Develop Reference

Terminate while loop from a inner if condition in for loop [duplicate]

Closed. This question is opinion-based. It is not currently accepting answers.
Want to improve this question? Update the question so it can be answered with facts and citations by editing this post.
Closed 6 months ago.
Improve this question
What's the best way to break from nested loops in Javascript?
//Write the links to the page.
for (var x = 0; x < Args.length; x++)
{
for (var Heading in Navigation.Headings)
{
for (var Item in Navigation.Headings[Heading])
{
if (Args[x] == Navigation.Headings[Heading][Item].Name)
{
document.write("<a href=\""
+ Navigation.Headings[Heading][Item].URL + "\">"
+ Navigation.Headings[Heading][Item].Name + "</a> : ");
break; // <---HERE, I need to break out of two loops.
}
}
}
}

Just like Perl,
loop1:
for (var i in set1) {
loop2:
for (var j in set2) {
loop3:
for (var k in set3) {
break loop2; // breaks out of loop3 and loop2
}
}
}
as defined in EMCA-262 section 12.12. [MDN Docs]
Unlike C, these labels can only be used for continue and break, as Javascript does not have goto.

Wrap that up in a function and then just return.

I'm a little late to the party but the following is a language-agnostic approach which doesn't use GOTO/labels or function wrapping:
for (var x = Set1.length; x > 0; x--)
{
for (var y = Set2.length; y > 0; y--)
{
for (var z = Set3.length; z > 0; z--)
{
z = y = -1; // terminates second loop
// z = y = x = -1; // terminate first loop
}
}
}
On the upside it flows naturally which should please the non-GOTO crowd. On the downside, the inner loop needs to complete the current iteration before terminating so it might not be applicable in some scenarios.

I realize this is a really old topic, but since my standard approach is not here yet, I thought I post it for the future googlers.
var a, b, abort = false;
for (a = 0; a < 10 && !abort; a++) {
for (b = 0; b < 10 && !abort; b++) {
if (condition) {
doSomeThing();
abort = true;
}
}
}

Quite simple:
var a = [1, 2, 3];
var b = [4, 5, 6];
var breakCheck1 = false;
for (var i in a) {
for (var j in b) {
breakCheck1 = true;
break;
}
if (breakCheck1) break;
}

Here are five ways to break out of nested loops in JavaScript:
1) Set parent(s) loop to the end
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
if (j === 2)
{
i = 5;
break;
}
}
}
2) Use label
exit_loops:
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
if (j === 2)
break exit_loops;
}
}
3) Use variable
var exit_loops = false;
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
if (j === 2)
{
exit_loops = true;
break;
}
}
if (exit_loops)
break;
}
4) Use self executing function
(function()
{
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
if (j === 2)
return;
}
}
})();
5) Use regular function
function nested_loops()
{
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
if (j === 2)
return;
}
}
}
nested_loops();

var str = "";
for (var x = 0; x < 3; x++) {
(function() { // here's an anonymous function
for (var y = 0; y < 3; y++) {
for (var z = 0; z < 3; z++) {
// you have access to 'x' because of closures
str += "x=" + x + " y=" + y + " z=" + z + "<br />";
if (x == z && z == 2) {
return;
}
}
}
})(); // here, you execute your anonymous function
}
How's that? :)

How about using no breaks at all, no abort flags, and no extra condition checks. This version just blasts the loop variables (makes them Number.MAX_VALUE) when the condition is met and forces all the loops to terminate elegantly.
// No breaks needed
for (var i = 0; i < 10; i++) {
for (var j = 0; j < 10; j++) {
if (condition) {
console.log("condition met");
i = j = Number.MAX_VALUE; // Blast the loop variables
}
}
}
There was a similar-ish answer for decrementing-type nested loops, but this works for incrementing-type nested loops without needing to consider each loop's termination value for simple loops.
Another example:
// No breaks needed
for (var i = 0; i < 89; i++) {
for (var j = 0; j < 1002; j++) {
for (var k = 0; k < 16; k++) {
for (var l = 0; l < 2382; l++) {
if (condition) {
console.log("condition met");
i = j = k = l = Number.MAX_VALUE; // Blast the loop variables
}
}
}
}
}

If you use Coffeescript, there is a convenient "do" keyword that makes it easier to define and immediately execute an anonymous function:
do ->
for a in first_loop
for b in second_loop
if condition(...)
return
...so you can simply use "return" to get out of the loops.

