is it possible to shrink and grow child HTML elements with just CSS. Here is an example below, I want to see how others would approach this. I have seen solutions with JQuery however wanted to know there is an easier way to do this.
<div class="your_custom_styling_here_for_resizing">
<div style="width: 400px; height: 400px; display: flex;">
<div style="height: 100px; background: #333333; flex: 1;"></div>
<div style="background: #cccccc; flex: 1;"></div>
</div>
</div>
An easier solution would be to create a class for those styles instead of using inline CSS, and for the new styles, then adding / removing / changing just classes from jquery.
You want a child element to scale to the parent elements dimensions? If you do then just do the following:
.parent {
border: 5px solid red;
}
.child {
width: inherit;
height: auto;
background-color: blue;
color: white;
}
<div class="parent">
<div class="child">Expand or shrink your screen to see me scale to my parent</div>
</div>
}
Related
Say I wanted an element to be positioned vertically absolutely, but horizontally relative. Is this possible with css/html/javascript?
Not sure which case could be fine to use this mix, but it is possible,
if you only define top/bottom properties in a position:absolute element.
The left/right position of the element will be "relative" if you leave it untouched.
In the following example, the second container has a mixed positioning.
.example{
margin: 30px;
position: relative;
border: 1px solid red;
}
.item1, .item2{
display: inline-block;
margin: 0;
}
#example2 .item2{
position: absolute;
top: 80px;
}
<div id="example1" class="example">
<div class="item1">Item1</div>
<div class="item2">Item2</div>
</div>
<div id="example2" class="example">
<div class="item1">Item1</div>
<div class="item2">Item2</div>
</div>
I'm needing to create CSS classes that can display content similar to this design image here: design concept
Obviously, the code statements themselves don't matter. But how can I create CSS that could wrap the containing content as seen in the image and have that work to n nested containers? I've been playing around with div tags and display: inline-block styling but nothing is working out.
Here is what I currently have, using flex-box. This is almost what I need except that the "rows" aren't setting their width to fit the text content as it just sets the width of everything to the largest width child... seems that this approach might not be possible.
.container {
display: inline-flex;
flex-direction: column;
padding-left: 15px;
}
.containerRow {
display: flex;
flex-direction: column;
justify-content: center;
height: 35px;
margin: 5px;
}
.dropContainer {
height: 70px;
border: 1px solid #ccc!important;
background-color: white;
color: black;
}
.purple {
background-color: #872A61;
color: white;
}
.green {
background-color: #478B26;
color: white;
}
<div class="container purple">
<div class="containerRow">
if (something == true) then
</div>
<div class="container green">
<div class="containerRow">
<div><b>where</b> something(x: Number, y:Number) <b>is</b></div>
</div>
<div class="dropContainer">
Some more stuff again
</div>
<div class="dropContainer">
Some more stuff again
</div>
<div class="containerRow">
<b>end</b>
</div>
</div>
<div class="containerRow">
<b>end</b>
</div>
</div>
Use margins or padding styles with percentages to achieve the nth term.
I have 3 questions about my jQuery study today.
Why my jQuery code not have the animation effect as it should be? for example, .slideUp() and .slideDown(), my code shows something strange instead of slideUp animation.
I understand, the .hide() or .slideUp() function is only to HIDE the div box, not DELETE them, however, in my code, why the position of other div boxes changed after a DIV .hide()? Shouldn't it stay at their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position, when one DIV box has been hided?
$(document).ready(function() {
$('#panel1').slideUp(1000).delay(1500).slideDown(1000);
});
.panel {
display: inline-block;
width: 80px;
height: 60px;
border: 1px solid green;
position: relative;
top: 20px;
margin-left: 45px;
border-radius: 5px;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
For your first question
Why my jQuery code not have the animation effect as it should be? for
example, .slideUp() and .slideDown(), my code shows something strange
instead of slideUp animation.
The .slideUp() method animates the height of the matched elements. Means it animates height so it reaches 0 (or, if set, to whatever the CSS min-height property is). See here for reference. That is exactly what is happening to your first box it is decreasing in height.
Afterwards the display style property is set to none to ensure that the element no longer affects the layout of the page.
What display none does ?
display:none means that the tag in question will not appear on the
page at all
Now for second and third question
I understand, the .hide() or .slideUp() function is only to HIDE the
div box, not DELETE them, however, in my code, why the position of
other div boxes changed after a DIV .hide()? Shouldn't it stay at
their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position,
when one DIV box has been hided?
The .hide() and .slideUp()function they both add display:none to your tag element. Means they are gone now
Now what can you do to let them stay there, But hidden from view ?
You can use visibility or opacity property instead rather than using display
property.
For example: visibility: hidden; will just hide it from the view.
