How do I use session variables with jQuery? - javascript

I have a button on one page another button on a different page. This second button has the text in it "0 items selected". When the first button is clicked I want to increase the number in the second button by one.
Seeing it is transferring data over different pages I didn't manage to do it the standard way.
Please do not suggest PHP, I am unable to use it.
var yetVisited = localStorage[0];
if ($('.#CallToActionCustomise').click()){
localStorage++;
}
$('.#CallToActionCustomise').click(function(){
$(".Main_MenuButtonReview").append(localStorage);
});
<button class="Main_MenuButtonReview">0 items selected <i class="fa fa-caret-down"></i></button>

You need to access localStorage as if it were an Object, not an array.
Also, you can only store String values, so to get a number to perform math on, you will need to use parseInt.
localStorage.setItem('yetVisited', 0);
$(".Main_MenuButtonReview").text(localStorage.yetVisited + ' items selected');
$('.CallToActionCustomise').click(function()){
localStorage.yetVisited = parseInt(localStorage.yetVisited) + 1;
$(".Main_MenuButtonReview").text(localStorage.yetVisited + ' items selected');
}
Here's an example.

In addition to the above answer, I think you need to init some tag when it loaded.
Put this code on another page.
$(document).ready(function() {
if (typeof localStorage.yetVisited === 'undefined') {
localStorage.setItem('yetVisited', 0);
}
yetVisited = localStorage.yetVisited;
$('.Main_MenuButtonReview').text(yetVisited + ' items selected');
});
$(document).ready(function() {
// this area means after your page(document) ready completely.
});

Related

Update/Refresh Listbox based on Dropdown selection with trigger("chosen:updated")

I have a Listbox that I need refreshed after a user selects an option in DropdownList.
Image is self explanatory. If one selects Department -> load list of departmetns in Listbox, if one selects Vat Rate refresh/load list of vat rates into the listbox below. (Default department list is loaded on page load). I am currently attempting this with trigger("chosen:updated") and having no luck refreshing listbox. Here is my code for that functionality.
$(function () {
$("#SelectFilter").change(function () {
if (document.getElementById('SelectFilter').value == 1) //dropdownlist
{
//empty listbox
$('#SelectItems').empty();
//append new list to listbox
$.each(data.Departments, function (index, element) {
$('#SelectItems').append('<option value="' + element.Value + '">'
+ element.Text + '</option>');
});
//refresh
$('#SelectItems').trigger("chosen:updated");
}
if (document.getElementById('SelectFilter').value == 2)
{
$('#SelectItems').empty();
$.each(data.VatRates, function (index, element) {
$('#SelectItems').append('<option value="' + element.Value + '">'
+ element.Text + '</option>');
});
$('#SelectItems').trigger("chosen:updated");
}
});
});
Recognising the selected value from the dropdownlist isnt an issue, that works fine. Listbox is currently not getting updated/refresh with new selection. And I cannot figure out were I am going wrong with this.
Try to put all your code for creating the list into a function, and then bind an event on chosing one of the selected items to call this function which generates a new list instead of using .trigger(). If you provide the HTML part as well, I'll post example code soon.
It's not clear to me if you have a problem with recognizing the selected value, or with populating the secondary select tag, or with the initial loading of the data. So I am providing an example of the three steps.
First, to detect the selected value, you need to provide a .change() handler and extract the selected value with .val(). Something similar to this:
$("#SelectFilter").change( function() {
var v = $(this).val();
if (v=="value1") {
} else if (v=="value2") {
} else {
}
});
then each of the changes detected has to refresh the contents of the secondary select tag, something as simple as this...
$("#SelectItems").empty();
['first item','second item','troisième'].forEach( (v,i) =>
$("#SelectItems").append($("<option>").val("item"+i).text(v))
);
}
And finally triggering the initial load should be as simple as triggering a change event
$("#SelectFilter").change();
I have put all the steps together in this fiddle https://jsfiddle.net/mud9u8yL/6/