I thought I'd show a functional-programming approach. You can break out of nested Array.prototype.some() and/or Array.prototype.every() functions, as in my solutions. An added benefit of this approach is that Object.keys() enumerates only an object's own enumerable properties, whereas "a for-in loop enumerates properties in the prototype chain as well".
Close to the OP's solution:
Args.forEach(function (arg) {
// This guard is not necessary,
// since writing an empty string to document would not change it.
if (!getAnchorTag(arg))
return;
document.write(getAnchorTag(arg));
});
function getAnchorTag (name) {
var res = '';
Object.keys(Navigation.Headings).some(function (Heading) {
return Object.keys(Navigation.Headings[Heading]).some(function (Item) {
if (name == Navigation.Headings[Heading][Item].Name) {
res = ("<a href=\""
+ Navigation.Headings[Heading][Item].URL + "\">"
+ Navigation.Headings[Heading][Item].Name + "</a> : ");
return true;
}
});
});
return res;
}
Solution that reduces iterating over the Headings/Items:
var remainingArgs = Args.slice(0);
Object.keys(Navigation.Headings).some(function (Heading) {
return Object.keys(Navigation.Headings[Heading]).some(function (Item) {
var i = remainingArgs.indexOf(Navigation.Headings[Heading][Item].Name);
if (i === -1)
return;
document.write("<a href=\""
+ Navigation.Headings[Heading][Item].URL + "\">"
+ Navigation.Headings[Heading][Item].Name + "</a> : ");
remainingArgs.splice(i, 1);
if (remainingArgs.length === 0)
return true;
}
});
});

How about pushing loops to their end limits
for(var a=0; a<data_a.length; a++){
for(var b=0; b<data_b.length; b++){
for(var c=0; c<data_c.length; c++){
for(var d=0; d<data_d.length; d++){
a = data_a.length;
b = data_b.length;
c = data_b.length;
d = data_d.length;
}
}
}
}

Already mentioned previously by swilliams, but with an example below (Javascript):
// Function wrapping inner for loop
function CriteriaMatch(record, criteria) {
for (var k in criteria) {
if (!(k in record))
return false;
if (record[k] != criteria[k])
return false;
}
return true;
}
// Outer for loop implementing continue if inner for loop returns false
var result = [];
for (var i = 0; i < _table.length; i++) {
var r = _table[i];
if (!CriteriaMatch(r[i], criteria))
continue;
result.add(r);
}

There are many excellent solutions above.
IMO, if your break conditions are exceptions,
you can use try-catch:
try{
for (var i in set1) {
for (var j in set2) {
for (var k in set3) {
throw error;
}
}
}
}catch (error) {
}

Hmmm hi to the 10 years old party ?
Why not put some condition in your for ?
var condition = true
for (var i = 0 ; i < Args.length && condition ; i++) {
for (var j = 0 ; j < Args[i].length && condition ; j++) {
if (Args[i].obj[j] == "[condition]") {
condition = false
}
}
}
Like this you stop when you want
In my case, using Typescript, we can use some() which go through the array and stop when condition is met
So my code become like this :
Args.some((listObj) => {
return listObj.some((obj) => {
return !(obj == "[condition]")
})
})
Like this, the loop stopped right after the condition is met
Reminder : This code run in TypeScript

Assign the values which are in comparison condition
function test(){
for(var i=0;i<10;i++)
{
for(var j=0;j<10;j++)
{
if(somecondition)
{
//code to Break out of both loops here
i=10;
j=10;
}
}
}
//Continue from here
}

An example with for .. of, close to the example further up which checks for the abort condition:
test()
function test() {
var arr = [1, 2, 3,]
var abort = false;
for (var elem of arr) {
console.log(1, elem)
for (var elem2 of arr) {
if (elem2 == 2) abort = true;
if (!abort) {
console.log(2, elem2)
}
}
}
}
Condition 1 - outer loop - will always run
The top voted and accepted answer also works for this kind of for loop.
Result: the inner loop will run once as expected
1 1
2 1
1 2
1 3

XXX.Validation = function() {
var ok = false;
loop:
do {
for (...) {
while (...) {
if (...) {
break loop; // Exist the outermost do-while loop
}
if (...) {
continue; // skips current iteration in the while loop
}
}
}
if (...) {
break loop;
}
if (...) {
break loop;
}
if (...) {
break loop;
}
if (...) {
break loop;
}
ok = true;
break;
} while(true);
CleanupAndCallbackBeforeReturning(ok);
return ok;
};

the best way is -
1) Sort the both array which are used in first and second loop.
2) if item matched then break the inner loop and hold the index value.
3) when start next iteration start inner loop with hold index value.

