I have string content that gets delivered to me via TCP. This info is only relevant because it means that I do not consistently retrieve the same string. I have a <start> and <stop> separator to ensure that any time I get the data via TCP, I am outputting the full content.
My incoming content looks like so:
<start>Apple Bandana Cadillac<stop>
I want to get everything in between <start> and <stop>. So just Apple Bandana Cadillac.
My script to do this looks like so:
servercsv.on("connection", function(socket){
let d_basic = "";
socket.on('data', function(data){
d_basic += data.toString();
let d_csvindex = d_basic.indexOf('<stop>');
while (d_csvindex > -1){
try {
let strang = d_basic.substring(0, d_csvindex);
let dyson = strang.replace(/<start>/g, '');
let dson = papaparse.parse(dyson);
myfunction(dson);
}
catch(e){ console.log(e); }
d_basic = d_basic.substring(d_csvindex+1);
d_csvindex = d_basic.indexOf('<stop>');
}
});
});
What this means is that I am getting everything before the <stop> string and outputting it. I have also included the line let dyson = strang.replace(/<start>/g, ''); because I want to remove the <start> text.
However, because this is TCP, I am not guranteed to get all parts of this string. As a result, I frequently get back stop>Apple Bandana Cadillac<stop> or some variation of this (such as start>Apple Bandana Cadillac<stop>. It is not consistent enough that I can just do strang.replace("start>", "")
Ideally, I would like my separator to select content that is in between <start> and <stop>. Not just <stop>. However, I am unsure how to do so.
Alternatively, I can also settle for a regex that retrieves all combination of <start><stop> strings during my while loop, and just delete them. So check for <, s, t, a, r, t individually and so forth. But unsure how to implement regex to delete portions of a whole string.
Assuming you get full response:
var test = "<start>Apple Bandana Cadillac<stop>";
var testRE = test.match("<start>(.*)<stop>");
testRE[1] //"Apple Bandana Cadillac"
If there are new lines between <start> and <stop>
var test = "<start>Apple Bandana Cadillac<stop>";
var testRE = test.match("<start>([\\S\\s]*)<stop>");
testRE[1] //"Apple Bandana Cadillac"
Using regular expressions capturing group here.
Try this regex with replace() method:
/<st.*?>(.*?)(?!<st)/g
Literal.................................................: <st
Any char zero or more times lazily...: .*?
Literal..................................................: >
Begin capture group..........................: (
Any char zero or more times lazily...: .*?
End capture group.............................: )
Begin negative lookahead.................: (?!
Literal...................................................: <st
End negative lookahead....................: )
In the Demo below notice that the test example consists of multiple lines, and variances of <start> and <stop> (basically <st).
Demo 1
var rgx = /<st.*?>(.*?)(?!<st)/g;
var str = `<start>Apple Bandana Cadillac<stop>
<stop>Grapes Trampoline Ham<stop>
<start>Kebab Matador Pencil<start>`;
var res = str.replace(rgx, `$1`);
console.log(res);
Update
"say I have op>Grapes Trampoline Ham<stop>...still trying to remove all parts of the string <stop>"
/^(.*?>)(.*?)(<.*?)$/gm;
A simple explanation will have to do since a step-by-step such as Demo 1 would take too much time.
This RegEx is multiline. /m
^..........Begin line.
(.*?>)..Lazily capture everything until literal >........[Return as $1]
(.*?)...Then lazily capture everything until................[Return as $2]
(<.*?)..Literal < and lazily capture everything until..[Return as $3]
$...........End line.
The trick is to replace the second capture $2 and leave $1 and $3 alone.
Demo 2
var rgx = /^(.*?>)(.*?)(<.*?)$/gm;
var str = `<start>Apple Bandana Cadillac<stop>
<stop>Grapes Trampoline Ham<stop>
<start>Kebab Matador Pencil<start>
op>Score False Razor<stop>
`;
var res = str.replace(rgx, `$2`);
console.log(res);
Related
I want get match with checking both side expropriation of main match.
var str = 1234 word !!! 5678 another *** 000more))) get word and another
console.log(str.match(/(?!\d+\s?)\w+(?=\s?\W+)/g))
>> (3) ["word", "another", "more"]
it check both side but not include in the main match sets.
But in html it not working [not working]
var str = ''; get url, url2 and url3
console.log(str.match(/(?!href=")[^"]+?(?=")/g))
>> (6) ["<a href=", "url3"]
I try to Negative lookarounds using (?!href=") and Positive lookarounds using (?=") to match only the value of its attribute but it return more attributes.
Is there any way to so like this here, Thanks
What you could do for your example data is capture what is between double quotes href="([^"]+) in an captured group and loop through the result:
var str = '';
var pattern = /href="([^"]+)/g;
var match = pattern.exec(str);
while (match != null) {
console.log(match[1]);
match = pattern.exec(str);
}
In other flavors of regex you could have used e.g. positive lookbehind
((?<=href="), but unfortunately Javascript regex does not support
lookbehinds.
