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Best way to to use async/promise/callbacks in for loop [duplicate]

This question already has answers here:
How do I convert an existing callback API to promises?
(24 answers)
Closed 2 years ago.
I'm building a trading bot that needs to get stock names from separate files. But even I have used async function and await in my code, that doesn't work.
My index file init method.
const init = async () => {
const symbols = await getDownTrendingStock();
console.log("All stocks that are down: " + symbols);
const doOrder = async () => {
//do stuff
}
doOrder();
}
my getDownTrendeingStock file
const downStocks = []
function getDownTrendingStock () {
for(i = 0; i < data.USDTPairs.length; i++){
const USDTPair = data.USDTPairs[i] + "USDT";
binance.prevDay(USDTPair, (error, prevDay, symbol) => {
if(prevDay.priceChangePercent < -2){
downStocks.push(symbol)
}
});
}
return downStocks;
}
I have tried to also use async in for loop because the getDownTrendinStock function returns an empty array before for loop is finished. I didn't find the right way to do that because I was confused with all async, promise and callback stuff. What is the right statement to use in this situation?
Output:
All stocks that are down:
Wanted output:
All stocks that are down: [BTCUSDT, TRXUSDT, ATOMUSDT...]

I think the main issue in the code you posted is that you are mixing callbacks and promises.
This is what's happening in your getDownTrendingStock function:
You start iterating over the data.USDTPairs array, picking the first element
You call binance.prevDay. This does nothing yet, because its an asynchronous function that takes a bit of time. Notably, no data is added to downStocks yet.
You continue doing 1-2, still, no data is added
You return downStocks, which is still empty.
Your function is complete, you print the empty array
Now, at some point, the nodejs event loop continues and starts working on those asynchronous tasks you created earlier by calling binance.prevDay. Internally, it probably calls an API, which takes time; once that call is completed, it calls the function you provided, which pushes data to the downStocks array.
In summary, you didn't wait for the async code to complete. You can achieve this in multiple ways.
One is to wrap this in a promise and then await that promise:
const result= await new Promise((resolve, reject) => {
binance.prevDay(USDTPair, (error, prevDay, symbol) => {
if (error) {
reject(error);
} else {
resolve({prevDay, symbol});
}
});
});
if(result.prevDay.priceChangePercent < -2){
downStocks.push(result.symbol)
}
Note that you can probably also use promisify for this. Also, this means that you will wait for one request to finish before starting the next, which may slow down your code considerably, depending on how many calls you need; you may want to look into Promise.all as well.

Generally speaking, I use two technics:
const asyncFunc = () => {smthAsync};
const arrayToProcess = [];
// 1
const result = await arrayToProcess.reduce((acc, value) => acc.then(() => asyncFunc(value)), Promise.resolve(someInitialValue));
// 2
// here will be eslint errors
for(let i = 0 i < arrayToProcess.length; i+=1) {
const processResult = await asyncFunc(value);
// do with processResult what you want
};

Javascript: Making sure one async function doesn't run until the other one is complete; working with promises

I'm working with fetching information from a github repository. I want to get the list of pull requests within that repo, get the list of commits associated with each pull request, then for each commit I want to get information such as the author of the commit, the number of files associated with each commit and the number of additions and deletions made to each file. I'm using axios and the github API to accomplish this. I know how to work with the API, but the promises and async functions are keeping me from accomplishing my task. I have the following code:
const axios = require('axios');
var mapOfInformationObjects = new Map();
var listOfCommits = [];
var listOfSHAs = [];
var gitApiPrefix = link I'll use to start fetching data;
var listOfPullRequestDataObjects = [];
var listOfPullRequestNumbers = [];
var mapOfPullNumberToCommits = new Map();
function getAllPullRequests(gitPullRequestApiLink) {
return new Promise((resolve, reject) => {
axios.get(gitPullRequestApiLink).then((response) =>{
listOfPullRequestDataObjects = response['data'];
var k;
for (k = 0; k < listOfPullRequestDataObjects.length; k++){
listOfPullRequestNumbers.push(listOfPullRequestDataObjects[k]['number']);
}
resolve(listOfPullRequestNumbers);
}).catch((error) => {
reject(error);
})
})
}
function getCommitsForEachPullRequestNumber(listOfPRNumbers) {
var j;
for (j = 0; j < listOfPRNumbers.length; j++) {
currPromise = new Promise((resolve, reject) => {
currentGitApiLink = gitApiPrefix + listOfPRNumbers[j] + "/commits";
axios.get(currentGitApiLink).then((response) => {
mapOfPullNumberToCommits.set(listOfPRNumbers[j], response['data']);
resolve("Done with Pull Request Number: " + listOfPRNumbers[j]);
}).catch((error) => {
reject(error);
})
})
}
}
function getListOfCommits(gitCommitApiLink){
return new Promise((resolve, reject) => {
axios.get(gitCommitApiLink).then((response) => {
resolve(response);
}).catch((error) => {
reject(error);
})
})
}
So far, I made some functions that I would like to call sequentially.
First I'd like to call getAllPullRequestNumbers(someLink)
Then I'd like to call getCommitsForEachPullRequestNumber(listofprnumbers)
Then getListOfCommits(anotherLink)
So it would look something like
getAllPullRequestNumbers(someLink)
getCommitsForEachPullRequestNumber(listofprnumbers)
getListOfCommits(anotherlink)
But two problems arise:
1) I'm not sure if this is how you would call the functions so that the first function in the sequence completes before the other.
2) Because I'm not familiar with Javascript, I'm not sure, especially with the getCommitsForEachPullRequestNumber function since you run a loop and call axios.get() on each iteration of the loop, if this is how you work with promises within the functions.
Would this be how you would go about accomplishing these two tasks? Any help is much appreciated. Thanks!

