Develop Reference

PHP translation From SQL Database

My site pulls test questions from a database, and some of these questions have images associated with them.
The images pull in fine and everything works as expected, but when trying to pull the answers for these questions, which sometimes also have images, there is a translation issue causing just the reference index to be called and no image displayed (the text still appears that is associated with the answer however).
Question Picture Example
Answer Picture Example - An image should appear in the highlighted area
I can't tell if the issue is caused in the HTML/PHP interpretation of calling an answer or in the function that defines the answer to be called. Code snippets below.
First is the HTML/PHP and JS. All things pertaining to answers are "Rationale" All things pertaining to images are "equations":
<?php
for ($i = 0; $i < $displayCount; $i++) {
$workingDate = date('Y-m-d', time()-($i*24*60*60));
$QID = updateQOTD($ar, $workingDate, $level);
$questionInfo = getQuestion($ar, $QID);
echo $workingDate."<br><br>";
if(isset($questionInfo->VIGNETTE)) {
echo "<strong>Vignette</strong>:<br>";
echo $questionInfo->VIGNETTE;
echo "<br><br>";
}
$equation = getEquation($ar, $QID);
$eq_text = '';
if (isset($equation)) {
$file = $equation->FILE_NAME;
$eq_text = '<img src="/lcms/images/equations/' . $file . '">';
}
echo "<strong>Question</strong>:<br><br>";
$qtext = $questionInfo->TEXT ;
$qtext = preg_replace('/<equation id="\d+"\/>/', $eq_text, $qtext);
echo $qtext;
echo "<br><br>";
?>
<div id='response_<?php echo $i; ?>'></div>
<div class='rationale margin-top-20'><br><strong>Rationale:</strong><br>
<?php echo $questionInfo->RATIONALE; ?>
</div>
<?php
}
?>
<button id="grade" class="btn-theme" type="button">Grade My Choices</button>
<? require_once(getenv("DOCUMENT_ROOT")."/inc/footer.pilot.php"); ?>
<script type="text/javascript">
$(document).ready(function(){
$(".rationale").hide();
$("response_1").hide();
$("response_2").hide();
$("response_3").hide();
$("response_4").hide();
$("response_5").hide();
$("#grade").click(function () {
$(".correctMark").html("<img src='../../images/600px-Green_check.png' />");
$(".incorrectMark").html("<img src='../../images/600px-Red_x.png' />");
$(".rationale").slideDown("fast");
if ($("input[name='question_1']:checked").val() == 'correct') {
$("#response_1").text("Your answer was correct!");
$("#response_1").slideDown("slow");
}
});
});
</script>
And here is the database code call SQL and function defining Rationale:
function getEquation($ar, $QID) {
if (isset($QID) && $QID > 0) {
$selectSql = sprintf("SELECT e.FILE_NAME FROM equation_tbl e, equation_question_link_tbl eq WHERE eq.QUESTION_ID = %s AND e.ID = eq.EQUATION_ID ",
$QID);
$equation = $ar->get_row($selectSql);
return $equation;
}
}
function getQuestion($ar, $QID) {
$selectSql = sprintf("SELECT case_tbl.TEXT as VIGNETTE, question_tbl.TEXT, question_tbl.ANSWER_1, question_tbl.ANSWER_2, question_tbl.ANSWER_3, question_tbl.ANSWER_4, question_tbl.ANSWER_5, question_tbl.ANSWER_6, question_tbl.ANSWER_7, question_tbl.ANSWER_8, question_tbl.RATIONALE FROM question_tbl LEFT JOIN case_tbl ON question_tbl.CASE_ID = case_tbl.ID WHERE question_tbl.ID = %s",
$QID);
$question = $ar->get_row($selectSql);
return $question;
}
function makeAnswerArray($questionInfo) {
$answers[0] = array($questionInfo->ANSWER_1, 'correct');
$answers[1] = array($questionInfo->ANSWER_2, 'incorrect');
$answers[2] = array($questionInfo->ANSWER_3, 'incorrect');
if(isset($questionInfo->ANSWER_4) && $questionInfo->ANSWER_4 > ' ') {
$answers[3] = array($questionInfo->ANSWER_4, 'incorrect');
if(isset($questionInfo->ANSWER_5) && $questionInfo->ANSWER_5 > ' ') {
$answers[4] = array($questionInfo->ANSWER_5, 'incorrect');
if(isset($questionInfo->ANSWER_6) && $questionInfo->ANSWER_6 > ' ') {
$answers[5] = array($questionInfo->ANSWER_6, 'incorrect');
if(isset($questionInfo->ANSWER_7) && $questionInfo->ANSWER_7 > ' ') {
$answers[6] = array($questionInfo->ANSWER_7, 'incorrect');
if(isset($questionInfo->ANSWER_8) && $questionInfo->ANSWER_8 > ' ') {
$answers[7] = array($questionInfo->ANSWER_8, 'incorrect');
}
}
}
}
}
return $answers;
}
Is there any reason why the images associated with Rationales are not pulling through when expected?

