I'm not sure why this modal isn't populating the post ajax data. Its actually supposed to update a row in my SQL DB upon success but the error I'm getting is "Uncaught TypeError: Cannot read property 'value' of null." Does anyone have any idea why this failing?
Updated: I apologize for leaving out the php which generated the partners item.
HTML:
while($row = mysqli_fetch_array($partners)) {
// $optionsPartners .="<option>" . $row['Partners'] . "</option>";
$optionsPartners.="<input type='checkbox' name='Partners[]' value=".$row['Partners']."> ".$row['Partners']."<br>";
}
$partnersmenu=
/*"<select name='Partners' id='Partners'>
" . $optionsPartners . "
</select>"*/
$optionsPartners;
?>
<div id="id02" class="modal">
<span onclick="document.getElementById('id02').style.display='none'"
class="close" title="Close Modal">×</span>
<!-- Modal Content -->
<form class="modal-content animate" action="modify_records.php" method="post">
<div class="container">
<h3>Edit an Existing Project</h3>
<label for="Project_Name" class="ui-hidden-accessible">Project Name:</label>
<input type="Project_Name" name="Project_Name" id="Project_Name" placeholder="Project Name">
<br><br>
<label for="Partners" class="ui-hidden-accessible">Partners:</label>
<?php
echo $partnersmenu;
?>
<br><br>
<input type="button" id="edit_button<?php echo $row['id'];?>" class="btn" value="Submit" data-dismiss="modal" onclick="edit_row('<?php echo $row['id'];?>');">
<button type="button" onclick="document.getElementById('id02').style.display='none'" class="cancelbtn">Cancel</button>
</div>
<div class="container" style="background-color:#f1f1f1">
</div>
</form>
</div>
PHP:
if(isset($_POST['edit_row']))
{
$row=$_POST['id'];
$Project_Name=$_POST['Project_Name'];
$Partners=$_POST['Partners'];
mysqli_query($conn,"update Project_Detail set Project_Name='$Project_Name',Partners='$Partners' where id=$row");
echo "success";
exit();
}
JS:
function edit_row(id)//save_row(id)
{
//var id=document.getElementById("id"+id).value;
var id=document.getElementById("id"+id);
var Project_Name=document.getElementById("Project_Name"+id).value;
var Partners=document.getElementById("Partners"+id).value;
$.ajax
({
type:'post',
url:'modify_records.php',
data:{
edit_row:'edit_row',
id:id,
Project_Name:Project_Name,
Partners:Partners,
},
success:function(response) {
if(response=="success")
{
//document.getElementById("id"+id).innerHTML=id;
document.getElementById("Project_Name"+id).innerHTML=Project_Name;
document.getElementById("Partners"+id).innerHTML=Partners;
//document.getElementById("edit_button"+id).style.display="block";
// document.getElementById("save_button"+id).style.display="none";
}
},
error: function(response) {
alert("some error");
}
});
}
I see a few problems and they all pertain to how you are calling you elements in your javascript and how your elements are labeled in your html.
Example:
<input type="Project_Name" name="Project_Name" id="Project_Name" placeholder="Project Name">
Should look like this:
<input type="text" name="Project_Name" id="Project_Name<?php echo $row['id']; ?>" placeholder="Project Name">
Look through all your elements and then look through your js so your are calling the correct ids.
Also in your html I copied in above, I changed the type to "text".
Also, I do not see an element with the id of "Partners" let alone "Partners" + id.
Hope that helps.
try
var id=document.getElementById("id");
instead of
var id=document.getElementById("id"+id);
Related
I have a webpage with dynamically loaded cards that pop up into individual modals to display more data. These modals all have their unique id in order to pop up the correct one.
I am attempting to put a unique comment section for each modal. What I have implemented works only for the first modal & doesnt even show the comments on the second modal onwards.
I would appreciate some direction in how to make them display per modal & how to make them unique. I am assuming I echo $test[id] just like I used for the modals. Need a little assistance in script side of things.