jQuery - remove li from array with delete image

I'm attempting to make a menu bar that can have <li> elements added and removed. So far so good, but when I try and remove them I'm running into issues. I've toyed with this for a couple hours and now I'm wondering if this whole process could just be made easier (maybe an object?).
Anyways, here's the full code (80 lines), with comments to follow along.
var tabs = $('.accountSelectNav');
var titles = [];
var listItems = [];
// when the page loads check if tabs need to be added to the ul (menu bar)
$(document).ready(function(e) {
if ($.cookie('listItems') != null) {
console.log('not null');
//return "listItems" to it's array form.
listItems = JSON.parse($.cookie('listItems'));
$('.accountSelectNav').append(listItems);
}
});
$('.selectTable td:first-child').on('click', function(e) {
$('#home_select').removeClass('navHighlight');
//grab the text value of this cell
title = $(this).text();
$.ajax({
url:'core/functions/getAccountId.php',
type: 'post',
data: {'title' : title}
}).fail (function() {
alert('error');
}).done(function(data) {
accountId = $.trim(data);
// store values in the cookie
$.cookie('account_id', accountId, {expires : 7});
$.cookie('title', title, {expires : 7});
window.location = ('home_table.php');
});
// make sure the value is NOT currently in the array. Then add it
var found = jQuery.inArray(title, titles);
if (found == -1) {
titles.push(title);
addTab();
}
// make sure the value is NOT currently in the array. Then add it
found = jQuery.inArray(title, listItems);
if (found == -1) {
addListItem();
//place <li>'s in cookie so they may be used on multiple pages
$.cookie('listItems', JSON.stringify(listItems));
};
});
$("body").on("click", ".deleteImage", function (e) {
var removeTitle = $(this).closest('li').find('a').text();
var removeItem = $(this).closest('li')[0].outerHTML;
//remove title from "titles" array
titles = jQuery.grep(titles, function (value) {
return value != removeTitle;
});
//remove <li> from "listItems" array
listItems = jQuery.grep(listItems, function (value) {
return value != removeItem;
});
// this shows the <li> is still in the listItemsarray
console.log(listItems);
// put the array back in the cookie
$.cookie('listItems', JSON.stringify(listItems));
removeTab(this);
});
$("body").on("mouseover", ".accountSelectNav li", function(e) {
$(this).find('.deleteImage').show();
});
$("body").on("mouseleave", ".accountSelectNav li", function(e) {
$(this).find('.deleteImage').hide();
});
function addTab() {
tabs.append('<li class="navHighlight">' + '' + title + '' + '' + '<img src="images/delete.png" class="deleteImage"/>' + '' + '</li>');
};
function removeTab(del) {
$(del).closest('li').remove();
}
function addListItem() {
var s = ('<li class="navHighlight">' + '' + title + '' + '' + '<img src="images/delete.png" class="deleteImage"/>' + '' + '</li>');
listItems.push(s);
}
So you see I have two arrays of equal length that should always be the same length. One stores the title to be displayed in the tab, the other holds the html for the <li> which will be appended to the <ul>. I have no problem removing the title from its array. However removing the <li> from it's array is becoming a rather big hassle. You see when I get the <li> element after its been inflated the html inside does not exactly match what was put in, the browser adds style elements.
Example, the variable "removeItem" represents the html value of the selected <li> I wish to remove. It looks like this:
<li class="navHighlight">Test1<img src="images/delete.png" class="deleteImage" style="display: inline;"></li>
yet the value in my array "listItems" looks like this:
<li class="navHighlight">Test1<img src="images/delete.png" class="deleteImage"/></li>
So my attempt at removing it from my array always fails because they aren't a perfect match.
Now my question is how do I remove this <li> item? Also is there an easier way to do this whole process and I'm just not seeing it?
Thanks for your time.
EDIT
Fiddle by request here
Easiest way I can explain it.
Click the link to the fiddle.
Click any cell in the "App Name" column
This will add a <li> to the <ul> (menu) above of the table
When you hover over the <li> a picture appears
Click the picture
This should remove the <li>, both from the <ul> and from the array listItems
