I am working inside of an Oracle package. I am trying to use an AJAX call to call a procedure from a button click. The ajax call is inside of a function. I am not getting any syntax errors from Oracle or when I'm using the browsers debug mode so I'm not sure what the problem is. Function is below.
htp.p('
function ApplyTest(_ht) {
var _inst = "";
var _pidm = '||v_web_pidm||';
var _inst = document.getElementById("Test").value;
alert("Heat Ticket value is: " + _ht);
alert("the instance is: " + _inst);
var resp = confirm("Are you sure you want patch applied to TEST8?");
if (resp == true) {
alert ("user pidm is: " + _pidm);
return $.ajax ({
type: "POST",
cache: false,
dataType: "json",
url: "gyapatch.p_update",
data: {"v_instance" : _inst, "v_ht" : _ht},
success : function(data) { alert("success"); }
});
alert("Got here");
alert("value: " + _inst);
window.location.reload;
alert("got to the end");
} else {
return;
}
}
');
code for the button is:
<button name="TestApply" id = "Test" onclick="ApplyTest('||val_patch.heat_ticket||')" type="button" value="T">Apply to TEST8</button>'
When I try to return the ajax call nothing is happening and I can't even reach the "Got Here" alert. When I remove the "return" keyword, I can reach the alerts but either way, nothing is happening. GYAPATCH.p_update is the package/procedure I wish to have executed when this is ran
I'm not sure what the problem is. Any help on this would be greatly appreciated. Thanks in advance.
So after a couple of hours, I had figured out the problem. This was more of a learning lesson as the issue was pretty simple. I needed to remember that I was working inside of an Oracle database AND also using WebTailor. The code posted above is correct. It turns out that the procedure I was trying to call (p_update) was not registered.
WebTailor allows you to build web applications utilizing Banner. In WebTailor, any pages that are used (usually stemming from a package.procedure), need to be registered or else they are not recognized.
I found this while debugging. Under the Network tab in my debugger, I noticed that when I click my button, I am getting a 404 error when my package.procedure is called. So I then realized it couldn't find my package and then proceeded to check if it was registered. This was a simple, silly error on my part. I am grateful for the feedback, but this will probably serve as a learning lesson or reminder to anyone trying to use ajax while working with Banner data.
Related
I would like to have an alert whenever people start typing in the text box. It will return "Data Saved: " + my msg that's in the test.php folder.
$("#textbox").on('change keyup paste', function() {
$.ajax({
method: "POST",
url: "test.php",
data: { content: $("#textbox").val() }
})
.done(function( msg ) {
alert( "Data Saved: " + msg );
});
});
I've tried changing "method" to "type".
Using .serialize().
Using success: function
I'm not sure what the problem is. Thank you!
Edit:
Added an error code. So far no error messages on console for this.
$.ajax({
method: "POST",
url: "test.php",
data: { content: $("#textbox").val() }
})
error: function (request, error) {
alert("An error occurred");
},
success: function (response) {
if (response == 'OK') {
$("#diary").val()
} else {
alert("An error occurred");
}
From your comment you are getting the following error:
$.ajax is not a function at HTMLTextAreaElement. (loggedinpage.php:92) at HTMLTextAreaElement.dispatch (jquery-3.1.1.slim.min.js:3) at HTMLTextAreaElement.q.handle (jquery-3.1.1.slim.min.js:3)
The error is telling you that the code cannot find the $.ajax() function anywhere in order to execute it.
At the same time, the message gives away the fact that you are using jQuery Slim. This cut-down version of the library does not include the $.ajax() function, among other things. You need to use the full version of jQuery.
Details in the latest (or any recent) release notes (in the "Slim build" section): https://blog.jquery.com/2017/03/20/jquery-3-2-1-now-available/
As a side note, I'm surprised that you want to show an alert every single time a user types a character into the textbox. I predict that this will quickly get very annoying for users. Maybe just showing a message inside a div nearby (which doesn't steal the focus and stop them typing) would be better. I'd also question whether it's really necessary to save the data to to the server every time a character is entered? If the user types quite a lot it will trigger off dozens of ajax requests. Your inclusion of the "keyup" is the reason for this. Perhaps have a rethink of exactly how you want this to work, and why.
I'm pretty much a complete beginner at javascript and jQuery, so please bear with me.
I have a Spark-API running, and a web front-end that uses it through ajax calls.