I would start by checking the values of $equation with var_dump($equation) and also var_dump($question) to look for any anomalies. I suspect you've got incomplete data creeping in that looks like /lcms/images/equations/NULL or something similar which should be obvious enough, when dumped.
If this is the case, look at extending your handling of these vars to be more strict about the expected value.
Truth be told, it's going to be difficult to help if we cannot run the code. But I would start by checking data integrity of the MySQL result. Bit of a SQL join in there too that only you will know the correct format of, which would be my next port of call.

Send two variables to js via php

I have
$userPostsInt = array("22", "45", "56");
I am receiving via ajax an id:
$post_id = $_POST['id'];
Then on front end I click and send an ID and I need to check if:
1. the clicked ID is in the array
2. if the array count is <= 2 if not do something
So I try:
$totSaved = array();
$userPostsInt = array("22", "45", "56");
$count = count($userPostsInt);
if($count<2) {
foreach($userPostsInt as $key=>$post){
if( $post == $post_id ) {
foreach($userPostsInt as $idInt){
array_push($totSaved, $idInt);
}
echo json_encode($count);
}
}
} else {
echo json_encode($count);
}
Then on ajax success I do:
success: function(data) {
var received = true;
if(received) {
if(data < 2) {
do_something
} else {
do_something
}
} else {
do_something else
}
}
How can I send 2 variable on echo json_encode($count); in order to do a double check for "is ID in the array? Is the array less than 2?" or is it there another way I'm missing?

the simple way to do is use in_array() along with array output:
$totSaved = array();
$userPostsInt = array("22", "45", "56");
$count = count($userPostsInt);
if(in_array($post_id,$userPostsInt)){
echo json_encode(array('found'=>'yes','count'=>$count));
}else{
$totSaved[] = $post_id;//add new value for next time checks
echo json_encode(array('found'=>'no','count'=>$count));
}

