Remove the duplicate values before pushing into an array - javascript

It's visible in the image that the array[0] and array[3], array1 and array[4] are same. I was checking why the values are duplicating but I failed. So thought to just remove if any duplicate values exists. I need to remove it from
$scope.arr array itself.
Code:
$scope.arr = [];
planReq.then(function (callplanList) {
$scope.callplanList = callplanList.data.callplans;
//console.log($scope.callplanList);
for(var i = 0; i < $scope.planMapping.length; i++){
//console.log($scope.planMapping[i].PlanScode);
for(var j = 0; j < $scope.callplanList.length; j++){
if(($scope.planMapping[i].PlanScode == $scope.callplanList[j].un_s_code) && ($scope.callplanList[j].offer_type == "REC")){
//console.log($scope.devicesList);
for(var a = 0; a < $scope.callplanList[j].upfront_cost.length; a++){
if($scope.callplanList[j].upfront_cost[a].upfront != ""){
//console.log($scope.callplanList[j].upfront_cost[a].handsetClass);
for(var k = 0; k < $scope.devicesList.length; k++){
if($scope.callplanList[j].upfront_cost[a].handsetClass == $scope.devicesList[k].device_class.toLowerCase()){
$scope.arr.push($scope.devicesList[k]);
}
}
}
}
}
}
}
console.log($scope.arr);
});
Any help would be appreciated.

Make use of filter.
Here is a simple filter, to remove duplicates from an array
Array.filter(function(elem, index, self){ return self.indexOf(elem) == index })
In your case it will be
$scope.arr = $scope.arr.filter(function(elem, index, self){
return self.indexOf(elem) == index
});

method 1:
var list =[{name:"a",age:2}, {name:"b",age:4}, {name:"c",age:6}, {name:"a",age:2}]
var arr = list.filter((elem, index, self) => self.findIndex(
(t) => {return (t.name === elem.name && t.age === elem.age)}) === index)
it return unique array based on all the properties
method 2:
If you want to remove duplicate elements from an array use the following function. Here the args are:
myArr: contain array ob objects
prop: the property of object by which the array elements should be removed
function removeDuplicates(myArr, prop) {
return myArr.filter((obj, pos, arr) => {
return arr.map(mapObj => mapObj[prop]).indexOf(obj[prop]) === pos;
});
}
It will remove the duplicates based on the elements property and return the array with unique elemnts.

ngRepeat uses $watchCollection to detect changes in the collection. When a change happens, ngRepeat then makes the corresponding changes to the DOM:
When an item is added, a new instance of the template is added to the DOM.
When an item is removed, its template instance is removed from the DOM.
When items are reordered, their respective templates are reordered in the DOM.
To minimize creation of DOM elements, ngRepeat uses a function to "keep track" of all items in the collection and their corresponding DOM elements. For example, if an item is added to the collection, ngRepeat will know that all other items already have DOM elements, and will not re-render them.
The default tracking function (which tracks items by their identity) does not allow duplicate items in arrays. This is because when there are duplicates, it is not possible to maintain a one-to-one mapping between collection items and DOM elements.
If you do need to repeat duplicate items, you can substitute the default tracking behavior with your own using the track by expression.
so you can do like this :
<div ng-repeat="n in [42, 42, 43, 43] track by $index">
{{n}}
</div>
If you want to remove duplicates from array :
function UniqueArraybyId(collection, keyname) {
var output = [],
keys = [];
angular.forEach(collection, function(item) {
var key = item[keyname];
if(keys.indexOf(key) === -1) {
keys.push(key);
output.push(item);
}
});
return output;
};
planReq.then(function (callplanList) {
$scope.callplanList = callplanList.data.callplans;
//console.log($scope.callplanList);
for(var i = 0; i < $scope.planMapping.length; i++){
//console.log($scope.planMapping[i].PlanScode);
for(var j = 0; j < $scope.callplanList.length; j++){
if(($scope.planMapping[i].PlanScode == $scope.callplanList[j].un_s_code) && ($scope.callplanList[j].offer_type == "REC")){
//console.log($scope.devicesList);
for(var a = 0; a < $scope.callplanList[j].upfront_cost.length; a++){
if($scope.callplanList[j].upfront_cost[a].upfront != ""){
//console.log($scope.callplanList[j].upfront_cost[a].handsetClass);
for(var k = 0; k < $scope.devicesList.length; k++){
if($scope.callplanList[j].upfront_cost[a].handsetClass == $scope.devicesList[k].device_class.toLowerCase()){
$scope.arr.push($scope.devicesList[k]);
}
}
}
}
}
}
}
$scope.arr = UniqueArraybyId($scope.arr ,"sub_family"); //you have to pass the key name
console.log($scope.arr);
})
Here is the fiddle :
function UniqueArraybyId(collection, keyname) {
var output = [],
keys = [];
angular.forEach(collection, function(item) {
var key = item[keyname];
if(keys.indexOf(key) === -1) {
keys.push(key);
output.push(item);
}
});
return output;
};
function test () {
var arr =[{sub_family:'j3 (2016)'},{sub_family:'j3 (2016)'},{sub_family:'j3 (2017)'}]
arr= UniqueArraybyId(arr ,"sub_family"); //you have to pass the key name
console.log(arr);
};
test();
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