When you a number of asynchronous operations (represented by promises) that you can run all together and you want to know when they are all done, you use Promise.all(). You collect an array of promises and pass it to Promise.all() and it will tell you when they have all completed or when one of them triggers an error. If all completed, Promise.all() will return a promise that resolves to an array of results (one for each asynchronous operation).
When you're iterating an array to do your set of asynchronous operations, it then works best to use .map() because that helps you create a parallel array of promises that you can feed to Promise.all(). Here's how you do that in getCommitsForEachPullRequestNumber():
function getCommitsForEachPullRequestNumber(listOfPRNumbers) {
let mapOfPullNumberToCommits = new Map();
return Promise.all(listOfPRNumbers.map(item => {
let currentGitApiLink = gitApiPrefix + item + "/commits";
return axios.get(currentGitApiLink).then(response => {
// put data into the map
mapOfPullNumberToCommits.set(item, response.data);
});
})).then(() => {
// make resolved value be the map we created, now that everything is done
return mapOfPullNumberToCommits;
});
}
// usage:
getCommitsForEachPullRequestNumber(list).then(results => {
console.log(results);
}).catch(err => {
console.log(err);
});
Then, in getListOfCommits(), since axios already returns a promise, there is no reason to wrap it in a manually created promise. That is, in fact, consider a promise anti-pattern. Instead, just return the promise that axios already returns. In fact, there's probably not even a reason to have this as a function since one can just use axios.get() directly to achieve the same result:
function getListOfCommits(gitCommitApiLink){
return axios.get(gitCommitApiLink);
}
Then, in getAllPullRequests() it appears you are just doing one axios.get() call and then processing the results. That can be done like this:
function getAllPullRequests(gitPullRequestApiLink) {
return axios.get(gitPullRequestApiLink).then(response => {
let listOfPullRequestDataObjects = response.data;
return listOfPullRequestDataObjects.map(item => {
return item.number;
});
});
}
Now, if you're trying to execute these three operations sequentially in this order:
getAllPullRequests(someLink)
getCommitsForEachPullRequestNumber(listofprnumbers)
getListOfCommits(anotherlink)
You can chain the promises from those three operations together to sequence them:
getAllPullRequests(someLink)
.then(getCommitsForEachPullRequestNumber)
.then(mapOfPullNumberToCommits => {
// not entirely sure what you want to do here, perhaps
// call getListOfCommits on each item in the map?
}).catch(err => {
console.log(err);
});
Or, if you put this code in an async function, then you can use async/awit:
async function getAllCommits(someLink) {
let pullRequests = await getAllPullRequests(someLink);
let mapOfPullNumberToCommits = await getCommitsForEachPullRequestNumber(pullRequests);
// then use getlistOfCommits() somehow to process mapOfPullNumberToCommits
return finalResults;
}
getAllCommits.then(finalResults => {
console.log(finalResults);
}).catch(err => {
console.log(err);
});

not as clean as jfriend00 solution,
but I played with your code and it finally worked
https://repl.it/#gui3/githubApiPromises
you get the list of commits in the variable listOfCommits
I don't understand the purpose of your last function, so I dropped it

How do I know which promise will resolve first?

