How do I toggle the visibility of an element using .hide(), .show(), or .toggle()?
How do I test if an element is visible or hidden?
Since the question refers to a single element, this code might be more suitable:
// Checks CSS content for display:[none|block], ignores visibility:[true|false]
$(element).is(":visible");
// The same works with hidden
$(element).is(":hidden");
It is the same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ.
We use jQuery's is() to check the selected element with another element, selector or any jQuery object. This method traverses along the DOM elements to find a match, which satisfies the passed parameter. It will return true if there is a match, otherwise return false.
You can use the hidden selector:
// Matches all elements that are hidden
$('element:hidden')
And the visible selector:
// Matches all elements that are visible
$('element:visible')
if ( $(element).css('display') == 'none' || $(element).css("visibility") == "hidden"){
// 'element' is hidden
}
The above method does not consider the visibility of the parent. To consider the parent as well, you should use .is(":hidden") or .is(":visible").
For example,
<div id="div1" style="display:none">
<div id="div2" style="display:block">Div2</div>
</div>
The above method will consider div2 visible while :visible not. But the above might be useful in many cases, especially when you need to find if there is any error divs visible in the hidden parent because in such conditions :visible will not work.
None of these answers address what I understand to be the question, which is what I was searching for, "How do I handle items that have visibility: hidden?". Neither :visible nor :hidden will handle this, as they are both looking for display per the documentation. As far as I could determine, there is no selector to handle CSS visibility. Here is how I resolved it (standard jQuery selectors, there may be a more condensed syntax):
$(".item").each(function() {
if ($(this).css("visibility") == "hidden") {
// handle non visible state
} else {
// handle visible state
}
});
From How do I determine the state of a toggled element?
You can determine whether an element is collapsed or not by using the :visible and :hidden selectors.
var isVisible = $('#myDiv').is(':visible');
var isHidden = $('#myDiv').is(':hidden');
If you're simply acting on an element based on its visibility, you can just include :visible or :hidden in the selector expression. For example:
$('#myDiv:visible').animate({left: '+=200px'}, 'slow');
Often when checking if something is visible or not, you are going to go right ahead immediately and do something else with it. jQuery chaining makes this easy.
So if you have a selector and you want to perform some action on it only if is visible or hidden, you can use filter(":visible") or filter(":hidden") followed by chaining it with the action you want to take.
So instead of an if statement, like this:
if ($('#btnUpdate').is(":visible"))
{
$('#btnUpdate').animate({ width: "toggle" }); // Hide button
}
Or more efficient, but even uglier:
var button = $('#btnUpdate');
if (button.is(":visible"))
{
button.animate({ width: "toggle" }); // Hide button
}
You can do it all in one line:
$('#btnUpdate').filter(":visible").animate({ width: "toggle" });
The :visible selector according to the jQuery documentation:
They have a CSS display value of none.
They are form elements with type="hidden".
Their width and height are explicitly set to 0.
An ancestor element is hidden, so the element is not shown on the page.
Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout.
This is useful in some cases and useless in others, because if you want to check if the element is visible (display != none), ignoring the parents visibility, you will find that doing .css("display") == 'none' is not only faster, but will also return the visibility check correctly.
If you want to check visibility instead of display, you should use: .css("visibility") == "hidden".
Also take into consideration the additional jQuery notes:
Because :visible is a jQuery extension and not part of the CSS specification, queries using :visible cannot take advantage of the performance boost provided by the native DOM querySelectorAll() method. To achieve the best performance when using :visible to select elements, first select the elements using a pure CSS selector, then use .filter(":visible").
Also, if you are concerned about performance, you should check Now you see me… show/hide performance (2010-05-04). And use other methods to show and hide elements.
