Jquery stop calculation using this [closed] - javascript

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I am trying to make some calculations between inputs , I have 7 inputs and what I want to do is making calculations between them , so this is my code
$('.empCosts').on('input', function () {
var perHour = parseInt($('#per_hour').val());
var hours = parseInt($('#hour').val());
var perDay = parseInt($('#per_day').val());
var days = parseInt($('#day').val());
var perMonth = parseInt($('#per_month').val());
var month = parseInt($('#months').val());
var perYear = parseInt($('#per_year').val());
var perdayVal = parseInt(perHour * hours);
var perMonthVal = parseInt(perDay * days);
var perYearVal = parseInt(perMonth * month);
var perHourVal = parseInt(perDay / hours);
var perMonthDivide = parseInt(perYearVal / month);
$("#per_day").val(perdayVal);
$("#per_month").val(perMonthVal);
$("#per_year").val(perYearVal);
$("#per_hour").val(perHourVal);
if($(this).is(":focus")){
alert('sdfasdfad');
}
});
these inputs should be connected either you multiply or divide , when I try to change per_day value it doesn't change because I already set the value of that input with var perdayVal = parseInt(perHour * hours);, I want either you increase the number or decrease it , it should make the calculation either multiplying or dividing the inputs, here you have the fiddle
DEMO


try this https://jsfiddle.net/2jb2e3Lv/7/
$('.empCosts').on('input', function () {
var perHour = parseInt($('#per_hour').val());
var hours = parseInt($('#hour').val());
var perDay = parseInt($('#per_day').val());
var days = parseInt($('#day').val());
var perMonth = parseInt($('#per_month').val());
var month = parseInt($('#months').val());
var perYear = parseInt($('#per_year').val());
var perdayVal = perHour * hours;
var perMonthVal = perDay * days;
var perYearVal = perMonth * month;
$(this).attr("id") !== "per_day" && $("#per_day").val(perdayVal);
$(this).attr("id") !== "per_month" && $("#per_month").val(perMonthVal);
$(this).attr("id") !== "per_year" && $("#per_year").val(perYearVal);
});

Related

Check if today is within 5 days of any of the future dates in array [closed]

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If I have a list of arrays as follows, what would be the quickest way to check if today i.e. 2022-03-08T23:30:00.000Z is within 5 days of any of the future dates and return true along with the nearest future date (within a 5 day window)?
For example, in this example, it would return 2022-03-13T13:00:00.000Z as the nearest future date and return as true because it falls under this date.
export const nextRotaSchedules = [
'2021-12-13T12:00:00.000Z',
'2021-12-13T14:00:00.000Z',
'2022-01-13T14:00:00.000Z',
'2022-01-23T14:00:00.000Z',
'2022-01-24T13:00:00.000Z',
'2022-02-12T17:02:33.000Z',
'2022-02-12T17:03:59.000Z',
'2022-02-12T17:36:18.000Z',
'2022-02-12T17:36:48.000Z',
'2022-02-12T17:37:22.000Z',
'2022-02-12T17:37:45.000Z',
'2022-02-13T13:00:00.000Z',
'2022-02-13T13:49:16.000Z',
'2022-02-13T14:00:00.000Z',
'2022-03-13T13:00:00.000Z',
'2022-04-13T13:00:00.000Z',
'2022-05-13T13:00:00.000Z',
'2022-06-13T13:00:00.000Z',
'2022-07-13T13:00:00.000Z',
'2022-08-13T13:00:00.000Z',
'2022-09-13T13:00:00.000Z',
'2022-10-13T13:00:00.000Z',
'2022-11-13T14:00:00.000Z',
'2022-12-13T14:00:00.000Z',
'2023-01-13T14:00:00.000Z',
'2023-02-13T14:00:00.000Z',
'2023-03-13T13:00:00.000Z',
'2023-04-13T13:00:00.000Z',
'2023-05-13T13:00:00.000Z',
'2023-06-13T13:00:00.000Z',
'2023-07-13T13:00:00.000Z',
'2023-08-13T13:00:00.000Z',
'2023-09-13T13:00:00.000Z',
'2023-10-13T13:00:00.000Z',
'2023-11-13T14:00:00.000Z',
'2023-12-13T14:00:00.000Z',
'2024-01-13T14:00:00.000Z',
];