<div id="myModal<?php echo $test['id']; ?>" class="modal">
<div class="modal-content">
<div class="container">
<form method="POST" id="comment_form">
<input type="hidden" id="id" name="id" value="<?php echo $test['id']; ?>">
<div class="form-group">
<input type="text" name="comment_name" id="comment_name" class="form-control" placeholder="Enter Name" />
</div>
<div class="form-group">
<textarea name="comment_content" id="comment_content" class="form-control" placeholder="Enter Comment" rows="5"></textarea>
</div>
<div class="form-group">
<input type="hidden" name="comment_id" id="comment_id" value="0" />
<input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
<span id="comment_message"></span>
<br />
<div id="display_comment<?php echo $test['id']; ?>"></div>
</div>
</div>
</div>
<script>
var data = 1;
$(document).ready(function(){
$('#comment_form').on('submit', function(event){
event.preventDefault();
var form_data = $(this).serialize();
$.ajax({
url:"add_comment.php",
method:"POST",
data:form_data,
dataType:"JSON",
success:function(data)
{
if(data.error != '')
{
$('#comment_form')[0].reset();
$('#comment_message').html(data.error);
$('#comment_id').val('0');
load_comment();
}
}
})
});
load_comment();
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment').html(data);
}
})
}
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
</script>
UPDATE:
Going with the response received, I made certain changes & noticed that even though the comment form is visible on all modals, the posted comments itself
only appear on the first modal. With a bit of hardcoding I am able to tell that the display_comment(id) in html & script needs to be same. The HTML id updates as per console, but I am unable to pass the correct id to $('#display_comment'+myData1).html(data); (it is always 1).
<div id="myModal<?php echo $test['id']; ?>" class="modal">
<div class="modal-content">
<div class="container">
<form method="POST" id="comment_form">
<input type="hidden" id="id" name="id" value="<?php echo $test['id']; ?>">
<div class="form-group">
<input type="text" name="comment_name" id="comment_name" class="form-control" placeholder="Enter Name" />
</div>
<div class="form-group">
<textarea name="comment_content" id="comment_content" class="form-control" placeholder="Enter Comment" rows="5"></textarea>
</div>
<div class="form-group">
<input type="hidden" name="comment_id" id="comment_id" value="0" />
<input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
<span id="comment_message"></span>
<br />
<div id="display_comment<?php echo $test['id']; ?>"></div>
</div>
<div id="dom-target" style="display: none;" data-id="<?php echo htmlspecialchars($test['id']);?>">
<?php
echo htmlspecialchars($test['id']);
?>
</div>
</div>
<script>
$(document).ready(function(){
$('#comment_form').on('submit', function(event){
event.preventDefault();
var form_data = $(this).serialize();
$.ajax({
url:"add_comment.php",
method:"POST",
data:form_data,
dataType:"JSON",
success:function(data)
{
if(data.error != '')
{
$('#comment_form')[0].reset();
$('#comment_message').html(data.error);
$('#comment_id').val('0');
load_comment();
}
}
})
});
load_comment();
function load_comment()
{
var myData1 = $("#dom-target").data("id");
console.log('#display_comment'+myData1);
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment'+myData1).html(data);
}
})
}
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
</script>
I have also tried the following & simply receive undefined as the value in console for myData2:
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {
myData2: $("#dom-target").data("id")
},
you should loop all the content according to your $test['id'].
each loop will generate each $test['id'], modals, form.
therefore, you will have multiple form according to each modals.
regarding the name of the input box (name="comment_id","comment_name" etc), just use the same name, as this will affect your backend on how you will process those input ($_POST['']).
this shouldn't be an issue if you area using same input name as user can only submit 1 form on each request.
just the value will be changing based on the form.
I will try to explain my code simple. Basicly I got 2 different files:
fun.php
class.fun.php
I want to post my forms with ajax, so it won't refresh page.
In class.fun.php I have got reportForm for each post.