How element visibility and jQuery works;
An element could be hidden with display:none, visibility:hidden or opacity:0. The difference between those methods:
display:none hides the element, and it does not take up any space;
visibility:hidden hides the element, but it still takes up space in the layout;
opacity:0 hides the element as "visibility:hidden", and it still takes up space in the layout; the only difference is that opacity lets one to make an element partly transparent;
if ($('.target').is(':hidden')) {
$('.target').show();
} else {
$('.target').hide();
}
if ($('.target').is(':visible')) {
$('.target').hide();
} else {
$('.target').show();
}
if ($('.target-visibility').css('visibility') == 'hidden') {
$('.target-visibility').css({
visibility: "visible",
display: ""
});
} else {
$('.target-visibility').css({
visibility: "hidden",
display: ""
});
}
if ($('.target-visibility').css('opacity') == "0") {
$('.target-visibility').css({
opacity: "1",
display: ""
});
} else {
$('.target-visibility').css({
opacity: "0",
display: ""
});
}
Useful jQuery toggle methods:
$('.click').click(function() {
$('.target').toggle();
});
$('.click').click(function() {
$('.target').slideToggle();
});
$('.click').click(function() {
$('.target').fadeToggle();
});
This works for me, and I am using show() and hide() to make my div hidden/visible:
if( $(this).css('display') == 'none' ){
/* your code goes here */
} else {
/* alternate logic */
}
You can also do this using plain JavaScript:
function isRendered(domObj) {
if ((domObj.nodeType != 1) || (domObj == document.body)) {
return true;
}
if (domObj.currentStyle && domObj.currentStyle["display"] != "none" && domObj.currentStyle["visibility"] != "hidden") {
return isRendered(domObj.parentNode);
} else if (window.getComputedStyle) {
var cs = document.defaultView.getComputedStyle(domObj, null);
if (cs.getPropertyValue("display") != "none" && cs.getPropertyValue("visibility") != "hidden") {
return isRendered(domObj.parentNode);
}
}
return false;
}
Notes:
Works everywhere
Works for nested elements
Works for CSS and inline styles
Doesn't require a framework
I would use CSS class .hide { display: none!important; }.
For hiding/showing, I call .addClass("hide")/.removeClass("hide"). For checking visibility, I use .hasClass("hide").
It's a simple and clear way to check/hide/show elements, if you don't plan to use .toggle() or .animate() methods.
Demo Link
$('#clickme').click(function() {
$('#book').toggle('slow', function() {
// Animation complete.
alert($('#book').is(":visible")); //<--- TRUE if Visible False if Hidden
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="clickme">
Click here
</div>
<img id="book" src="https://upload.wikimedia.org/wikipedia/commons/8/87/Google_Chrome_icon_%282011%29.png" alt="" width="300"/>
Source (from my blog):
Blogger Plug n Play - jQuery Tools and Widgets: How to See if Element is hidden or Visible Using jQuery
ebdiv should be set to style="display:none;". It works for both show and hide:
$(document).ready(function(){
$("#eb").click(function(){
$("#ebdiv").toggle();
});
});
One can simply use the hidden or visible attribute, like:
$('element:hidden')
$('element:visible')
Or you can simplify the same with is as follows.
$(element).is(":visible")
Another answer you should put into consideration is if you are hiding an element, you should use jQuery, but instead of actually hiding it, you remove the whole element, but you copy its HTML content and the tag itself into a jQuery variable, and then all you need to do is test if there is such a tag on the screen, using the normal if (!$('#thetagname').length).
When testing an element against :hidden selector in jQuery it should be considered that an absolute positioned element may be recognized as hidden although their child elements are visible.
This seems somewhat counter-intuitive in the first place – though having a closer look at the jQuery documentation gives the relevant information:
Elements can be considered hidden for several reasons: [...] Their width and height are explicitly set to 0. [...]
So this actually makes sense in regards to the box-model and the computed style for the element. Even if width and height are not set explicitly to 0 they may be set implicitly.
