So I have been looking for a solution to this for a while but can't seem to figure it out. I am trying to merge together the subscriptionArray and userArray by matching on the companyId, but if a company has multiple users (like companyA), I want the subscription Id to repeat and create a new object with a duplicate subscriptionId for each user (see the resultArray). I have a much larger data set i'm working with, but the end goal would be to have an array of every user as an object associated with a subscriptionId, with multiple repeating subscription id's for multiple users.
I am able to merge the two currently, but it doesn't create duplicate subscriptionId objects, it just replaces the previous object.
I can't use ES6, lodash or JQuery, so please just plain vanilla JS
var subscriptionArray = [
{
"subscriptionId" : 2,
"CompanyId" : 20,
},
{
"subscriptionId" : 3,
"CompanyId" : 30,
},
{
"subscriptionId" : 4,
"CompanyId" : 40,
}
]
var userArray = [
{"FirstName" : "Matt",
"CompanyId" : 20,
"CompanyName" : "CompanyA",
},
{"FirstName" : "Bob",
"CompanyId" : 20,
"CompanyName" : "CompanyA",
},
{"FirstName" : "John",
"CompanyId" : 30,
"CompanyName" : "CompanyB",
},
{"FirstName" : "Tim",
"CompanyId" : 40,
"CompanyName" : "CompanyC",
}
]
var resultArray = [
{
"subscriptionId" : 2,
"FirstName" : "Matt"
"CompanyId" : 20,
"CompanyName" : "CompanyA",
},
{
"subscriptionId" : 2,
"FirstName" : "Bob"
"CompanyId" : 20,
"CompanyName" : "CompanyA",
},
{
"subscriptionId" : 3,
"FirstName" : "John"
"CompanyId" : 30,
"CompanyName" : "CompanyB",
},
{
"subscriptionId" : 4,
"FirstName" : "Tim"
"CompanyId" : 40,
"CompanyName" : "CompanyC",
},
]
You really should share what you have tried and what isn't working. That said this is fairly easy to do with Object.assign()
here is a fiddle that shows this in action https://jsfiddle.net/ysy50edf/1/
Lets check out the code:
userArray.forEach( function(user) {
subscriptionArray.forEach( function(sub) {
if( sub.CompanyId == user.CompanyId ){
var result = Object.assign(user, sub);
results.push( result );
}
});
});
Looping each user and then looping over the subscriptions to find the matching property. Then create a new result object that gets assigned the user and the subscription. This merges the two objects and then push that result into your results.
you could do it by using an intermediate structure {[companyId]: items[]} which would be the userArray indexed by company Id (and the values are arrays because multiple people can be in the same company). And then loop onto the subscriptionArray adn return a new correct value.
var userByCompanyId = userArray.reduce(function (users, item) {
if (!users[item.CompanyId]) {
users[item.CompanyId] = [];
}
users[item.CompanyId].push(item);
return users;
}, {});
var subscriptionResultArray = [].concat.apply([], subscriptionArray
.filter(function (item) {
return userByCompanyId[item.CompanyId] !== undefined;
})
.map(function (item) {
var subId = item.subscriptionId;
return userByCompanyId[item.CompanyId].map(function (sub) {
// deepMerge merge recursively objects, see loadash
return deepMerge({}, sub, {
subscriptionId: subId
});
});
}));
Note that I mutate the items in userArray, you can avoid this by using Object.assignin Es6 env or write your own implemantation.
