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Insert data into MySQL Databse with PHP/AJAX, execute success option AFTER it's inserted (Callback)

I've been trying to make a simple site, and I can't quite wrap my head around some of the things said here, some of which are also unrelated to my situation.
The site has a form with 3 input boxes, a button, and a list. The info is submitted through a separate PHP file to a MySQL database, once the submit button is clicked. I'm supposed to make the list (it's inside a div) update once the info is successfully sent and updated in the database. So far I've made it work with async:false but I'm not supposed to, because of society.
Without this (bad) option, the list doesn't load after submitting the info, because (I assume) the method is executed past it, since it doesn't wait for it to finish.
What do I exactly have to do in "success:" to make it work? (Or, I've read something about .done() within the $.ajax clause, but I'm not sure how to make it work.)
What's the callback supposed to be like? I've never done it before and I can get really disoriented with the results here because each case is slightly different.
function save() {
var name = document.getElementById('name');
var email = document.getElementById('email');
var telephone = document.getElementById('telephone');
$.ajax({
url: "save.php",
method: "POST",
data: { name: name.value, email: email.value, telephone: telephone.value },
success: $("List").load(" List")
});
}
Thank you in advanced and if I need include further info don't hesitate to ask.

From this comment
as far as i know the success function will be called on success you should use complete, A function to be called when the request finishes (after success and error callbacks are executed). isnt that what you want ? – Muhammad Omer Aslam
I managed to solve the issue simply moving the $.load clause from the success: option to a complete: option. (I think they're called options)
I haven't managed error handling yet, even inside my head but at least it works as it should if everything is entered properly.
Thanks!
(Won't let me mark as answered until 2 days)

I would first create an AJAX call inside a function which runs when the page loads to populate the list.
window.onload = populatelist();
function populatelist() {
$.ajax({
type: "POST",
url: "list.php",
data: {function: 'populate'},
success: function(data) { $("#list").html("data"); }
});
}
Note: #list refers to <div id="list> and your list should be inside this.
I would then have another AJAX call inside a different function which updates the database when the form is submitted. Upon success, it will run the populatelist function.
function save() {
var name = document.getElementById('name');
var email = document.getElementById('email');
var telephone = document.getElementById('telephone');
$.ajax({
type: "POST",
url: "list.php",
data: {function: 'update', name: name.value, email: email.value, telephone: telephone.value },
success: function() { populatelist(); }
});
}
list.php should look like this:
<?php
if($_POST['function'] == "populate") {
// your code to get the content from the database and put it in a list
}
if($_POST['function'] == "update") {
// your code to update the database
}
?>

I will show you piece of solution that I use in my project. I cannot say it is optimal or best practices, but it works for me and can work for you:
PHP:
function doLoadMails(){
//initialize empty variable
$mails;
$conn = new mysqli($_POST['ip'], $_POST['login'], $_POST['pass'], $_POST['db']);
// Check connection
if ($conn->connect_error) {
die("");
}
//some select, insert, whatever
$sql = "SELECT ... ... ... ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row, j is counter for rows
$j =0;
while($row_a = $result->fetch_assoc()) {
//for each row, fill array
$mails[$j][0] = $row_a["name"] ;
$mails[$j][1] = $row_a["mail"] ;
$mails[$j][2] = $row_a["language"] ;
$j++;
}
}
//if $mails has results (we added something into it)
if(isset($mails)){
echo json_encode($mails);/return json*/ }
else{
//some error message you can handle in JS
echo"[null]";}
}
and then in JS
function doLoadMails() {
$.ajax({
data: { /*pass parameters*/ },
type: "post",
url: "dataFunnel.php",
success: function(data) { /*data is a dummy variable for everything your PHP echoes/returns*/
console.log(data); //you can check what you get
if (data != "[null]") { /*some error handling ..., in my case if it matches what I have declared as error state in PHP - !(isset($mails))*/ }
}
});
Keep in mind, that you can echo/return directly the result of your SQL request and put it into JS in some more raw format, and handle further processing here.
In your solution, you will probably need to echo the return code of the INSERT request.

