Selectizejs isn't loading the options correctly - javascript

I'm using ajax, creating a dependent category and subcategory, everything works, my html is valid, I'm using selectizejs on both category and sub category. the category is working fine, the subcategory isn't. If I don't use selectize, everything works perfectly
$(".category").change(function () {
var id = $(this).val();
var dataString = 'id=' + id;
$.ajax
({
type: "POST",
url: "subcat.php",
data: dataString,
cache: false,
success: function (html) {
$(".subcat").html(html);
}
});
});
$('#subcat').selectize({
plugins: ['remove_button'],
persist: false,
});
index.php
<label class="control-label col-md-3 col-3">Sub Category <span class="required">*</span>
<select name="post[subcategory]" class="subcat" id="subcat">
<option selected="selected" value="">Select Sub Category</option>
</select> </label>
subcat.php
foreach ($children as $child) {?>
<option value="<?php echo $child->id; ?>"><?php echo $child->name; ?></option>
<? } ?>
No errors in console. When you select a category then all the sub categories gets displayed in the browser as static text without the possibility of selecting an option.
Again, if I remove selectize, I get a perfectly normal dropdown.

Related

Trying to populate select based on previous 2 selection

Can You Please Find Out The Problem In The Following Code
I am trying to populate 1 select option based on previous 2 select options.
For example, you will select option 1 and then select option 2 based on those 2 options I will get 3rd option.
Here is my jquery part
/*This Is Basically My Jquery Part Which will Take 2 values from selects*/
$(".asset").change(function(){
var id=$(this).val();
console.log(id);
var dataString1 = 'id='+ encodeURIComponent(id);
console.log(dataString1);
$(".amc").change(function(){
var aid=$(this).val();
console.log(aid);
var dataString2 = 'aid='+ encodeURIComponent(aid);
console.log(dataString2);
//console.log(data);
$.ajax({
type: "POST",
url: "fetch.php",
data : {dataString1: id,dataString2: aid},
cache: false,
success: function(html)
{
$(".scheme").html(html);
}
});
});
});
Here is the fetch part
<?php
include('dbconfig.php');
if($_POST['id'] && $_POST['aid'])
{
$id=$_POST['id'];
$aid=$_POST['aid'];
$stmt = $DB_con->prepare("SELECT * FROM Master_MutualFundMasters WHERE AssetClassID=:id AND AMCID = :aid");
$stmt->execute(array(':id' => $id));
$stmt->execute(array(':aid' => $aid));
?><option selected="selected">Select City :</option>
<?php while($row=$stmt->fetch(PDO::FETCH_ASSOC))
{
?>
<option value="<?php echo $row['WW_UniqueInvestmentCode']; ?>"><?php echo $row['PrimarySchemeName']; ?></option>
<?php
}
}
?>
When I check my console it is showing me the data but its not passing on next page
You should use select at beginning.
Example:
<select>
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="vw">VW</option>
<option value="audi" selected>Audi</option>
</select>
since you are asking
In your console it is showing me the data but its not passing on next page means (fetch.php).
then you can do-
$.ajax({
type: "POST",
url: "fetch.php",
data : {"id":dataString1,"aid":dataString2},
cache: false,
success: function(html)
{
$(".scheme").html(html);
}
});
and in fetch.php page.
if($_POST["id"] && $_POST["aid"])
{
$id=$_POST["id"];
$aid=$_POST["aid"];
//write ur code here...
}
I Hope this help u.