right now it does not
In the process of making this easier to check, I've taken your JSFiddle and did the following:
removed extra console.log and comments
removed interaction with cookies (since I did not have them in the first place, I figured they wouldn't just the first scenario)
After doing so I reached a point (you can see it here) where the desired functionality just works.
I even went ahead and removed the ajax stuff because that alert was driving me crazy. (here)
Since this works fine, my guess is that your issue lies between the lines that I removed.
Your usage of cookies is as follows:
To load existing tabs and add them back again
To save account_id and title, which is not used back again
To persist the listItems after a new item has been added
I then opened up the console with your version of the fiddle and the execution of javascript stops at $.cookie() with the error undefined is not a function.
This clearly indicates that the issue present in the Fiddle is that jQuery.cookie is not present and so those calls are halting the execution of the rest of your script. This also explains why it just started working when I took them out.
I posted the whole process of how I got there to indicate how I trimmed down the problem to specific parts, which is useful to reduce the problem space. When you're out of options and reach a place when you're lost, it's easier to post a question with less code and the specific part of the problem that you've identified. This will help you in finding the issues that you're facing and StackOverflow to provide proper answers to your questions.
Hope it helps!
Here is the solution I came up with. It should be much easier for people to understand than my original post. Although it's a long read it may be worth it, especially for new developers.
The point of this code is to make a menu bar out of an un-ordered list or <ul>. The menu bar needs to be used on multiple pages. So I'll be using cookies.
I start with this code to get a text value from my table.:
$('.selectTable td:first-child').on('click', function(e) {
// This value will be used later for the name of the tab or `<li>` inside our menu bar or `<ul>`
title = $(this).text();
});
Then I place the value in an array. I do this only if the array does not already have this string inside it. I do not want duplicates:
var found = jQuery.inArray(title, titles);
var titles = [];
if (found == -1) {
titles.push(title);
}
Then I store the array into a cookie, using a library like this:
$.cookie('titles', JSON.stringify(titles));
Now when any page loads that needs this menu bar I run this code to check if there are any values:
$(document).ready(function() {
if ($.cookie('titles') != null) {
titles = JSON.parse($.cookie('titles'));
}
});
Now I need to loop through the array. When I loop through the array I have to do 3 things:
1) Grab the string value.
2) Add the html to my new string so it becomes a list item or <li>.
3) Append the newly created <li> to our <ul>.
Like so:
for(var i = 0; i < titles.length; i++) {
var str = titles[i];
var listItem = '<li class="navHighlight">'
+ '<a href="#">'
+ str
+ '</a>'
+ '<a href="#">'
+ '<img src="images/delete.png" class="deleteImage"/>'
+ '</a>'
+ '</li>';
$('.accountSelectNav').append(listItem);
}
Now, if I want to remove this <li> I click the delete image found inside our <li>. What delete image you say? Look at the html I added again. You will see I add an <img> tag in there.
Now delete like so:
$("body").on("click", ".deleteImage", function (e) {
// grabs the text value of my li, which I want to remove
var removeTitle = $(this).closest('li').find('a').text();
// runs through my titles array and returns an array without the value above
titles = jQuery.grep(titles, function (value) {
return value != removeTitle;
});
});
Then I simply place the new array inside my cookie once again. Like this:
$.cookie('titles', JSON.stringify(titles));
And finally I remove the tab like this:
removeTab(this);
function removeTab(del) {
$(del).closest('li').remove();
}
Yay, I'm done. So now, if anyone has a more elegant way of accomplishing this I'm listening. I have no doubt there's a better way, javascript/jQuery isn't even close to my strong point.
The full code can be found here.

