Unconditional use of conditional expression for default assignment - javascript

I'm getting the following linting error: Unconditional use of conditional expression for default assignment
What is wrong with the below?
(myOverride) ? myOverride : MAGIC_HOST,
Where if myOverride is defined I want to use myOverride, if it is not defined I want to use the env var MAGIC_HOST.

Apparently you're using ESLint (as that error is an ESLint) error. It's because of the no-unneeded-ternary rule which is meant to flag up unnecessary use of the conditional operator (they call it the "ternary")¹. From the linked docs:
Another common mistake is using a single variable as both the conditional test and the consequent. In such cases, the logical OR can be used to provide the same functionality. Here is an example:
// Bad
var foo = bar ? bar : 1;
// Good
var foo = bar || 1;
So the rule is telling you to use myOverride || MAGIC_HOST instead.
You don't have to, the code you've shown isn't wrong. It's just it doesn't pass that ESLint rule.
¹ "they call it the 'ternary'" - The conditional operator is a ternary operator (an operator accepting three operands, just like * is a binary operator — an operator accepting two operands). And it is, for now, the only ternary operator JavaScript has. But that doesn't necessarily always have to be true as the language evolves. It's correctly called the conditional operator.

It is not inherently wrong, but it is better written as:
myOverride || MAGIC_HOST
as explained here.

Related

Understanding New Javascript Ternary Condition Convention

I don't know this condition convention in JS(!params?.q). I know the ternary condition but I don't understand this. Can anyone provide insights on this or what should I learn to understand similar conventions?
JS Code Block
if (!params?.q) {// I don't understand a '?' without a ternary //condition
setSkipFirstRender(false);
setSort({
name: PersonEnum.keys.displayName,
dir: PersonEnum.sortOrder.asc,
});
}
The ?. operator is the optional chaining operator, sometimes also called the Elvis operator.
Despite both using the ? character, the optional chaining operator and ternary statements serve two different purposes.
Normally if you were to access params.q and params was null or undefined, an error would be thrown. What the optional chaining operator allows you to do is safely attempt to access the q property without an error being thrown. In this case, if params were null or undefined, params?.q would evaluate to undefined.
Essentially this is equivalent to checking if(!(params && params.q)).
You can read more about the optional chaining operator at https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining

What does the myObj.param?.otherParam operator do and how is it used?

I was reading the fundamentals guide for React Navigation and in the section for passing parameters to routes I came across this bit of code that I've never seen before.
if (route.params?.post) {
// Do something
}
I've never seen the ? operator used that way, I've only used the ternary operator. When searching the only other thing I found is the nullish assignment operator ??=.
I fiddled with it in the console and it seems to check if param exists so that if it doesn't exist it doesn't error when asking for .post
My first thought was that is a ternary operator without the second argument, but the third argument appears to be required.
So my question is, in the above code block, what is the ? doing, what is that called, and how/when is it used?
Thanks
It's called optional chaining. You can use it to check if the preceding variable is null, so that you could spare yourself checking for null/undefined properties.
// want to access blub.test.smth
if(blub && blub.test) {
// possibly access blub.test.smth
const value = blub.test.smth;
}
vs
const value = blub?.test?.smth

Testing out my understanding of expressions and statements with two examples [duplicate]