I think this is the best way to remove duplicates from an Array. Note that this requires ES6.
arr = Array.from(new Set(arr));
Example:
var arr = [0, 1, 1, 1, 1, 2, 3, 4, 3, 4, 2, 2, 4];
console.log(arr.join(", "));
arr = Array.from(new Set(arr));
console.log(arr.join(", "));

Related

Remove data from an array comparing it to an other array

I am trying to compare the items in "item" array and the copyofOpList array to retrieve the data occurrences in copyofOpList
this is my try:
var _deleteUsedElement1 = function(item) {
for (var i = 0; i < item.length-1; i++){
for (var j = 0; j< $scope.copyofOpList.length-1; j++){
if (item[i].operationCode == $scope.copyofOpList[j].code) {
$scope.copyofOpList.splice(j, 1);
} } } };
$scope.compareArrays = function() {
...Get data from web Service
_deleteUsedElement1(item);
}
the copyofOpList array has 14 elements,and the item array has 2 array
but my code deletes only one occurrence (the first),so please how can I correct my code,to retrieve any occurances in the copyofOpList array comparing to the item array
thanks for help
I'd try to avoid looping inside a loop - that's neither a very elegant nor a very efficient way to get the result you want.
Here's something more elegant and most likely more efficient:
var item = [1,2], copyofOpList = [1,2,3,4,5,6,7];
var _deleteUsedElement1 = function(item, copyofOpList) {
return copyofOpList.filter(function(listItem) {
return item.indexOf(listItem) === -1;
});
};
copyofOpList = _deleteUsedElement1(item, copyofOpList);
console.log(copyofOpList);
//prints [3,4,5,6,7]
}
And since I just noticed that you're comparing object properties, here's a version that filters on matching object properties:
var item = [{opCode:1},{opCode:2}],
copyofOpList = [{opCode:1},{opCode:2},{opCode:3},{opCode:4},{opCode:5},{opCode:6},{opCode:7}];
var _deleteUsedElement1 = function(item, copyofOpList) {
var iOpCodes = item.map(function (i) {return i.opCode;});
return copyofOpList.filter(function(listItem) {
return iOpCodes.indexOf(listItem.opCode) === -1;
});
};
copyofOpList = _deleteUsedElement1(item, copyofOpList);
console.log(copyofOpList);
//prints [{opCode:3},{opCode:4},{opCode:5},{opCode:6},{opCode:7}]
Another benefit of doing it in this manner is that you avoid modifying your arrays while you're still operating on them, a positive effect that both JonSG and Furhan S. mentioned in their answers.
Splicing will change your array. Use a temporary buffer array for new values like this:
var _deleteUsedElement1 = function(item) {
var _temp = [];
for (var i = 0; i < $scope.copyofOpList.length-1; i++){
for (var j = 0; j< item.length-1; j++){
if ($scope.copyofOpList[i].code != item[j].operationCode) {
_temp.push($scope.copyofOpList[j]);
}
}
}
$scope.copyofOpList = _temp;
};

