Is that possible to output some php code, in JS, than includes a php template when clicked on a buton? I am trying the following way like below without success. How can i do it?
$("#show").one('click', function () {
$("#showTemplate").html("<?php require_once 'php-template.php'; ?>")
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id = "showTemplate"> </div>
<button id="show"></button>
Use ajax instead and since you want to output some php code then you'll have to set the header from your php template to text/plain.
$.ajax ({
url: 'php-template.php',
type: 'get',
dataType: 'text',
success: function (data){
$('#showTemplate').html (data);
});
})
And in your php template, you'll need to set the header,
header ('Content-Type: text/plain');
Related
when clicking （.refresh）button、how would you pass $data_name to ajax which you'll get by for() in body field of php script?
I would like to pass the variable for selecting data from database.
2Scripts:
(1) html formated .php file>
ajax written in header field,
php for() written in body field
(2) SQL select script in php, added
$dataname= $_POST['dataname'];
In for() I'm getting data from DB and showing data tables, DATA A～C.
When clicking the button for each data, I would want to get the new data from data base.
I was able to get it, just writting "A" for Ajax, but I would want to pass variable for many tables.
[enter image description here][1]
[1]: https://i.stack.imgur.com/zpJ7B.png
<head>
<script>
$(document).ready(function(){
$('.refresh').click(function(){
$.ajax({
// 通信先ファイル名
url: "select.php",
type: "POST",
data: ({"data_name": $data_name}),
success: function(data) {
//more code
},
error: function(data) {
//more code
}
});
</script>
</head>
<body>
<?php
//more code for(){ getting $data_name（A、B、C）here >
echo <<<EOD
<button class='refresh'>REFRESH DATA</button>
<table class='show'></table>
EOD;
?>
</body>
You can use a different PHP to return the JSON or the same.
So if you want to use the same script you basically want to send a JSON with the data when your PHP script gets a POST.
So you have to check:
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// The request comes from Javascript doing POST
// Query Database and return a JSON with the field "data_name"
} else {
// Render your form like now you're doing now, the request com from the browser loading the page
}
//select.php
<?php
$data= $_POST["data_name"];
echo json_encode( $data);
?>
<script>
$(document).ready(function(){
$('.refresh').click(function(){
$.ajax({
// 通信先ファイル名
url: "select.php",
type: "POST",
data: ({"data_name": $data_name}),
success: function(data) {
// getting $data_name（A、B、C）here
},
error: function(data) {
//more code
}
});
</script>
I try to get post data from using alert() and its worked problem is that data is not passing to php page result is always {"success":false,"result":0}
What I want is send password to php page and hash it using password_hash() and return result
$('#spass').on('submit',function(){
var that=$(this),
contents=that.serialize();
alert(contents);
$.ajax({
url:'passwordhashing.php',
dataType:'json',
data:contents,
success:function(data){
alert(JSON.stringify(data));
console.log(data);
}
});
return false;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="spass" >
<h4>Change Your Password</h4>
<input type='password'name="passc" >
<!--<input type='password' name="cpass" id="cpass"> -->
<input type="submit">
</form>
**this my php code**
<?php
header('Content-type: text/javascript');
$json=array(
'success'=>false,
'result'=>0
);
if(isset($_POST['passc']) && !empty($_POST['passc'])) {
$pass=password_hash($_POST['passc'],PASSWORD_DEFAULT);
$json['success']=true;
$json['result']=$pass;
}
echo json_encode($json);
?>
You can test that your data has not actually been passed to a PHP page.
In the PHP code, do the following: echo $ _POST ['YOUR_VARIABLE'].
Check the INSPECT_ELEMENT / NETWORK browser to make sure you actually send data to the correct link. Your link may be relative, so you may be sending data to the wrong link.
So, try to put the entire link in the ajax url
$ .ajax ({
url: 'HTTP: //WHOLE_LINK_IN_HERE.COM/passwordhashing.php',
});
SET method in Ajax: type: "POST"
$.ajax({
type: "POST",
url: url,
data: data,
success: success,
dataType: dataType
});
**i used $.post() instead of using $.ajax() and it fix my problem**
$('#spass').on('submit',function(){
var that=$(this),
contents=that.serialize();
alert(contents);
$.post({
url:'passwordhashing.php',
dataType:'json',
data:contents,
success:function(data){
alert(JSON.stringify(data));
console.log(data);
}
});
return false;
});
i want to send/pass data from the client to server by (ajax to php) but when i try this code
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
type: 'post',
url: 'loo.php',
data: { data: 'some data' },
success: function(response,w) {
console.log(w);
}
});
</script>
<?php
echo $_POST['data'];
?>
in my browser i got success print out which mean that the javascript code is working fine i guess , by in php i got Undefined index
p.s my file name is loo.php all the code is in the same file
edit: i have tried to separate my files like this:
my loo.php file:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
type: 'post',
url: 'test.php',
data: {data: 'some data'},
success: function (response, w) {
console.log(w);
}
});
</script>
my test.php file:
<?php
echo $_POST['data'];
?>
still got undefined index
p.s. i navigate Manual to test.php file after i run loo.php file
You get this error because when loading the page the POST request has not yet been sent. So show the submitted data only if it exists, otherwise, show the JavaScript code.
<?php
if (isset($_POST['data'])) {
die($_POST['data']);
}
?>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
type: 'post',
url: 'loo.php',
data: {data: 'some data'},
success: function (response, w) {
console.log(w);
}
});
</script>
Try this.