dynamic select option in codeigniter

I am creating dependable select option in codeigniter. To populate first option was easy but i am bit troubling in displaying the second option and third option. Need help on this
My database contain:
In head table:
h_id, head fields,
subhead table
h_id, sh_id, subhead fields and
points table
sh_id, points_name fields
controller
class Mobile extends App_Controller {
function __construct()
{
parent::__construct();
$this->load->database();
$this->load->helper(array('url','language','form'));
$this->load->library('form_validation');
$this->form_validation->set_error_delimiters('<p class="text-red">', '</p>');
$this->lang->load('auth');
$this->load->model('mobiles_model');
}
function index()
{
if (!$this->data['logged_in'])
{
redirect('auth/login','refresh');
}
$rows = $this->mobiles_model->get_users_devices();
if ($rows)
{
$this->data['devices_list'] = $rows;
}
$this->_render_page('trackall', $this->data);
}
function _render_page($view, $data=null, $render=false)
{
$this->viewdata = (empty($data)) ? $this->data: $data;
$view_html = $this->load->view($view, $this->viewdata, $render);
if (!$render) return $view_html;
}
}
modal
public function get_users_devices()
{
$this->db->select('A.h_id as id,A.head');
$this->db->from($this->table_head.' as A');
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result_array();
}
return FALSE;
}
view
<select id="head" name="head" class="form-control input-sm" onchange = "calljavascriptfunction();">
<option value="default">--Select--</option>
<?php if(isset($devices_list))
foreach ($devices_list as $value) { ?>
<option value="<?php echo $value['h_id'] ?>"><?php echo $value['head'] ?></option>
<?php } ?>
</select>
<select id="subhead" name="subhead" class="form-control input-sm">
<option value="default">--Select--</option>
</select>
<select id="points" name="points" class="form-control input-sm">
<option value="default">--Select--</option>
</select>
I have to populate the other depending on what i select. i tried several methods but none of them worked.
Thanks for help i am really stuck in this.
Suppose your you had following views loaded in HTML and you need to fetch value depending on first dropdown #head.
view code :
<select id="head">
<option id="1"> Mobile </option>
<option id="2"> Tabs </option>
<option id="3"> Laptops </option>
</select>
<select id="subhead">
</select>
jquery ajax
$("#head").change(function(){
var post_url = '<?php echo base_url() ?>mobile/getByDeviceId'
$.ajax({
type: "POST",
url: post_url,
data : { "hid" : $(this).val() },
success: function(response){
$.each(response, function(value, key) {
$("#subhead").append("<option id="+value.modelId+">"+value.modelName+"</option>");
})
}
});
});
controller function :
function getByDeviceId(){
$hid = $this->input->post("hid");
$modelList = $this->mobile_model->getByDeviceId($hid);
echo(json_encode($modelList));
}
model function :
function getByDeviceId($hid){
$this->db->select("modelId, modelName");
$this->db->from("models");
$this->db->where("hid", $hid);
$query = $this->db->get();
return $query->result();
}
Use jquery ajax() to do this, as ajax() do not disturb the current state of page and get the data from server and you can append it to the dropdown.
ajax() syntax:
$.ajax({
url: 'process.php',
type: 'POST',
data: {
var1 :val1,
var2 :val2
},
success: function(response){ // response from process
// do your stuff here
}
});

two dropdowns on one dependent dropdown codeigniter

I have this dependent dropdown function where I have a dropdown and another one depending on it,
here is the HTML
<select class="form-control" name = "PROV_ID" id = "PROV_ID">
<option></option>
<?php foreach ($content2 as $cs) {?>
<option value="<?php echo $cs->PROV_ID; ?>"><?php echo $cs->PROVINCE; ?></option>
<?php } ?>
</select>
<select class="form-control" name = 'CT_ID' id = 'CT_ID'>
<option value=""></option>
</select>
and here is the javascript
jQuery(document).ready(function(){
$("#PROV_ID").change(function() {
var PROVID = {"PROVID" : $('#PROV_ID').val()};
console.log(PROVID);
$.ajax({
type: "POST",
data: PROVID,
url: "<?php base_url(); ?>Employees/dependent_dropdown/",
success: function(data){
var select = $('#CT_ID');
select.html('');
$.each(data, function(i, option){
select.append("<option value='"+option.CT_ID+"'>"+option.CITY+"</option>");
});
}
});
});
});
now I want to have one like this, but I wanted to have selected values for the first two dropdowns before the dependent one shows the values.
e.g.
first dropdown -->select a value
second dropdown -->selects a value
dependent dropdown --> gives values according to first and second dropdown.
example: select * from thistable where column1 = 'firstdropdownvalue' and column2 = 'seconddropdownvalue'
then the dropdown values would be the result.
jQuery(document).ready(function(){
$("#CT_ID").change(function() {
var PROVID_two = {"PROVID" : $('#PROV_ID').val(), "CT_ID" : $('#CT_ID').val()};
console.log(PROVID);
$.ajax({
type: "POST",
data: PROVID_two,
url: "<?php base_url(); ?>Employees/dependent_dropdown2/",
success: function(data){
var select = $('#PROVID_two');
select.html('');
$.each(data, function(i, option){
select.append("<option value='"+option.CT_IDnew+"'>"+option.CITYnew+"</option>");
});
}
});
});
});
You can try like this. Pass two selected values. Hope you understood