Javascript: Write a function that takes in an array, and then returns an array with only unique numbers, only arrays removed

Write a function that takes in a list and returns a list with all of the duplicates removed (list will only have unique numbers).
Here's what I have so far:
var lista = [1,4,5,1,1,3,5,6,4,4,3];
function dupRemove (lista) {
//Sort the array in case it isn't sorted
lista.sort();
//Object to store duplicates and unique numbers
var listNumbers = {
"Duplicate Numbers": [],
"Unique Numbers": []
};
for (var i = 0; i < lista.length; i++) {
//check if it is not equal to the index of the array before it and after. if it isn't, that means its unique, push it in the uniques array.
if (lista[i] !== lista[i-1] && lista[i] !== lista[i+1]) {
listNumbers["Unique Numbers"].push(lista[i]);
} else {
listNumbers["Duplicate Numbers"].push(lista[i]);
}
}
return listNumbers;
}
Currently, my solution returns an object with keys with the values of "Duplicates": 1, 1, 1, 3, 3, 4, 4, 4, 5, 5 and "Uniques": 6.
How do I remove the duplicates from duplicates and then join these two keys into a single array?
Thank you.
that answer is seriously over -engineered- all you need to to is push all values into a new array if they are not already in it.
function=removeDups()
{
var lista = [1,4,5,1,1,3,5,6,4,4,3];
var uniqueValues=[];
var duplicateValues=[];
for(i=0;i<lista.length;i++)
{
if(uniqueValues.indexof(lista[i] == -1){uniqueValues.push(lista[i]}else{duplicateValues.push(lista[i]}
}
}
You could just use the default filter method that is on all Arrays
You don't need the sort function either. If the item is already found using the indexOf method it will not be added to the newly returned array created by the filter method
var list = [1,4,5,1,1,3,5,6,4,4,3];
function removeDup (arr) {
return arr.filter(function(item, pos) {
return arr.indexOf(item) == pos;
})
}
var sortedList = removeDup(list).sort(function(a,b){
return a - b
})
document.getElementsByTagName('div')[0].textContent = sortedList
<div></div>
Kind of a non elegant solution but it gives you the two arrays: one with the duplicate values and one with the unique ones. Since you cannot rely on .sort() you can just count things.
Function checkList will give you back those two arrays.
var list = [1,4,5,1,1,3,5,6,4,4,3];
console.log(checkList(list));
function checkList(list) {
var uniques = []; // will be [6]
var dups = []; // will be [1, 4, 5, 3]
var checked = []; // save what you have already checked so far
for(i = 0; i < list.length; i++) {
if(notChecked(list[i], checked)) {
checked.push(list[i]);
if(count(list[i], list) > 1) {
dups.push(list[i]);
} else {
uniques.push(list[i]);
}
}
}
return {dups: dups, uniques: uniques}
}
// count how many num in arr
function count(num, arr) {
var count = 0;
var i;
for(i = 0; i < arr.length; i++) {
if(arr[i] == num) count++;
if(count > 1) return count;
}
return count;
}
// check if num has not been checked
function notChecked(num, arr) {
return (arr.indexOf(num) == -1) ? true : false;
}

