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I have the following array of object.
[
{ claimNumber1: 'R12345', checkNumber1: '' },
{ claimNumber2: 'T1234', checkNumber2: 'abcd' },
{ claimNumber3: 'Z4567', checkNumber3: 'qwer' }
]
Using reduce, I want to convert this to below.
{
claimNumber1:'R12345',
checkNumber1:'',
claimNumber2:'T1234',
checkNumber2:'',
claimNumber3:'Z4567',
checkNumber3:'',
}
I tried below but didn't get what I expected.
.reduce((obj, item) =>{
return {...obj,item}
} ,{});
You should spread the item object, because item is an object
const arr = [
{ claimNumber1: "R12345", checkNumber1: "" },
{ claimNumber2: "T1234", checkNumber2: "abcd" },
{ claimNumber3: "Z4567", checkNumber3: "qwer" },
];
const result = arr.reduce((obj, item, i) => {
return { ...obj, ...item, [`checkNumber${i + 1}`]: "" };
}, {});
console.log(result);
Almost there. You just need to spread the item as well.
.reduce((obj, item) => {
return {
...obj,
...item,
};
}, {});
I think you should spread every item in reducer.
Here is my code.
const res = arr.reduce((prev, item) => {
return { ...prev, ...item };
}, {});
And result is
{
claimNumber1: 'R12345',
checkNumber1: '',
claimNumber2: 'T1234',
checkNumber2: 'abcd',
claimNumber3: 'Z4567',
checkNumber3: 'qwer'
}
I'm not sure of the benefit of using reduce in this situation. A simple loop would be self-documenting, and easier to read.
const data = [
{ claimNumber1: 'R12345', checkNumber1: '' },
{ claimNumber2: 'T1234', checkNumber2: 'abcd' },
{ claimNumber3: 'Z4567', checkNumber3: 'qwer' }
];
const out = {};
// For every object in the array
for (const obj of data) {
// Get an array of its keys and iterate over them
for (const key of Object.keys(obj)) {
// If it's a claim add that value to the output
// object property, otherwise set that property value
// to an empty string.
if (key.startsWith('claim')) {
out[key] = obj[key];
} else {
out[key] = '';
}
}
}
console.log(out);
Additional documentation
Object.keys
I have an array of objects which looks like
arr = [
{"className":"section", "name":"input"},
{"className":"col", "name":"dropdown"},
{"className":"section", "name":"table"}
]
Now I want to push an object {"fieldName":"new"} after every object which has "className":"section"
So my final output should look like something like this
arr = [
{"className":"section", "name":"input"},
{"fieldName":"new"},
{"className":"col","name":"dropdown"},
{"className":"section", "name":"table"},
{"fieldName":"new"}]
How do I acheive this in Javascript?
Use Array.reduce.
let arr = [{"className":"section", "name":"input"},{"className":"col", "name":"dropdown"},{"className":"section", "name":"table"}];
arr = arr.reduce((acc, item) => {
acc.push(item);
if (item.className === "section") {
acc.push({ fieldName: "new" });
}
return acc;
}, []);
console.log(arr);
try this...
arr.forEach(obj => {
if (obj.className === 'section') {
const index = arr.indexOf(obj)
arr.splice(index, 0,
{"fieldName":"new"} )
}
})
I need to create a new array from another with the condition:
for example from an array
mainArr: [
{
"id":1,
"name":"root"
},
{
"id":2,
"parentId":1,
"name":"2"
},
{
"id":148,
"parentId":2,
"name":"3"
},
{
"id":151,
"parentId":148,
"name":"4"
},
{
"id":152,
"parentId":151,
"name":"5"
}
]
I need to make an array ['1','2','148','151'] which means the path from "parentId"'s to "id":152 - (argument for this function).
I think main logic can be like this:
const parentsArr = [];
mainArr.forEach((item) => {
if (item.id === id) {
parentsArr.unshift(`${item.parentId}`);
}
and the result {item.parentId} should be used to iterate again. But I don't understand how to do it...
