I am trying to get two buttons groups with checkboxes mutually exclusive.
Here's my current result on this JS Fiddle
As you can see, there are four divs (with id="UserVsComputer", id="User1VsUser2", id="PlayableHits" and id="button-new-game").
I want the two first <div> ( UserVsComputer and User1VsUser2 ) to be mutually exclusive when we click on the checkbox of concerning <input> (i.e corresponding to the right <div>).
In JavaScript part, I did:
// Select the clicked checkbox for game type
$('input.game').on('click',function(){
setGameType();
});
function setGameType() {
// Get state of the first clicked element
var element = $('#UserVsComputer input.game');
var checkBoxState = element.prop('checked');
// Set !checkBoxState for the sibling checkbox, i.e the other
element.siblings().find('input.game').prop('checked',!checkBoxState);
updateGameType();
}
function updateGameType() {
// Set type of game
if ($('#UserVsComputer input').prop('checked'))
gameType = 'UserVsComputer';
else
gameType = 'User1VsUser2';
}
I don't want the <div id="PlayableHits" class="checkbox"> to be concerned by this mutual exclusion on two first checkboxes.
For example, below a capture showing that I can set the two first checkbox to true without making them exclusive:
What might be wrong here?
Try the following - it uses the target of the click event to ascertain which checkbox was checked:
// Select the clicked checkbox for game type
$('input.game').on('click',function(e){
setGameType(e.target);
});
function setGameType(cb) {
var container = $(cb).parent().parent();
var checkBox = $(cb);
var checkBoxState = checkBox.prop('checked');
// Set !checkBoxState for the sibling checkbox, i.e the other
container.siblings().find('input.game').prop('checked', !checkBoxState);
updateGameType();
}
function updateGameType() {
// Set type of game
if ($('#UserVsComputer input').prop('checked')) {
gameType = 'UserVsComputer';
} else {
gameType = 'User1VsUser2';
}
}
There are other bits which could use some attention (the hardcoded .parent().parent() isn't pretty but works in this case..
Related
How to correctly control the visibility of primitives from Cesium3DTileset?
First I create a checkbox element in HTML, and a checkbox addEventListener to control the visibility of DataSource from my local geojson file. And it goes well.
And then I did the same thing to control whether the 3DTile from my Cesium ion account needs to be shown. At the fist check and uncheck, everything goes well. But the second time when I check the box, nothing shows up in the scene. And the second time of uncheck do nothing and no error as well.
//this is my checkbox elements
<input type="checkbox" id="showCheckbox1" > geojson1<br>
<input type="checkbox" id="showCheckbox2" > geojson2<br>
<input type="checkbox" id="showCheckbox_1" > ion_1<br>
<input type="checkbox" id="showCheckbox_2" > ion_2<br>
//this is my first try to control the visibility of geojson, and it goes well
var obj1 = new Cesium.GeoJsonDataSource();
obj.load('../DataSource/GeoJson/airport_cesium2.geojson')
var obj2 = new Cesium.GeoJsonDataSource();
obj2.load('../DataSource/GeoJson/LiangMau.geojson')
function handleCheckbox(id,datasource){
var checkbox = document.getElementById(id);
checkbox.addEventListener('change', function() {
// Checkbox state changed.
if (checkbox.checked) {
// Show if not shown.
if (!viewer.dataSources.contains(datasource)) {
viewer.dataSources.add(datasource);
}
} else {
// Hide if currently shown.
if (viewer.dataSources.contains(datasource)) {
viewer.dataSources.remove(datasource);
}
}
}, false);
}
handleCheckbox('showCheckbox1',obj1)
handleCheckbox('showCheckbox2',obj2)
//then I try to control the visibility of 3DTile
var obj_1 = new Cesium.Cesium3DTileset({
url: Cesium.IonResource.fromAssetId(35386)
})
var obj_2 = new Cesium.Cesium3DTileset({
url: Cesium.IonResource.fromAssetId(35381)
})
function handleCheckbox_(id,datasource){
var checkbox = document.getElementById(id);
checkbox.addEventListener('change', function() {
// Checkbox state changed.