how to fetch data from sql server database in php without refreshing the page

I am trying to get some data from the database. I create a function that is located in functions.php file that return a value. On another page, I create a variable and just get that value. I was trying to use the onkey to check the database but then I realize that i need to know the amount of tickets even if they don't type anything.
Here is the function:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$amount_of_tickets = $row['number_of_tickets'];
}
return $amount_of_tickets;
}
And, I am trying to check the database (without refreshing the page) and get the value on this page:
application.php
$amount_of_tickets = is_ticket_able($conn);
Then, I just check that $amount_of_tickets is not 0 or 1. Because if is one then some stuff have to change.
I am doing this (inside application.php):
if($amount_of_tickets !=0){
//show the form and let them apply for tickets.
//also
if($amount_of_tickets == 1){
//just let them apply for one ticket.
}
}
EDIT: I saw that AJAX would be the right one to use, but I am so confuse using it.
UPDATE:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
return $ticket;
}
application.php
$amount_of_tickets = is_ticket_able($conn);
<script type="text/javascript">
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
alert(global_isTicketAble);
if( global_isTicketAble == 0 ){
window.location.replace("http://www.google.com");
}
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
});
}
</script>
So, now the problem is that when I alert(global_isTicketAble); it doesn't alert the value from the database but it does alert everything that is inside application.php...Help plzzz

Server side
Assuming you need to check $amount_of_tickets periodically and this can be computed into application.php, inside that file you'll have
<?php
// $conn is defined and set somewhere
$amount_of_tickets = is_ticket_able($conn);
echo $amount_of_tickets;
exit(0);
?>
This way when the script is invoked with a simple GET request the value is returned in the response as simple text.
Client Side
ajax is the way to go if you want to update information on page without reloading it.
Below is just a simple example (using jQuery) that may be extended to fit your needs.
The code below is a JavaScript snippet. A global is used to store the value (globals should be avoided but it's just for the purpose of the example)
Then a function is invoked and the updated value is fetched from function.php script.
The function -prior termination- schedules itself (with setTimeout) to be re-invoked after a given amount of milliseconds (to repeat the fetch value process).
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
// eventually do something here
// with the value just fetched
// (ex. update the data displayed)
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
}
}
Note that $.ajax() sends the request but does not wait for the response (as async is set to true). When the request is received the function specified as success is executed.
Complete jQuery ajax function documentation can be found here
http://api.jquery.com/jquery.ajax/