Get data from database using php,ajax

I have a simple section in which I am displaying data from the database, my database looks like this.
Now I have four buttons looks like this
When a user clicks one of the above buttons it displays this
So now when user eg select construction and next select eg Egypt' in the console and clicks buttonconfirmdisplays [855,599075], user can select multiple countries, this works as expected forconstruction ,power,oil`,
Now I want if user eg clicks All available industries button in those four buttons and next select eg Egypt and click confirm it should display
the sum of egypt total projects in construction, oil, power sector 855+337+406 =1598 and the sum of total budgets in both sectors 1136173
Here is my solution
HTML
<div id="interactive-layers">
<div buttonid="43" class="video-btns">
<span class="label">Construction</span></div>
<div buttonid="44" class="video-btns">
<span class="label">Power</span></div>
<div buttonid="45" class="video-btns">
<span class="label">Oil</span></div>
<div buttonid="103" class="video-btns">
<span class="label">All available industries</span>
</div>
</div>
Here is js ajax
$("#interactive-layers").on("click", ".video-btns", function(){
if( $(e.target).find("span.label").html()=="Confirm" ) {
var selectedCountries = [];
$('.video-btns .selected').each(function () {
selectedCountries.push( $(this).parent().find("span.label").html() ) ;
});
if( selectedCountries.length>0 ) {
if(selectedCountries.indexOf("All available countries")>-1) {
selectedCountries = [];
}
} else {
return;
}
var ajaxurl = "";
if(selectedCountries.length>0) {
ajaxurl = "data.php";
} else {
ajaxurl = "dataall.php";
}
$.ajax({
url: ajaxurl,
type: 'POST',
data: {
countries: selectedCountries.join(","),
sector: selectedSector
},
success: function(result){
console.log(result);
result = JSON.parse(result);
$(".video-btns").each(function () {
var getBtn = $(this).attr('buttonid');
if (getBtn == 106) {
var totalProjects = $("<span class='totalprojects'>"+ result[0] + "</span>");
$(this).append(totalProjects)
}else if(getBtn ==107){
var resultBudget = result[1]
var totalBudgets = $("<span class='totalbudget'>"+ '&#36m' +" " + resultBudget +"</span>");
$(this).append( totalBudgets)
}
});
return;
}
});
}
});
Here is php to get all dataall.php
$selectedSectorByUser = $_POST['sector'];
$conn = mysqli_connect("localhost", "root", "", "love");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = array();
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result))
{
if($row['Sector']==$selectedSectorByUser ) {
$totalProjects+= $row['SumofNoOfProjects'];
$totalBudget+= $row['SumofTotalBudgetValue'];
}
}
echo json_encode([ $totalProjects, $totalBudget ] );
exit();
?>
Here is data.php
<?php
$selectedSectorByUser = $_POST['sector'];
$countries = explode(",", $_POST['countries']);
//var_dump($countries);
$conn = mysqli_connect("localhost", "root", "", "meedadb");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = array();
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result))
{
if($row['Sector']==$selectedSectorByUser && in_array($row['Countries'],$countries ) ) {
// array_push($data, $row);
$totalProjects+= $row['SumofNoOfProjects'];
$totalBudget+= $row['SumofTotalBudgetValue'];
}
}
// array_push($wynik, $row);
echo json_encode([ $totalProjects, $totalBudget ] );
//echo json_encode($data);
exit();
?>
Now when the user clicks All available industries btn and selects a country I get [0,0] on the console.
What do I need to change to get what I want? any help or suggestion will be appreciated,

in you dataAll.php
If you have select All available industries
you shold not check for sector because you need all sector (eventually you should check for countries )
so you should avoid the check for this condition
<?php
$conn = mysqli_connect("localhost", "root", "", "love");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = [];
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result)) {
$totalProjects += $row['SumofNoOfProjects'];
$totalBudget += $row['SumofTotalBudgetValue'];
}
echo json_encode([$totalProjects, $totalBudget]);

You can use the SQL JOIN operator, or in this case an implicit join would be cleanest:
$result = mysqli_query($conn, "SELECT * FROM construction, power, oil_and_gas, industrial WHERE construction.Countries = power.Countries AND power.Countries = oil_and_gas.Countries AND oil_and_gas.Countries = industrial.Countries");
You need the WHERE conditions so it knows how the rows of each different table are related to each other. You can shorten it a bit with aliases for the tables:
$result = mysqli_query($conn, "SELECT * FROM construction as C, power as P, oil_and_gas as G, industrial as I WHERE C.Countries = P.Countries AND P.Countries = G.Countries AND G.Countries = I.Countries");
In this case, however, I think you may want to consider changing the structure of your database. It seems like you repeat columns quite a bit across them. Perhaps these can all be in a single table, with a "type" column that specifies whether it's power, construction, etc. Then you can query just the one table and group by country name to get all your results without the messy joins across 4 tables.

The single table looks OK.
(The rest of this Answer is not complete, but might be useful.)
First, let's design the URL that will request the data.
.../foo.php?industry=...&country=...
But, rather than special casing the "all" in the client, do it in the server. That is, the last button for industry will generate
?industry=all
and the PHP code will not include this in the WHERE clause:
AND industry IN (...)
Similarly for &country=all versus &country=egypt,iran,iraq
Now, let me focus briefly on the PHP:
$wheres = array();
$industry = #$_GET['industry'];
if (! isset($industry)) { ...issue error message or use some default... }
elseif ($industry != 'all') {
$inds = array();
foreach (explode(',', $industry) as $ind) {
// .. should test validity here; left to user ...
$inds[] = "'$ind'";
}
$wheres[] = "industry IN (" . implode(',', $inds) . )";
}
// ... repeat for country ...
$where_clause = '';
if (! empty($wheres)) {
$where_clause = "WHERE " . implode(' AND ', $wheres);
}
// (Note that this is a generic way to build arbitrary WHEREs from the data)
// Build the SQL:
$sql = "SELECT ... FROM ...
$where_clause
ORDER BY ...";
// then execute it via mysqli or pdo (NOT mysql_query)
Now, let's talk about using AJAX. Or not. There were 2 choices:
you could have had the call to PHP be via a GET and have that PHP display a new page. This means that PHP will be constructing the table of results.
you could have used AJAX to request the data. This means that Javascript will be constructing the data of results.
Which choice to pick probably depends on which language you are more comfortable in.

