I want to click on Item1, replace the label "Item1" with "Saved", then fade out the button after 500ms and place back the label "Item1" (saved in var currentText)
If I click the button multiple times it fires too many times. How can I prevent that?
$('body').on('click', ".item", function() {
var currentText = $(this).text();
$(this).text('Saved!').delay(500).fadeOut("fast", function() {
$(this).text(currentText).css('display', '');
});
});
This could be solved with a simple flag indicating that you are in the process of fading it out.
var isFadingOut = false;
$('body').on('click', ".item", function() {
if (isFadingOut) {
return;
}
isFadingOut = true;
var currentText = $(this).text();
$(this).text('Saved!').delay(500).fadeOut("fast", function() {
$(this).text(currentText).css('display', '');
isFadingOut = false;
});
});
Note: this solution works globally. So if you have multiple different buttons on screen that you want to be able to fade out simultaneously, this will not work. If that's the case, something more like what #Phiter wrote would be better.
I'd do something like this:
$('body').on('click', ".item", function() {
if ($(this).data('off')) return;
$(this).data('off', true);
var currentText = $(this).text();
$(this).text('Saved!').delay(500).fadeOut("fast", function() {
$(this).text(currentText).css('display', '');
$(this).data('off', false);
});
});
The function will not execute while the button has the off data. Kinda like Mike's answer but without the global variable.
Can use not(':animated'). The :animated pseudo selector is used internally by jQuery and is only active when an animation is in progress
$('body').on('click', ".item", function() {
var currentText = $(this).text();
$(this).not(':animated').text('Saved!').delay(500).fadeOut("fast", function() {
$(this).text(currentText).css('display', '');
});
});
Related
I have a jQuery function which, on the events mouseover and mouseout of the <div>s with the class .myshp_list_product_image, changes their src attribute.
The issue is that when I hover one of them, it also changes the others.How can I make it only change the one being hovered?
Here's the code of the function:
$(function() {
$('.myshp_list_product_image').mouseover(function() {
$('.myshp_list_product_image').each(function() {
var $this = $(this);
$this.attr('src', $this.attr('src').replace('1s', '2s'));
});
});
$('.myshp_list_product_image').mouseout(function() {
$('.myshp_list_product_image').each(function() {
var $this = $(this);
$this.attr('src', $this.attr('src').replace('2s', '1s'));
});
});
});
You don't need .each() here, get rid of it. You just need to target the current element i.e. this.
$(function() {
$('.myshp_list_product_image').mouseover(function() {
var $this = $(this);
$this.attr('src', $this.attr('src').replace('1s', '2s'));
});
$('.myshp_list_product_image').mouseout(function() {
var $this = $(this);
$this.attr('src', $this.attr('src').replace('2s', '1s'));
});
});
I would recommend you to use mouseenter and mouseleave event, A small demo for the difference between mouseover and mouseenter
I would use .hover() from jQuery
$(function () {
$('.myshp_list_product_image').hover(function () { // mouse in
var $this = $(this);
$this.attr('src', $this.attr('src').replace('1s', '2s'));
}, function () { // mouse out
var $this = $(this);
$this.attr('src', $this.attr('src').replace('2s', '1s'));
});
});
Just target the currently hovered/hovered out element instead of iterating over all elements with same class.
Also you can use .hover instead of mouseover and mouseout and callback function of .attr() to minimize your code:
$('.myshp_list_product_image').hover(
function() {
$(this).attr('src',function(i,oldattr){return oldattr.replace('1s', '2s')});
}, function() {
$(this).attr('src',function(i,oldattr){return oldattr.replace('2s', '1s')});
});
I have one question about jQuery close system. I have created this DEMO from codepen.io
In this demo you can see there are two div (red and blue). When you click the red div then the .CRtW11 will be an active. But after you click the blue div the .CRtW11 stayed on there; it needs to be inactive. What is the problem there, can anyone tell me ?
JS
// FOR cR
$("body").on("click", ".cR", function(event) {
event.stopPropagation();
var $current = $(this).find('.CRtW11').toggleClass("CRtW11-active");
$('.CRtW11').not($current).removeClass('CRtW11-active');
var $currenta = $(this).find('.ReaC').toggleClass("ReaC-active");
$(".ReaC").not($currenta).removeClass("ReaC-active");
});
$("body").click(function() {
$(".CRtW11").removeClass("CRtW11-active");
$(".ReaC").removeClass("ReaC-active");
});
// FOR Br
$("body").on("click",".Br", function(event) {
event.stopPropagation();
var $current = $(this).find(".BRc").toggleClass("BRc-active");
$(".BRc").not($current).removeClass("BRc-active");
});
$("body").on("click", function(){
$(".BRc").removeClass("BRc-active");
});
$("body").click(function() {
$(".CRtW11").removeClass("CRtW11-active");
$(".ReaC").removeClass("ReaC-active");
});
This function wont work for the red and blue div as their click events are stopped in their respective click functions. So the simple solution will be to add the remove class function in the opposite click functions. i.e.
// FOR cR
$("body").on("click", ".cR", function(event) {
$(".BRc").removeClass("BRc-active");
event.stopPropagation();
var $current = $(this).find('.CRtW11').toggleClass("CRtW11-active");
$('.CRtW11').not($current).removeClass('CRtW11-active');
var $currenta = $(this).find('.ReaC').toggleClass("ReaC-active");
$(".ReaC").not($currenta).removeClass("ReaC-active");
});
$("body").click(function() {
$(".CRtW11").removeClass("CRtW11-active");
$(".ReaC").removeClass("ReaC-active");
});
// FOR Br
$("body").on("click",".Br", function(event) {
$(".CRtW11").removeClass("CRtW11-active");
$(".ReaC").removeClass("ReaC-active");
event.stopPropagation();
var $current = $(this).find(".BRc").toggleClass("BRc-active");
$(".BRc").not($current).removeClass("BRc-active");
});
$("body").on("click", function(){
$(".BRc").removeClass("BRc-active");
});
I have this JSfiddle and i need to slide in, when clicking on a div, and not when page is loaded. Simultaneously it should be possible to close by clicking anywhere outside the slide-in box.