Have a look at the following example:
console.log($('.foo').is(':hidden')); // true
console.log($('.bar').is(':hidden')); // false
.foo {
position: absolute;
left: 10px;
top: 10px;
background: #ff0000;
}
.bar {
position: absolute;
left: 10px;
top: 10px;
width: 20px;
height: 20px;
background: #0000ff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="foo">
<div class="bar"></div>
</div>
Update for jQuery 3.x:
With jQuery 3 the described behavior will change! Elements will be considered visible if they have any layout boxes, including those of zero width and/or height.
JSFiddle with jQuery 3.0.0-alpha1:
http://jsfiddle.net/pM2q3/7/
The same JavaScript code will then have this output:
console.log($('.foo').is(':hidden')); // false
console.log($('.bar').is(':hidden')); // false
expect($("#message_div").css("display")).toBe("none");
$(document).ready(function() {
if ($("#checkme:hidden").length) {
console.log('Hidden');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="checkme" class="product" style="display:none">
<span class="itemlist"><!-- Shows Results for Fish --></span> Category:Fish
<br>Product: Salmon Atlantic
<br>Specie: Salmo salar
<br>Form: Steaks
</div>
To check if it is not visible I use !:
if ( !$('#book').is(':visible')) {
alert('#book is not visible')
}
Or the following is also the sam, saving the jQuery selector in a variable to have better performance when you need it multiple times:
var $book = $('#book')
if(!$book.is(':visible')) {
alert('#book is not visible')
}
Use class toggling, not style editing . . .
Using classes designated for "hiding" elements is easy and also one of the most efficient methods. Toggling a class 'hidden' with a Display style of 'none' will perform faster than editing that style directly. I explained some of this pretty thoroughly in Stack Overflow question Turning two elements visible/hidden in the same div.
JavaScript Best Practices and Optimization
Here is a truly enlightening video of a Google Tech Talk by Google front-end engineer Nicholas Zakas:
Speed Up Your Javascript (YouTube)
After all, none of examples suits me, so I wrote my own.
Tests (no support of Internet Explorer filter:alpha):
a) Check if the document is not hidden
b) Check if an element has zero width / height / opacity or display:none / visibility:hidden in inline styles
c) Check if the center (also because it is faster than testing every pixel / corner) of element is not hidden by other element (and all ancestors, example: overflow:hidden / scroll / one element over another) or screen edges
d) Check if an element has zero width / height / opacity or display:none / visibility:hidden in computed styles (among all ancestors)
Tested on
Android 4.4 (Native browser/Chrome/Firefox), Firefox (Windows/Mac), Chrome (Windows/Mac), Opera (Windows Presto/Mac WebKit), Internet Explorer (Internet Explorer 5-11 document modes + Internet Explorer 8 on a virtual machine), and Safari (Windows/Mac/iOS).
var is_visible = (function () {
var x = window.pageXOffset ? window.pageXOffset + window.innerWidth - 1 : 0,
y = window.pageYOffset ? window.pageYOffset + window.innerHeight - 1 : 0,
relative = !!((!x && !y) || !document.elementFromPoint(x, y));
function inside(child, parent) {
while(child){
if (child === parent) return true;
child = child.parentNode;
}
return false;
};
return function (elem) {
if (
document.hidden ||
elem.offsetWidth==0 ||
elem.offsetHeight==0 ||
elem.style.visibility=='hidden' ||
elem.style.display=='none' ||
elem.style.opacity===0
) return false;
var rect = elem.getBoundingClientRect();
if (relative) {
if (!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2, rect.top + elem.offsetHeight/2),elem)) return false;
} else if (
!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2 + window.pageXOffset, rect.top + elem.offsetHeight/2 + window.pageYOffset), elem) ||
(
rect.top + elem.offsetHeight/2 < 0 ||
rect.left + elem.offsetWidth/2 < 0 ||
rect.bottom - elem.offsetHeight/2 > (window.innerHeight || document.documentElement.clientHeight) ||
rect.right - elem.offsetWidth/2 > (window.innerWidth || document.documentElement.clientWidth)
)
) return false;
if (window.getComputedStyle || elem.currentStyle) {
var el = elem,
comp = null;
while (el) {
if (el === document) {break;} else if(!el.parentNode) return false;
comp = window.getComputedStyle ? window.getComputedStyle(el, null) : el.currentStyle;
if (comp && (comp.visibility=='hidden' || comp.display == 'none' || (typeof comp.opacity !=='undefined' && comp.opacity != 1))) return false;
el = el.parentNode;
}
}
return true;
}
})();
How to use:
is_visible(elem) // boolean
Example of using the visible check for adblocker is activated:
$(document).ready(function(){
if(!$("#ablockercheck").is(":visible"))
$("#ablockermsg").text("Please disable adblocker.").show();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="ad-placement" id="ablockercheck"></div>
<div id="ablockermsg" style="display: none"></div>
"ablockercheck" is a ID which adblocker blocks. So checking it if it is visible you are able to detect if adblocker is turned On.