I'm trying to call this function
function getSpotifyURL(ms, name) {
$.ajax({
url: "http://localhost:8081/playlist?ms=" + ms + "&name=" + name,
dataType: "json",
})
.done(function( data ) {
console.log(data);
})
}
The method is placed outside of:
$(document).ready(function() {
The reason it's outside is that I get an error upon calling it saying it's "undefined" if it's within $(document).ready.
The Spark-method is supposed to return a String (and it does when you try it directly through the browser).
The way I'm calling the getSpotifyURL-method is through a html button's "onclick". Like this:
<a href='#' onclick='getSpotifyURL(" + data[i].duration + ",\"" + data[i].destination + "\")'>Create Spotify playlist for this trip</a>"
The problem:
The .done-block does nothing in my code. Nothing is printed to console.
What I've tried:
Using "success" within the ajax part instead of .done
Placing the function with $(document).ready(function() { ... }
I understand that you might need more information to be able to help me, but I'm not sure what else information to provide right now. So if there's something you need to know, just ask.
Ideas?
SOLVED!
I'm a dumb person and forgot to remove dataType: "json", as the Spark-server in this instance returned a String, not a json object. Anyway, thanks for your input everybody. Much appreciated.
I think the problem is when you bind your function onclick. There is a syntax error, as you can see on the browser console
function getSpotifyURL(ms, name) {
console.log("http://localhost:8081/playlist?ms=" + ms + "&name=" + name);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<a href='#' onclick='getSpotifyURL(" + data[i].duration + ",\"" + data[i].destination + "\")'>Create Spotify playlist for this trip</a>"
I guess data is a variable, so you should call it without brackets
<a href='#' onclick='getSpotifyURL(data[i].duration, data[i].destination)'>Create Spotify playlist for this trip</a>
The reason you are getting undefined method when you are placing the function inside the $(document).ready(function() { ... }); call is because you are using the onclick attribute to call the function. $(document).ready(...) is not in global context as to where you onclick attribute is, and would therefore not recognize it from within the document.ready resulting in your undefined method error.
When sending your Ajax request, you also need to specify a type of request (GET or POST) that you are making. I would also suggest restructuring your ajax call to look more like #Moe's answer.
If you want to get it inside the DOM, consider doing the following:
HTML
<!-- I gave the link a class name and removed the onclick= attribute -->
Create Spotify playlist for this trip
JavaScript
$(document).ready(function() {
// I gave the <a> link a click handler
$(".create-spotify-playist").on("click", function(e) {
e.preventDefault(); // prevents link from requesting
var ms = ?? //I'm not sure where you're getting your parameters from,
var name = ?? //so you will probably have to figure out how to get those in here yourself
$.ajax({
type: "GET",
url: "http://localhost:8081/playlist",
data: { ms: ms, name: name },
success: function(data) {
console.log("Success: " + data);
},
error: function(data) {
console.log("Error: " + data);
}
});
});
});
I gave the link a click handler and placed it inside the $(document).ready, and by removing the onclick attribute from earlier, it can now be triggered from inside $(document).ready.
At the moment I have multiple forms, and am writing the JavaScript out very simply. I want to create a simple comment system using the following AJAX, but am running into troubles that I cannot sort out..
The AJAX call looks like this:
var dataString = 'commentauthor=' + commentauthor + '&parentid=' + parentid +'&linkid='+
linkid + '&comment=' + comment + '&location=' + location;
alert("check : " + dataString)
$.ajax({
type: "POST",
url: "comments/addcomment.php",
datatype: "html",
data: dataString,
success: function(){
alert('comment added!');
},
error: function(){
alert('failed adding comment!' +dataString);
}
The dataString at all times pulls out the correct information from the forms. Also, the PHP the AJAX is sending it to already works when it's set as the forms action, and all the $_POST[''] names match up.
I've been looking around but can't figure it out. Am I encoding the data wrong or something? The PHP side of things doesn't even get to the AJAX response, so it's got to be just failing to send right?
Also, is there a better way to check JavaScript errors? I've been using the google chrome console but half the time when something goes wrong it doesn't through up an error anyway (like this time)
Is addcomment.php printing anything out? I vaguely remember having a similar problem which was because the PHP file wasn't returning anything. If it isn't, try this before the end of the file:
echo 1;
I recently started learning javascript, and I'm currently trying to make a small script to automate a login procedure by filling the user name/password fields, and then clicking the 'Submit'-button.