jquery append element and keep reference for removing it later

what is the correct method to append a div to dom, and keep a handle for manipulating that dom later ? and case removing it will the refrence be deleted also ? if not how can i ?
this is an example code of what i came out with, please let me know your opinon and if there is a better more solid method for doing this.
note that i keep reference in an array because many elements can manipulate element.
var layovers=[];
function ajaxMe($e){
//do some ajax call
var lay=layoverThis($e);
layovers[lay].remove(); //does this remove added element from dom ? does it unset layouvers[lay] too ?
}
function layoverThis($e){
var p=layover.push($('<div class="overlay" ><span><i class="fa fa-spinner fa-spin"/>loading</span></div>')) - 1;
$e.append(layover[p]);
return p;
}
nearest example i can think of is like opening a folder in windows Os.
when you open a folder: a new window opens to your desktop, while also there is a taskbar tab that is added linked to same window that was appended to your desktop, allowing system to manipulate window (close-restore minimize etc..), so how do i do this in javasript.
my question is how to make such behavior in a manner that is flexible and not hacky or memory wasteful.
You can use a psudoClass and an index - add the event to the delete element as you create the element in the DOM. OR have an onclick that removes the parent div that was appended..
So, you're code will look like:
function layoverThis($e){
var p=layover.push($('<div class="overlay" ><span><i class="fa fa-spinner fa- spin"/>loading</span> <span class="closeThis" onclick="$(this).parent().remove();" > Close </span></div>')) - 1;
$e.append(layover[p]);
return p;
}
Let me know if this works for you, i have a number of other solutions.
Update:
To facilitate the object to be selectable, I would use a psudoClass..
document.ready(function() {
addADiv($('#myParent'));
getArrayOfDivs().css('background-color', 'red');
doAjax(lastClicked);
});
function doAjax(ctrl)
{
}
var lastClicked = "";
$('.dynamicDivs').click(function() {
lastClicked = $(this);
});
function getArrayOfDivs() {
return $('.dynamicDivs');
}
function addADiv($where){
var uniqueIdentifier = $('.dynamicDivs').count() + 1;
$where.append($('<div class="overlay dynamicDivs ' + uniqueIdentifier + ' " ><span><i class="fa fa-spinner fa- spin"/>loading</span></div>'));
}

Jquery Chosen plugin. Select multiple of the same option

I'm using the chosen plugin to build multiple select input fields. See an example here: http://harvesthq.github.io/chosen/#multiple-select
The default behavior disables an option if it has already been selected. In the example above, if you were to select "Afghanistan", it would be greyed out in the drop-down menu, thus disallowing you from selecting it a second time.
I need to be able to select the same option more than once. Is there any setting in the plugin or manual override I can add that will allow for this?
I created a version of chosen that allows you to select the same item multiple times, and even sends those multiple entries to the server as POST variables. Here's how you can do it (fairly easily, I think):
(Tip: Use a search function in chosen.jquery.js to find these lines)
Change:
this.is_multiple = this.form_field.multiple;
To:
this.is_multiple = this.form_field.multiple;
this.allows_duplicates = this.options.allow_duplicates;
Change:
classes.push("result-selected");
To:
if (this.allows_duplicates) {
classes.push("active-result");
} else {
classes.push("result-selected");
}
Change:
this.form_field.options[item.options_index].selected = true;
To:
if (this.allows_duplicates && this.form_field.options[item.options_index].selected == true) {
$('<input>').attr({type:'hidden',name:this.form_field.name,value:this.form_field.options[item.options_index].value}).appendTo($(this.form_field).parent());
} else {
this.form_field.options[item.options_index].selected = true;
}
Then, when calling chosen(), make sure to include the allows_duplicates option:
$("mySelect").chosen({allow_duplicates: true})
For a workaround, use the below code on each selection (in select event) or while popup opened:
$(".chosen-results .result-selected").addClass("active-result").removeClass("result-selected");
The above code removes the result-selected class and added the active-result class on the li items. So each selected item is considered as the active result, now you can select that item again.
#adam's Answer is working very well but doesn't cover the situation that someone wants to delete some options.
So to have this functionality, alongside with Adam's tweaks you need to add this code too at:
Chosen.prototype.result_deselect = function (pos) {
var result_data;
result_data = this.results_data[pos];
// If config duplicates is enabled
if (this.allows_duplicates) {
//find fields name
var $nameField = $(this.form_field).attr('name');
// search for hidden input with same name and value of the one we are trying to delete
var $duplicateVals = $('input[type="hidden"][name="' + $nameField + '"][value="' + this.form_field.options[result_data.options_index].value + '"]');
//if we find one. we delete it and stop the rest of the function
if ($duplicateVals.length > 0) {
$duplicateVals[0].remove();
return true;
}
}
....