Error-notice on blog-page from Content Aware Sidbars plugin

I'm using a Genesis LifeStyle Pro child theme.
URL: https://www.test.rainerklar.de/blog-fuer-verjuengung-und-gesundheit/
On my Blog-page that is showing all posts with an excerpt I see an Error-notice on top of the header:
Notice: Array to string conversion in /home/jungvita/public_html/test/wp-content/plugins/content-aware-sidebars/lib/wp-content-aware-engine/core.php on line 312
If I use the sidebar-plugin or not for this page this error is visible and needs a fix. The page should have the standard primary sidebar. I tried to work without the plugin for this page, and with the plugin by setting "posts" for the page-type, without anything else for definition.
Here is the code of line 312 and 313:
$data = "({$id}.meta_value IS NULL OR {$id}.meta_value IN ('".implode("','",$data) ."'))";
}
EDIT: With a debug-plugin I got this notice:
NOTICE: wp-content/plugins/content-aware-sidebars/lib/wp-content-aware- engine/core.php:312 - Array to string conversion
require('wp-blog-header.php'), require_once('wp-includes/template-loader.php'), include('/themes/lifestyle-pro/home.php'), genesis, get_header, locate_template, load_template, require_once('/themes/lifestyle-pro/header.php'), do_action('genesis_meta'), WP_Hook->do_action,WP_Hook->apply_filters, blog_page_genesis_meta, is_active_sidebar, wp_get_sidebars_widgets, apply_filters('sidebars_widgets'), WP_Hook->apply_filters, CAS_Sidebar_Manager->replace_sidebar, WPCACore::get_posts, WPCACore::get_conditions, implode
Maybe it helps?!
EDIT2: Here is the complete code of the section
// Return cache if present
of "core.php" (plugin):
// Return cache if present
if(isset(self::$condition_cache[$post_type])) {
return self::$condition_cache[$post_type];
}
$excluded = array();
$where = array();
$join = array();
$cache = array(
$post_type
);
$modules = self::$type_manager->get($post_type)->get_all();
foreach (self::$type_manager->get_all() as $key => $type) {
if($key == $post_type) {
continue;
}
if($type->get_all() === $modules) {
$cache[] = $key;
}
}
foreach ($modules as $module) {
$id = $module->get_id();
if(apply_filters("wpca/module/{$id}/in-context", $module->in_context())) {
$join[$id] = apply_filters("wpca/module/{$id}/db-join", $module->db_join());
$data = $module->get_context_data();
if(is_array($data)) {
$data = "({$id}.meta_value IS NULL OR {$id}.meta_value IN ('".implode("','",$data) ."'))";
}
$where[$id] = apply_filters("wpca/module/{$id}/db-where", $data);
} else {
$excluded[] = $module;
}
}
There are no line-numbers, so look for
if(is_array($data)) {
$data = "({$id}.meta_value IS NULL OR {$id}.meta_value IN ('".implode("','",$data) ."'))";
}
These lines are 311 to 313.

In this thread I found a solution:
Mit einem # kannst du normalerweise die Fehlermeldungen ausschalten
I did so putting the # just before 'implode':
$data = "({$id}.meta_value IS NULL OR {$id}.meta_value IN ('".#implode("','",$data) ."'))";
}
Now the notice is gone.

How can I pass multiple data from PHP to jQuery/AJAX?