Create subcategory select box onChange

I am creating a category system where users can select category from DB and after they select it creates another select box with subcategory of that category.
So, my question is how can I do it the best way?
BTW I am using Laravel Framework and first category is simple
<select>
#foreach(Category::all() as $k)
<option value="{{ $k['id'] }}">{{ $k['name'] }}</option>
#endforeach
</select>
But what should I do after they pick a category? Is it better to do the AJAX call to send the ID of picked category and returns the subcategory or what?
I need the best and professional way to do this.
In my Database I have
ID, name, parent
Use ajax, after selecting the category send the ajax request and to do this you need to use change event on your select, for example:
// Assumed category is id of the select
$('#category').on('change', function(){
var id = $(this).val();
$.getJSON("subcategory/" + id , function(data){
// Assumed subcategory is id of another select
var subcat = $('#subcategory').empty();
$.each(data, function(k, v){
var option = $('<option/>', {id:k, value});
subcat.append(option);
});
});
});
On the server side, create a route like this (You may use a controller and Eloquent):
Route('subcategory/{id}', function($id){
// Get the data from database according to the id
// Build an array as: id => value and then return
return Response::json($subcat);
});
Populate a dropdown on selecting an option from another dropdown Laravel
This might surely help you. Otherwise ask if you do not understand
select_cat.php
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(".category").change(function()
{
var id=$(this).val();
var dataString = 'id='+ id;
$.ajax
({
type: "POST",
url: "select_subcat.php",
data: dataString,
cache: false,
success: function(html)
{
$(".subcat").html(html);
}
});
});
});
</script>
Category :
<select name="category" class="category">
<option selected="selected">--Select Category--</option>
<?php
include('databasefile');
mysql_connect($server,$username,$password)or die(mysql_error());
mysql_select_db($database)or die(mysql_error());
$sql=mysql_query("select cat_name from category order by cat_name");
while($row=mysql_fetch_array($sql))
{
$cname=$row['cat_name'];
echo '<option value="'.$cname.'">'.$cname.'</option>';
} ?>
</select> <br/><br/>
SubCategory :
<select name="subcat" class="subcat">
<option selected="selected">--Select SubCat--</option>
</select>
2.select_subcat.php
<?php
include('databasefile);
mysql_connect($server,$username,$password)or die(mysql_error());
mysql_select_db($database)or die(mysql_error());
if($_POST['id'])
{
$id=$_POST['id'];
$sql=mysql_query("select s_name from subcat_l1 where cat_name='$id'");
while($row=mysql_fetch_array($sql))
{
$sname=$row['s_name'];
echo '<option value="'.$sname.'">'.$sname.'</option>';
}
}
?>
SubCategory :
<select name="subcat" class="subcat">
<option selected="selected">--Select SubCat--</option>
</select>

How to display the data came from controller/model using Ajax process?

I have a problem here about ajax. Actually I'm a beginner in using Ajax that's why I can't figure out my problem. I have a form that have 4 select boxes. The initial or main selectbox is the country selector. Second is the state next is city and last is barangay. My goal is like this. After the user select his'her country the second selectbox which is state will automatically change according to the user's country. And after selecting the state it will automatically change also the city and last is the barangay. It is just like a dynamic address fields. I am using codeigniter. Here's what I did. This is the process for getting the state.
In my PHP form I have this:
<tr>
<td><label style="font-weight: normal">State / Province: </label></td>
<td >
<select class="form-control" name="c_state" id="c_state">
<option value="">--Select State--<option>
</select>
</td>
</tr>
<tr>
<td><label style="font-weight: normal">Country: </label></td>
<td >
<select class="form-control" name="c_country" id="c_country">
<option value="">--Select Country--</option>
<?php
foreach($countries as $country){
if($country['country'] == 'Philippines'){
echo "<option value='".$country['code']."'selected='selected'>".$country['country']."</option>";
}else{
echo "<option value='".$country['code']."'>".$country['country']."</option>";
}
}
?>
</select>
</td>
</tr>
....
$("#c_country").on('change',function(){
var c_country = $("#c_country").val();
var var_country_selection = '<?php echo site_url("alliance_controller/get_provinces/'+c_country+'"); ?>';
console.log(c_country);
$.ajax({
type: 'POST',
url: var_country_selection,
data: { id: $(this).val() },
dataType: 'json',
success: function(d){
alert(d['c_country']);
}
});
});
In my controller I have this:
public function get_provinces($id){
$country = $this->alliance_model->hhj_provinces($id);
echo json_decode($country);
}
In my model I have this:
public function hhj_provinces($id) {
$query = "SELECT * FROM ref_region_province WHERE country_code = '".$id."'";
$result = $this->db->query($query);
echo json_encode($result->result_array());
}
The output in the success in jquery which is in alert is 'undefined'. And I also use the developer tool in Chrome and I looked in the Network tab it shows the URL of my ajax together the Code. But in my preview I have something like this.
[]
No Properties
That's all guys. I just want to get the state of the country selected.
you must return a JSON object in the controller like this
public function get_provinces(){
$id = $this->input->post('id');
$country = $this->alliance_model->hhj_provinces($id);
$this->output->set_content_type('application/json');
$this->output->set_output(json_encode( $country));
}
then in the View
$.ajax({
type: 'POST',
url: var_country_selection,
data: { id: $(this).val() },
dataType: 'json',
success: function(data){
$.each(data, function (key, value) {
console.log(value.field)
}
});

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