if (checkbox.checked) {
// Show if not shown.
if (!scene.primitives.contains(datasource)) {
scene.primitives.add(datasource);
}
} else {
// Hide if currently shown.
if (scene.primitives.contains(datasource)) {
scene.primitives.remove(datasource);
}
}
}, false);
}
handleCheckbox_('showCheckbox_1',obj_1)
handleCheckbox_('showCheckbox_2',obj_2)
I can control the visibility of 3DTile at the first check and uncheck, but nothing happens at the second time. It really confuse me because there is no error showing, and I don't know what do next.
As mentioned in comments, the answer for this turned out to be to set the dataSource.show flag to toggle the visibility. Adding and removing the same dataSource multiple times was the problem, as typically when a dataSource is removed it is being destroyed. So, toggling visibility with the show flag is preferred.
When selecting a row in my SAPUI5 tree table I have to make sure that
all existing selections are removed
check if selected row has children and if so, select the item and all its children
To do that I use a function that gets called on the rowSelectionChange-Event of my table:
onRowSelectionChange: function(oEvent) {
if (oEvent.getParameters().userInteraction)
var oTable = oEvent.getSource();
var oObject = oEvent.getParameters().rowContext.getObject();
var iIndex = oEvent.getParameters().rowIndex;
// Check if row was selected or deselected
if (oTable.isIndexSelected(iIndex)) {
// Deselect other items
oTable.clearSelection();
// Select row again
oTable.addSelectionInterval(iIndex, iIndex);
// Check if object has children
if (oObject.content) {
//Select child rows here
} else {
// Do stuff
}
} else {
// Do stuff
}
}
}
As you can see the first thing I do is to check if the selection change's origin was an explicit user interaction, because, of course, clearing the selection and then adding the selection for the child rows will call the function again.
My problem is now, that when clearSelection() calls my function, the userInteraction-parameter is again set to true, despite not being an explicit user interaction. Am I missing something here?
Thank you!
I have a form with multiple HTML checkboxes. I want to hide some dividers only if at least one checked checkbox have a custom HTML5 attribute called "terminator". Otherwise I would want to show the dividers.
I tried to accomplish this by using the change() event to check if one has the terminator attribute.
Here is what I have done.
$("input[type='checkbox']").change(function(e) {
var className = 'terminated_' + getContronId($(this).attr('name'));
var existingElements = $('#survey-optional-controls').val().split('|') || [];
//Hide all groups that have the class equal to className
if( $(this).is(':checked') ){
if( $(this).data('terminator') ){
hideControls($(this), existingElements, className);
}
} else {
showControls(existingElements, className);
}
}).change();
The function hideControls will hide the desire inputs. The function showControls will display the desired inputs if any are hidden.
My code kinda works, but has one problem that I can't figure out a solution to. The problem happens after checking a box that has the terminator attribute and checking a box that does NOT have the terminator attribute, and then "un-checking" a box that does NOT have the terminator attribute.
When first checking the box with the terminator attribute the dividers hide as expected.
Then when un-checking a box that does not have a terminator attribute it shows dividers that should be hidden with appear since I still have 1 checked box with the terminator attribute.
How can I fix this problem?
I created this jFiddle to show the code and the problem in action. You can re-create the problem by jumping into the "1:b) More Questions" section on the jFiddle, then check the "Red" box and then the "Green - Terminator" box, and finally unchecking the "Red" box. You will see how the dividers below will appear where they should be hidden since "Green - terminator" is still checked"
You should be checking for the "checked" status of the checkbox with data-terminator attribute set on each change.