Modify an object to a new Array in Javascript

sorry, i m a beginner in javascript.
Can someone explain me how to modify this Object
{toto:[12,13,15],titi:[45,12,34]}
to this Array
newArray = [
{
toto:12,
titi:45
},{
toto:13,
titi:12
},{
toto:15,
titi:34}
]
Also, what the solution if the toto and titi doesn't have the same lenght
Thanks for support!
Here's how I did it. In this way, you don't need to know the names of the keys or the size of the array, but it does require a few loops.
obj = {toto:[12,13,15],titi:[45,12,34]};
newArray = [];
// Find the longest array in your data set
longest = 0;
Object.keys(obj).forEach(function(key) {
if (obj[key].length > longest) {
longest = obj[key].length;
}
});
// Loop through the existing data set to create new objects
for (i = 0; i<longest; i++) {
newObject = {};
Object.keys(obj).forEach(function(key) {
newObject[key] = obj[key][i];
});
newArray.push(newObject);
}
console.log(newArray);
plnkr.co demo in the script.js file.
If you want to ignore keys that would have undefined values for uneven loops, you can add a conditional inside the forEach loop that creates a new object:
Object.keys(obj).forEach(function(key) {
if (obj[key][i] !== undefined) {
newObject[key] = obj[key][i];
}
});
Assuming lengths of toto and titi are the same:
Obj = {toto:[12,13,15],titi:[45,12,34]};
newArray = [];
for (var k in Obj["toto"]) {
newArray.push({ toto:Obj["toto"][k],titi:Obj["titi"][k] });
}
Since the lengths of your inner arrays are equal, you should be able to simply loop through them and add a value from each array (for each iteration) into a new array :
// Your input
var input = {toto:[12,13,15],titi:[45,12,34]};
// An array to store your output
var output = [];
// Since your inner arrays are of equal size, you can loop through them
// as follows
for(var i = 0; i < input.toto.length; i++){
output.push({ toto: input.toto[i], titi: input.titi[i]});
}
You can see a working example of this here and what the output array looks like below :
A more generic approach
var object = { toto: [12, 13, 15], titi: [45, 12, 34] },
newArray = function (o) {
var keys = Object.keys(o),
l = keys.reduce(function (r, a) { return Math.max(r, o[a].length); }, 0),
i = 0,
t,
result = [];
while (i < l) {
t = {};
keys.forEach(function (k) { t[k] = o[k][i]; });
result.push(t);
i++;
}
return result;
}(object);
document.write('<pre>' + JSON.stringify(newArray, 0, 4) + '</pre>');

cut object's value to the last JavaScript

How can I cut the 6th object's value and paste it into the last object? Below is the result of this code :
JSON.parse(json).forEach(function(obj, idx, array) {
console.log(obj);
});
Updated: As you mentioned that if any object has an value must be cut
and moved to the last,
var array = JSON.parse(json),
index;
array.forEach(function(obj, idx) {
if(obj.itemId) {
index = idx;
}
});
if(typeof index !=="undefined") {
var tempObj = array.splice(index,1);
// adding it the end
array.push(tempObj);
}
It will remove the last element with itemId and move it to the end.
If I understand your question, you want to replace the last object with the object with type:"award".
Then I would do it like this:
JSON.parse(json).forEach(function(obj, idx, array) {
if (obj.type === "award") {
array[array.length - 1] = obj;
}
});
if the award is already the last, it will only be overwritten by itself.
Considering that your get an array of objects, iterate through all the objects and you will end up with the last object that has award in its type key.
for(var i = 0, _len = obj.length; i < _len; i += 1) {
if(obj[i].type === "award") {
ourObj = obj[i];
}
}
obj[obj.length-1] = ourObj;
James,
I have some few question just to get my understanding clear before providing an answer.
So, you want to remove the 6th item in array and want to replace that with the last item ?
The item you are going to remove is always going to be 6th item ?
Answer:
var item, items = JSON.parse(json), itemCount = items.length, obj, position;
for (var i = 0; i < itemCount; i++) {
item = items[i];
if (item.itemId) {
position = i;
}
}
if (position) {
items.push(items.splice(position, 1));
}
The code above will make sure that if the item appears at last position will also be handled. If you want to clone the object instead of referencing the old one then you need to loop through the object and update the new one like below
if (position) {
obj = items.splice(position, 1);
item = {};
for (var property in obj) {
if (obj.hasOwnProperty(property)) {
item[property] = obj[property];
}
}
items.push(item);
}
Just filter it:
var res = JSON.parse(json).filter(function(value) {
return value.itemId == 6;
});
Use Array.prototype.splice() to remove the element you want. Push it to the end.
var arr = [];
var tgtIdx = -1;
var lastID = -1;
JSON.parse(json).forEach(function (obj, idx, array) {
if(obj.itemId !== null && obj.itemId > lastID) {
tgtIdx = idx;
lastID = obj.itemId;
}
arr.push(obj);
})
if(tgtIdx >= 0 && tgtIdx < arr.length - 1) {
arr.push(arr.splice(tgtIdx, 1)[0]);
}