Related
I need help putting together an array search that is based on multiple conditions. Furthermore, all the conditions are conditional, meaning I may or may not need to filter on those conditions. What I have:
Array of objects to filter:
var data = [{
"_id" : ObjectId("583f6e6d14c8042dd7c979e6"),
"transid" : 1,
"acct" : "acct1",
"transdate" : ISODate("2012-01-31T05:00:00.000Z"),
"category" : "category1",
"amount" : 103
},
{
"_id" : ObjectId("583f6e6d14c8042dd7c2132t6"),
"transid" : 2,
"acct" : "acct2",
"transdate" : ISODate("2012-01-31T05:00:00.000Z"),
"category" : "category2",
"amount" : 103
},
{
"_id" : ObjectId("583f6e6d14c8042dd7c2132t6"),
"transid" : 3,
"acct" : "acct2",
"transdate" : ISODate("2016-07-31T05:00:00.000Z"),
"category" : "category1",
"amount" : 103
},
{
"_id" : ObjectId("583f6e6d14c8042dd7c2132t6"),
"transid" : 4,
"acct" : "acct2",
"transdate" : ISODate("2012-01-31T05:00:00.000Z"),
"category" : "category2",
"amount" : 103
},
{
"_id" : ObjectId("583f6e6d14c8042dd7c2132t6"),
"transid" : 5,
"acct" : "acct2",
"transdate" : ISODate("2012-01-31T05:00:00.000Z"),
"category" : "category3",
"amount" : 103
},
{
"_id" : ObjectId("583f6e6d14c8042dd7c152g2"),
"transid" : 6,
"acct" : "acct3",
"transdate" : ISODate("2016-10-31T05:00:00.000Z"),
"category" : "category3",
"amount" : 103
}]
I am filtering the above array of objects based on another array of mixed elements. The elements represent the following search fields:
"searchstring": to search on all fields in the data array for any
matched text sequence
object with key values reprsenting account type and a true or false
for value indicating if it should be used to filter
startdate to filter transdate on
enddate to filter transdate
category name to filter category on
The array that has the search conditions looks like this (but if some of the fields are not necessary they will be set to undefined or just an empty string or array):
var filtercondition = {
"p",
{acct1:true,acct2:false,acct3:true...}
"2016-06-01",
"2016-11-30",
"category3"
}
What is the best way to accomplish this? What I've devised is a separate search for each element in the filter array, but this seems non optimal and very tedious. I'm open to a redesign of my setup...
// You wrote that it's an array, so changed the braces
var filtercondition = ["p",
{acct1:true,acct2:false,acct3:true...}
"2016-06-01",
"2016-11-30",
"category3"
];
var filtered = data.filter(o => {
if(filtercondition[0] && !o.category.includes(filtercondition[o])) { // checking just the category, but you can check if any of more fields contains the conditions
return false;
}
if(filtercondition[1]) {
for(var key in filtercondition[1]) {
if(filtercondition[1][key] === true && o.acct != key) {
return false;
}
}
}
if(filtercondition[2] && o.transdate < filtercondition[2]) {
return false;
}
if(filtercondition[3] && o.transdate > filtercondition[3]) {
return false;
}
if(filtercondition[4] && o.category !== filtercondition[4]) {
return false;
}
return true;
});
Two notes:
- changed the braces of filtercondition so that it is an array, however I would suggest to use an object instead.
- this {acct1:true,acct2:false,acct3:true...} sample doesn't make sense for me, since it suggests that the acct field should be acct1 and acct3 at the same time.
Create an array of functions, each function representing a condition.
Here's some sample code which demonstrates the approach...
var conditions = [];
// Dynamically build the list of conditions
if(startDateFilter) {
conditions.push(function(item) {
return item.transdate >= startDateFilter.startDate;
});
};
if(categoryFilter) {
conditions.push(function(item) {
return item.cateogry === categoryFilter.category;
});
};
// etc etc
Once you have an array of conditions, you can use Array.prototype.every to run each condition on an item.
var itemsMatchingCondition = data.filter(function(d) {
return conditions.every(function(c) {
return c(d);
});
});
Or, using the more compact arrow functions:
const itemsMatchingCondition = data.filter(d => conditions.every(c => c(d));
First, you'll want to use brackets for your array not curly braces:
var filtercondition = [
"p",
{acct1:true,acct2:false,acct3:true...},
"2016-06-01",
"2016-11-30",
"category3"
];
Then again, I don't think that an array is the best data type for that. Try an object like this:
var filtercondition = {
query: "p",
accounts: {acct1:true,acct2:false,acct3:true...},
date1: "2016-06-01",
date2: "2016-11-30",
category: "category3"
};
Then, try using Array.prototype.filter:
var filtered = data.filter(function(obj) {
for (var key in filtercondition) {
// if condition not met return false
}
return true;
});
I'd go with a bunch of small granular functions and compose them.