Something like
$("input[type='checkbox']").change(function(e) {
var className = 'terminated_' + getContronId($(this).attr('name'));
var existingElements = $('#survey-optional-controls').val().split('|') || [];
var isTerminatorChecked = $("input:checkbox[data-terminator='Yes']").is(":checked");
//Hide all groups that have the class equal to className
if (isTerminatorChecked) {
hideControls($(this), existingElements, className);
} else {
showControls(existingElements, className);
}
});
Updated fiddle
To make sure that showControls will only get invoked when the checkbox with the data-terminator attribute gets unchecked,
change this :
...
} else {
showControls(existingElements, className);
}
to
...
} else if ($(this).is("[data-terminator]")) {
showControls(existingElements, className);
}
Updated jsFiddle: http://jsfiddle.net/8yf0v3xt/10/
the code below said 'If any input that have the type checkbox is changing'
$("input[type='checkbox']").change(function(e) { /*hide*/ }
else { /*show*/}
when you uncheck the "red" checkbox this="red", and red is not checked so... it automatically go to the else statment which in to show divider
I have a webpage I'm building where I need to be able to select 1-9 members via a dropdown, which then provides that many input fields to enter their name. Each name field has a "suggestion" div below it where an ajax-fed member list is populated. Each item in that list has an "onclick='setMember(a, b, c)'" field associated with it. Once the input field loses focus we then validate (using ajax) that the input username returns exactly 1 database entry and set the field to that entry's text and an associated hidden memberId field to that one entry's id.
The problem is: when I click on the member name in the suggestion box the lose focus triggers and it attempts to validate a name which has multiple matches, thereby clearing it out. I do want it to clear on invalid, but I don't want it to clear before the onclick of the suggestion box name.
Example:
In the example above Paul Smith would populate fine if there was only one name in the suggestion list when it lost focus, but if I tried clicking on Raphael's name in the suggestion area (that is: clicking the grey div) it would wipe out the input field first.
Here is the javascript, trimmed for brevity:
function memberList() {
var count = document.getElementById('numMembers').value;
var current = document.getElementById('listMembers').childNodes.length;
if(count >= current) {
for(var i=current; i<=count; i++) {
var memberForm = document.createElement('div');
memberForm.setAttribute('id', 'member'+i);
var memberInput = document.createElement('input');
memberInput.setAttribute('name', 'memberName'+i);
memberInput.setAttribute('id', 'memberName'+i);
memberInput.setAttribute('type', 'text');
memberInput.setAttribute('class', 'ajax-member-load');
memberInput.setAttribute('value', '');
memberForm.appendChild(memberInput);
// two other fields (the ones next to the member name) removed for brevity
document.getElementById('listMembers').appendChild(memberForm);
}
}
else if(count < current) {
for(var i=(current-1); i>count; i--) {
document.getElementById('listMembers').removeChild(document.getElementById('listMembers').lastChild);
}
}
jQuery('.ajax-member-load').each(function() {
var num = this.id.replace( /^\D+/g, '');
// Update suggestion list on key release
jQuery(this).keyup(function(event) {
update(num);
});
// Check for only one suggestion and either populate it or clear it
jQuery(this).focusout(function(event) {
var number = this.id.replace( /^\D+/g, '');
memberCheck(number);
jQuery('#member'+number+'suggestions').html("");
});
});
}
// Looks up suggestions according to the partially input member name
function update(memberNumber) {
// AJAX code here, removed for brevity
self.xmlHttpReq.onreadystatechange = function() {
if (self.xmlHttpReq.readyState == 4) {
document.getElementById('member'+memberNumber+'suggestions').innerHTML = self.xmlHttpReq.responseText;
}
}
}
// Looks up the member by name, via ajax
// if exactly 1 match, it fills in the name and id
// otherwise the name comes back blank and the id is 0
function memberCheck(number) {
// AJAX code here, removed for brevity
if (self.xmlHttpReq.readyState == 4) {
var jsonResponse = JSON.parse(self.xmlHttpReq.responseText);
jQuery("#member"+number+"id").val(jsonResponse.id);
jQuery('#memberName'+number).val(jsonResponse.name);
}
}
}
function setMember(memberId, name, listNumber) {
jQuery("#memberName"+listNumber).val(name);
jQuery("#member"+listNumber+"id").val(memberId);
jQuery("#member"+listNumber+"suggestions").html("");
}
// Generate members form
memberList();
The suggestion divs (which are now being deleted before their onclicks and trigger) simply look like this:
<div onclick='setMember(123, "Raphael Jordan", 2)'>Raphael Jordan</div>
<div onclick='setMember(450, "Chris Raptson", 2)'>Chris Raptson</div>
Does anyone have any clue how I can solve this priority problem? I'm sure I can't be the first one with this issue, but I can't figure out what to search for to find similar questions.