A reasonable solution is:
Match href=" as "ordinary" content, to be ignored.
Match the attribute value as a capturing group ((\w+)),
to be "consumed".
Set the boundary of the above group with a *positive lookup"
((?=")), just as you did.
So the whole regex can be:
href="(\w+)(?=")
and read "your" value from group 1.
You can't parse HTML with regex. Because HTML can't be parsed by regex.
Have you tried using the DOM parser that's right at your fingertips?
var str = '';
var div = document.createElement('div');
div.innerHTML = str; // parsing magic!
var links = Array.from(div.getElementsByTagName("a"));
var urls = links.map(function(a) {return a.href;});
// above returns fully-resolved absolute URLs.
// for the literal attribute value, try a.getAttribute("href")
console.log(urls);
I'm trying to extract out a group of words from a larger string/cookie that are separated by hyphens. I would like to replace the hyphens with a space and set to a variable. Javascript or jQuery.
As an example, the larger string has a name and value like this within it:
facility=34222%7CConner-Department-Store;
(notice the leading "C")
So first, I need to match()/find facility=34222%7CConner-Department-Store; with regex. Then break it down to "Conner Department Store"
var cookie = document.cookie;
var facilityValue = cookie.match( REGEX ); ??
var test = "store=874635%7Csomethingelse;facility=34222%7CConner-Department-Store;store=874635%7Csomethingelse;";
var test2 = test.replace(/^(.*)facility=([^;]+)(.*)$/, function(matchedString, match1, match2, match3){
return decodeURIComponent(match2);
});
console.log( test2 );
console.log( test2.split('|')[1].replace(/[-]/g, ' ') );
If I understood it correctly, you want to make a phrase by getting all the words between hyphens and disallowing two successive Uppercase letters in a word, so I'd prefer using Regex in that case.
This is a Regex solution, that works dynamically with any cookies in the same format and extract the wanted sentence from it:
var matches = str.match(/([A-Z][a-z]+)-?/g);
console.log(matches.map(function(m) {
return m.replace('-', '');
}).join(" "));
Demo:
var str = "facility=34222%7CConner-Department-Store;";
var matches = str.match(/([A-Z][a-z]+)-?/g);
console.log(matches.map(function(m) {
return m.replace('-', '');
}).join(" "));
Explanation:
Use this Regex (/([A-Z][a-z]+)-?/g to match the words between -.
Replace any - occurence in the matched words.
Then just join these matches array with white space.
Ok,
first, you should decode this string as follows:
var str = "facility=34222%7CConner-Department-Store;"
var decoded = decodeURIComponent(str);
// decoded = "facility=34222|Conner-Department-Store;"
Then you have multiple possibilities to split up this string.
The easiest way is to use substring()
var solution1 = decoded.substring(decoded.indexOf('|') + 1, decoded.length)
// solution1 = "Conner-Department-Store;"
solution1 = solution1.replace('-', ' ');
// solution1 = "Conner Department Store;"
As you can see, substring(arg1, arg2) returns the string, starting at index arg1 and ending at index arg2. See Full Documentation here
If you want to cut the last ; just set decoded.length - 1 as arg2 in the snippet above.
decoded.substring(decoded.indexOf('|') + 1, decoded.length - 1)
//returns "Conner-Department-Store"
or all above in just one line:
decoded.substring(decoded.indexOf('|') + 1, decoded.length - 1).replace('-', ' ')
If you want still to use a regular Expression to retrieve (perhaps more) data out of the string, you could use something similar to this snippet:
var solution2 = "";
var regEx= /([A-Za-z]*)=([0-9]*)\|(\S[^:\/?#\[\]\#\;\,']*)/;
if (regEx.test(decoded)) {
solution2 = decoded.match(regEx);
/* returns
[0:"facility=34222|Conner-Department-Store",
1:"facility",
2:"34222",
3:"Conner-Department-Store",
index:0,
input:"facility=34222|Conner-Department-Store;"
length:4] */
solution2 = solution2[3].replace('-', ' ');
// "Conner Department Store"
}
I have applied some rules for the regex to work, feel free to modify them according your needs.
facility can be any Word built with alphabetical characters lower and uppercase (no other chars) at any length
= needs to be the char =
34222 can be any number but no other characters
| needs to be the char |
Conner-Department-Store can be any characters except one of the following (reserved delimiters): :/?#[]#;,'
Hope this helps :)
edit: to find only the part
facility=34222%7CConner-Department-Store; just modify the regex to
match facility= instead of ([A-z]*)=:
/(facility)=([0-9]*)\|(\S[^:\/?#\[\]\#\;\,']*)/
You can use cookies.js, a mini framework from MDN (Mozilla Developer Network).
Simply include the cookies.js file in your application, and write:
docCookies.getItem("Connor Department Store");
I need a regex in Javascript that would allow me to match an order number in two different formats of order URL:
The URLs:
http://store.apple.com/vieworder/1003123464/test#test.com
http://store.apple.com/vieworder/W411234368/test#test.com/AOS-A=
M-104121
The first one will always be all numbers, and the second one will always start with a W, followed by just numbers.