//only some utilities, from the top of my mind
var identity = v => v;
//string-related
var string = v => v == null? "": String(v);
var startsWith = needle => haystack => string(haystack).startsWith(needle);
var endsWith = needle => haystack => string(haystack).endsWith(needle);
var contains = needle => haystack => string(haystack).contains(needle);
//do sth with an object
var prop = key => obj => obj != null && prop in obj? obj[prop]: undefined;
var someProp = fn => obj => obj != null && Object.keys(obj).some(k => fn(k) );
var someValue = fn => obj => obj != null && Object.keys(obj).some(k => fn(obj[k]) );
//logic
var eq = b => a => a === b;
var not = fn => function(){ return !fn.apply(this, arguments) };
var and = (...funcs) => funcs.reduce((a, b) => function(){
return a.apply(this, arguments) && b.apply(this, arguments);
});
var or = (...funcs) => funcs.reduce((a, b) => function(){
return a.apply(this, arguments) || b.apply(this, arguments);
});
//composition
var compose = (...funcs) => funcs.reduce((a, b) => v => return a(b(v)));
var chain = (...funcs) => funcs.reduceRight((a, b) => v => return a(b(v)));
//and whatever else you want/need
//but stay granular, don't put too much logic into a single function
and an example composition:
var filterFn = and(
//some value contains "p"
someValue(contains("p")),
//and
chain(
//property "foo"
prop("foo"),
or(
//either contains "asdf"
contains("asdf"),
//or startsWith "123"
startsWith("123")
)
),
)
since I don't know how you build your filterconditions, I cannot tell you exactly how to parse them into such a composition, but you could compose them like this:
//start with something basic, so we don't ever have to check wether filterFn is null
var filterFn = identity;
//and extend/compose it depending on some conditions
if(/*hasQuery*/){
filterFn = and(
// previous filterFn(obj) && some value on obj contains `query`
filterFn,
someValue(contains(query)))
)
}
if(/*condition*/){
//extend filterFn
filterFn = or(
// (obj.foo === null) || previous filterFn(obj)
chain(prop("foo"), eq(null)),
filterFn
);
}
and so on
First, some points:
Your data object is invalid if you're going to use it in the browser. Probably the data comes from MongoDB, right? Your backend (data source) should have a method to encode it properly and remove ObjectID and ISODate references.
Your filtercondition is not a valid JavaScript object/JSON. Check my example.
So, you can filter your data array with Array#filter method.
Something like that:
let data = [{
"_id" : "583f6e6d14c8042dd7c979e6",
"transid" : 1,
"acct" : "acct1",
"transdate" : "2012-01-31T05:00:00.000Z",
"category" : "category1",
"amount" : 103
},
{
"_id" : "583f6e6d14c8042dd7c2132t6",
"transid" : 2,
"acct" : "acct2",
"transdate" : "2012-01-31T05:00:00.000Z",
"category" : "category2",
"amount" : 103
},
{
"_id" : "583f6e6d14c8042dd7c2132t6",
"transid" : 5,
"acct" : "acct2",
"transdate" : "2012-01-31T05:00:00.000Z",
"category" : "category3",
"amount" : 103
}];
let filterToApply = {
acct: {
acct1: true,
acct2: false,
acct3: true
},
initialDate: "2016-06-01",
finalDate: "2016-11-30",
category: "category3"
}
let filterData = (array, filter) => {
return array.filter( (item) => {
/* here, you iterate each item and compare with your filter,
if the item pass, you must return true. Otherwise, false */
/* e.g.: category check (if present only) */
if (filter.category && filter.category !== item.category)
return false;
}
/* add other criterias check... */
return true;
});
}
let dataFiltered = filterData(data, filterToApply);
console.log(dataFiltered);
If you want to filter an array with multiple conditions and the conditions may be optional, then use the following method.
const data = [
{ name: 'John', age: 25, city: 'New York' },
{ name: 'John', age: 25, city: 'New' },
{ name: 'Jane', age: 32, city: 'Los Angeles' },
{ name: 'Bob', age: 45, city: 'New York' },
{ name: 'Alice', age: 38, city: 'Los Angeles' }
];
const filteredData = (n, c, a) => data.filter(item => {
if (n || c || a) {
return (n ? item.name === n : true) && (c ? item.city === c : true) && (a ? item.age === a : true); // keep adding conditons as much as u want
}
});
console.log(filteredData('John', null, 25));
console.log(filteredData(null, 'Los Angeles', 38));
console.log(filteredData(null, 'Los Angeles', null));
You can chain as many as conditions
i have this function:
exports.getRules = function(user) {
if (!user) {
return Promise.resolve(null);
} else {
return Rule.findAllPr({
'status': 'published',
'type': 'price'
}).then(function(rules) {
return _.zipObject(rules.map(function(r) {
var skus;
skus = _.zipObject(r.sizeIds.map(function(s) {
return [s, r.discount];
}));
return console.log(skus);
}));
});
}
};
i am trying to return a combined skus array, currently i am getting two arrays
{ 'SA40-MRE0': 5,
'SA40-MRE1': 5,
'SA40-MRE2': 5,
'SA40-MRE3': 5,
'SA40-MRE4': 5,
'SA40-MRE5': 5 }
{ 'N50P-IB0': 15,
'N50P-IB1': 15,
'N68Z-BL4': 15 }
The data comes from mongo as:
{
"__v" : 11,
"_id" : ObjectId("5627c993dc8c59e63f4b87f6"),
"discount" : 5,
"from" : ISODate("2015-10-20T23:00:00Z"),
"sizeIds" : [
"SA40-MRE0",
"SA40-MRE1",
"SA40-MRE2",
"SA40-MRE3",
"SA40-MRE4",
"SA40-MRE5"
],
"status" : "published",
"to" : ISODate("2015-10-31T00:00:00Z"),
"type" : "price"
}
{
"to" : ISODate("2015-11-02T00:00:00Z"),
"from" : ISODate("2015-10-22T23:00:00Z"),
"type" : "price",
"_id" : ObjectId("562a50e0da1312415f73568c"),
"status" : "published",
"sizeIds" : [
"N50P-IB0",
"N50P-IB1",
"N68Z-BL4"
],
"discount" : 15,
"__v" : 0
}
Is there a better way to write this code, basically i have two or more mongo documents, for each document, i want to extract the sizeIds and store these in the skus array.