I have a snippet that I'm playing around with where I've purposely placed Promise.resolve(c) before Promise.resolve(a) but I am noticing that the true value from bottom Promise.all(...) is being logged first.
const https = require('https');
function getData(substr) {
let url = ``;
return new Promise((resolve, reject) => {
try {
https.get(url, res => {
let s = '';
res.on('data', (d) => {
s += d
});
res.on('end', () => {
let data = JSON.parse(s);
resolve(data);
})
})
} catch (e) {
reject(e);
}
})
}
let a = getData('spiderman');
let b;
let c = getData('superman');
Promise.resolve(c)
.then(value => console.log(value));
Promise.resolve(a)
.then(value => b = value);
Promise.all([a]).then(values => console.log(values[0] === b));
Is there any explanation as to why this is the case? I would think that since Promise.resolve(c) comes first, that the Promise c would resolve first and be logged. Or is there no way to actually rely on the order of the logs aside from using callbacks? What are the best practices to avoid such issues?

These are asynchronous calls that on complete resolve using the supplied function passed into then.
There is no way to force one of these to finish before and if you need that you should be running these synchronous.
When you call .then() this only gets called when the function finished not when the .resolve gets called.

Promise resolution order is not guaranteed. That's kinda the point of asynchronous code.
If you rely on order of execution, you should be using synchronous code.

Use Promise.all() with both requests if you want them both completed before you do your next step.
let a = getData('spiderman');
let c = getData('superman');
Promise.all([a, c]).then(([spidyResults, superResults]) => {
// both have sompleted
// do stuff with each set of results
}).catch(err => console.log('Ooops, one of them failed') );

Well, as said before, the order of the promise completion is not guaranteed, because it's an async operation.
If you really need the execution to follow a certain order you need to put the the next thing to be executed inside then or use async and await which is much cleaner.

Call hierarchy of async functions inside a loop?

There's a async call I'm making that queries a database on a service, but this service has a limit of how many it can output at once, so I need to check if it hit its limit through the result it sends and repeat the query until it doesn't.
Synchronous mockup :
var query_results = [];
var limit_hit = true; #While this is true means that the query hit the record limit
var start_from = 0; #Pagination parameter
while (limit_hit) {
Server.Query(params={start_from : start_from}, callback=function(result){
limit_hit = result.limit_hit;
start_from = result.results.length;
query_result.push(result.results);
}
}
Obviously the above does not work, I've seen some other questions here about the issue, but they don't mention what to do when you need each iteration to wait for the last one to finish and you don't know before hand the number of iterations.
How can I turn the above asynchronous? I'm open to answers using promise/deferred-like logic, but preferably something clean.
I can probably think of a monstruous and horrible way of doing this using waits/timeouts, but there has to be a clean, clever and modern way to solve it.
Another way is to make a "pre-query" to know the number of features before hand so you know the number of loops, I'm not sure if this is the correct way.
Here we use Dojo sometimes, but the examples I found does not explain what to do when you have an unknown amount of loops https://www.sitepen.com/blog/2015/06/10/dojo-faq-how-can-i-sequence-asynchronous-operations/

although many answers already, still I believe async/await is the cleanest way.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
and you might need babel
https://babeljs.io/
JS async logic syntax changed from callback to promise then to async/await, they all do the same thing, when callback nests a lot we need something like a chain, then promise come, when promise goes in loop, we need something make the chain more plain more simple, then async/await come. But not all browsers support the new syntax, so babel come to compile new syntax to old syntax, then you can always code in new syntax.
getData().then((data) => {
//do something with final data
})
async function getData() {
var query_results = [];
var limit_hit = true;
var start_from = 0;
//when you use await, handle error with try/catch
try {
while (limit_hit) {
const result = await loadPage(start_from)
limit_hit = result.limit_hit;
start_from = result.results.length;
query_result.push(result.results);
}
} catch (e) {
//when loadPage rejects
console.log(e)
return null
}
return query_result
}
async function loadPage(start_from) {
//when you use promise, handle error with reject
return new Promise((resolve, reject) => Server.Query({
start_from
}, (result, err) => {
//error reject
if (err) {
reject(err)
return
}
resolve(result)
}))
}

If you want to use a loop then I think there is no (clean) way to do it without Promises.
A different approach would be the following:
var query_results = [];
var start_from = 0;
funciton myCallback(result) {
if(!result) {
//first call
Server.Query({ start_from: start_from}, myCallback);
} else {
//repeated call
start_from = result.results.length
query_result.push(result.results);
if(!result.limit_hit) {
//limit has not been hit yet
//repeat the query with new start value
Server.Query({ start_from: start_from}, myCallback);
} else {
//call some callback function here
}
}
}
myCallback(null);
You could call this recursive, but since the Query is asynchronous you shouldn't have problems with call stack limits etc.
Using promises in an ES6 environment you could make use of async/await. Im not sure if this is possible with dojo.