Remove Duplicates from Sorted Array JS

I'm trying to understand why my solution to this problem is only partially working.
Problem:
Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
My Solution:
var removeDuplicates = function(nums) {
if (nums.length === 0) return 0;
for (let i = 1; i <= nums.length; i++){
if(nums[i] === nums[i-1]){
nums.splice(nums[i], 1);
}
}
return nums.length;
};
This is the outcome I'm getting on leetcode but I don't understand why my solution stops working and the '3s' are not removed?
Output screenshot:

When you splice an array while iterating over it, the whole array will change in-place. For example, let's say that indexes 0 and 1 are duplicates (i is 1). Then, if you remove index 1 from the array, what used to be at index 2 will now be at index 1, and what used to be at index 3 will now be at index 2, etc.
So, you need to subtract 1 from i when an element is removed, otherwise the next element will be skipped.
You also have an off-by-one-error - iterate i from 1 to i < nums.length so you don't go past the end of the array.
You also need to pass the index to remove to splice, not the value to remove.
var removeDuplicates = function(nums) {
for (let i = 1; i < nums.length; i++){
if(nums[i] === nums[i-1]){
nums.splice(i, 1);
i--;
}
}
return nums.length;
};
console.log(removeDuplicates([0, 0, 0]));

Simple version. Using functions already created
let array = new Set(nums);
let values = array.values();
return Array.from(values);

This'd also pass just fine on constant memory:
const removeDuplicates = function (nums) {
let count = 0;
nums.forEach(function (num) {
if (num !== nums[count]) {
nums[++count] = num;
}
});
return nums.length && count + 1;
};

function removeDuplicates(nums) {
let i = 0;
while(i < nums.length - 1) {
i += 1 - ((nums[i] === nums[i+1]) && nums.splice(i, 1).length)
}
return nums.length;
}

C# simple solution:
public int RemoveDuplicates(int[] nums) {
if (nums.Length == 0)
return 0;
var i = 0;
var start = 0;
var end = 0;
while (end < nums.Length)
{
if (nums[start] != nums[end])
{
nums[++i] = nums[end];
start = end;
}
end++;
}
return i + 1;
}

Write a sum() function that takes an array of numbers

Can someone please explain to me what I am doing wrong here...
This code is from eloquent javascript and it works fine
function sum(array) {
let total = 0;
for (let value of array) {
total += value;
}
return total;
}
And this is what I wrote for the exercise but returns NaN..
function sum(numArray) {
let add = 0;
for (let a = 0; a <= numArray.length; a++) {
let addIndex = numArray[a];
add += addIndex;
}
return add;
}

Your for loop goes out of array indexes. You have to use:
a < numArray.length
Instead of:
a <= numArray.length

You simply add undefined to add, because you run the index count to long.
for (let a = 0; a <= numArray.length; a++) {
// ^ wrong, takes last index + 1
function sum(numArray) {
let add = 0;
for (let a = 0; a < numArray.length; a++) {
let Addindex = numArray[a];
add += Addindex;
}
return add;
}
console.log(sum([1, 2, 3, 4]));

The issue is because of this a <= numArray.length. Change it to a < numArray.length. This case a[5] that is the 6th element or the element at 5th index is undefined as the array starts from 0 index. So it will add an undefined with previously added number and hence it will be NaN
function sum(numArray) {
let add = 0;
for (let a = 0; a < numArray.length; a++) {
let Addindex = numArray[a];
add += Addindex;
}
return add;
}
console.log(sum([1, 2, 3, 4, 5]))

You're getting an out-of-bounds error. In your for loop, you can change it to:
for (let a = 0; a < numArray.length; a++) {
OR
for (let a = 0; a <= numArray.length - 1; a++) {
The latter works too, but is harder to read.

You can also write a function that has two parameters, an array and a callback function that adds the values of the array like
function forEach(array, arrayAdder){
for (var i = 0; i < array.length; i ++)
arrayAdder(array[i]) ;
}
We can now initialize both the array and the sum like
var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], sum = 0;
After that we pass it into the function like this
forEach(array, function(number){
sum += number ;
});
Then print the answer
console.log(sum);

Looping through array using splice method infinite loop javascript

When i loop through the array using the splice method, the page just freezes. It looks like i caused an infinite loop. lib.randomInt() works, so that is not the problem.
function() {
return function(string) {
var arr = string.split("")
arr.sort();
for(var i = 0; arr.length;i++){
arr.splice((i+1),0,lib.randomInt(9));
}
var pseudocryptarr = arr.join("");
}
})()("example");
This is from a different file that is placed above the main file in html
var lib = {
factorial: function(num){
function _factorial(num){
if(num === 1){
return 1;
} else {
return num*_factorial(num-1);
}
}
console.log(num+"! = " + _factorial(num));
},
randomInt: function(int,offset){
if(offset == undefined || null || NaN){
offset = 0;
}
return Math.floor(Math.random()*int)+offset;
},
display: function(m, fn){
fn(m);
}
};

You've got to loop in reverse when modifying the array itself to avoid corrupting the loop like this...
for (var i=arr.length-1; i>=0; i--){}