Can't get sessionStorage to work correctly

I have multiple buttons that when they are clicked an image is loaded and the image is supposed to stay there based even when the page refreshes. When I use this the button with the highest setItem value always shows even if I click on other button. How do I fix this?
here is one of the scripts:
<script type="text/javascript">
var isImage1 = sessionStorage.getItem('2');
function showImage1() {
sessionStorage.setItem('isImage1', '2');
$("#loadingImage1").show();
$("#loadingImage").hide();
$("#loadingImage2").hide();
$("#loadingImage3").hide();
$("#loadingImage4").hide();
$("#loadingImage5").hide();
$("#loadingImage6").hide();
}
if(isImage1 == 2) showImage1();
</script>
and here is one of my buttons:
<input name="EPL/MECH DESIGN - TECHS" style="white-space:normal"
onclick="moveText(this.name);showImage1();form1.submit()"
style="width: 275px" type="button" value="7SBD EPL/Mech. Design Techs" />
Update: I have updated this line
var isImage1 = sessionStorage.getItem('2');
to
var isImage1 = sessionStorage.getItem('isIamge1');
but my issue still exists, that the isImage with the largest value stays even when i click the other buttons, so help is still needed.
In your session storage, you are setting the value of the 'isImage1' Item to '2'
sessionStorage.setItem('isImage1', '2');
But in your code to retrieve the value you are actually retrieving the item '2'
var isImage1 = sessionStorage.getItem('2');
You need to change your sessionStorage.getItem to reference 'isImage1'
var isImage1 = sessionStorage.getItem('isImage1');
Then you should get the value you are expecting.
There are loads of good jsfiddles on session storage. you may get some ideas from this one:
http://jsfiddle.net/gabrieleromanato/XLRAH/
Incidently; this is a very small value you are storing, why not store it in a cookie instead?
EDIT:
based on the fact that you have multiple functions exactly like this one, you are better off following Ken's solution, the only thing I would add is a wildcard to turn off the other images:
function showImage(imgNum) {
sessionStorage.setItem('Image',imgNum);
$("[id^=loadingImage]").hide();
$("#loadingImage" + imgNum).show();
}
showImage(sessionStorage.getItem('Image'));
The code in the buttons would then be showImage(1) instead of showImage1();
_Pez
By re-factoring the code a little you can do something like this:
/// setup some vars including max number of images
var maxImages = 6, i = 1, v;
/// now loop through and get the items for each image
for(; i =< maxImages; i++) {
v = sessionStorage.getItem('isImage' + i);
/// if in storage, call show image with the number to show
if (v !== null) showImage(i);
}
/// show image based on number
function showImage(num) {
sessionStorage.setItem('isImage' + num, '1');
$("#loadingImage" + num).show();
}
Also note that sessionStorage only deals with strings. So in order to check a specific number you need to convert it to one first parseInt(value, 10);.
But in this case the 1 that we set can be anything - it's just to store some value so sessionStorage doesn't return null.
In the button code you can change it to do this:
<input name="EPL/MECH DESIGN - TECHS" style="white-space:normal"
onclick="moveText(this.name);showImage(1);form1.submit()"
style="width: 275px" type="button" value="7SBD EPL/Mech. Design Techs" />

Categories

Resources