$(document).ready(function() {
var visible = $('#tElement').is(':visible');
if(visible) {
alert("visible");
// Code
}
else
{
alert("hidden");
}
});
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<input type="text" id="tElement" style="display:block;">Firstname</input>
You need to check both... Display as well as visibility:
if ($(this).css("display") == "none" || $(this).css("visibility") == "hidden") {
// The element is not visible
} else {
// The element is visible
}
If we check for $(this).is(":visible"), jQuery checks for both the things automatically.
Simply check visibility by checking for a boolean value, like:
if (this.hidden === false) {
// Your code
}
I used this code for each function. Otherwise you can use is(':visible') for checking the visibility of an element.
Because Elements with visibility: hidden or opacity: 0 are considered visible, since they still consume space in the layout (as described for jQuery :visible Selector) - we can check if element is really visible in this way:
function isElementReallyHidden (el) {
return $(el).is(":hidden") || $(el).css("visibility") == "hidden" || $(el).css('opacity') == 0;
}
var booElementReallyShowed = !isElementReallyHidden(someEl);
$(someEl).parents().each(function () {
if (isElementReallyHidden(this)) {
booElementReallyShowed = false;
}
});
But what if the element's CSS is like the following?
.element{
position: absolute;left:-9999;
}
So this answer to Stack Overflow question How to check if an element is off-screen should also be considered.
A function can be created in order to check for visibility/display attributes in order to gauge whether the element is shown in the UI or not.
function checkUIElementVisible(element) {
return ((element.css('display') !== 'none') && (element.css('visibility') !== 'hidden'));
}
Working Fiddle
Also here's a ternary conditional expression to check the state of the element and then to toggle it:
$('someElement').on('click', function(){ $('elementToToggle').is(':visible') ? $('elementToToggle').hide('slow') : $('elementToToggle').show('slow'); });
if($('#postcode_div').is(':visible')) {
if($('#postcode_text').val()=='') {
$('#spanPost').text('\u00a0');
} else {
$('#spanPost').text($('#postcode_text').val());
}
Related
I build a UI interface that show messages and after confirming them they become :"display=none", now i want to check if all the elements are been confirm meaning all hidden. so that my interface wont start.
This is the code:
this is visible:
<li id="announcement4" class="announcement"></li>
this is not visible:
<li id="announcement4" class="announcement" style="display: none"></li>
can i check via the class or type? like
if(all elements type li are hidden)
if(all elements class announcement are hidden)
what is a good way of doing this?
Thanks
Simply use is(':visible')
var allLiHidden = !$('li').is(':visible');
var allClassHidden = !$('.announcement').is(':visible')
FIDDLE
you can do like this:
if($('ul#SomeId').children(':visible').length == 0) {
// all are hidden
}
or:
if($('li.announcement:visible').length == 0) {
// all are hidden
}
Fiddle Example
if($('.announcement:visible').length>0)
{
//something is visible
}
For such a query, you can use the jQuery :visible selector, which gives you only visible elements (everything that Consumes space in the layout) As return.