I assume that you have a page (application.php) that displays a table somewhere.
And that you wish to fill that table with the data found in you database.
I'm not sure about WHEN you want these data to be refreshed.
On button click or periodically (like ervery 5 seconds)... But it doesn't matter for what I explain below.
In application.php:
Assemble all your page as you already know how.
But inside it, somewere, just insert an empty div where your table should show:
<div id="dynamicContent"></div>
Also add this script at the bottom of the page:
<script>
function getData(){
PostData="";
$.ajax({
type: "POST",
url: "function.php",
data: PostData,
cache: true,
success: function(html){
$(Destination).html(html);
}
});
}
getData(); // Trigger it on first page load !
</script>
There is 2 variables here... I named it "PostData" and "Destination".
About PostData:
You can pass data collected on the client side to your PHP function if needed.
Suppose you'd need to pass your user's first and last name, You'd define PostData like this:
Fname=$("#Fname").val(); // user inputs
Lname=$("#Lname").val();
PostData="Fname="+Fname+"&Lname="+Lname;
In your function.php, you will retreive it like this (like any normal POST data):
$Fname=$_POST['Fname'];
$Lname=$_POST['Lname'];
If you do not need to pass data from your client side script to you server side PHP... Just define it empty.
PostData="";
Then, about Destination:
This is the place for the empty "dynamic div" id ( I named it "dynamicContent" above).
Don't forget about the hashtag (#) for an id or the dot for a class.
This is a jQuery selector.
So here, PostData would be defined like this:
Destination="#dynamicContent";
The result of the ajax request will land into that "dynamic div".
This WILL be the result of what's defined in function.php..
So, if you follow me, you have to build your table in function.php...
I mean the part where you do your database query and your while fetch.
echo "<table>";
echo "<tr><th>column title 1</th><th>column title 2</th></tr>"
while ($row = sqlsrv_fetch_array($stmt)){
echo "<tr><td>" . $row['data1'] . "</td><td>" . $row['data2'] . "</td></tr>";
}
echo "</table>";
So if you have no data, the table will be empty.
You'll only get the table and table headers... But no row.
There is then no need for a function that checks if there is data or not.
Finally... About the trigger to refresh:
In application.php, you may place a button that fires getData()... Or you may define a setInterval.
It's up to you.
This is how I use ajax to refresh part of a page without reloading it completly.
Since ajax is new to you, I hope this answer will help.
;)
------------------------
EDIT based on Ariel's comment (2016-05-01)
Okay, I understand! Try this:
In application.php:
<div id="dynamicDiv"></div>
<script type="text/javascript">
// timer to trigger the function every seconds
var checkInterval = setInterval(function(){
checkTicket();
},1000);
function checkTicket(){
$.ajax({
type: "POST",
url: "function.php",
data: "",
cache: true,
success: function(html){
$("#dynamicDiv").html(html);
}
});
}
function noMoreTikets(){
clearInterval(checkInterval);
window.location.replace("http://www.google.com");
}
</script>
In function.php:
// Remove the "function is_ticket_able($conn){" function wrapper.
// Define $conn... Or include the file where it is defined.
// I assume that your query lookup works.
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
// Add this instead of a return.
if($ticket>0){
echo "There is still some tickets!"; // Text that will show in "dynamicDiv"
}else{
?>
<script>
$(document).ready(function(){
noMoreTikets();
});
</script>
<?php
}
Remember that your PHP scripts are executed server-side.
That is why your "return $ticket;" wasn't doing anything.
In this ajax way to call function.php, its script is executed alone, like a single page, without any relation with application.php, which was executed long ago.
It produces text (or javascript) to be served to the client.
If you want to pass a PHP variable to the client-side javascript, you have to echo it as javascript.
So here, if the PHP variable $ticket is more than zero, some text saying that there is still tickets available will show in "dynamicDiv" and the application page will not be refreshed. I suppose it shows a button or something that allows students to get a ticket.
Else, it will be the javascript trigger to "noMoreTikets()" that will land in the "dynamicDiv".

Unable to send jQuery variable with string content to PHP using jQuery AJAX function?

The code snippet for the jQuery function looks like:
function addMessage() {
if (textval != "") {
text_string='<div class="alert-box round"><p class="text-left">' + userName + ':' + textval + '</p></div></br>';
alert(text_string);
$.ajax({
type:"POST",
url:"process.php",
data: {'text_string': text_string},
cache:false,
success:function(){
alert("submitted")
}
});
$("input[type=text]:last").val("");
}
enterButton = 0;
}
The process.php code looks like:
<body>
<?php
//$host = "localhost";
$text_string=$_POST['text_string'];
echo "string submitted is".$text_string;
?>
</body>
I get alerts showing value of text_string and then the "submitted", but when I open the php page, it shows an error:
Undefined index: text_string
I've seen various answers, none of them seem to be the case for mine. Is the problem in PHP code or jQuery code or both?

If you want to save the value passed by the AJAX request for the next time you load "process.php", try saving it in the session. So, you could change your code to:
<?php
session_start();
// Store value in session if it is passed
if (isset($_POST['text_string'])){
$_SESSION['text_string'] = $_POST['text_string'];
}
// Read and echo value from session if it is set
else if (isset($_SESSION['text_string'])){
$text_string=$_SESSION['text_string'];
echo "string submitted is".$text_string;
}
?>
Now, your PHP script will store the passed value in the session, and will echo that stored value should you load the page elsewhere. (Another alternative is to store the value in a database...though I'm not sure if you have one set up at the moment.)
Hope this helps! Let me know if you have any questions.