You don't understand callbacks until you have written a rate limiter or queue ;) The trick is to use a counter: Increment the counter before the async request, and decrement it when you get the response, then you will know how many requests are "in flight".
If the server is choked you want to put the item back in the queue.
There are many things you need to take into account:
What will happen to the queue if the process is killed ?
How long to wait before sending another request ?
Make sure the callback is not called many times !
How many times should you retry ?
How long to wait before giving up ?
Make sure there are no loose ends ! (callback is never called)
When all edge cases are taken into account you will have a rather long and not so elegant solution. But you can abstract it into one function! (that returns a Promise or whatever you fancy).
If you have a user interface you also want to show a loading bar and some statistics!

You must await for the server response every time. Here a encapsulated method
var query = (function(){
var results = [];
var count = 0;
return function check(fun){
Server.Query({ start_from: count}, function(d){
count = d.results.length;
results.push(d.results);
if (d.limit_hit && fun) fun(results);
else check(fun);
});
};
})();
// Call here
var my_query = query(function(d){
// --> retrive all data when limit_hit is true)
});

You can use a generator function Generators to achieve this
For POC:
some basics
- You define a generator with an asterick *
- it exposes a next function which returns the next value
- generators can pause with yield statement internally and can resume externally by calling the next()
- While (true) will ensure that the generator is not done until limit has reached
function *limitQueries() {
let limit_hit = false;
let start_from = 0;
const query_result = [];
while (true) {
if (limit_hit) {break;}
yield Server.Query(params={start_from : start_from},
callback=function* (result) {
limit_hit = result.limit_hit;
start_from = result.results.length;
yield query_result.push(result.results);
}
}
}
So apparently, the generator function maintains its own state. Generator function exposes two properties { value, done } and you can call it like this
const gen = limitQueries();
let results = [];
let next = gen.next();
while(next.done) {
next = gen.next();
}
results = next.value;
You might have to touch your Server.Query method to handle generator callback. Hope this helps! Cheers!

Is Node.js native Promise.all processing in parallel or sequentially?

I would like to clarify this point, as the documentation is not too clear about it;
Q1: Is Promise.all(iterable) processing all promises sequentially or in parallel? Or, more specifically, is it the equivalent of running chained promises like
p1.then(p2).then(p3).then(p4).then(p5)....
or is it some other kind of algorithm where all p1, p2, p3, p4, p5, etc. are being called at the same time (in parallel) and results are returned as soon as all resolve (or one rejects)?
Q2: If Promise.all runs in parallel, is there a convenient way to run an iterable sequencially?
Note: I don't want to use Q, or Bluebird, but all native ES6 specs.

Is Promise.all(iterable) executing all promises?
No, promises cannot "be executed". They start their task when they are being created - they represent the results only - and you are executing everything in parallel even before passing them to Promise.all.
Promise.all does only await multiple promises. It doesn't care in what order they resolve, or whether the computations are running in parallel.
is there a convenient way to run an iterable sequencially?
If you already have your promises, you can't do much but Promise.all([p1, p2, p3, …]) (which does not have a notion of sequence). But if you do have an iterable of asynchronous functions, you can indeed run them sequentially. Basically you need to get from
[fn1, fn2, fn3, …]
to
fn1().then(fn2).then(fn3).then(…)
and the solution to do that is using Array::reduce:
iterable.reduce((p, fn) => p.then(fn), Promise.resolve())

In parallel
await Promise.all(items.map(async (item) => {
await fetchItem(item)
}))
Advantages: Faster. All iterations will be started even if one fails later on. However, it will "fail fast". Use Promise.allSettled, to complete all iterations in parallel even if some throw. Technically, these are concurrent invocations not in parallel.
In sequence
for (const item of items) {
await fetchItem(item)
}
Advantages: Variables in the loop can be shared by each iteration. Behaves like normal imperative synchronous code.