I need to be able to use a single regex to return these matches:
1003123464
W411234368
This is what I've tried so far:
/(vieworder\/)(.*?)(?=\/)/g
RegExr link
That allows me to match:
vieworder/1003123464
vieworder/W411234368
but I'd like it to not include the first capture group.
I know I could then run the result through a string.replace('vieworder/'), but it'd be cool to be able to do this in just one command.
Use your expression without grouping vieworder
vieworder\/(.*?)(?=\/)
DEMO
var string = 'http://store.apple.com/vieworder/1003123464/test#test.com http://store.apple.com/vieworder/W411234368/test#test.com/AOS-A=M-104121';
var myRegEx = /vieworder\/(.*?)(?=\/)/g;
var index = 1;
var matches = [];
var match;
while (match = myRegEx.exec(string)) {
matches.push(match[index]);
}
console.log(matches);
Use replace instead of match since js won't support lookbehinds. You could use capturing groups and exec method to print the chars present inside a particular group.
> var s1 = 'http://store.apple.com/vieworder/1003123464/test#test.com'
undefined
> var s2 = 'http://store.apple.com/vieworder/W411234368/test#test.com/AOS-A='
undefined
> s1.replace(/^.*?vieworder\/|\/.*/g, '')
'1003123464'
> s2.replace(/^.*?vieworder\/|\/.*/g, '')
'W411234368'
OR
> s1.replace(/^.*?\bvieworder\/([^\/]*)\/.*/g, '$1')
'1003123464'
I'd suggest
W?\d+
That ought to translate to "one or zero W and one or more digits".
I have a requirement where there is a customet name text box and the user able to input customer name to search customer. And the condition is user can add do wild card search putting * either infront or after the customer name. And the customer name should be minimum three characters long. I am using Regex to validate the user entry.
Now in case the input is like "*aaa*" .. I am validate this type of input using the following regex :
[*]{1}([a-z]|[A-Z]|[0-9]){3,}[*]{1}
The code is like below:
var str = "*aaa*";
var patt = new RegExp("[*]{1}([a-z]|[A-Z]|[0-9]){3,}[*]{1}");
var res = patt.test(str);
alert(res);
var str = "*aaa***";
var patt = new RegExp("[*]{1}([a-z]|[A-Z]|[0-9]){3,}[*]{1}");
var res = patt.test(str);
alert(res);
var str = "*aaa*$$$$";
var patt = new RegExp("[*]{1}([a-z]|[A-Z]|[0-9]){3,}[*]{1}");
var res = patt.test(str);
alert(res);
Now for the input "*aaa*" res is coming true. But for this type of inputs also "*aaa**", "*aaa*$" its comimg true. And this expected as these expressions also contains the part( *aaa*) which satisfies the regex.But these inputs("*aaa**", *aaa*$** etc. ) are wrong.
Please let me know where I am doing wrong ? is there any issue with the regex or the way checking is wrong ?
^(?:[*]([a-z]|[A-Z]|[0-9]){3,}[*])$
Use anchors ^$ to disable partial matching.See demo.
https://regex101.com/r/tS1hW2/17
The string *aaa*$$$ contains a segment of *aaa*, so it will yield true; to match against the whole string you need to add anchors on both sides. The $ and ^ anchors assert the start and end of the subject respectively.
Also, you can simply the expression greatly by using a character class trick. The \w is comprised of [0-9a-zA-Z_], and we only don't want the underscore, so we can use a negative character class with the opposite of \w (which is \W) and an underscore; I agree, it takes some mental power ;-)
var str = "*aaa*$";
var patt = /^\*[^\W_]{3,}\*$/;
var res = patt.test(str);
alert(res); // false
Alternatively, you can merge all your character classes together into one like so:
[A-Za-z0-9]
text = 'ticket number #1234 and #8976 ';
r = /#(\d+)/g;
var match = r.exec(text);
log(match); // ["#1234", "1234"]
In the above case I would like to capture both 1234 and 8976. How do I do that. Also the sentence can have any number of '#' followed by integers. So the solution should not hard not be hard coded assuming that there will be at max two occurrences.
Update:
Just curious . Checkout the following two cases.
var match = r.exec(text); // ["#1234", "1234"]
var match = text.match(r); //["#1234", "#8976"]
Why in the second case I am getting # even though I am not capturing it. Looks like string.match does not obey capturing rules.
exec it multiple times to get the rest.
while((match = r.exec(text)))
log(match);
Use String.prototype.match instead of RegExp.prototype.exec:
var match = text.match(r);
That will give you all matches at once (requires g flag) instead of one match at a time.
Here's another way
var text = 'ticket number #1234 and #8976 ';
var r = /#(\d+)/g;
var matches = [];
text.replace( r, function( all, first ) {
matches.push( first )
});
log(matches);
// ["1234", "8976"]