$( document ).ready(function() {
$(function(){
$(".slide-in").addClass("active");
console.log($(".slide-in"));
});
});
I think the solution could be some kind of toggle system, but i can't figure out how to?
Thank you!
Opens the slider on click of .button. Closes it on click anywhere outside the slider (including the button)
var isOpened = false;
$(document).click(function(e) {
if(isOpened && e.target.className=='slide-in') {
$(".slide-in").removeClass("active");
isOpened = false;
} else if(!isOpened && e.target.className=='button'){
$(".slide-in").addClass("active");
isOpened = true;
}
});
Better is to use IDs. So your code would be:
<div id="slide-in"></div>
<div id="button"></div>
and the javascript:
var isOpened = false;
$(document).click(function(e) {
if(isOpened && e.target.id!='slide-in') {
$("#slide-in").removeClass("active");
isOpened = false;
} else if(!isOpened && e.target.id=='button'){
$("#slide-in").addClass("active");
isOpened = true;
}
});
You'll also need to change the CSS from classes to IDs
Try this.
var someDiv = document.getElementById('yourDiv');
someDiv.style.cursor = 'pointer';
someDiv.onclick = function() {
//do something
}
how to make div click-able?
https://jsfiddle.net/zer00ne/jne1rasb/
$(document).ready(function() {
$('.button').on('click dblclick', function(e) {
$('.slide-in').toggleClass('active');
e.stopPropagation();
});
$(document).on('click', function() {
$(".slide-in").removeClass("active");
});
});
I think this should do the trick.
Edit:
$( document ).ready(function() {
$(".button").on("click",function(){
if($(".slide-in").hasClass("active")){
$(".slide-in").removeClass("active");
}else{
$(".slide-in").addClass("active");
}
});
});
Here is my piece of code in jquery actuall I want in such way where :
Where by default value of Ball will be shown in Textbox.
same time either All or Stopall will be work(it's not working here properly :( )
For multiple times checking All button,which is not working according to the expectation
here is the fiddle link : http://jsfiddle.net/bigzer0/PKRVR/11/
$(document).ready(function() {
$('.check').click(function(){
$("#policyName").val('Start');
$("#features").val('');
$('[name="startall"]').on('click', function() {
var $checkboxes = $('input[type="checkbox"]').not('[name="startall"], [name="stopall"]');
if (this.checked) {
$checkboxes.prop({
checked: true,
disabled: true
});
}
else{
$checkboxes.prop({
checked: false
});
}
});
$(".check").each(function(){
if($(this).prop('checked')){
$("#policyName").val($("#policyName").val() + $(this).val());
$("#features").val($("#features").val() + $(this).data('name'));
}
});
});
});
Any comments on this context will be welcome
You're code is broken in many ways. You are binding a click event inside a click event. You should take that outside and just make sure it's inside the document.ready function since your element is a static element.
$(document).ready(function() {
// cache features
var $features = $('#features');
// cache policyname
var $policy = $("#policyName");
// cache all/stopall
var $ss = $('[name="startall"],[name="stopall"]');
// cache all others
var $checkboxes = $('input[type="checkbox"]').not($ss);
// function to update text boxes
function updateText() {
var policyName = 'Start';
var features = '';
// LOOP THROUGH CHECKED INPUTS - Only if 1 or more of the 3 are checked
$checkboxes.filter(':checked').each(function(i, v) {
policyName += $(v).val();
features += $(v).data('name');
});
// update textboxes
$policy.val(policyName);
$features.val(features);
}
$checkboxes.on('change', function() {
updateText();
// check startall if all three boxes are checked
$('input[name="startall"]').prop('checked', $checkboxes.filter(':checked').length == 3);
});
$('input[name="startall"]').on('change', function() {
$checkboxes.prop({
'checked': this.checked,
'disabled': false
});
updateText();
});
$('input[name="stopall"]').on('change', function() {
$checkboxes.add('[name="startall"]').prop({
'checked': false,
'disabled': this.checked
});
updateText();
});
// updatetext on page load
updateText();
});
FIDDLE
you are checking click function in click function. you should use if statement.
i have the following jQuery code.
$(function() {
$('.clickme').click(function() {
$('.totalthing').slideToggle('slow','easeInOutQuart', function() {
// Animation complete.
});
$('.expandedcase').slideToggle('slow','easeInOutQuart', function() {
// Animation complete.
});
});
});
At the moment it closes one of the div's and opens another at the same time. What I want it to do is close the open div then once it is fully closed it opens the other.
try:
$(function() {
$('.clickme').click(function() {
var tot = $('.totalthing');
var exp = $('.expandedcase');
var frt = (tot.is(":visible"))?tot:exp;
var lst = (tot.is(":visible"))?exp:tot;
frt.stop().slideToggle('slow','easeInOutQuart', function() {
lst.stop().slideToggle('slow','easeInOutQuart', function() {/*complete*/});
});
});
});
Your comments should point you in the right direction. If you want one animation to start once the other is complete, then move it to the function.
$(function() {
$('.clickme').click(function() {
$('.totalthing').slideToggle('slow','easeInOutQuart', function() {
// Animation complete.
$('.expandedcase').slideToggle('slow','easeInOutQuart', function() {
// Animation complete.
});
});
});
});