This question already has answers here:
How to deal with floating point number precision in JavaScript?
(47 answers)
Closed 5 years ago.
for example in javascript addition of 1 + 0.59 is 1.5899999999999999 but I want output of 1.59 which looks right to me.
Use .toFixed() to round your number.
alert((1+0.58999999999).toFixed(2));
Related
This question already has answers here:
Why are two different numbers equal in JavaScript?
(4 answers)
How to deal with floating point number precision in JavaScript?
(47 answers)
Is floating point math broken?
(31 answers)
Closed 3 years ago.
Why 888888888888888888888 equals 888888888888888900000 in JavaScript
console.log(888888888888888888888 === 888888888888888900000)
in chrome console
That is because integers can only be precisely represented in JavaScript up to 2^53 - 1
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/MAX_SAFE_INTEGER
The problem is that, after 2^53 - 1, there is not enough bits to represent the number. So, when you set a higher number, you lose information and what you are actually storing in memory is not reliable. In your case, these 2 numbers, after converting to binary, are the same. That is why they are equal
This question already has answers here:
Large integers in javascript (more the 2^53-1)
(2 answers)
What is JavaScript's highest integer value that a number can go to without losing precision?
(21 answers)
Closed 7 years ago.
I am making a calculator in JavaScript that needs to be able to do precise math on numbers larger than 2^53, which is 9007199254740992. Is there any way to do this?
You can use the "strint" library https://github.com/rauschma/strint.
For example:
> var strint = require("./strint");
> strint.add("9007199254740992", "1")
'9007199254740993'
This question already has answers here:
Is floating point math broken?
(31 answers)
How to deal with floating point number precision in JavaScript?
(47 answers)
Closed 7 years ago.
I have a problem with rounding float number. Here the source code, very simple :
a = "2.3";
result = parseFloat(a)+0.01
console.log(result);
Console displays 2.3099999999999996 instead of 2.31. You can try here : https://jsfiddle.net/fh9bj83u/
Have you a solution ?
Thank you in advance, cordially
Use toFixed to trim to 2 decimal places.
result = (parseFloat(a)+0.01).toFixed(2)
"2.31"
This question already has answers here:
How to round to at most 2 decimal places, if necessary
(91 answers)
Closed 8 years ago.
I have the following number
0.135
I'd like to round it to 2 decimal places, I'm using...
(newCostDiff/2).toFixed(2)
only this returns
0.13
Can anyvody advise me on how to do this?
What's need of jquery
var newCostDiff = 0.135;
Math.round(newCostDiff *100)/100; //returns 0.14
You should first multiply the result by 10^(number of decimals), then round the number, than divide this number by 10^(number of decimals).
In this case:
Math.round((newCostDiff/2)*100) / 100;
This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 8 years ago.
This code snippet:
Math.pow(10,20)+20000 == Math.pow(10,20) + 10000
evaluates to true. Is this a JS bug?
No. Javascript uses floating point numbers to represent large values, and the value 1020 exceeds the precision of the floating point numbers. When you add a relatively tiny value such as 20000 or 10000 to the result, the resulting sums are indistinguishable.