You could use a recursive function for this. First you can transform your array to a Map, where each id from each object points to its object. Doing this allows you to .get() the object with a given id efficiently. For each object, you can get the parentId, and if it is defined, rerun your traverse() object again searching for the parent id. When you can no longer find a parentid, then you're at the root, meaning you can return an empty array to signify no parentid object exist:
const arr = [{"id":1,"name":"root"},{"id":2,"parentId":1,"name":"2"},{"id":148,"parentId":2,"name":"3"},{"id":151,"parentId":148,"name":"4"},{"id":152,"parentId":151,"name":"5"}];
const transform = arr => new Map(arr.map((o) => [o.id, o]));
const traverse = (map, id) => {
const startObj = map.get(+id);
if("parentId" in startObj)
return [...traverse(map, startObj.parentId), startObj.parentId];
else
return [];
}
console.log(traverse(transform(arr), "152"));
If you want to include "152" in the result, you can change your recursive function to use the id argument, and change the base-case to return [id] (note that the + in front of id is used to convert it to a number if it is a string):
const arr = [{"id":1,"name":"root"},{"id":2,"parentId":1,"name":"2"},{"id":148,"parentId":2,"name":"3"},{"id":151,"parentId":148,"name":"4"},{"id":152,"parentId":151,"name":"5"}];
const transform = arr => new Map(arr.map((o) => [o.id, o]));
const traverse = (map, id) => {
const startObj = map.get(+id);
if("parentId" in startObj)
return [...traverse(map, startObj.parentId), +id];
else
return [+id];
}
console.log(traverse(transform(arr), "152"));
I would start by indexing the data by id using reduce
var byId = data.reduce( (acc,i) => {
acc[i.id] = i
return acc;
},{});
And then just go through using a loop and pushing the id to a result array
var item = byId[input];
var result = []
while(item.parentId) {
result.push(item.parentId)
item = byId[item.parentId];
}
Live example:
const input = 152;
const data = [ { "id":1, "name":"root" }, { "id":2, "parentId":1, "name":"2" }, { "id":148, "parentId":2, "name":"3" }, { "id":151, "parentId":148, "name":"4" }, { "id":152, "parentId":151, "name":"5" } ]
var byId = data.reduce( (acc,i) => {
acc[i.id] = i
return acc;
},{});
var item = byId[input];
var result = []
while(item.parentId) {
result.push(item.parentId)
item = byId[item.parentId];
}
console.log(result.reverse());
Try changing this line
parentsArr.unshift(`${item.parentId}`);
To this
parentsArr.push(`${item.parentId}`);
Then try
console.log(parentsArr);
This is what I ended up with. Basically a mix of Janek and Nicks answers. It's just 2 steps:
transform code to a map.
extract the ancester_id's with a little function
let data = [
{"id":1,"name":"root"},
{"id":2,"parentId":1,"name":"2"},
{"id":148,"parentId":2,"name":"3"},
{"id":151,"parentId":148,"name":"4"},
{"id":152,"parentId":151,"name":"5"}
];
data = data.reduce( (acc, value) => {
// could optionally filter out the id here
return acc.set(value.id, value)
}, new Map());
function extract_ancestors( data, id ) {
let result = [];
while( data.get( id ).parentId ) {
id = data.get( id ).parentId;
result.push(id)
}
return result;
}
// some visual tests
console.log( extract_ancestors( data, 152 ) );
console.log( extract_ancestors( data, 148 ) );
console.log( extract_ancestors( data, 1 ) );
PS: My OOP tendencies start to itch so much from this haha.
My array comes like this
var data=[{PRODUCT : P1}, {PRODUCT: P2}]
I wantt to convert this into [P1, P2].
Sometimes my array comes like this
var data=[{ITEM: I1, QUANTITY:1}, {ITEM: I2, QUANTITY:2}]
I wantt to convert this into [I1, I2].
so can we make a common function, where I just want to extract particular value of array and make a new array.
p.s. Thank you in advance
I tried to write the logic like this:
data.map((d, index) => { var result= [];
result.includes(d[0]); })
but it,s not dynamic
You could define a function which will always get the first value of the first object key, this should satisfy your needs based on the above
var data1 = [{
ITEM: 'I1',
QUANTITY: 1
}, {
ITEM: 'I2',
QUANTITY: 2
}]
var data2 = [{
PRODUCT: 'P1'
}, {
PRODUCT: ' P2'
}]
function getArrayOfValues(list) {
return list.reduce((acc, x) => {
const firstValue = Object.values(x)[0];
acc.push(firstValue)
return acc;
}, [])
}
const result1 = getArrayOfValues(data1)
console.log(result1)
const result2 = getArrayOfValues(data2)
console.log(result2)
function getProductOrItem(list) {
return list.reduce((accumulator, obj) => {
if (obj.PRODUCT) {
accumulator.push(obj.PRODUCT);
} else if (obj.ITEM) {
accumulator.push(obj.ITEM);
}
return accumulator;
}, [])
}
you can iterate through your array with map() method and inside it extract the value of a first entity of an object in your array and simply get a new array with all values:
const data1 =[{PRODUCT : 'P1'}, {PRODUCT: 'P2'}]
const data2 = [{ITEM: 'I1', QUANTITY: 1}, {ITEM: 'I2', QUANTITY: 2 }]
const transformValuesOfArray = (arrayToTransform) =>
arrayToTransform.map(value => {
const firstObjectValue = Object.values(value)[0]
return firstObjectValue
})
console.log(transformValuesOfArray(data1))
console.log(transformValuesOfArray(data2))
I have an array like this
let oldArray=[
{type:16,img:['1']},
{type:16,img:['2']},
{type:16,img:['3']},
{type:17,img:['4']}
]
if the type is the same, i want to concat the value.
