I would like to split a string where the delimiter is a pipe.
But the pipe can be escaped and not splitted than.
example:
'aa|bb|cc'.split(/*??*/) // ['aa','bb','cc']
'aa\|aa|bb|cc|dd\|dd|ee'.split(/*??*/) // ['aa|aa', 'bb', 'cc', 'dd|dd', 'ee']
I try this, but it not work in javascript: (?<!\\)[\|]
Try this:
console.log('aa|bb|cc'.split('|'));
console.log('aa\|aa|bb|cc|dd\|dd|ee'.split('|'));
I assume that you want to skip splitting on escaped pipes. Use match instead:
console.log(
'aa\\|aa|bb|cc|dd\\|dd|ee'.match(/[^\\|]*(?:\\.[^\\|]*)*/g).filter(Boolean)
);
Hi the Regex I created
https://www.regexpal.com/index.php?fam=100132
What you need to do is concact the matches in an array
the code generated looks like this...
const regex = /(([^\\\|]+)\\?\|\2)|(\w+)/g;
const str = `aa\\|aa|bb|cc|dd\\|dd|ee`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Hope this help you.
Related
I am doing a RegExp in javascript and I need to be able to access the value returned to a matching run, I'm using the online tool of Regexp and I saw that this matching works, I also found a "code generator" related to the online tool that produces a code that shows me how to return the values. I also report the values that are returned in the console, I wanted to know, how can I retrieve only the group "value" of these attributes without the name?
RegExp
const regex = /\[(\w{1,10}\^\w{1,10}\^\^\w{1,10}|\w{1,10}\s\w{1,10}\s\w{1,10}\s\w{1,10}\s\w{1,10}\^\w{1,10}\s\w{1,10}\s\w{1,10}\s\w{1,10}\s\w{1,10}\^\^)\]/gm;
String to match
const str = `
code that is generated automatically by the tool Online Regexp:
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Your regexp is ok, the exec method will return an array with your found values.
Yo should try to get the index of the group you want, try this way.
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
// The result can be accessed through the `m`-variable.
/*
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
*/
console.log(`Found: ${m[1]}`);
//console.log('Found:'+m[1]); //same result/
}
Hope this way helps you.
I am trying to split string in 3 different parts with regex.
I can only get function parameters from string but i also want to other parts of the string
const regex = /(\(.*?\))+/g;
const sampleString = 'collection.products(take:12|skip:16)';
const result = sampleString.match(regex)
It gives me (take:12|skip:16)
But i also want to get collection and products
Expected result in match
collection
products
take:12|skip:16
Here, we can alter two expressions together:
(\w+)|\((.+?)\)
which group #1 would capture our desired words (\w+) and group #2 would capture the desired output in the brackets.
const regex = /(\w+)|\((.+?)\)/gm;
const str = `collection.products(take:12|skip:16)`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Demo
RegEx Circuit
jex.im visualizes regular expressions:
You can split the string on . and (\(.*?\))+ and then use reduce to get values in desired format
const sampleString = 'collection.products(take:12|skip:16)';
const result = sampleString.split(/\.|(\(.*?\))+/).reduce((op,inp) => {
if(inp){
inp = inp.replace(/[)(]+/g,'')
op.push(inp)
}
return op
},[])
console.log(result)
This splits on what you want.
const sampleString = 'collection.products(take:12|skip:16)';
const result = sampleString.split(/[.()]*([^.()]+)[.()]*/).filter(function (el) {return el != "";});
console.log(result)
I'm trying to get a regex that can extract data from
BAYARPLN ke 116160029354, SUKSES. Hrg: 84.822. SN: TGK IMUM M SAMIN/R1/450/MAR,APR/Rp.89222/Adm6000/977-1071/047421CA414149E5CEC5. Saldo: 7
and I want to find this value like this...
977-1071
I tried to using parameter regex link this
"/(Adm6000)([^\7]+)/"
But I cant find the string regex 977-1071. Can I ask for help for this?
Did you try like this? see regex https://regex101.com/r/tccJ42/1
const regex = /\d+\-\d+/g; //use \d{3}\-\d{4} if you've digit limit
const str = `BAYARPLN ke 116160029354, SUKSES. Hrg: 84.822. SN: TGK IMUM M SAMIN/R1/450/MAR,APR/Rp.89222/Adm6000/977-1071/047421CA414149E5CEC5. Saldo: 7`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
If you want to match 977-1071 after /Adm6000/ you could first match /Adm6000/ and then capture in a group not a forward slash one or more times ([^/]+)
\/Adm6000\/([^/]+)
Your value 977-1071 will be in captured group 1:
const regex = /Adm6000\/([^/]+)/;
const str = `BAYARPLN ke 116160029354, SUKSES. Hrg: 84.822. SN: TGK IMUM M SAMIN/R1/450/MAR,APR/Rp.89222/Adm6000/977-1071/047421CA414149E5CEC5. Saldo: 7`;
let match = regex.exec(str);
console.log(match[1]);
I want to find match all the strings which will have emojis in the form of \u codes. I'm trying with below regexp but is not working.
/([\uE000-\uF8FF]|\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDFFF]|[\u2694-\u2697]|\uD83E[\uDD10-\uDD5D])/g
But, it is not detecting. I want to match and get
\ud83d\ude04\ud83d\ude04\ud83d\ude04\ud83d\ude04\ud83d\ude04\ud83d\ude04
these type of characters.
Well if you want to match emojis in the format \uXXXX using Regex, you can use this Regex:
/\\u[a-z0-9]{4}/gi
This is a simple Demo:
const regex = /\\u[a-z0-9]{4}/gi;
const str = `This is a pragraph \\ud83d having some emojis like these ones:
\\ude04
\\ud83d
\\ude04
Have you seen them?
\\ud83d\\ude04
Great!
`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
The regex you wrote won't work because you were not escaping the \.
I have the following string
this is the string and THIS is the word I want
I've tried using a regex for this:
var to_search = "is"
var regex = "/\S+(?="+to_search+")/g";
var matches = string.match(regex);
And I wanted matches to contain "THIS" (word that comes after the second if) but it does not seem to be working
Any idea? Thanks
regex101.com is a really great site to test your regex and it even generates the code for you.
const regex = /\bis.*(this)/gi;
const str = `this is the string and THIS is the word I want`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
First you have to double backslashes when using the string form of regexes.
Second, you forgot whitespace in your pattern:
var regex = new RegExp("\\S+\\s+(?="+to_search+")", "g");