For the past few hours I have been trying to find the difference between the 3, not just the difference, I also have been trying to find out which are sort of synonymous, MDN calls all declarations "statements", so I presume that is true. However, none of the articles and SO questions I read provided me with a cheatsheet of sorts to distinguish between the 3 (or the 2, expressions vs statements).
Something I have noticed with statements is that they all somehow involve a special JavaScript keyword like break or for or var. The articles say that an expression evaluates to something, while a statement performs an action. What is a function then ? Is it a statement-expression hybrid (since it both performs an action when called, and returns a value) ? Right now, I am assuming that this is not the case since a function call does not involve a JavaScript keyword.
And then there are declarations, is every declaration also a statement ?
I am also aware of expression statements like 20 + 5 * 2 / 3;, but aren't these virtually useless ? Why would anyone pollute their code with a line like this ?
I would be more than glad if someone could ask the above questions (or at least some of them), or if someone could provide me with some sort of a cheatsheet. Why is there so little material on a topic that appears to be so simple in such a popular language ?
There are standard definitions of these terms that all languages, including JS, follow. My takes on them are the following:
An expression produces a value and can be written wherever a value is expected.
A statement on the other hand is is a standalone unit of execution. It does not return anything.
A declaration is a statement in which a value is assigned to a variable.
All declarations are statements, but not all statements are declarations.
Most statements and all declarations contain expressions.
Javadoc also gives nice, succinct definitions:
An expression is a construct made up of variables, operators, and method invocations, which are constructed according to the syntax of the language, that evaluates to a single value.
Statements are roughly equivalent to sentences in natural languages. A statement forms a complete unit of execution.
Now, your theory on keywords being necessarily involved is incorrect. Here is a statement that includes a keyword:
break;
And here is one that does not:
foo();
In the first example I execute a break, whereas in the second one I call a function. Both are statements, however only one includes any special keyword.
A function is not a statement. A function call is a statement, as demonstrated above. In the case of a function that returns something, the call can also be a declaration:
var bar = foo();
And for your final question, the reason there is so little material out there on this is because this is merely an issue of semantics. People do not linger on the exact definitions of these terms.
For further clarification, I recommend taking a look at this blog post by Axel Rauschmayer that specifically talks about the difference between statements and expressions in JS.
For the past few hours I have been trying to find the difference between the 3, not just the difference, I also have been trying to find out which are sort of synonymous, MDN calls all declarations "statements", so I presume that is true.
A declaration is any construct that "declares" a variable name into existence at compile/load time before the program executes. All declared names in their respective scopes are therefore known in advance.
Statements and expressions differ from each other in that the former does not produce a value a result, whereas the latter does. So an expression may be used anywhere a value is expected, and a statement may not be used in those places.
An expression statement is one where the statement is a single expression, or several included in an expression that requires zero or more sub-expressions. While the expression(s) produce a result, the statement does not.
Here's an expression:
x = foo() + 2
A full expression statement could be explicitly shown by adding a semicolon to the end.
x = foo() + 2;
The first example can be wrapped in a set of parens, because the parens as a grouping operator expects an expression, often provided as several expressions joined by the comma operator.
The second example can not be wrapped in parens (if you include the semicolon) because then it is a statement, and does not produce a value, which the grouping operator expects to receive and return as its own value.
Something I have noticed with statements is that they all somehow involve a special JavaScript keyword like break or for or var.
While most statements do involve a keyword, not all do. Most notably, the block statement has no keyword. Instead it uses a set of curly braces to delimit its start and end.
The articles say that an expression evaluates to something, while a statement performs an action. What is a function then ? Is it a statement-expression hybrid (since it both performs an action when called, and returns a value) ? Right now, I am assuming that this is not the case since a function call does not involve a JavaScript keyword.
There are three kinds of functions in JS. If you're talking about the ones that use the function keyword, then the may be either a declaration or an expression depending on its context.
If the function is used where an expression would be expected, then it's evaluated as an expression that returns a new function object. If not, then it is expected to be a declaration, which basically creates a variable with the function object assigned to it. As a declaration, a function name is required (for the variable name). As an expression, it's optional.
I am also aware of expression statements like 20 + 5 * 2 / 3;, but aren't these virtually useless ? Why would anyone pollute their code with a line like this ?
If the resulting value is ignored, it would be useless, given that example. But here's another expression statement.
foobar();
Now we have a side effect from the function call, which is most likely desired and useful.
Let's talk about expressions first. As you say, an expression is something that evaluates to a value. A function is a value. A function call, on the other hand, is an expression.
I don't agree with the characterization of a statement as something that "performs an action". As you say, calling a function involves running the function body, which consists of statements and declarations, so it performs actions "on the inside".
A better way to look at it is that expressions, statements, and declarations are syntactic categories. They arise from trying to describe the structure of the JavaScript grammar. See e.g. the ECMAScript 8 specification on expressions, statements, and declarations.
An expression statement like 20 + 5 * 2 / 3; is indeed useless because it has no effects, and the only point of a statement is its effects. But there are other kinds of much more useful expression statements:
a function call: foo();
assignment: x = 42; (= is an operator and can be used in expressions)
increment/decrement: i++; (similarly, ++ is an operator)
Statements other than expression statements tend to start with a special keyword to avoid syntactic ambiguity: The parser wants to be able to tell what kind of construct it is dealing with right from the start. Hence we get:
if statements: if (EXPR) STMT
while statements: while (EXPR) STMT
return statements: return; or return EXPR;
etc.
However, there are some statements that don't start with a keyword:
the empty statement: ;
a block: { ... }
Finally, declarations. In JavaScript the distinction between statements and declarations is somewhat arbitrary. The grammar distinguishes between the two, but in practice you can often treat them the same (e.g. the contents of a block statement are defined as a sequence of statement list items, and a statement list item is defined to be either a statement or a declaration). Declarations include:
function declarations: function foo() { ... } (including variants such as generators (function* foo() { ... }) and asynchronous functions (async function foo() { ... }))
let and const
class declarations
(But for some reason var foo; is classified as a statement, not a declaration.)

