch);
//the login is now done and you can continue to get the
//protected content.
//set the URL to the protected file
curl_setopt($ch, CURLOPT_URL, 'https://site_url/statistics');
//execute the request
$content = curl_exec($ch);
curl_close($ch);
//save the data to disk
file_put_contents('~/file.txt', $content);
?>
Does it have to be via cURL?
Have you considered leveraging a library like Guzzle?
They have good documentation that covers scenarios as you have described.
https://docs.guzzlephp.org/en/stable/quickstart.html#post-form-requests
Something like the below but could be laid out better
use GuzzleHttp\Client;
use GuzzleHttp\Exception\BadResponseException;
$client = new Client(['base_uri' => 'https://url_site/', 'cookies' => true]);
// Login
try {
$client->request(
'POST',
'login/',
[
'form_params' => [
'username' => $username,
'password' => $password,
],
]
);
} catch (BadResponseException $e) {
echo "Error Logging On for User {$username}";
exit;
}
// Navigate
$response = $client->request('GET', '/statistics');
$content = $response->getBody()->getContents();
file_put_contents('~/file.txt', $content);
I need to convert this PHP cURL request to JavaScript. I'm not exactly sure how to go about doing it.
I basically need to make this request be client sided instead of server sided.
function createSite($template_id) {
//create array with data
$data = array("template_id"=>$template_id);
//turn data into json to pass via cURL
$data = json_encode($data);
print $data;
//Set cURL parameters
$ch = curl_init();
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch,
CURLOPT_URL,'https://api.duda.co/api/sites/multiscreen/create');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, API_USER.':'.API_PASS);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:
application/json'));
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
//execute cURL call and get template_idte data
$output = curl_exec($ch);
//check for errors in cURL
if(curl_errno($ch)) {
die('Curl error: ' . curl_error($ch));
}
//decode result
$output = json_decode($output);
//return unique site_name
return $output->site_name;
I looked around a lot before posting this question so my apologies if it is on another post and this is only my second quesiton on here so apologies if I don't format this question correctly.
I have a really simple web service that I have created that needs to take post values and return a JSON encoded array. That all worked fine until I was told I would need to post the form data with a content-type of application/json. Since then I cannot return any values from the web service and it is definitely something to do with how I am filtering their post values.
Basically in my local setup I have created a test page that does the following -
$curl = curl_init();
curl_setopt($curl, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data))
);
curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); // Set the url path we want to call
$result = curl_exec($curl);
//see the results
$json=json_decode($result,true);
curl_close($curl);
print_r($json);
On the webservice I have this (I have stripped out some of the functions) -
<?php
header('Content-type: application/json');
/* connect to the db */
$link = mysql_connect('localhost','root','root') or die('Cannot connect to the DB');
mysql_select_db('webservice',$link) or die('Cannot select the DB');
if(isset($_POST['action']) && $_POST['action'] == 'login') {
$statusCode = array('statusCode'=>1, 'statusDescription'=>'Login Process - Fail');
$posts[] = array('status'=>$statusCode);
header('Content-type: application/json');
echo json_encode($posts);
/* disconnect from the db */
}
#mysql_close($link);
?>
Basically I know that it is due to the $_POST values not being set but I can't find what I need to put instead of the $_POST. I tried
json_decode($_POST), file_get_contents("php://input") and a number of other ways but I was shooting in the dark a bit.
Any help would be greatly appreciated.
Thanks, Steve
Thanks Michael for the help, that was a definite step forward I now have at least got a repsonse when I echo the post....even if it is null
updated CURL -
$curl = curl_init();
curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, json_encode($data));
updated php on the page that the data is posted to -
$inputJSON = file_get_contents('php://input');
$input= json_decode( $inputJSON, TRUE ); //convert JSON into array
print_r(json_encode($input));
As I say at least I see a response now wheras prior it was returning a blank page
You have empty $_POST. If your web-server wants see data in json-format you need to read the raw input and then parse it with JSON decode.
You need something like that:
$json = file_get_contents('php://input');
$obj = json_decode($json);
Also you have wrong code for testing JSON-communication...
CURLOPT_POSTFIELDS tells curl to encode your parameters as application/x-www-form-urlencoded. You need JSON-string here.