Passing values from jQuery to PHP in same page instantly

I have written a PHP program to confirm deletion of data through jQuery confirm message (Refer: http://rathur.fr/jQuery/MsgBox/) and record the result back to the same page itself instantly. If the page refreshes, it'll return back its state to previous.
The part of line is below:
print "
<script type='text/javascript'>
$(document).ready(function(){
$.msgbox('<br/>Are you sure you want to delete the selected record from the database?', {
type : 'confirm'
}, function(result){
$('#output').text(result);
var output = result;
});
});
</script>";
I want to get the result of the action button to PHP variable instantly, like below (just a trial):
$x = $_SESSION['output']; OR
$x = $_POST['output']; OR
$x = print "<div id=\"output\"></div>"; OR
$x = some_function(output);
Please help me, or suggest if there is other better options.

Here is a simple Ajax call to a Php File by an event : Click on a button.
Javascript client side :
$("body").on("click", "#mybutton", function() {
var mydata = $("#form").serialize();
$.ajax({
type: "POST",
url: "/api/api.php",
data: {data : mydata},
timeout: 6e3,
error: function(a, b) {
if ("timeout" == b) $("#err-timedout").slideDown("slow"); else {
$("#err-state").slideDown("slow");
$("#err-state").html("An error occurred: " + b);
}
},
success: function(a) {
var e = $.parseJSON(a);
if (true == e["success"]) {
$("#action").html(e['message']);
// here is what you want, callback Php response content in Html DOM
}
}
});
return false;
});
Next in your Php code simply do after any success function :
if ($result) {
echo json_encode(array(
'success' => true,
'msg' => "Nice CallBack by Php sent to client Side by Ajax Call"
));
}

You should use jQuery to POST the data to a PHP script using AJAX if you want to use the second pass.
http://api.jquery.com/category/ajax/ has many functions and tutorials on writing AJAX functions and handling return data. In particular, look at the post() function.

Ajax driven content using CodeIgniter

I'm making an web that is a single-page website interacting with the server through Ajax in CodeIgniter. The general coding is of the following type:
controller (user.php):
public function get_user_content() {
$id = $this->input->post('id');
$hits = $this->user_model->user_data($id);
$s = '';
foreach ($hits as $hit) {
$s .= $hit->name;
$s .= $hit->age;
}
echo $s;
}
model(user_model.php):
function user_data($id) {
//do sql operation
return $query->result();
}
view:
...
...
Click here for user details
...
...
javascript:
('.user-data').click(get_user_data);
....
....
function get_user_data(response) {
return $.ajax({
type: "POST",
url: "<?php echo base_url();?>index.php/user/get_user_content",
data: { id: this.id },
success: function(response) {
$("#somediv").append(response);
$(".someclass").click(another_function);
},
error: function(error) {
alert("Error");
}
});
}
So, looking at the above javascript, there are separate functions for all actions that send some data to the server and the particular html content is updated via Ajax.
I had the following questions (I'm just new to this stuff):
1. Is there any better way of doing ajax in javascript than my implementation.
2. I'm not using the concept of views in CodeIgniter. I just `echo` results through my controller functions that gets embedded in javascript. This is because I want dynamic update in my app. It is a single page and there is no concept of new-page/new-tab. Is there any better way?
I'm not aware of any open-source projects that might make it easier/more optimized.