Any advice much appreciated.
use _.extend
exports.getRules = (user) ->
if !user
Promise.resolve null
else
discountCache = {}
Rule.findAllPr(
'status': 'published'
'type': 'price')
.then (rules) ->
_.zipObject rules.map (r) ->
skus = _.zipObject(r.sizeIds.map((s) ->
[
s
r.discount
]
))
extended = _.extend(discountCache, skus)
.then (skus) ->
discountCache
I have a collection of documents which contain unique id field. Now I have a list of ids which may contain some ids that do not exist in the collection. What's the best way to find out those ids from the list?
I know I can use $in operator to get the documents which have ids contained in the list then compare with the given id list, but is there better way to do it?
I suppose you have the following documents in your collection:
{ "_id" : ObjectId("55b725fd7279ca22edb618bb"), "id" : 1 }
{ "_id" : ObjectId("55b725fd7279ca22edb618bc"), "id" : 2 }
{ "_id" : ObjectId("55b725fd7279ca22edb618bd"), "id" : 3 }
{ "_id" : ObjectId("55b725fd7279ca22edb618be"), "id" : 4 }
{ "_id" : ObjectId("55b725fd7279ca22edb618bf"), "id" : 5 }
{ "_id" : ObjectId("55b725fd7279ca22edb618c0"), "id" : 6 }
and the following list of id
var listId = [ 1, 3, 7, 9, 8, 35 ];
We can use the .filter method to return the array of ids that is not in your collection.
var result = listId.filter(function(el){
return db.collection.distinct('id').indexOf(el) == -1; });
This yields
[ 7, 9, 8, 35 ]
Now you can also use the aggregation frameworks and the $setDifference operator.
db.collection.aggregate([
{ "$group": { "_id": null, "ids": { "$addToSet": "$id" }}},
{ "$project" : { "missingIds": { "$setDifference": [ listId, "$ids" ]}, "_id": 0 }}
])
This yields:
{ "missingIds" : [ 7, 9, 8, 35 ] }
Unfortunately MongoDB can only use built in functions (otherwise I'd recommend using a set) but you could try and find all distinct id's in your list then just manually pull them out.
Something like (untested):
var your_unique_ids = ["present", "not_present"];
var present_ids = db.getCollection('your_col').distinct('unique_field', {unique_field: {$in: your_unique_ids}});
for (var i=0; i < your_unique_ids.length; i++) {
var some_id = your_unique_ids[i];
if (present_ids.indexOf(some_id) < 0) {
print(some_id);
}
}
Below query will fetch you the result :
var listid = [1,2,3,4];
db.collection.aggregate([
{$project: { uniqueId :
{
"$setDifference":
[ listid , db.collection.distinct( "unique_field" )]} , _id : 0 }
},
{$limit:1}
]);
I'm trying to sort a JSON into multiple arrays based on type, my current json is:
// current json file:
{
"res": [
{
"type" : "stream",
"price" : "3.99",
"id" : "13nee"
},
{
"type" : "stream",
"price" : "2.99",
"id" : "8ejwj"
},
{
"type" : "buy",
"price" : "3.99".
"id" : "9akwk"
},
...
]
}
I'm looking to sort it into multiple arrays by type like below:
var sorted = {
"stream" : [
{
"price" : "2.99",
"id" : "8ejwj"
},
{
"price" : ".99",
"id" : "13nee"
},
... // other objects with type: "stream"
],
"buy" : [
{
"price" : "3.99".