How to get unique values in an array [duplicate]

This question already has answers here:
Get all unique values in a JavaScript array (remove duplicates)
(91 answers)
Closed 1 year ago.
How can I get a list of unique values in an array? Do I always have to use a second array or is there something similar to java's hashmap in JavaScript?
I am going to be using JavaScript and jQuery only. No additional libraries can be used.
Here's a much cleaner solution for ES6 that I see isn't included here. It uses the Set and the spread operator: ...
var a = [1, 1, 2];
[... new Set(a)]
Which returns [1, 2]
Or for those looking for a one-liner (simple and functional) compatible with current browsers:
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);
Update 2021
I would recommend checking out Charles Clayton's answer, as of recent changes to JS there are even more concise ways to do this.
Update 18-04-2017
It appears as though 'Array.prototype.includes' now has widespread support in the latest versions of the mainline browsers (compatibility)
Update 29-07-2015:
There are plans in the works for browsers to support a standardized 'Array.prototype.includes' method, which although does not directly answer this question; is often related.
Usage:
["1", "1", "2", "3", "3", "1"].includes("2"); // true
Pollyfill (browser support, source from mozilla):
// https://tc39.github.io/ecma262/#sec-array.prototype.includes
if (!Array.prototype.includes) {
Object.defineProperty(Array.prototype, 'includes', {
value: function(searchElement, fromIndex) {
// 1. Let O be ? ToObject(this value).
if (this == null) {
throw new TypeError('"this" is null or not defined');
}
var o = Object(this);
// 2. Let len be ? ToLength(? Get(O, "length")).
var len = o.length >>> 0;
// 3. If len is 0, return false.
if (len === 0) {
return false;
}
// 4. Let n be ? ToInteger(fromIndex).
// (If fromIndex is undefined, this step produces the value 0.)
var n = fromIndex | 0;
// 5. If n ≥ 0, then
// a. Let k be n.
// 6. Else n < 0,
// a. Let k be len + n.
// b. If k < 0, let k be 0.
var k = Math.max(n >= 0 ? n : len - Math.abs(n), 0);
// 7. Repeat, while k < len
while (k < len) {
// a. Let elementK be the result of ? Get(O, ! ToString(k)).
// b. If SameValueZero(searchElement, elementK) is true, return true.
// c. Increase k by 1.
// NOTE: === provides the correct "SameValueZero" comparison needed here.
if (o[k] === searchElement) {
return true;
}
k++;
}
// 8. Return false
return false;
}
});
}
Since I went on about it in the comments for #Rocket's answer, I may as well provide an example that uses no libraries. This requires two new prototype functions, contains and unique
Array.prototype.contains = function(v) {
for (var i = 0; i < this.length; i++) {
if (this[i] === v) return true;
}
return false;
};
Array.prototype.unique = function() {
var arr = [];
for (var i = 0; i < this.length; i++) {
if (!arr.contains(this[i])) {
arr.push(this[i]);
}
}
return arr;
}
var duplicates = [1, 3, 4, 2, 1, 2, 3, 8];
var uniques = duplicates.unique(); // result = [1,3,4,2,8]
console.log(uniques);
For more reliability, you can replace contains with MDN's indexOf shim and check if each element's indexOf is equal to -1: documentation
One Liner, Pure JavaScript
With ES6 syntax
list = list.filter((x, i, a) => a.indexOf(x) === i)
x --> item in array
i --> index of item
a --> array reference, (in this case "list")
With ES5 syntax
list = list.filter(function (x, i, a) {
return a.indexOf(x) === i;
});
Browser Compatibility: IE9+
Using EcmaScript 2016 you can simply do it like this.
var arr = ["a", "a", "b"];
var uniqueArray = Array.from(new Set(arr)); // Unique Array ['a', 'b'];
Sets are always unique, and using Array.from() you can convert a Set to an array. For reference have a look at the documentations.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set