<?php
$data = json_decode(file_get_contents('php://input'), true);
echo $data['data'];
?>
Try this
Html file
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="data_value"></div>
<script type="text/javascript">
$( document ).ready(function() {
$.ajax({
type: 'post',
url: 'loo.php',
data: { data: 'some data' },
success: function(response,w) {
$("#data_value").html(response);
}
});
});
PHP file (loo.php)
<?php
print_r($_POST);
?>
try to change the handler this way:
if(isset($_POST['data'])){
function return_data() {
die(json_encode($_POST['data'])));
}
return_data();
}
Answer after you edit the question:
$_POST is the array sent by the HTTP Post request. so if the request to the page named test.php or whatever is not HTTP POST Request the $_POST array will be empty. but the $_GET array may have some data if you sent them.
and navigation to a page is a get request to that page unless you used a form with method="post".
so what you are doing with ajax call is correct. but navigating to test.php manually without a form with post method is not gonna fill the $_POST array.
because when you make the Ajax call, it is done, it just makes the post-call correctly and everything is ok but when you navigate to that page it is a get request and it won't fill the $_POST array.
to do so, you don't need ajax at all. you can have this form
<form method="POST" action="test.php">
<input type="text" name="data" value="some data" />
<input type="submit" value="submit" />
</form>
so either you use ajax and handle whatever you want to handle in the ajax success method. or use form and send the request to the page and handle it there.
the answer to the question before the edit
If they are in the same file it won't work like that, because when the file loads the $_POST['data'] is not exists at all, and after you run the ajax call, it exists within that call, not in your browser window.
so you can check if $_POST['data'] exists so you are sending it from ajax call so you can return it and use it inside your ajax success function.
conclusion:
you cannot put them in the same file and expect ajax will load before the actual php.
it will first load the whole file then it will run the ajax.
the undefined index is from the server before you even see the HTML page.
A solution could be:
File with your html and ajax functions index.html
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
type: 'post',
url: 'loo.php',
data: { data: 'some data' },
success: function(response,w) {
// use the response here
console.log(w);
}
});
</script>
and another with your logic loo.php
<?php
header("Content-Type: text/plain"); // if you want to return a plain text
// if you want to return json it could be header('Content-type: application/json');
echo isset($_POST['data'])? $_POST['data']: ''
?>
this is my html code:
<form id="form" action="javascript:void(0)">
<input type="submit" id="submit-reg" value="Register" class="submit button" onclick="showtemplate('anniversary')" style='font-family: georgia;font-size: 23px;font-weight: normal;color:white;margin-top:-3px;text-decoration: none;background-color: rgba(0, 0, 0, 0.53);'>
</form>
this is my javascript code:
function showtemplate(temp)
{
$.ajax({
type: "POST",
url: 'ajax.php',
data: "section="+temp ,
success: function(data)
{
alert(data);
}
});
}
this is my ajax.php file:
<?php
$ajax=$_POST['section'];
echo $ajax;
?>
The above html and javascript code is included in a file named slider.php. In my index file i have included this slider.php file and slider.php is inside slider folder. So basically index.php and slider.php are not inside the same folder.
Javascript code alerts the data properly. But in my php code (ajax.php file) the value of $_POST['section'] is empty. What is the problem with my code. I tried googling everything and tried a few codes but it still doesn't work. Please help me out
Try this instead:
$.ajax({
type: "POST",
url: 'ajax.php',
data: { 'section': temp},
success: function(data)
{
alert(data);
}
});
It is quite possible that your server does not understand the string you have constructed ( "section="+temp ). When using ajax I prefer sending objects since for an object to be valid it requires a certain format.
EDIT1:
Try this and let me know if it doesn't work either:
$.post('ajax.php', {'section': temp}, function(data}{
alert(data);
});
Add jquery plugin(jQuery library) ,then only ajax call works
for eg
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
check your input data , whether it contain '&,/' charators,then use encodeURIComponent()
for Ajax Call Eg:
var gym_name = encodeURIComponent($("#gym_name").val());
$.ajax({
type: "POST",
url: "abc.php",
data:string_array,
success: function(msg) {
console.log(msg);
}
});
In abc.php
<?php
$id = $_POST['gym_name'];
echo "The id is ".id;
?>
Give a try to the following (although I cannot work out why #Grimbode's answer is not working):
$("#submit-reg").on( "click", function() {
$.ajax({
type: "POST",
url: 'ajax.php',
data: {'section': 'anniversary'},
success: function(data)
{
alert(data);
}
});
});
Note: I don't know what your underlying code is doing. However, I would suggest not using HTML element properties to handle events for numerous reasons, but separate the JS/event handling appropriately (separate js file(s) (recommended) or inside <script> tags). Read more...
When a form sends variable with GET Method, the URL changes, putting the variables that you are passing in this way
url?variable=....
How can I get the same result with jQuery Ajax? Is it possible? Thank you
set path in your php layout/view file where you include this code
<script>
var path="<?php echo $this->webroot;?>";
</script>
and add following jquery code to post the data through ajax.
$.ajax({
type: 'POST',
url: path+'homes/createEvent',
data: {eventname:eventname,manager:manager},
async: false,
success: function(resulthtml)
{
alert(resulthtml);
},
error: function(message)
{
alert('error');
}
});
and on homes_controller.php, u will get this ajax data in createEvent function,
<?php
function createEvent()
{
$eventName=$_POST['eventname'];
$manager=$_POST['manager'];
}
?>