<!-- REPORT MODAL -->
<div class="modal fade report_post_<?php echo $post['id'];?>" tabindex="-1" role="dialog" aria-hidden="true">
<div class="modal-dialog modal-lg">
<div class="modal-content">
<b><center><div class="modal-header">Report Post</div></center></b>
<form class="horiziontal-form" id="reportForm" action="../Pages/fun.php?action=reportPostForm" method="post">
<center><textarea name="report" style="width:80%; height:200px; margin-top:20px; resize:vertical;" placeholder="Please describe your Report!"></textarea></center>
<input type="hidden" name="addedby" class="form-control col-md-7 col-xs-12" value="<?php echo $myRow['id']; ?>" />
<input type="hidden" name="image_id" class="form-control col-md-7 col-xs-12" value="<?php echo $post['id']; ?>" />
<div class="modal-footer"> <input type="submit" name="submit" value="Submit Form" /></div>
</div>
</div>
</form>
</div>
<!-- END OF REPORT MODAL -->
And after form I got ajax function:
<script>
$("#reportForm").submit(function(event){
event.preventDefault(); //prevent default action
var post_url = $(this).attr("action"); //get form action url
var request_method = $(this).attr("method"); //get form GET/POST method
var form_data = $(this).serialize(); //Encode form elements for submission
$.ajax({
url : post_url,
type: request_method,
data : form_data
}).done(function(response){ //
$("#server-results").html(response);
});
});
</script>
When I click button submit I want to send form data to fun.php
This is how I receive data in fun.php
if(isset($_POST['reportPostForm'])){
$image_id = strip_tags($_POST['image_id']);
$report = strip_tags($_POST['report']);
$addedby = strip_tags($_POST['addedby']);
$fun->reportPost($image_id,$report,$addedby);
}
And send them to other function in class.fun.php
But at this moment nothing happens. I have been looping trought many
tutorials and can't understand how to make this work. Im newbie in
javascript. I have got working upvote/downvotes scripts where I pass only post_id and it works.
I have got script for upvote that works:
$("#upvote_<?php echo $post['id'];?>").click(function(){
$.ajax(
{ url: "fun.php?upvote-btn=true?action=select&image_id=<?php echo $post['id'];?>",
type: "get",
success: function(result){
$('#upvote_<?php echo $post['id'];?>').load(document.URL + ' #upvote_<?php echo $post['id'];?>');
$('#downvote_<?php echo $post['id'];?>').load(document.URL + ' #downvote_<?php echo $post['id'];?>');
$('#comment_<?php echo $post['id'];?>').load(document.URL + ' #comment_<?php echo $post['id'];?>');
$('#share_<?php echo $post['id'];?>').load(document.URL + ' #share_<?php echo $post['id'];?>');
$('#report_<?php echo $post['id'];?>').load(document.URL + ' #report_<?php echo $post['id'];?>');
$('#report_btn_<?php echo $post['id'];?>').load(document.URL + ' #report_btn_<?php echo $post['id'];?>');
document.getElementById("result-box").innerHTML = result;
}
});
});
On fun.php you are checking for $_post['reportPostForm'] but this is not sent via post on this ajax call. your firm doesn't have this inputime and that's why nothing is happening. Try if(isset($_POST['report'])
Change this:
if(isset($_POST['report'])){
$image_id = strip_tags($_POST['image_id']);
$report = strip_tags($_POST['report']);
$addedby = strip_tags($_POST['addedby']);
$fun->reportPost($image_id,$report,$addedby);
echo "Done";
}
Also add the <div id='server-results'></div> to your form so that you can show the resutls.
<div class="modal-dialog modal-lg">
<div class="modal-content">
<b>
<center>
<div class="modal-header">Report Post</div>
</center>
</b>
<form class="horiziontal-form" id="reportForm" action="../Pages/fun.php?action=reportPostForm" method="post">
<center>
<textarea name="report" style="width:80%; height:200px; margin-top:20px; resize:vertical;" placeholder="Please describe your Report!"></textarea>
</center>
<input type="hidden" name="addedby" class="form-control col-md-7 col-xs-12" value="<?php echo $myRow['id']; ?>" />
<input type="hidden" name="image_id" class="form-control col-md-7 col-xs-12" value="<?php echo $post['id']; ?>" />
<div class="modal-footer">
<input type="submit" name="submit" value="Submit Form" />
</div>
</div>
</div>
<div id='server-results'></div>
</form>
</div>
It is not very clear what is not working.
The file is correct.
Only problem is in fun.php as you do:
if(isset($_POST['reportPostForm'])){
$image_id = strip_tags($_POST['image_id']);
$report = strip_tags($_POST['report']);
$addedby = strip_tags($_POST['addedby']);
$fun->reportPost($image_id,$report,$addedby);
}
But you are sending $_POST['addedby'], $_POST['image_id'] and $_POST['report'].
The one you are checking $_POST['reportPostForm'] do not exists.
Try to do the if against one of the three values you are passing.
Have been working on a form with Ajax and used to work on a version with no extras (css and so on) before. It worked all fine, data has been inserted successfully into the database and I have been able to show and hide two divs.
Now I used to apply it to the form I've been working on. It acts different from the previous version, so it's exactly the same (sure, changed some names, added some inputs), like no "success message" from the PHP-file, suddenly all data visible in the URL, the current form doesn't hide and shows the next one.