is there any equivalent for PHP's "??" operation in javascript? [duplicate]

This question already has answers here:
Null-safe property access (and conditional assignment) in ES6/2015
(11 answers)
Closed 2 years ago.
I've been programming a lot in Swift recently. Today I did some work in JavaScipt when question popped up to me:
Is there something similar to optional chaining in JavaScript? A way to prevent undefined is not an object without any variables?
Example:
function test(){
if(new Date() % 2){
return {value: function(){/*code*/}};
}
}
test().value();
will fail half of time because sometimes test returns undefined.
The only solution I can think of is a function:
function oc(object, key){
if(object){
return object[key]();
}
}
oc(test(), 'value');
I would like to be able to do something like:
test()?.value()
The part after the question mark is only executed if test returned an object.
But this is not very elegeant. Is there something better? A magic combination of operators?
Edit I know I could rewrite test to return something. But I'm wondering if there's something like optional chaining. I'm not interested in a particular solution to the above example. Something that I also can use if have no control over the function returning undefined.
This is currently a Stage 4 proposal you can check on the progress of it here:
https://github.com/tc39/proposal-optional-chaining
You can use the babel plugin today:
https://www.npmjs.com/package/babel-plugin-transform-optional-chaining
Update 11th January 2020:
Babel now supports optional chaining by default
https://babeljs.io/blog/2020/01/11/7.8.0
The Optional Chaining operator is spelled ?.. It may appear in three positions:
obj?.prop // optional static property access
obj?.[expr] // optional dynamic property access
func?.(...args) // optional function or method call
Notes:
In order to allow foo?.3:0 to be parsed as foo ? .3 : 0 (as required for backward compatibility), a simple lookahead is added at the level of the lexical grammar, so that the sequence of characters ?. is not interpreted as a single token in that situation (the ?. token must not be immediately followed by a decimal digit).
Also worth checking out:
https://github.com/tc39/proposal-nullish-coalescing
https://github.com/babel/babel/tree/master/packages/babel-plugin-proposal-nullish-coalescing-operator
In plain JavaScript you have to do type checks or structure your code so that you know an object will exist.
CoffeeScript, a language that compiles down to JavaScript, provides an existential operator ?. for safe chaining if you're willing to consider a preprocessed language.
There's another discussion here about why you can't reproduce this behavior in JS.
There is also a discussion on the ESDiscuss forums about adding an existential operator to a future version of JavaScript. It doesn't seem very far along though, certainly nowhere close to practical use. More of an idea at this point.
Optional chaining has landed in JS. We can use optional chaining via the ?. operator in object property access. It allows us to try accessing properties of objects which might not exists (i.e. are undefined) without throwing an error.
Here is a code example:
const obj = {
foo: {
bar: 1
}
};
// If we try to access property which doesn't exists
// it just returns undefined
console.log(obj.baz);
try {
// Now we try to access a property of undefined which throws an error
obj.baz.foz;
} catch (e) {
console.dir(e.message);
}
// Now we use the optional chaining operator ?.
// We get undefined instead of an error
console.log(obj.baz?.foz);
console.log(obj.foo?.bar);
You can use
test() && test().value();
or
var testResult = test();
testResult && testResult.value();
If you ask me this is most similar to Swift's optional chaining.