const nextRotaSchedules = [
'2021-12-13T12:00:00.000Z',
'2021-12-13T14:00:00.000Z',
'2022-01-13T14:00:00.000Z',
'2022-01-23T14:00:00.000Z',
'2022-01-24T13:00:00.000Z',
'2022-02-12T17:02:33.000Z',
'2022-02-12T17:03:59.000Z',
'2022-02-12T17:36:18.000Z',
'2022-02-12T17:36:48.000Z',
'2022-02-12T17:37:22.000Z',
'2022-02-12T17:37:45.000Z',
'2022-02-13T13:00:00.000Z',
'2022-02-13T13:49:16.000Z',
'2022-02-13T14:00:00.000Z',
'2022-03-13T13:00:00.000Z',
'2022-04-13T13:00:00.000Z',
'2022-05-13T13:00:00.000Z',
'2022-06-13T13:00:00.000Z',
'2022-07-13T13:00:00.000Z',
'2022-08-13T13:00:00.000Z',
'2022-09-13T13:00:00.000Z',
'2022-10-13T13:00:00.000Z',
'2022-11-13T14:00:00.000Z',
'2022-12-13T14:00:00.000Z',
'2023-01-13T14:00:00.000Z',
'2023-02-13T14:00:00.000Z',
'2023-03-13T13:00:00.000Z',
'2023-04-13T13:00:00.000Z',
'2023-05-13T13:00:00.000Z',
'2023-06-13T13:00:00.000Z',
'2023-07-13T13:00:00.000Z',
'2023-08-13T13:00:00.000Z',
'2023-09-13T13:00:00.000Z',
'2023-10-13T13:00:00.000Z',
'2023-11-13T14:00:00.000Z',
'2023-12-13T14:00:00.000Z',
'2024-01-13T14:00:00.000Z',
];
const isWithin5Days = (today, futureDates) => {
let isWithin5Days = false;
let nearestFutureDate = '';
for (let i = 0; i < futureDates.length; i++) {
const futureDate = futureDates[i];
const difference = new Date(futureDate) - today;
if (difference > 0 && difference < 5 * 24 * 60 * 60 * 1000) {
isWithin5Days = true;
nearestFutureDate = futureDate;
break;
}
}
return { isWithin5Days, nearestFutureDate };
}
console.log(isWithin5Days(new Date(), nextRotaSchedules));
Strongly typed alternate:
const isWithin5Days = (futureDates: string[]) => {
const today = new Date();
const futureDatesWithToday = futureDates.map((date) => {
return {
date,
diff: Math.abs(new Date(date).getTime() - today.getTime()),
};
});
const sortedFutureDatesWithToday = futureDatesWithToday.sort(
(a, b) => a.diff - b.diff
);
const nearestFutureDate = sortedFutureDatesWithToday[0].date;
const diff = Math.abs(new Date(nearestFutureDate).getTime() - today.getTime());
return {[nearestFutureDate]: diff < 5 * 24 * 60 * 60 * 1000};
}

Adding commas to number toFixed toLocaleString [duplicate]