I can't understand the sudden change in behavior, took a look for mistakes, compared the codes, but have no idea. It seems to be such a small mistake that I don't spot it or something is wrong with the whole construction.
The current file is:
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<?
require 'config.php';
session_start();
// Check if user is logged in using the session variable
if ( $_SESSION['logged_in'] != 1 ) {
$_SESSION['message'] = "You must log in before viewing your profile page!";
header("location: error.php");
}
else {
// Makes it easier to read
$id = $_SESSION['id'];
$name = $_SESSION['name'];
$email = $_SESSION['email'];
$active = $_SESSION['active'];
$hash = $_SESSION['hash'];
}
?>
<script type="text/javascript">
function getState(val) {
$.ajax({
type: "POST",
url: "demo_ajax.php",
data:'country_id='+val,
success: function(data){
$("#region").html(data);
}
});
}
$(document).ready(function(){
$("#submit").click(function(){
var size=$("#size").val();
var industry=$("#industry").val();
var country=$("#country").val();
var region=$("#region").val();
var url=$("#website").val();
var fb=$("#fb").val();
var lkdn=$("#lkdn").val();
$.ajax({
type:"post",
url:"process2.php",
data:"size="+size+"&industry="+industry+"&country="+country+"®ion="+region+"&url="+url+"&fb="+fb+"&lkdn="+lkdn,
success:function(data){
$("#theform").hide();
$("#info").html(data);
//$("#partone").css();
$("#partone").show();
alert("Hello");
}
});
});
});
</script>
<?php include 'js/js.html'; ?>
<?php include 'css/css.html'; ?>
</head>
<body class="w3-blue r_login_corp_body">
<div id="info" style="color:white"></div>
<div class="r_login_corp_body"></div>
<div class="w3-content w3-white r_siu r_centered_div">
<header class="w3-camo-black w3-container">
<div class="w3-container ">
<span class="w3-xlarge r_caption">eRecruiter</span> <span class="large">Corporate Login</span>
</div>
<div class="w3-black">
<a href="javascript:void(0)" onclick="selectForm('register');">
<div class="w3-half tablink w3-hover-text-yellow w3-padding w3-center w3-padding-16">Register</div>
</a>
</div>
</header>
<!-- Register -->
<div id="register" role="form" class="r_form_elements">
<form name="formone" class="form" autocomplete="off">
<div id="profed" class="w3-container w3-padding-16">
<div class="alert alert-error"></div>
<label>Company Industry</label>
<input class="w3-input" name="industry" id="industry" type="text" placeholder="Your Industry" >
<label>Company Size</label>
<input class="w3-input" name="size" id="size" type="integer" placeholder="Your Company Size" >
<label >Country:</label>
<select name="country" id="country" class="demoInputBox" onChange="getState(this.value);" >
<option value="">Select Country</option>
<?php
$sql1="SELECT * FROM pentagonal_country";
$results=$mysqli->query($sql1);
while($rs=$results->fetch_assoc()) {
?>
<option value="<?php echo $rs["country_code"]; ?>"><?php echo $rs["country_name"]; ?></option>
<?php
}
?>
</select>
<label>State:</label>
<select id="region" name="region" onKeyup="checkform()">
<option value="">Select State</option>
</select>
<label>Website</label>
<input class="w3-input" name="website" id="website" type="url" placeholder="Your Website-Address" >
<label>Facebook</label>
<input class="w3-input" name="fb" id="fb" type="url" placeholder="https://facebook.com/" >
<label>Linkedin</label>
<input class="w3-input" name="lkdn" id="lkdn" type="url" placeholder="https://linkedin.com/in/">
</div>
<div class="w3-row">
<button type="submit" id="submit" class="w3-button w3-black w3-half w3-hover-yellow" >Add</button>
<button class="w3-button w3-black w3-half w3-hover-pale-yellow">Forgot Password</button>
</div>
</form>
</div>
<!-- Register -->
<div id="partone" style="display:none">
<form>
name : <input type="text" name="name" id="name">
</br>
message : <input type="text" name="message" id="message">
</br>
</br>
name : <input type="text" name="url" id="url">
</br>
message : <input type="text" name="fb" id="fb">
</br>
name : <input type="text" name="lkdn" id="lkdn">
</br>
</br> </br>
Send;
</form>
</div>
</div>
</body>
</html>
and the PHP-file to insert data is:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "remotejobs";
session_start();
// Check if user is logged in using the session variable
if ( $_SESSION['logged_in'] != 1 ) {
$_SESSION['message'] = "You must log in before viewing your profile page!";
header("location: error.php");
}
else {
// Makes it easier to read
$id = $_SESSION['id'];
$name = $_SESSION['name'];
$email = $_SESSION['email'];
$active = $_SESSION['active'];
$hash = $_SESSION['hash'];
}
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$industry=$_POST["industry"];
$size=$_POST["size"];
$country=$_POST["country"];
$region=$_POST["region"];
$website=$_POST["url"];
$fb=$_POST["fb"];
$lkdn=$_POST["lkdn"];
$usrid=$id;
$sql = "INSERT INTO corp_user_profile (id, industry, size, nation, region, url, facebook, linkedin)
VALUES ('$usrid', '$industry','$size', '$country', '$region', '$website', '$fb', '$lkdn')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
I used to work with the previous file I've worked with just to be sure that everything's right after a week of bug fixing.