These days, you can use ES6's Set data type to convert your array to a unique Set. Then, if you need to use array methods, you can turn it back into an Array:
var arr = ["a", "a", "b"];
var uniqueSet = new Set(arr); // {"a", "b"}
var uniqueArr = Array.from(uniqueSet); // ["a", "b"]
//Then continue to use array methods:
uniqueArr.join(", "); // "a, b"
If you want to leave the original array intact,
you need a second array to contain the uniqe elements of the first-
Most browsers have Array.prototype.filter:
const unique = array1.filter((item, index, array) => array.indexOf(item) === index);
//if you need a 'shim':
Array.prototype.filter= Array.prototype.filter || function(fun, scope){
var T= this, A= [], i= 0, itm, L= T.length;
if(typeof fun== 'function'){
while(i<L){
if(i in T){
itm= T[i];
if(fun.call(scope, itm, i, T)) A[A.length]= itm;
}
++i;
}
}
return A;
}
Array.prototype.indexOf= Array.prototype.indexOf || function(what, i){
if(!i || typeof i!= 'number') i= 0;
var L= this.length;
while(i<L){
if(this[i]=== what) return i;
++i;
}
return -1;
}
Fast, compact, no nested loops, works with any object not just strings and numbers, takes a predicate, and only 5 lines of code!!
function findUnique(arr, predicate) {
var found = {};
arr.forEach(d => {
found[predicate(d)] = d;
});
return Object.keys(found).map(key => found[key]);
}
Example: To find unique items by type:
var things = [
{ name: 'charm', type: 'quark'},
{ name: 'strange', type: 'quark'},
{ name: 'proton', type: 'boson'},
];
var result = findUnique(things, d => d.type);
// [
// { name: 'charm', type: 'quark'},
// { name: 'proton', type: 'boson'}
// ]
If you want it to find the first unique item instead of the last add a found.hasOwnPropery() check in there.
Not native in Javascript, but plenty of libraries have this method.
Underscore.js's _.uniq(array) (link) works quite well (source).
If you don't need to worry so much about older browsers, this is exactly what Sets are designed for.
The Set object lets you store unique values of any type, whether
primitive values or object references.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set
const set1 = new Set([1, 2, 3, 4, 5, 1]);
// returns Set(5) {1, 2, 3, 4, 5}
Using jQuery, here's an Array unique function I made:
Array.prototype.unique = function () {
var arr = this;
return $.grep(arr, function (v, i) {
return $.inArray(v, arr) === i;
});
}
console.log([1,2,3,1,2,3].unique()); // [1,2,3]
Short and sweet solution using second array;
var axes2=[1,4,5,2,3,1,2,3,4,5,1,3,4];
var distinct_axes2=[];
for(var i=0;i<axes2.length;i++)
{
var str=axes2[i];
if(distinct_axes2.indexOf(str)==-1)
{
distinct_axes2.push(str);
}
}
console.log("distinct_axes2 : "+distinct_axes2); // distinct_axes2 : 1,4,5,2,3
Majority of the solutions above have a high run time complexity.
Here is the solution that uses reduce and can do the job in O(n) time.
Array.prototype.unique = Array.prototype.unique || function() {
var arr = [];
this.reduce(function (hash, num) {
if(typeof hash[num] === 'undefined') {
hash[num] = 1;
arr.push(num);
}
return hash;
}, {});
return arr;
}
var myArr = [3,1,2,3,3,3];
console.log(myArr.unique()); //[3,1,2];
Note:
This solution is not dependent on reduce. The idea is to create an object map and push unique ones into the array.
You only need vanilla JS to find uniques with Array.some and Array.reduce. With ES2015 syntax it's only 62 characters.
a.reduce((c, v) => b.some(w => w === v) ? c : c.concat(v)), b)
Array.some and Array.reduce are supported in IE9+ and other browsers. Just change the fat arrow functions for regular functions to support in browsers that don't support ES2015 syntax.
var a = [1,2,3];
var b = [4,5,6];