This question already has answers here:
JavaScript: Format whole numbers using toLocaleString()
(4 answers)
Closed 1 year ago.
I am creating a calculator and need guidance on adding thousand separators to a whole number.
//logic
var portVal = 100000000;
var rateUSD = 1.3654;
var sustPortBase = 22;
var avgPortBase = 66;
var sustPortCarb = (portVal*rateUSD/1000000)*sustPortBase;
var avgPortCarb = (portVal*rateUSD/1000000)*avgPortBase;
var diff = avgPortCarb - sustPortCarb;
var nbHomes = diff * 0.115;
var nbCars = diff * 0.216;
var nbTrees = diff * 16.5;
var nbPlanes = diff * 0.833359;
var avgPortCarbRound = avgPortCarb.toFixed();
var sustPortCarbRound = sustPortCarb.toFixed();
console.log("Cars:"+(nbCars).toFixed());
console.log("Cars Decimals:"+(nbCars).toLocaleString('en'))
Outputs:
Cars:1298
Cars Decimals:1,297.676
I would like to keep only thousand seperators but nothing after the (dot.) i.e. 1,297
https://jsfiddle.net/ge5oj2xk/1/

Try using Math.floor function.
console.log("Cars Decimals:"+Math.floor(nbCars).toLocaleString('en'))

multiple a variable with number and adding the result again to the variable is returning wrong result [duplicate]

This question already has answers here:
Plus operator in JavaScript doesn't sum my values
(4 answers)
Closed 3 years ago.
function calculateAmount(val) {
var price = val;
if (quantity >= 100 && quantity < 1000) {
var divobj = document.getElementById('discount');
divobj.value = 20;
var divobj1 = document.getElementById('total');
var total = ((20 / 100) * parseInt(price)) + parseInt(price);
divobj1.value = total;
}
}
For example if enter the quantity to be 100 then the output return is 10020 instead 100+20 = 120

var price = val;
because the val is a string:
var price = +val;
please test this code, I hope this code works
divobj.value = 20;
please delete above line code:
var total = ((divobj.value / 100) * parseInt(price)) + parseInt(price);
and use above line code instead of use below code:
var total = ((20 / 100) * parseInt(price)) + parseInt(price);

Why is my number coming up as 0? [duplicate]

This question already has answers here:
How do I get the value of text input field using JavaScript?
(16 answers)
Closed 6 years ago.
I am trying to make a calculator that calculates the amount of calories that have been burned in a certain amount of time, but whenever I run it, I get 0 as the output. I have tried setting the calorieCountOut variable to an arbitrary number, and then it works fine, but every time I run it with this code here, I get 0. Here is my code:
const AGECONST = 0.2017;
const WEIGHTCONST = 0.09036;
const HRCONST = 0.6309;
const SUBTRACTCONST = 55.0969;
const TIMECONST = 4.184;
//var gender = document.getElementById("gender").innerHTML;
var gender = "male";
var weight = document.getElementById("weight");
var age = document.getElementById("age");
var time = document.getElementById("time");
var hr = 140;//dummy number
function calculate(){
if (gender = "male"){
var calorieCount = ((age * AGECONST) - (weight * WEIGHTCONST) + (hr * HRCONST) - SUBTRACTCONST) * time / TIMECONST;
}
//else if (gender = "female"){
//}
var calorieCountOut = calorieCount.toString();
document.getElementById("output").innerHTML = calorieCountOut;
}

Try getElementById('myId').value for the value inside the control instead of the control itself as an object.
Right now you assign a html object to a variable, but what you want (i assume) is the number stored in that html object.

Get the percentage of a number with javascript [closed]

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Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 6 years ago.
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So I am creating a web app and I get some data.
There are points you have now (now=284), and total points (total=1000). So, The difference between them is dif=716.
How do I use javascript to turn the difference into a percentage value, for example, 32% or whatever?
Thanks

This is a math question, not programming, but you ask for javascript here you are an example:
var value = 249;
var total = 1000;
var calcPercent = function(v, t) {
return 100*v/t;
};
alert(calcPercent(value, total)+"%");

var total = 1000,
subtract = 284;
var differencePercentage = ((total - subtract) / total) * 100; // 71.6

Simple math would be
var now = 284;
var total = 1000;
console.log( "percentage is " + (now* 100/total) );
console.log( "Negative percentage is " + (100-(now* 100/total)) );

(function(){
var now = 284;
var total = 1000;
var difference = ((total - now) / total) * 100;
alert(difference);
})()

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