I guess that you wanted to insert a random value after every array element, so that the string "example" would become something like "e5x9a2m4p7l1e3"
There are two issues:
Your for loop has no end condition that will become false. You need to state i < arr.length instead of just arr.length which is always truthy for non-empty arrays.
You add array elements in every iteration, but then also visit them in the next iteration, and from there on you will only be visiting the new inserted values and never get to the next original element that keeps being 1 index away from i. You need to increment i once more. For that you can use ++i instead if i+1 as the splice argument.
So your loop should be:
for(var i = 0; i < arr.length; i++) {
arr.splice(++i,0,lib.randomInt(9));
}
const lib = { randomInt: n => Math.floor(Math.random()*n) };
(function() {
return function(string) {
var arr = string.split("")
arr.sort();
for(var i = 0; i < arr.length; i++) {
arr.splice(++i,0,lib.randomInt(9));
}
var pseudocryptarr = arr.join("");
console.log(pseudocryptarr);
}
})()("example");
Or to save an addition:
for(var i = 1; i <= arr.length; i+=2) {
arr.splice(i,0,lib.randomInt(9));
}
const lib = { randomInt: n => Math.floor(Math.random()*n) };
(function() {
return function(string) {
var arr = string.split("")
arr.sort();
for(var i = 1; i <= arr.length; i+=2) {
arr.splice(i,0,lib.randomInt(9));
}
var pseudocryptarr = arr.join("");
console.log(pseudocryptarr);
}
})()("example");

I fixed it. I wanted after each character for there to be a number. Using the pre-looped array length and doubling it while iterating twice, means that the splice adds the number after the new number element and then the character.
Edit: My typo was the problem. I didnt even have to use len, just iterate by 2.
for(var i = 0;i < arr.length;i+=2){
arr.splice((i+1),0,lib.randomInt(9));
}
(function() {
return function(string) {
var arr = string.split("")
arr.sort();
var len = arr.length
for(var i = 0;i < len*2;i+=2){
arr.splice((i+1),0,lib.randomInt(9));
}
var pseudocryptarr = arr.join("");
console.log(pseudocryptarr);
}
})()("example");
Edit: user4723924 method is better:
(function() {
return function(string) {
var arr = string.split("")
arr.sort();
for(var i = arr.length;i >= 0;i--){
arr.splice((i+1),0,lib.randomInt(9));
}
var pseudocryptarr = arr.join("");
console.log(pseudocryptarr);
}
})()("example");

Code to display all prime numbers not working in JavaScript?

I'm trying to display all the prime numbers up to 10 and it isn't working. Can you see what I did wrong?
function findPrimeNumbers() {
var count = 10,
primes = [];
for (var i = 0; i <= count; i++) {
if (count / i === 1 || count) primes.push(i);
else continue;
count -= 1;
}
for (var i = 0, len = primes.length; i < len; i++) return primes[i];
}
console.log(findPrimeNumbers());
It only returns 0 in the console.

Here's about the simplest way to generate primes. Note that there are more efficient methods, but they are harder to understand.
function findPrimeNumbers (count) {
var primes = [];
for (var J = 2; J <= count; J++) {
var possPrime = true;
for (var K = 2, factorLim = Math.sqrt (J); K <= factorLim; K++) {
if (J % K == 0) {
possPrime = false;
break;
}
}
if (possPrime)
primes.push (J);
}
return primes;
}
console.log (findPrimeNumbers (10) );
This yields all the primes <= 10:
[2, 3, 5, 7]
See Wikipedia for an explanation.

for (var i = 0, len = primes.length; i < len; i++) return primes[i];
Here you are return just the first element of the array. I think you meant something like this
var retstr = "";
for (var i = 0, len = primes.length; i < len; i++)
{
//To improve str format
if(i == len-1)
retstr += primes[i];
else
retstr += primes[i] + ", ";
}
return retstr;
Hope this helps.

if (count / i === 1 || count / i === count)

You don't say how it's not working, but the first thing that comes to my attention is that you're incrementing i, while at the same time decrementing count, so i will never get all the way to 10.
Also, count / i will cause a divide-by-zero error on the first iteration as it's written (unless Javascript magically handles that case in some way I'm not familiar with).
Then you "loop" through your return values--but you can only return once from a function, so of course you're only going to return the first value.

And you are returning from the function in the last for loop. Remove that for loop, just return the array.

function PrimeCheck(n){ //function to check prime number
for(i=2;i<n;i++){
if(n%i==0){
return false
}
}
return true;
}
function print(x){ //function to print prime numbers
var primeArray=[];
for(j=2;j<x;j++){
if(PrimeCheck(j)==true){
primeArray.push(j);
}
}
console.log(primeArray);
}
print(10); //[2,3,5,7]