Currently I am using Flask and Jquery and getting a 500 Internal Server Error response in my console. When I post with Ajax to the url on flask, shouldn't it be able to be received? I don't understand why I am getting this error.
Jquery
$('.movie').click(function(){
console.log(this);
$(this).toggleClass('green blue').promise().done(function(){
if ($(this).html() == "Add Movie"){
$(this).html("Added");
}
});
id = $(this).val();
//get information from API
$.ajax({
url: "/profile",
dataType: 'json',
async: true,
data: {id: id},
success: function(data) {
}
});
Python/Flask
#app.route("/profile", methods = ["GET"])
def profile(id):
print("mydata is: ", request.args['id'])
if request.args.get:
print("this API is reached")
id = request.args.get['id']
url_movie = 'https://api.themoviedb.org/3/movie/{}?api_key=78cb6b67a99ce26e6d6619c617d9c907&language=en-US'.format(id)
r = requests.get(url_movie)
code = r.json();
return jsonify(code)
500 is a server error. There is something wrong with the request execution at server side only.
Related
i have problem with ajax when i send a request from my form it doesn't get the value from the form
this is my view code
def create(request):
if request.method == 'POST':
msg_text = request.POST.get('the_massage')
data = {}
form = ChatApp(message=msg_text, user=request.user)
form.save()
data['message']=form.message
data['user']=form.user.username
return JsonResponse(data)
else:
return JsonResponse({'nothing coming thrue'})
it shod get the_massage variable but it give me null value
this is my ajax function :
$(function () {
$('#main-form').on("submit" ,function () {
console.log("create function is here");
var form = $(this);
$.ajax({
url: form.attr('action'),
type: form.attr('method'),
data: {the_massage:$('#msgbox').val()},
dataType: 'json',
success: function(json) {
console.log(json);
console.log('success');
},
error: function(error){
console.log('we have error');
},
});
});
});
when i console log the value it just come through in the console
please help me
and show me this in the console :
Resource interpreted as Document but transferred with MIME type
application/json: "http://localhost:8000/create/".
Call the function in your event:
$('#main-form').on("submit" ,function (event) {
event.preventDefault();
console.log('submited');
console.log($('#msgbox').val())
created();
});
I see many possibles problems here.
1) just for dev propose, delete #login_required (if you have) from your view and add #csrf_exempt to avoid this problem on dev.
2) Please look inside request.body on your view.
3) if point 1 and 2 doesn't work, please put the server response of this call: POST localhost:8000/create 403 (Forbidden)
this is the write answer : i solve this and its on git hub now https://github.com/mhadiahmed/tinypice
I am using node.js and Express.js on the back end, and am trying to make a server call from the client via AJAX.
So I have this POST request that works fine with AJAX:
node.js/Express.js:
app.post('/createNewThing', function(req, res) {
var userInput = req.body.userInput;
if (userInput) {
res.send('It worked!');
}
});
Client Side/AJAX request:
var userInputForm = $('#userInputForm.val()')
$.ajax({
url: "/createNewThing",
type: "POST",
data: "userInput=" + userInputForm,
dataType: "text",
success: function(response, status, http) {
if (response) {
console.log('AJAX worked!);
}
}
});
The userInputForm comes from an HTML form.
This POST request works fine. But I want to change this to a GET request. If I change app.post to app.get, and change type in the AJAX call to GET, I get this 500 error:
GET /createNewThing?userInput= 500
When you make a GET request, the data appears in the query string (of the URL in the request headers). It doesn't appear in the request body. There is no request body.
When you try to read from the request body, you are trying to access a property of an undefined object, which triggers an exception and cause an internal server error.
This answer explains how to read a query string:
var id = req.query.id; // $_GET["id"]
So
var userInput = req.query.userInput;
I think var userInputForm = $('#userInputForm.val()') will get error or get wrong data..This may be the reason for the error. Due to userInputForm may not be a string and concatenate with userInput=
Actually it is bad data.
And for the data in ajax, you should modify data from data: "userInput=" + userInputForm,
to:
data: {
userInput: userInputForm
},
dataType: "json"
And var userInputForm = $('#userInputForm.val()')
to var userInputForm = $('#userInputForm').val();
At last, you could modify as bellow, I believe it works:
var userInputForm = $('#userInputForm').val();
$.ajax({
url: "/createNewThing?userInput=" + userInputForm,
type: "GET",
success: function(response, status, http) {
if (response) {
console.log('AJAX worked!);
}
}
});
I have the following code (jQuery) to create a json file:
$( ".save" ).on("click", function(){
var items=[];
$("tr.data").each(function() {
var item = {
item.Code : $(this).find('td:nth-child(1) span').html(),
itemQuantity : $(this).find('td:nth-child(4) span').html()
};
items.push(item);
});
});
Now this is my AJAX function:
(function() {
$.ajax({
url : "",
type: "POST",
data:{ //I need my items object, how do I send it to backend server (django)??
calltype:'save'},
dataType: "application/json", // datatype being sent
success : function(jsondata) {
//do something
},
error : function() {
//do something
}
});
}());
Now, my doubt is how do I send the 'item[]' object that I created to the backend? I do need to send both the item[] object and the variable 'calltype' which signals what made the AJAX call, as I have the same Django View (its the Controller equivalent for Django) in the backend being called by different AJAX functions.
How will my AJAX function look like?
Hey guys just got my answer right.
I used the following ajax function to get it right:
(function() {
$.ajax({
url : "",
type: "POST",
data:{ bill_details: items,
calltype: 'save',
'csrfmiddlewaretoken': csrf_token},
dataType: 'json',
// handle a successful response
success : function(jsondata) {
console.log(jsondata); // log the returned json to the console
alert(jsondata['name']);
},
// handle a non-successful response
error : function() {
console.log("Error"); // provide a bit more info about the error to the console
}
});
}());
So, this is sort of a self answer!!! :) Thanks a lot SO!!