"id" : "9akwk"
},
... // other objects with type: "buy"
]
}
I've tried it, but the only solution I can think of is by cases - run if loop, if case matches type, then push object to array. Is there a more elegant solution?
var items = {};
var i = 0;
for(i; i < res.length; i += 1){
var resItem = res[i];
if(items.hasOwnProperty(resItem.type)){
items[resItem.type].push({price:resItem.price, id:resItem.id});
} else {
items[resItem.type] = [{price:resItem.price, id:resItem.id}];
}
}
The properties on JavaScript objects are hashed, so you can dynamically match and generate new objects like above. If you want to apply a well ordering sort, you'll need to apply it to the arrays of the newly generated items object.
Step 1 :
Convert the JSON to a jquery object :
var x = jQuery.parseJSON( jsonString );
Step 2:
Use underscore library's _.groupBy to group :
_.groupBy(x,'type');
There might be some adjustment you need to do for x being array or object.
Edit :
You don't need step1. Just do :
sorted = _.groupBy(json.res,'type');
You could do something like this with ECMA5. This performs, generically, the sort and reduce that you have indicated in your question, so you can add more fields to your data without having to change the routine. It also leaves your original data intact.
Javascript
var original = {
'res': [{
'type': 'stream',
'price': '3.99',
'id': '13nee'
}, {
'type': 'stream',
'price': '2.99',
'id': '8ejwj'
}, {
'type': 'buy',
'price': '3.99',
'id': '9akwk'
}]
},
sorted = {};
original.res.slice().sort(function (a, b) {
a = +(a.price);
b = +(b.price);
if (a < b) {
return -1;
}
if (a > b) {
return 1;
}
return 0;
}).reduce(function (acc, element) {
if (!acc[element.type]) {
acc[element.type] = [];
}
acc[element.type].push(Object.keys(element).filter(function (name) {
return name !== 'type';
}).reduce(function (prev, name) {
prev[name] = element[name];
return prev;
}, {}));
return acc;
}, sorted);
console.log(JSON.stringify(sorted));
Output
{
"stream": [{
"price": "2.99",
"id": "8ejwj"
}, {
"price": "3.99",
"id": "13nee"
}],
"buy": [{
"price": "3.99",
"id": "9akwk"
}]
}
On jsFiddle
For example with have this code:
var json = {
"user1" : {
"id" : 3
},
"user2" : {
"id" : 6
},
"user3" : {
"id" : 1
}
}
How can I sort this json to be like this -
var json = {
"user3" : {
"id" : 1
},
"user1" : {
"id" : 3
},
"user2" : {
"id" : 6
}
}
I sorted the users with the IDs..
I don't know how to do this in javascript..
First off, that's not JSON. It's a JavaScript object literal. JSON is a string representation of data, that just so happens to very closely resemble JavaScript syntax.
Second, you have an object. They are unsorted. The order of the elements cannot be guaranteed. If you want guaranteed order, you need to use an array. This will require you to change your data structure.
One option might be to make your data look like this:
var json = [{
"name": "user1",
"id": 3
}, {
"name": "user2",
"id": 6
}, {
"name": "user3",
"id": 1
}];
Now you have an array of objects, and we can sort it.
json.sort(function(a, b){
return a.id - b.id;
});
The resulting array will look like:
[{
"name": "user3",
"id" : 1
}, {
"name": "user1",
"id" : 3
}, {
"name": "user2",
"id" : 6
}];
Here is a simple snippet that sorts a javascript representation of a Json.
function isObject(v) {
return '[object Object]' === Object.prototype.toString.call(v);
};
JSON.sort = function(o) {
if (Array.isArray(o)) {
return o.sort().map(JSON.sort);
} else if (isObject(o)) {
return Object
.keys(o)
.sort()
.reduce(function(a, k) {
a[k] = JSON.sort(o[k]);
return a;
}, {});
}
return o;
}
It can be used as follows:
JSON.sort({
c: {
c3: null,
c1: undefined,
c2: [3, 2, 1, 0],
},
a: 0,
b: 'Fun'
});
That will output:
{
a: 0,
b: 'Fun',
c: {
c2: [3, 2, 1, 0],
c3: null
}
}
In some ways, your question seems very legitimate, but I still might label it an XY problem. I'm guessing the end result is that you want to display the sorted values in some way? As Bergi said in the comments, you can never quite rely on Javascript objects ( {i_am: "an_object"} ) to show their properties in any particular order.
For the displaying order, I might suggest you take each key of the object (ie, i_am) and sort them into an ordered array. Then, use that array when retrieving elements of your object to display. Pseudocode:
var keys = [...]
var sortedKeys = [...]
for (var i = 0; i < sortedKeys.length; i++) {
var key = sortedKeys[i];
addObjectToTable(json[key]);
}
if(JSON.stringify(Object.keys(pcOrGroup).sort()) === JSON.stringify(Object.keys(orGroup)).sort())
{
return true;
}