Will update your fiddle in order to demonstrate it in a while. Hope this will help you. Please feel free to ask if not clear. Thank you.
$(document).ready(function() {
setInterval(function(){
$('#panel1').slideUp(1000).delay(500).slideDown(1000);
}, 3000);
});
.outer-div
{
position: relative;
display: inline-block;
min-height: 1px;
margin-right: 15px;
margin-left: 15px;
width: 130px;
height: 90px;
}
.panel {
border: 1px solid green;
margin-left: 45px;
border-radius: 5px;
position:absolute;
top:0;
width: 100%;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div class="outer-div">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
</div>
You should use display:flex on .panels, that solves your first question.
For second question you should use visibility or opacity.
With current code you are removing it, although it is called hide() it is equivalent to CSS display:none; which doesn't keep space of element.
Although you actually don't need to set visibility in your case because sliding it up will hide element and down show.
Something like this:
$('#panel1').animate({
top: -62 // 60 is height of element plus 2px of borders
}, 1000).delay(1500).animate({
top: 0
}, 1000);
Also you have to change CSS a bit.
Add this to your CSS:
.panels {
display: flex;
overflow: hidden;
margin-top: 20px;
}
And from .panel remove top: 20px;
Full example is here https://jsfiddle.net/_jakob/cphptby3/1/
I have a main div under which there can be one or two sub divs. When there are two sub-divs, I would want them to be displayed side-by-side. But If I have only one sub div, then I'd want it to be displayed in the center. Can this be achieved by using CSS or should I take help of JavaScript? Using the following CSS I'm able to achieve the side-by-side part of it. But I'm not sure how to go forward when there is only one sub div
HTML:
<div id="maindiv">
<div class="subdiv">
<p>Div One</p>
</div>
<div class="subdiv">
<p>Div Two</p>
</div>
</div>
CSS:
div.subdiv {
float: left;
padding: 20px;
}
div#maindiv {
border: 2px solid black;
height: 120px;
width: 200px;
}
Use display:inline-block instead of float:left. Try to remove the second sub div in my example fiddle and you can see the desired result.
div.subdiv {
display:inline-block;
padding: 20px;
}
div#maindiv {
border: 2px solid black;
height: 120px;
width: 200px;
text-align:center;
}
DEMO
I created a notecard image where i overlayed multiple images on top of it. These are elements of the notecard. I want it so that when I hover over the notecard, I can completely change the contents on the notecard image (overlaying new things onto the notecard).
So right now, I have this right now:
<div style="position:relative;">
<a href="#games">
<img id "image_a" a" src="images/card_normal.png" onmouseover "this.src rc 'images/hover/card_hover.png';" ;" onmouseout "this.src rc 'images/card_normal.png';" ;" style="position: absolute; top: 0; left: 0;"/>
<img id "image_b" b" src="images/category_icons/icon_games.png" style="position: absolute; top: 10px; left: 40px;"/>
<img id "image_c" c" src="images/category_titles/title_games.png" style="position: absolute; top: 160px; left: 40px;"/>
</a>
</div>
Where the notecard changes into a "hovered" version, but I am unable to change anything else. I want it so that whenever the mouse pointer is in the notecard (including if its on other elements inside the notecard), the contents change. I want to completely scrap the contents of it (so the title and icon) and change it so I can add text and overlay new images.
How can I do this in JS/HTML/etc?
If the two versions (hover/non-hover) are significantly different (and you want a no-js solution), you could have two divs, one set to hide, one set to show. Then on-hover, you change their visibility. Fiddle.
<div class="card">
<div class="no-hover">
stuff you want to show when the user is just looking
</div>
<div class="on-hover">
stuff you want to show when the user hovers
</div>
</div>
CSS:
.no-hover {
display: block;
}
.on-hover {
display: none;
}
.card:hover > .on-hover {
display: block;
}
.card:hover > .no-hover {
display: none;
}
It's extra HTML elements, but might be easier to maintain.
Based on your comment to Learner's answer, here is an example of the idea you are describing:
HTML:
<div class="outer">
<div class="inner"></div>
<div class="inner"></div>
<div class="inner"></div>
<div class="inner"></div>
</div>
CSS:
.outer {
width: 304px;
height: 304px;
background-color: black;
}
.inner {
float: left;
width: 150px;
height: 150px;
background-color: red;
border: 1px solid black;
display: none;
}
.outer:hover .inner {
display: block;
}
DEMO
If you are trying to achieve something like this:
http://spoonfedproject.com/wp-content/uploads/demo/jquery-slide-hover/index.htm
Here's your solution:
http://www.robertkuzma.com/2011/01/jquery-animated-swap-div-content-on-hover-effect/