I have a main select list of courses which drives various things on a page. When a course is selected another select list will be repopulated with the start date of that course up to 6 months in advance. Also, I have a table on the page with the students name and phone number, when a course is selected, the table will be repopulated with all the students enrolled onto that course. My problem is I will be getting various different things from PHP via JSON i.e. the students and the starting date. How can I therefore pass more than one thing to jQuery? What if the course select list affected not just 2 things but 3, 5 or even 10? How would we handle that with PHP and jQuery?
foreach($m as $meta)
{
$metaCourse = $this->getCourseInfo($meta['parent_course']);
//populate the select list with the name of each course
$metaSelectList .= '<option id="select'.$count.'" value="'.$metaCourse['id'].'">'.$metaCourse['fullname'].'</option>';
$count++;
//get only the first course's dates
if($count3 == 1)
{
$startDate = intval( $course->getStartDate(50) );
$endDate = strtotime('+6 month', $startDate);
//populates the select list with the starting date of the course up to the next six months
for($date = $startDate; $date <= $endDate ; $date = strtotime('+1 day', $date))
{
$dateSelectList .= '<option id="select'.$count2.'" value="'.$date.'">'.date('D d F Y', $date).'</option>';
$count2++;
}
$count3++;
$students = $s->getStudents($metaCourse['id']);
$content = $this->createStudentTable($students);
}
}
This is my handler for the AJAX...FOR NOW (I haven't implemented the students table yet as I'm still trying to figure out how to pass multiple pieces of data to jQuery). Basically each time a course is selected, PHP creates a new select list with the appropriate dates and then passes it to jQuery. I'm not sure if I should do this in JavaScript or in PHP.
if (isset($_GET['pid']) && (isset($_GET['ajax']) && $_GET['ajax'] == "true"))//this is for lesson select list
{
$pid = intval( $_GET['pid'] );
$c = new CourseCreator();
$startDate = intval( $c->getStartDate($pid) );
$endDate = strtotime('+6 month', $startDate);
$dateSelectList = '<select name="dateSelect" id="dateSelect">';
//populates the select list with the starting date of the course up to the next six months
for($date = $startDate; $date <= $endDate ; $date = strtotime('+1 day', $date))
{
$dateSelectList .= '<option id="select'.$count2.'" value="'.$date.'">'.date('D d F Y', $date).'</option>';
$count2++;
}
$dateSelectList .= '</select>';
echo json_encode($dateSelectList);
exit;
}
My jQuery handler:
$('#metaSelect').live('change', function()
{
$.getJSON('?ajax=true&pid='+$('#metaSelect').val(), function(data)
{
alert(data);
$('#dateSelectDiv').html(data);
});
});

You can easily pass ALOT of data from PHP to your HTML via JSON (which you seem to of put in basic already)
However to expand on what you have - heres a quick example
<?php
$arrayOfStuff = array("theKey" => "theEntry", 123 => "Bob Dow", 56 => "Charlie Bronw", 20 => 'Monkey!', "theMyID" => $_POST['myID']);
echo json_encode($arrayOfStuff);
?>
On your HTML side.
<script>
$.post("/theurl/", {type: "fetchArrayOfStuff", myID: 24}, function(success) {
//your success object will look like this
/*
{
theKey: 'theEntry',
123: 'Bob Dow',
56: 'Charlie Bronw',
20: 'Monkey!',
theMyID: 24
}
so you can easily access any of the data.
alert(success.theKey);
alert(success[123]);
alert(success[56]);
alert(success[20]);
alert(success.theMyID);
*/
//we can iterate through the success JSON!
for(var x in success) {
alert(x + "::" + success[x]);
};
}, "json");
</script>
In the long run - your MUCH better of letting the backend do the backend stuff, and the front end doing the front-end stuff.
What this means is, try keep the HTML generation as far away as possible from the back-end, so instead of constantly passing
for($date = $startDate; $date <= $endDate ; $date = strtotime('+1 day', $date))
{
$dateSelectList .= '<option id="select'.$count2.'" value="'.$date.'">'.date('D d F Y', $date).'</option>';
$count2++;
}
You could perhaps
$date = $startDate;
$myJson = array()
while($date <= $endDate) {
$myJson[] = array("date" => $date, "formattedDate" => date('D d F Y', $date));
$date += 86400; //86400 is the value of 1 day.
}
echo json_encode($myJson);
And you can just do a simple iteration on your HTML code.
<script>
$.get("/", {ajax: true, pid: $('#metaSelect').val()}, function(success) {
//we can iterate through the success JSON!
var _dom = $('#dateSelectDiv').html(''); //just to clear it out.
for(var x in success) {
_dom.append("<option value='"+success[x].date+"'>"+success[x].formattedDate+"</option>");
};
}, "json");
</script>
So as you can see - you can pass alot of data using JSON
Maybe look at some of the documentation to - http://api.jquery.com/jQuery.get/ , http://api.jquery.com/jQuery.post/ - might give you more ideas.
Best of luck to you