Can somebody tell me where the problem is, probably why it is a mistake to avoid future problems like this?
The most obvious bug (aside from the SQL injection stuff mentioned above) is that
<button type="submit" will cause the form to submit normally via postback, unless you prevent it using script. Add event.preventDefault() to the first line of your "click" handler.
$("#submit").click(function(event){
event.preventDefault(); //prevent default postback behaviour
var size=$("#size").val();
//...etc
You're seeing the data in the URL because the form is posting normally (before the ajax has chance to run) and doing a GET because there's no other method specified in the form's markup, and GET is the default..
You may want to prevent the default behavior by passing the event to your click function and calling event.preventDefault().
I've put a modal popup box for getting inputs and then stores via ajax. It's inserted values succesfully.. but the popup stills after submittion. i've try everything like window.close(); ... ('#modalname').hide(); but nothing works for me. please help me to fix this bug.
Here's my part of working code,
<!--css for display subject in row (starts)-->
<span class="b-messages__subject">
<span>
<a href="index.php?subject=<?php echo $results[$result]['subject']; ?>&username=<?php echo $results[$result]['username']; ?>#openModal" onclick="fetch_select(<?php echo $results[$result]["id"]; ?>);">
<?php echo "Reply"; ?>
</a>
</span>
</span>
<!--css for display subject in row (ends)-->
and then modal div is,
<!--Modal box starts-->
<div id="openModal" class="modalDialog" align="center">
<div>
X
<h2><strong>Reply Message</strong></h2>
<br>
<label><strong>Enter Your Message Here</strong></label>
<br>
<label><b>From:</b> <?php echo $user; ?></label>
<span id="content-info" class="info"></span>
<br/>
<!--set session username for hidden-->
<input type="hidden" name="username" id="username" value="<?php echo $user; ?>">
<textarea name="content" id="content" class="demoInputBox"></textarea>
<!--send fusername with hidden-->
<input type="text" name="fusername" id="fusername" value="<?php echo $_GET["username"] ?>">
<!--send subject with hidden-->
<input type="text" name="subject" id="subject" value="<?php echo $_GET["subject"] ?>">
<!--status init="0"-->
<input type="hidden" name="status" id="status" value="0">
<!--time-->
<input type="hidden" name="created" id="created" value='<?php echo date("Y-m-d H:i:s"); ?>'>
<br><br>
<input type="button" name="submit" id="but-sub" value="Send Message" onClick="add();" />
</div>
</div>
<!--Modal box ends-->
My js file contains:
function add() {
/*initialize valid and assign to function validate()*/
var valid = validate();
//alert(valid); returns true
//if function validate() returns valid.. then go away
if (valid){
$.ajax({
url: "add.php",
type: "POST",
data: {
username: $("#username").val(),
fusername: $("#fusername").val(),
subject: $("#subject").val(),
content: $("#content").val(),
status: $("#status").val(),
created: $("#created").val()}
});
}
}
I am not sure if you are using JSON, but you should definitely be checking the response for pass or fail. Try adding success after your data like this (doesn't include check for pass or fail, but should close modal upon success response of the AJAX):
$.ajax({
url: "add.php",
type: "POST",
data: {
username: $("#username").val(),
fusername: $("#fusername").val(),
subject: $("#subject").val(),
content: $("#content").val(),
status: $("#status").val(),
created: $("#created").val()
},
success: function (returndata) {
//try this first
$("#openModal").modal('hide');
//try this second and uncomment if you aren't using jquery/bootstrap modal
//$("#openModal").hide();
}
});
Put your form elements in a <form></form>.