// .reduce can return a subset or superset
var uniques = a.reduce(function(c, v){
// .some stops on the first time the function returns true
return (b.some(function(w){ return w === v; }) ?
// if there's a match, return the array "c"
c :
// if there's no match, then add to the end and return the entire array
c.concat(v)}),
// the second param in .reduce is the starting variable. This is will be "c" the first time it runs.
b);
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/some
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
Another thought of this question. Here is what I did to achieve this with fewer code.
var distinctMap = {};
var testArray = ['John', 'John', 'Jason', 'Jason'];
for (var i = 0; i < testArray.length; i++) {
var value = testArray[i];
distinctMap[value] = '';
};
var unique_values = Object.keys(distinctMap);
console.log(unique_values);
Array.prototype.unique = function () {
var dictionary = {};
var uniqueValues = [];
for (var i = 0; i < this.length; i++) {
if (dictionary[this[i]] == undefined){
dictionary[this[i]] = i;
uniqueValues.push(this[i]);
}
}
return uniqueValues;
}
I have tried this problem in pure JS.
I have followed following steps 1. Sort the given array, 2. loop through the sorted array, 3. Verify previous value and next value with current value
// JS
var inpArr = [1, 5, 5, 4, 3, 3, 2, 2, 2,2, 100, 100, -1];
//sort the given array
inpArr.sort(function(a, b){
return a-b;
});
var finalArr = [];
//loop through the inpArr
for(var i=0; i<inpArr.length; i++){
//check previous and next value
if(inpArr[i-1]!=inpArr[i] && inpArr[i] != inpArr[i+1]){
finalArr.push(inpArr[i]);
}
}
console.log(finalArr);
Demo
You can enter array with duplicates and below method will return array with unique elements.
function getUniqueArray(array){
var uniqueArray = [];
if (array.length > 0) {
uniqueArray[0] = array[0];
}
for(var i = 0; i < array.length; i++){
var isExist = false;
for(var j = 0; j < uniqueArray.length; j++){
if(array[i] == uniqueArray[j]){
isExist = true;
break;
}
else{
isExist = false;
}
}
if(isExist == false){
uniqueArray[uniqueArray.length] = array[i];
}
}
return uniqueArray;
}
Here is an approach with customizable equals function which can be used for primitives as well as for custom objects:
Array.prototype.pushUnique = function(element, equalsPredicate = (l, r) => l == r) {
let res = !this.find(item => equalsPredicate(item, element))
if(res){
this.push(element)
}
return res
}
usage:
//with custom equals for objects
myArrayWithObjects.pushUnique(myObject, (left, right) => left.id == right.id)
//with default equals for primitives
myArrayWithPrimitives.pushUnique(somePrimitive)
I was just thinking if we can use linear search to eliminate the duplicates:
JavaScript:
function getUniqueRadios() {
var x=document.getElementById("QnA");
var ansArray = new Array();
var prev;
for (var i=0;i<x.length;i++)
{
// Check for unique radio button group
if (x.elements[i].type == "radio")
{
// For the first element prev will be null, hence push it into array and set the prev var.
if (prev == null)
{
prev = x.elements[i].name;
ansArray.push(x.elements[i].name);
} else {
// We will only push the next radio element if its not identical to previous.
if (prev != x.elements[i].name)
{
prev = x.elements[i].name;
ansArray.push(x.elements[i].name);
}
}
}
}
alert(ansArray);
}
HTML:
<body>
<form name="QnA" action="" method='post' ">
<input type="radio" name="g1" value="ANSTYPE1"> good </input>
<input type="radio" name="g1" value="ANSTYPE2"> avg </input>
<input type="radio" name="g2" value="ANSTYPE3"> Type1 </input>
<input type="radio" name="g2" value="ANSTYPE2"> Type2 </input>
<input type="submit" value='SUBMIT' onClick="javascript:getUniqueRadios()"></input>
</form>
</body>

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