My code is as follows:
window.open("");
document.getElementById('ctl00_Username').value = "XXXX";
document.getElementById('ctl00_Password').value="XXXX";
document.getElementById('ctl00_ButtonLogin').click();
If I run it once, the site is opened but no text fields are filled.
If I run the code twice (when the site is already opened) the login is successful.
I tried putting "console.log" after "window.open", but for some reason that never seems to get called.
What might I be doing wrong?
Edit: Removed unnecessary code. I am also no longer sure that the document-object actually points to the newly opened window. Calls to "console.log" and "alert" don't seem to do anything, either.
Is it possible to get the correct document-object from the window?
Is it even possible to use "window.open" and then access the new document-object?
Help would be greatly appreciated!
A reference to the window is returned from the window.open call, you can use it to modify the window.
win=window.open(...);
win.document.doYourThing
You also probably need to wait until the document is ready (aka loaded). Using jquery below
$(win.document).ready(function() {
//the document is loaded by here, this is probably where you should do your stuff.
});
1.Pass your values as query string. Example: www.test.com?username=bro&password=bro.
2.On the other page paste the below code.
$(function () {
$(document).ready(function () {
var amount = $('money').val();
var from = "INR";
var to = "SGD";
$.ajax({ type: "POST",
url: "WebService.asmx/CurrencyConversion",
data: "{amount:" + amount + ",fromCurrency:'" + from + "',toCurrency:'" + to + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
var money = $(".money").val();
$(".money").replace(money, data.d);
}
});
});
});
3.Now paste this code too.
var uname = getUrlVars()["username"];
var psw = getUrlVars()["password"];
4.You will be having values in the above variables.Enjoy doing whatever you want.
My users keep complaining that a link does not show up for them. For me, I have tested this on several browsers and it works for me.
What should happen is that a process is started via AJAX using JQuery and once that is done I keep checking with the server via AJAX how much of the process has been done and once the process is complete I show them a link. But a lot of users tell me that it shows them the link and it quickly disappears back to showing 100.0%!
I can't see how I can fix this and I was hoping you guys could help me write something fool proof so that the link is always shown!
Here is the code concerned (its been shortened).
var startTime;
var continueTime;
var done = false;
function convertNow(validURL){
startTime = setTimeout('getStatus();', 6000);
$.ajax({
type: "GET",
url: "main.php",
data: 'url=' + validURL + '&filename=' + fileNameTxt,
success: function(msg){
done = true;
$("#loading").hide("slow");
$("#done").html("LINK SHOWN HERE");
}//function
});//ajax
}//function convertNow
function getStatus()
{
if(done==false){
$.ajax({
type: "POST",
url: "fileReader.php",
data: 'textFile=' + fileNameTxt,
success: function(respomse){
textFileResponse = respomse.split(" ");
$("#done").html("PROGRESS SHOWN HERE IN PERCENTAGES");
}
});//ajax
continueTime = setTimeout('getStatus();', 3000);
}
}
Thanks all
P.S. I have this question before and was given an idea of using a conditional in the function but that didn't work when it should have!!
UPDATE
I have some of my users what OS and browsers they are using and they usually say a Mac Os and firefox or safari. Not sure if that help with the solution.
The behaviour described by the users suggests that the success callback of your getStatus function is called after the one in convertNow. You should test done variable in this callback
function getStatus(){
if(done==false){
$.ajax({
type: "POST",
url: "fileReader.php",
data: 'textFile=' + fileNameTxt,
success: function(respomse){
// FIX : Already done, just ignore this callback
if (done) return;
textFileResponse = respomse.split(" ");
$("#done").html("PROGRESS SHOWN HERE IN PERCENTAGES");
// BONUS : call getStatus only when previous ajax call is finished
continueTime = setTimeout('getStatus();', 3000);
}
});//ajax
}
}
EDIT : This solution should prevent the bug from appearing most of the time, but there is still a chance. The only way to be sure is to remove the callback from convertNow and let the one in getStatus set the link when the processing is done (don't forget to allow only one call to getStatus at a time, see "BONUS" modification above).
If done is never set back to false then the reported behavior would be expected upon the second call to convertNow.
Since the ajax call in convertNow uses GET instead of POST, it is possible that a browser is returning a cached result whenever parameters are identical to a previous call.