NodeJS does not run promises in parallel, it runs them concurrently since it’s a single-threaded event loop architecture. There is a possibility to run things in parallel by creating a new child process to take advantage of the multiple core CPU.
Parallel Vs Concurent
In fact, what Promise.all does is, stacking the promises function in the appropriate queue (see event loop architecture) running them concurrently (call P1, P2,...) then waiting for each result, then resolving the Promise.all with all the promises results.
Promise.all will fail at the first promise which fails unless you have to manage the rejection yourself.
There is a major difference between parallel and concurrent, the first one will run a different computation in a separate process at exactly the same time and they will progress at their rhythm, while the other one will execute the different computation one after another without waiting for the previous computation to finish and progress at the same time without depending on each other.
Finally, to answer your question, Promise.all will execute neither in parallel nor sequentially but concurrently.

Bergi's answer got me on the right track using Array.reduce.
However, to actually get the functions returning my promises to execute one after another I had to add some more nesting.
My real use case is an array of files that I need to transfer in order one after another due to limits downstream...
Here is what I ended up with:
getAllFiles().then( (files) => {
return files.reduce((p, theFile) => {
return p.then(() => {
return transferFile(theFile); //function returns a promise
});
}, Promise.resolve()).then(()=>{
console.log("All files transferred");
});
}).catch((error)=>{
console.log(error);
});
As previous answers suggest, using:
getAllFiles().then( (files) => {
return files.reduce((p, theFile) => {
return p.then(transferFile(theFile));
}, Promise.resolve()).then(()=>{
console.log("All files transferred");
});
}).catch((error)=>{
console.log(error);
});
didn't wait for the transfer to complete before starting another and also the "All files transferred" text came before even the first file transfer was started.
Not sure what I did wrong, but wanted to share what worked for me.
Edit: Since I wrote this post I now understand why the first version didn't work. then() expects a function returning a promise. So, you should pass in the function name without parentheses! Now, my function wants an argument so then I need to wrap in in a anonymous function taking no argument!

You can also process an iterable sequentially with an async function using a recursive function. For example, given an array a to process with asynchronous function someAsyncFunction():
var a = [1, 2, 3, 4, 5, 6]
function someAsyncFunction(n) {
return new Promise((resolve, reject) => {
setTimeout(() => {
console.log("someAsyncFunction: ", n)
resolve(n)
}, Math.random() * 1500)
})
}
//You can run each array sequentially with:
function sequential(arr, index = 0) {
if (index >= arr.length) return Promise.resolve()
return someAsyncFunction(arr[index])
.then(r => {
console.log("got value: ", r)
return sequential(arr, index + 1)
})
}
sequential(a).then(() => console.log("done"))

Just to elaborate on #Bergi's answer (which is very succinct, but tricky to understand ;)
This code will run each item in the array and add the next 'then chain' to the end:
function eachorder(prev,order) {
return prev.then(function() {
return get_order(order)
.then(check_order)
.then(update_order);
});
}
orderArray.reduce(eachorder,Promise.resolve());

Using async await an array of promises can easily be executed sequentially:
let a = [promise1, promise2, promise3];
async function func() {
for(let i=0; i<a.length; i++){
await a[i]();
}
}
func();
Note: In above implementation, if a promise is rejected, the rest wouldn't be executed.If you want all your promises to be executed, then wrap your await a[i](); inside try catch

parallel
see this example
const resolveAfterTimeout = async i => {
return new Promise(resolve => {
console.log("CALLED");
setTimeout(() => {
resolve("RESOLVED", i);
}, 5000);
});
};
const call = async () => {
const res = await Promise.all([
resolveAfterTimeout(1),
resolveAfterTimeout(2),
resolveAfterTimeout(3),
resolveAfterTimeout(4),
resolveAfterTimeout(5),
resolveAfterTimeout(6)
]);
console.log({ res });
};
call();
by running the code it'll console "CALLED" for all six promises and when they are resolved it will console every 6 responses after timeout at the same time