Thank you!
If you use mousedown instead of click on the suggestions binding, it will occur before the blur of the input. JSFiddle.
<input type="text" />
Click
$('input').on('blur', function(e) {
console.log(e);
});
$('a').on('mousedown', function(e) {
console.log(e);
});
Or more specifically to your case:
<div onmousedown='setMember(123, "Raphael Jordan", 2)'>Raphael Jordan</div>
using onmousedown instead of onclick will call focusout event but in onmousedown event handler you can use event.preventDefault() to avoid loosing focus. This will be useful for password fields where you dont want to loose focus on input field on click of Eye icon to show/hide password
I'm using the chosen plugin to build multiple select input fields. See an example here: http://harvesthq.github.io/chosen/#multiple-select
The default behavior disables an option if it has already been selected. In the example above, if you were to select "Afghanistan", it would be greyed out in the drop-down menu, thus disallowing you from selecting it a second time.
I need to be able to select the same option more than once. Is there any setting in the plugin or manual override I can add that will allow for this?
I created a version of chosen that allows you to select the same item multiple times, and even sends those multiple entries to the server as POST variables. Here's how you can do it (fairly easily, I think):
(Tip: Use a search function in chosen.jquery.js to find these lines)
Change:
this.is_multiple = this.form_field.multiple;
To:
this.is_multiple = this.form_field.multiple;
this.allows_duplicates = this.options.allow_duplicates;
Change:
classes.push("result-selected");
To:
if (this.allows_duplicates) {
classes.push("active-result");
} else {
classes.push("result-selected");
}
Change:
this.form_field.options[item.options_index].selected = true;
To:
if (this.allows_duplicates && this.form_field.options[item.options_index].selected == true) {
$('<input>').attr({type:'hidden',name:this.form_field.name,value:this.form_field.options[item.options_index].value}).appendTo($(this.form_field).parent());
} else {
this.form_field.options[item.options_index].selected = true;
}
Then, when calling chosen(), make sure to include the allows_duplicates option:
$("mySelect").chosen({allow_duplicates: true})
For a workaround, use the below code on each selection (in select event) or while popup opened:
$(".chosen-results .result-selected").addClass("active-result").removeClass("result-selected");
The above code removes the result-selected class and added the active-result class on the li items. So each selected item is considered as the active result, now you can select that item again.
#adam's Answer is working very well but doesn't cover the situation that someone wants to delete some options.
So to have this functionality, alongside with Adam's tweaks you need to add this code too at:
Chosen.prototype.result_deselect = function (pos) {
var result_data;
result_data = this.results_data[pos];
// If config duplicates is enabled
if (this.allows_duplicates) {
//find fields name
var $nameField = $(this.form_field).attr('name');
// search for hidden input with same name and value of the one we are trying to delete
var $duplicateVals = $('input[type="hidden"][name="' + $nameField + '"][value="' + this.form_field.options[result_data.options_index].value + '"]');
//if we find one. we delete it and stop the rest of the function
if ($duplicateVals.length > 0) {
$duplicateVals[0].remove();
return true;
}
}
....