UPDATE
Your php code for test page should be like that:
$data_string = json_encode($data);
$ch = curl_init('http://webservice.local/');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
$result = curl_exec($ch);
$result = json_decode($result);
var_dump($result);
Also on your web-service page you should remove one of the lines header('Content-type: application/json');. It must be called only once.
Hello this is a snippet from an old project of mine that uses curl to get ip information from some free ip databases services which reply in json format. I think it might help you.
$ip_srv = array("http://freegeoip.net/json/$this->ip","http://smart-ip.net/geoip-json/$this->ip");
getUserLocation($ip_srv);
Function:
function getUserLocation($services) {
$ctx = stream_context_create(array('http' => array('timeout' => 15))); // 15 seconds timeout
for ($i = 0; $i < count($services); $i++) {
// Configuring curl options
$options = array (
CURLOPT_RETURNTRANSFER => true, // return web page
//CURLOPT_HEADER => false, // don't return headers
CURLOPT_HTTPHEADER => array('Content-type: application/json'),
CURLOPT_FOLLOWLOCATION => true, // follow redirects
CURLOPT_ENCODING => "", // handle compressed
CURLOPT_USERAGENT => "test", // who am i
CURLOPT_AUTOREFERER => true, // set referer on redirect
CURLOPT_CONNECTTIMEOUT => 5, // timeout on connect
CURLOPT_TIMEOUT => 5, // timeout on response
CURLOPT_MAXREDIRS => 10 // stop after 10 redirects
);
// Initializing curl
$ch = curl_init($services[$i]);
curl_setopt_array ( $ch, $options );
$content = curl_exec ( $ch );
$err = curl_errno ( $ch );
$errmsg = curl_error ( $ch );
$header = curl_getinfo ( $ch );
$httpCode = curl_getinfo ( $ch, CURLINFO_HTTP_CODE );
curl_close ( $ch );
//echo 'service: ' . $services[$i] . '</br>';
//echo 'err: '.$err.'</br>';
//echo 'errmsg: '.$errmsg.'</br>';
//echo 'httpCode: '.$httpCode.'</br>';
//print_r($header);
//print_r(json_decode($content, true));
if ($err == 0 && $httpCode == 200 && $header['download_content_length'] > 0) {
return json_decode($content, true);
}
}
}
you can put your json in a parameter and send it instead of put only your json in header:
$post_string= 'json_param=' . json_encode($data);
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS, $post_string);
curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); // Set the url path we want to call
//execute post
$result = curl_exec($curl);
//see the results
$json=json_decode($result,true);
curl_close($curl);
print_r($json);
on the service side you can get your json string as a parameter:
$json_string = $_POST['json_param'];
$obj = json_decode($json_string);
then you can use your converted data as object.
i am trying to send an array of JSON objects to
PHP server using an hidden field
but all i am getting in the server is just a string
this is my javascript
function CreateArrayOfJSON()
{
var all_childrens = $('#form_div').find('*');//get all root element childrens
var form_elements = {
elements: []
};
for(var i=0;i<all_childrens.length;i++)
{
var id='#'+$(all_childrens[i]).attr('id'); //get id
var style_attr=$(all_childrens[i]).attr('style'); //get style inline
var classes=$(all_childrens[i]).attr("class");
form_elements.elements.push
({
"id" : id,
"style_attr" :style_attr,
"classes" :classes
});
}
document.getElementById('form_elements_array').value=form_elements;//fill hidden field
}
this is my PHP:
this will return Object object (as in the picture above)
$form_elements=$_POST['form_elements_array'];
this will return null
$form_elements=json_decode($_POST['form_elements_array']);
any ideas ?
thank you
document.getElementById('form_elements_array').value=JSON.stringify(form_elements);
can you paste the output string ?
or alternatively
You can use Curl for the same
$url = "URL Where you want to send data";
$ch = curl_init();
$attachment = array(
'name' => 'Your first field',
'link' => 'Second Field',
'description' => 'description here',
);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $attachment);
$result = curl_exec($ch);
curl_close($ch);
now php code on the receiver page
can you paste the output string ?
or alternatively
You can use Curl for the same
$url = "URL Where you want to send data";
$ch = curl_init();
$attachment = array(
'name' => 'Your first field',
'link' => 'Second Field',
'description' => 'description here',
);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $attachment);
$result = curl_exec($ch);
curl_close($ch);
now php code on the receiver page
echo $_POST['name']; // get your data with POST method