I stumbled across this page while trying to solve a problem in NodeJS: reassembly of file chunks. Basically:
I have an array of filenames.
I need to append all those files, in the correct order, to create one large file.
I must do this asynchronously.
Node's 'fs' module does provide appendFileSync but I didn't want to block the server during this operation. I wanted to use the fs.promises module and find a way to chain this stuff together. The examples on this page didn't quite work for me because I actually needed two operations: fsPromises.read() to read in the file chunk, and fsPromises.appendFile() to concat to the destination file. Maybe if I was better with JavaScript I could have made the previous answers work for me. ;-)
I stumbled across this and I was able to hack together a working solution:
/**
* sequentially append a list of files into a specified destination file
*/
exports.append_files = function (destinationFile, arrayOfFilenames) {
return arrayOfFilenames.reduce((previousPromise, currentFile) => {
return previousPromise.then(() => {
return fsPromises.readFile(currentFile).then(fileContents => {
return fsPromises.appendFile(destinationFile, fileContents);
});
});
}, Promise.resolve());
};
And here's a jasmine unit test for it:
const fsPromises = require('fs').promises;
const fsUtils = require( ... );
const TEMPDIR = 'temp';
describe("test append_files", function() {
it('append_files should work', async function(done) {
try {
// setup: create some files
await fsPromises.mkdir(TEMPDIR);
await fsPromises.writeFile(path.join(TEMPDIR, '1'), 'one');
await fsPromises.writeFile(path.join(TEMPDIR, '2'), 'two');
await fsPromises.writeFile(path.join(TEMPDIR, '3'), 'three');
await fsPromises.writeFile(path.join(TEMPDIR, '4'), 'four');
await fsPromises.writeFile(path.join(TEMPDIR, '5'), 'five');
const filenameArray = [];
for (var i=1; i < 6; i++) {
filenameArray.push(path.join(TEMPDIR, i.toString()));
}
const DESTFILE = path.join(TEMPDIR, 'final');
await fsUtils.append_files(DESTFILE, filenameArray);
// confirm "final" file exists
const fsStat = await fsPromises.stat(DESTFILE);
expect(fsStat.isFile()).toBeTruthy();
// confirm content of the "final" file
const expectedContent = new Buffer('onetwothreefourfive', 'utf8');
var fileContents = await fsPromises.readFile(DESTFILE);
expect(fileContents).toEqual(expectedContent);
done();
}
catch (err) {
fail(err);
}
finally {
}
});
});

You can do it by for loop.
async function return promise:
async function createClient(client) {
return await Client.create(client);
}
let clients = [client1, client2, client3];
if you write following code then client are created parallelly:
const createdClientsArray = yield Promise.all(clients.map((client) =>
createClient(client);
));
But if you want to create client sequentially then you should use for loop:
const createdClientsArray = [];
for(let i = 0; i < clients.length; i++) {
const createdClient = yield createClient(clients[i]);
createdClientsArray.push(createdClient);
}

Bergi's answer helped me to make the call synchronous. I have added an example below where we call each function after the previous function is called:
function func1 (param1) {
console.log("function1 : " + param1);
}
function func2 () {
console.log("function2");
}
function func3 (param2, param3) {
console.log("function3 : " + param2 + ", " + param3);
}
function func4 (param4) {
console.log("function4 : " + param4);
}
param4 = "Kate";
//adding 3 functions to array
a=[
()=>func1("Hi"),
()=>func2(),
()=>func3("Lindsay",param4)
];
//adding 4th function
a.push(()=>func4("dad"));
//below does func1().then(func2).then(func3).then(func4)
a.reduce((p, fn) => p.then(fn), Promise.resolve());

I've been using for of in order to solve sequential promises. I'm not sure if it helps here but this is what I've been doing.
async function run() {
for (let val of arr) {
const res = await someQuery(val)
console.log(val)
}
}
run().then().catch()

Yes, you can chain an array of promise returning functions as follows
(this passes the result of each function to the next). You could of course edit it to pass the same argument (or no arguments) to each function.
function tester1(a) {
return new Promise(function(done) {
setTimeout(function() {
done(a + 1);
}, 1000);
})
}
function tester2(a) {
return new Promise(function(done) {
setTimeout(function() {
done(a * 5);
}, 1000);
})
}
function promise_chain(args, list, results) {
return new Promise(function(done, errs) {
var fn = list.shift();
if (results === undefined) results = [];
if (typeof fn === 'function') {
fn(args).then(function(result) {
results.push(result);
console.log(result);
promise_chain(result, list, results).then(done);
}, errs);
} else {
done(results);
}
});
}
promise_chain(0, [tester1, tester2, tester1, tester2, tester2]).then(console.log.bind(console), console.error.bind(console));

see this sample
Promise.all working parallel
const { range, random, forEach, delay} = require("lodash");
const run = id => {
console.log(`Start Task ${id}`);
let prom = new Promise((resolve, reject) => {
delay(() => {
console.log(`Finish Task ${id}`);
resolve(id);
}, random(2000, 15000));
});
return prom;
}
const exec = () => {
let proms = [];
forEach(range(1,10), (id,index) => {
proms.push(run(id));
});
let allPromis = Promise.all(proms);
allPromis.then(
res => {
forEach(res, v => console.log(v));
}
);
}
exec();