The modal should close if form is submited.
I've got a forum in which user is allowed to edit and delete only his comments, I've defined an "edit" button, that by a click of mouse brings down a modal, and in that modal user is allowed to get access to the data's he/she has been sent before, I've written an ajax to target these field and update them whenever the users clicks on "edit" button, code totally makes sense, but so far the functionality doesn't, to make it more clear, user clicks, modal comes down, whatever he/she has been posted will appear in fields, and there is an "edit" button at the bottom of modal, which is responsible for changing and updating data. here is the modal code :
<button id="btn-btnedit" class="btn btn-primary " data-toggle="modal" data-target="#myModal<?php echo $list['id']; ?>">
Edit <i class="fa fa-pencil-square-o"></i>
</button>
<!-- Modal -->
<div class="modal fade" id="myModal<?php echo $list['id']; ?>" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal"><span aria-hidden="true">×</span><span class="sr-only">Close</span></button>
<h4 class="modal-title" id="myModalLabel">Modal title</h4>
</div>
<div class="modal-body">
<div class="container">
<form style="width: 550px;" action="" method="post" id="signin-form<?php echo $list['id']; ?>" role="form">
<input type="hidden" name="commentID" value="<?php echo $list['id']; ?>">
<div class="from-group">
<label for="title">Title: </label>
<input class="form-control" type="text" name="title" id="txttitle" value="<?php echo $list['title']; ?>" placeholder="Page Title">
</div>
<div class="from-group">
<label for="label">Label: </label>
<input class="form-control" type="text" name="label" id="txtlabel" value="<?php echo $list['label']; ?>" placeholder="Page Label">
</div>
<br>
<div class="from-group">
<label for="body">Body: </label>
<textarea class="form-control editor" name="body" id="txtbody" row="8" placeholder="Page Body"><?php echo $list['body']; ?></textarea>
</div>
<br>
<input type="hidden" name="editted" value="1">
<br>
<br>
<input type="submit" id="btnupdate" value="Edit">
</form>
</div>
</div>
as you can see I've assigned "editted" to my "name" attribute, which is later on used to call the query in the database, sql code is as below :
case 'postupdate';
if(isset($_GET['editted'])){
$title = $_GET['title'];
$label = $_GET['label'];
$body = $_GET['body'];
$action = 'Updated';
$q = "UPDATE posts SET title ='".$title."', label = '".$label."', body = '".$body."' WHERE id = ".$_GET['commentID'];
$r = mysqli_query($dbc, $q);
$message = '<p class="alert alert-success"> Your Post Is Succesfully '.$action.'</p>' ;
}
and here is the ajax code snippet;
$('#btnupdate').click(function() {
var tempTitle = $('#txttitle').val();
var tempLabel = $('#txtlabel').val();
var tempBody = $('#txtbody').val();
var tempUrl = "index.php?page=postupdate"+"&title="+tempTitle+"&label="+tempLabel+"&body="+tempBody+"&commentID=30&editted=1";
$.get(tempUrl);
});
I assume there is nothing advance about this segment of code, and i'm missing something very simple, any consideration is highly appreciated :)
This (untested code) may be similar to what you should do:
$('#btnupdate').click(function() {
var tempTitle = $('#txttitle').val();
var tempLabel = $('#txtlabel').val();
var tempBody = $('#txtbody').val();
var tempParams = {"page":"postupdate","title":tempTitle,"label":tempLabel,"body":tempBody,"commentID":30,"editted":1};
$.post("index.php",tempParams,function(data) {
alert(data);
});
});
UPDATE
Try ajax instead of get to see if some error occurs in the loading
$.ajax( {url:"index.php",data:tempParams,type: "POST"} ).done(function() {
alert( "success" );
}).fail(function() {
alert( "error" );
}).always(function() {
alert( "complete" );
});`
UPDATE
Start testing if the click handler works then (just to be sure!):
$('#btnupdate').click(function() { alert("yes at least the button was pressed"); });
UPDATE
Start testing if the script gets executed then:
alert("yes at least the script gets executed");
$('#btnupdate').click(function() { alert("yes at least the button was pressed"); });
If not you must have a javascript error somewhere.
https://webmasters.stackexchange.com/questions/8525/how-to-open-the-javascript-console-in-different-browsers
If yes, your button does not get caught by JQuery (no idea why)
anyway it's got nothing to do with ajax or get!