var Obj = {Prop: {name: 'peter'}}
console.log(Obj.Prop.name)
console.log(Obj?.Prop?.name)
In the first sentence, you're just accessing object properties. The problem with that is that if you find Prop to be something other than an object, it will throw an exception. That's the reason of the optional chainig operator.
Lets say you try to do Obj.Prop2.name.
You'll get Uncaught TypeError: Cannot read property 'name' of undefined
if Instead you did Obj.Prop2?.name, You'll only receive undefined as a value, instead of an exception.
This is particularly useful when accessing deeply nested properties.
WARNING: This is a relatively new JS feature that's not yet implemented in all browsers, so be careful while using it for production applications.
Optional Chaining is finally in the JavaScript standard!
Here are a few examples:
// properties
foo?.bar
foo?.bar()
foo?.bar.baz()
foo?.bar?.baz()
// indexing
foo?.[0]
foo?.['bar']
// check if a function is defined before invoking
foo?.()
foo.bar?.()
foo?.bar?.()
And this is way better than what most people use for manually checking for nulls
Instead of evaluating
foo?.bar
to this little code snippet we are all used to writing
foo ? foo.bar : null
it actually evaluates to
foo == null ? undefined : foo.bar
which works for all the falsey values like an empty string, 0 or false.
Unrelated to the question, but you might also be interested in the ?? operator.
It has a similar purpose as || except it only checks for null or undefined.
For example:
foo ?? bar
would be the same as:
foo != null ? foo : bar
This is a very new feature, so even thought a lot of users already use a browser that supports this you will still want to use a tool to convert it to an older version of javascript.
What about returning a noop function that does nothing when the condition isn't met?
function test(){
if(new Date() % 2){
return {value: function(){/*code*/}};
}
return {value: function(){ /* just return a type consistent with the function above */ }
}
You can always return this; if test is a object method.
But why do you want to prevent such errors by creating mock functions?

How can I add a property to an object conditionally

I have read this In Javascript, how to conditionally add a member to an object? but in my case, it doesn't work.
I have the following situation:
angular.forEach(vm.someData.entities, entity => {
...(entity.type === "section" && { entity.styleFormats = entity[`${vm.activeTab}StyleFormats`]});
entity.content = entity[`${vm.activeTab}Content`];
entity.stateClasses = determinateStateClasses(false);
entity.isNew = false;
});
The spread operator gives me a parsing error.
Don't use the spread operator here. That operator is used when constructing an object literal, which isn't what you're doing here. You're simply writing a line of code in a function.
You may be able to use && short circuiting to perform the intended operation:
entity.type === "section" && entity.styleFormats = entity[`${vm.activeTab}StyleFormats`];
But this is a little unclear. Normally this kind of short-circuiting is used when resolving to a value, not when performing an operation. Think of this as structurally like the difference between using the conditional operator (?:) vs. using an if block. The former is not a drop-in substitute for the latter, they have their own uses.
In this case what you're looking to do is conditionally perform an operation within your function. That's exactly what an if block is for:
if (entity.type === "section") {
entity.styleFormats = entity[`${vm.activeTab}StyleFormats`];
}
Basically, don't try to write the cleverest code possible, write the clearest code possible. There's no reason to avoid using an if block.

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