I am doing the login throgh ajax. jquery function is working fine but its not going to the ajax url. So django view is not getting executed.
Ajax.html
$(function()
{
localStorage['domain'] = "http://122.172.64.142";
var domain = localStorage['domain'];
$('#fac1').on('click', function () {
var username = $("#username").val();
var password = $("#pwd").val();
data = {
name: username,
password: password
};
alert(domain);
$.ajax({
url: domain + "/login/login_android_here/",
type: "POST",
data: data,
success: function (response) {
alert("success");
window.location = 'file:///android_asset/www/posts.html';
},
error: function () {
alert('some error in login');
}
});
return false;
});
});
My django views.py
#csrf_exempt
def login_android(request):
print "i am in view"
if request.method == "POST":
print "you are in method"
username = request.POST['name']
password = request.POST['password']
login_api(request,username,password)
#return HttpResponseRedirect('/home/')
messages.success(request, 'You Loged In Successfully')
response = json.dumps(username)
return HttpResponse(response, mimetype="application/json")
When i click on login button i am getting alert but its not getting entered to view. Url is correct.
I would first recommend using Chrome with the developer tools console open.
You could change you alerts for console.log().
When your trying window.location = 'file:///android_asset/www/posts.html';
You are trying to access a local resource. If I post that in my Chrome developer tools I get back
Not allowed to load local resource: file:///android_asset/www/posts.html
If you would use window.location.replace("a url to your view"); this will work like a HTTP redirect.
for more information redirect page
and you should be able to see your view.
I was made a silly mistake. I provided a wrong domain address on this page. Now it worked.
localStorage['domain'] = "http://122.172.64.142";
This address was wrong. Thats why it was not able to enter in to the view.
You forgot dataType ajax param
$.ajax({
url: domain + "/login/login_android_here/",
type: "POST",
data: data,
dataType : 'json', //dataType param IS MISSING
success: function (response) {
alert("success");
window.location = 'file:///android_asset/www/posts.html';
},
error: function () {
alert('some error in login');
}
});
I am trying to implement file upload using ajax with Django but facing some problem.
When the user tries to upload the files after selecting the file and submitting the form, then as per my understanding , an ajax request should be send to the server using POST method ,but in my case a POST request is being made to the server, but the server is not able to identify it as an ajax request and browser is redirected to http://<server>:<port>/upload/ and the contents on this page are as follows.
{"status": "error", "result": "Something went wrong.Try Again !!"}
Django Version: 1.6.2
Python Version: 2.7.5
Also, testing on Django Development Server.
views.py
def upload(request):
logging.info('Inside upload view')
response_data = {}
if request.is_ajax():
logging.info('Is_AJAX() returned True')
form = UploaderForm(request.POST, request.FILES)
if form.is_valid():
logging.info('Uploaded Data Validated')
upload = Upload( upload=request.FILES['upload'] )
upload.name = request.FILES['upload'].name
upload.save()
logging.info('Uploaded Data Saved in Database and link is %s' % upload.upload)
response_data['status'] = "success"
response_data['result'] = "Your file has been uploaded !!"
response_data['fileLink'] = "/%s" % upload.upload
return HttpResponse(json.dumps(response_data), content_type="application/json")
response_data['status'] = "error"
response_data['result'] = "Something went wrong.Try Again !!"
return HttpResponse(json.dumps(response_data), content_type='application/json')
Template
<form id="uploadForm" action="/upload/" method="post" enctype="multipart/form-data">
{% csrf_token %}
<input id="fileInput" class="input-file" name="upload" type="file">
<input type="submit" value="Post Images/Files" />
</form>
Javascript 1:
$('#uploadForm').submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: '/upload/',
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
Javascript 2
var options = {
url: '/upload/',
type: "POST",
error: function(response) {
alert('Something went Wrong. Try Again');
},
success: function(response) {
if ( response.status == 'success' ) {
alert('success');
}
}
};
$('#uploadForm').ajaxSubmit(options);
Question:
1) Why is Django not able to recognize the ajax request and value of request.is_ajax() is always False.
2) Even if the server doesn't recognize ajax request why is my browser getting redirected to another page ?
There is another similar question here but with no result.
This works for me. You need a jquery.form.js
$("#uploadForm").submit(function(event) {
$(this).ajaxSubmit({
url:'{% url upload_file %}',
type: 'post',
success: function(data) {
console.log(data)
},
error: function(jqXHR, exception) {
console.log("An error occurred while uploading your file!");
}
});
return false;
});
Here's the similar question here with answers.
Make sure that javascript code block
$('#uploadForm').submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: '/upload/',
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
loaded after your uploadForm html form in DOM on page. In your case seems you trying to bind submit handler with form element which not yet loaded so when you click, it send simple POST request.
1) why is_ajax() not working?
Have you included the JQuery form plugin (jquery.form.js) ? ajaxSubmit() needs that plugin.
Take a look at http://jquery.malsup.com/form/
If it's already done, you might take a look at the HTTPRequest object
Django Documentation says HttpRequest.is_ajax()
Returns True if the request was made via an XMLHttpRequest. And if you are using some javascript libraries to make the ajax request, you dont have to bother about this matter. Still you can verify "HTTP_X_REQUESTED_WITH" header to see if Django received an XMLHttpRequest or not.
2) Why page redirects?
As I said above, JQuery form plugin is needed for handling the ajax request and its call back. Also, for ajaxSubmit() you need to override the $(#uploadForm).submit()
$('#uploadForm').submit( function (){
$(this).ajaxSubmit(options);
return false;
});
Hope this was helpful :)