For making code more simplified, readable & with great coding standard answer will be yes for both to improve your javascript code & way you are getting a response from the Ajax call.
Improve Javascript :
You might have one common js included in you header portion, if not create & include one. This common jar contains only common functions throughout the application. Create one function with the name may be like sendAjaxRequest() in that common.js. This function will have some parameters like divId (refresh div id), url(post url), options(array of options) & function will look like this:
function sendAjaxRequest(strDivId, strRequestUrl, options) {
options = options || {};
var defaultOptions = {url: strRequestUrl, type: 'POST', beforeSend: function(request,options){showLoadingImage(strDivId);}, success: function(html){$('#'+strDivId).html(html); removeLoadingImage(strDivId); }};
options = $.extend({},defaultOptions,options);
$.ajax(options);
}
Call this function from where ever required on application.
like
('.user-data').click( function() { sendAjaxRequest('somediv', url,{data: { id: this.id }}) });
Benefit : This method is very useful in the future when you want to keep google analytics on ajax call also or want to track your ajax calls. It is always good to have common functions.
Resposnse from ajax call: You can load views in Controller->function in case of ajax call also, nothing need to change or configure for this. Use of this way is always good practice to maintain standardness & readablity in the code.
Note : Here in this case you might worry about using a second action on load of your first Ajax call, for this standard way is to write second action on load of view of that particular Ajax call view (Write second click code in that particular view only) like
('.someclass').click( function() { sendAjaxRequest('someOtherDiv', otherUrl,{data: { id: this.id }}) });
In short at the end user divide & conquer rule (Divide an html page into blocks & create the huge page) to create good applications. Its really fantastic way, as I am using this way in my codings overall.

1- There is other ways to do ajax calls , being better or not is based on your needs, This post clears this point
2- your way is good, still you could use some enhancements to your functions to be a complete web-services same as handling errors - in case - and to return the output data as json allowing you to control it from your JavaScript function for a better handling & representation.
3- from what i understood you're getting data for single user each time ,in this case using $query->row() would be make your life easier extracting the data than using $query->result() , but in case you are getting multiple records you could loop it withing your JavaScript function.
here's another approach to your example with little enhancements that might be helpful :
controller (user.php):
public function get_user_content($id) {
$output -> hit = $this -> user_model -> user_data($id);
if (!$output -> hit) {
$output -> msg = "NORECORDS";
} else {
$output -> msg = "SUCCESS";
}
echo json_encode($output);
}
model(user_model.php):
function user_data($id) {
//do sql operation
return $query -> row();
}
JavaScript :
function get_user_data(response) {
$.get("<?php echo base_url();?>index.php/user/get_user_content/" + this.id, function(data) {
if (data.msg != 'SUCCESS') {
alert(data.msg);
return;
}
var hit = data.hit;
$("#somediv").append("Name: " + hit.name + "Age: " + hit.age);
$(".someclass").click(another_function);
}, "json");
}

First Answer:
The ajax request seems fine, you can add dataType option also to expect particular type of response,
As you are using post you can use jquery.post as an alternative
Example
$.post( "<?php echo base_url();?>index.php/user/get_user_content", function(data) {
alert( "success" );
}, 'html') // here specify the datatype
.fail(function() {
alert( "error" );
})
You can also use done callback instead of success
Second answer:
Controller
public function get_user_content() {
$id = $this->input->post('id');
$hits = $this->user_model->user_data($id);
$user_array = array();
foreach ($hits as $hit) {
$temp_array = array();
$temp_array = array('name' => $hit->name);
$temp_array = array('age' => $hit->age);
$user_array = array($temp_array);
}
$this->load->view('user', $user_array);
}
Modal
Remains the same
View (user.php)
example say user.php
<?php
echo "<div class='somediv'>";
if (sizeof($user_array)) {
for ($row = 0; $row < sizeof($user_array); $row++ ) {
echo "User Details: Name - " . $user_array[$row]['name'] . ", Age - " . $user_array[$row]['age'];
echo "<br/>";
}
} else {
Click here for user details
}
echo "</div>";
?>
Javascript
$('.user-data').on('click' function () { // better to use event delegation as content is loaded dynamically
get_user_data();
});
function get_user_data() {
$.post( "<?php echo base_url();?>index.php/user/get_user_content", function(data) {
alert( "success" );
$("#somediv").append(data);
$(".someclass").click(another_function);
}, 'html') // here specify the datatype
.fail(function() {
alert( "error" );
});
}
Reference
stackoverflow.com/questions/18471627/codeigniter-load-a-view-using-post-and-ajax