The result I want is:
let newArray=[
{type:16,img:['1','2','3']},
{type:17,img:['4']}
]
I tried to used reduce function:
oldArray.reduce((acc,cur,idx,src)=>{
if(cur.type===a[idx+1].type){
cur.img.concat(a[idx+1].img);
acc.push(cur)
} else {
acc.push(a[idx+1])
}
return acc
},[])
It seems that there is an error
Can anyone help? Thanks.
Alternative to Bibberty's solution:flatMap is much clearer than reduce
let newArray = [...new Set(oldArray.map(e => e.type))]
.map(e => {
return {
type: e,
img: (oldArray.filter(i => i.type === e).map(x => x.img)).reduce((acc,cur,idx,src)=>{
let length=src.length
let tep=cur.concat(src[idx+1]);
src[idx+1]=tep
return src[idx=length-1]
},[])
}
});
console.log(newArray);
You can use reduce:
let oldArray = [{type: 16,img: ['1']},{type: 16,img: ['2']},{type: 16,img: ['3']},{type: 17,img: ['4']}];
let newArray = oldArray.reduce((acc, curr) => {
acc.some(({
type
}) => type == curr.type) ? acc.find(({
type
}) => type == curr.type).img.push(curr.img[0]) : acc.push(curr);
return acc;
}, []);
console.log(newArray);
We use a Set and then a map.
The Set is populate with the unique types by using a map to extract.
We wrap in [] to give us an array the we then re map to build our object back.
The map then rebuilds our objects and note the use of filter and map to get the img values from the original host array.
let oldArray=[
{type:16,img:['1']},
{type:16,img:['2']},
{type:16,img:['3']},
{type:17,img:['4']}
]
let newArray = [...new Set(oldArray.map(e => e.type))]
.map(e => {
return {
type: e,
img: oldArray.filter(i => i.type === e).flatMap(x => x.img)
}
});
console.log(newArray);
This solution is not a reduce but return result you are looking for is the same
let oldArray = [
{type:16,img:['1']},
{type:16,img:['2']},
{type:16,img:['3']},
{type:17,img:['4']}
];
const transitoryMap = new Map();
for (const item of oldArray) {
if (!transitoryMap.has(item.type)) {
transitoryMap.set(item.type, [item.img[0]])
} else {
const value = transitoryMap.get(item.type)
value.push(item.img[0])
transitoryMap.set(item.type, value)
}
}
const newArray = [];
for (const item of transitoryMap.keys()) {
newArray.push({type:item,img:transitoryMap.get(item)})
}
console.log(newArray)
Here is an example using reduce. I have added a tracker to keep track of type in the newArray.
let oldArray = [
{type:16,img:['1']},
{type:16,img:['2']},
{type:16,img:['3']},
{type:17,img:['4']}
];
oldArray.reduce((a,c)=>{
let index = a.tracker.indexOf(c.type);
if(index === -1) {
a.tracker.push(c.type);
a.newArray.push({...c, img:[...c.img]});
} else {
a.newArray[index].img.push(...c.img);
}
return a;
},{tracker:[],newArray:[]}).newArray;
You might want to consider breaking up the processing into separate simple steps, for example:
Create a flattened object with the appropriate data.
build a new array with the wanted structure.
This will not only keep your code simple, but will allow you to focus on what your code is actually doing instead of how it is doing the task.
var oldArray=[
{type:16,img:['1']},
{type:16,img:['2']},
{type:16,img:['3']},
{type:17,img:['4']}
]
flattenMyObject = (arr) =>
arr.reduce((accum, current) => {
!!accum[current.type] ? accum[current.type].push(...current.img) : accum[current.type] = current.img;
return accum;
}, {});
buildNewArray = (type) => {
return {type: type, img: flattenedObject[type] }
}
Object
.keys(flattenMyObject(oldArray))
.map(buildNewArray);