If you then compare the amount of visible elements with the invisible, you'll see whether one is not visible.
if( $('.announcement').length === $('.announcement:visible').length ){
//all visible
} else{
//not all visible
}
Or
if( $('li').length === $('li:visible').length ){
//all visible
} else{
//not all visible
}
My code looks like this
if($(element).css("background-color") == null){
$(element).css("background-color", "white");
}
I want to make sure that if the color wasn't set in the style.css file, I add it. But that code is not working. It's always returning rgba(0,0,0,0). The browser I am working with is Chrome.
Is there another way to check if the color wasn't set?
CSS:
.background-set { background-color: white; }
jQuery:
var $el = $(element);
if( !$el.hasClass('background-set') ){
$el.addClass('background-set');
}
Though I'm not sure why you'd need to check. You can just add it without the condition.
Alternatively:
if ( $el.prop('style').backgroundColor == '' ) {
...
}
or
if ( $el.get(0).style.backgroundColor == '' ) {
...
}
The method suggested by elclanrs is the most elegant way of handling this and should be the preferred method. However, for the sake of sating curiosity, you could achieve the same result using a jQuery Attribute Contains Selector.
$("div[style*='background-color']").text("I have a background color!");
jsFiddle demo
I was wondering how I can combine a hide function and show function into 1 toggle Function that either fades in content or fades it out, im guessing this argument would update the fade method:
This is my current effort of JS using jQuery from my object but is totally wrong:
toggleAlertOverlay: function (state) {
var instance = this;
if (state === hide) {
instance.selector.fadeOut();
}
elseif(state === show) {
instance.selector.fadeIn();
}
},
toggleAlertOverlay(hide);
Try using .fadeToggle()
The .fadeToggle() method animates the opacity of the matched elements. When called on a visible element, the element's display style property is set to none once the opacity reaches 0, so the element no longer affects the layout of the page.
$(<element>).fadeToggle();
Where <element> is a valid selector ....
var toggleState = 'none';
toggleAllertOverlay: function()
{
if(toggleState == 'none')
{
$('#element').fadeIn();
toggleState == 'showing';
}
else
{
$('#element').fadeOut();
toggleState == 'none';
}
}
is just a concept based on what you have. Note the variable outside of the function. Its outside so it doesn't get destroyed upon function complete. But aside from that, theres various other methods you can try if this doesn't suit you. Up to and including jQuery toggle()
<div id="content">
<div class="oddpost">
<div class="arrow"></div>
</div>
<div class="oddpost">
<div class="arrow"></div>
</div>
<div class="oddpost">
<div class="arrow"></div>
</div>
<div class="oddpost">
<div class="arrow"></div>
</div>
</div>
$(function() {
if (($(".oddpost").position().left + $(".oddpost").width()) >= $("#content").width()) {
$('.arrow').hide();
}
});
http://jsfiddle.net/Ek5Gy/52/
In the code, I have a div(.arrow) nested on another div(.oddpost). What I want to do is hide the .arrow of the left .oddpost only. The idea is .arrow hides when .oddpost is near the left side of #content.
I've tried using offset but it gives the same offset().left value on all the oddpost div so all the arrow div still hides, even the one on the right.
Can anybody tell me how to fix this?
Your main problem lies in your selector usage:
// selecting stuff
$(".oddpost")
// doing stuff on the selection
.position().left
But, you'll have to know how those helper methods work on the given set. position (and many others) will only work on the very first element in the set. Not on every element.
So what you have to do is, iterate over each element in the set and do the test for every element independently, like:
$(".oddpost").each(function () {
if ($(this).prev().length === 0 || $(this).offset().left < $(this).prev().offset().left) {
$('.arrow', this).hide();
}
});
// or
$(".oddpost").each(function () {
if ($(this).position().left === 0) {
$('.arrow', this).hide();
}
});
http://jsfiddle.net/Ek5Gy/53/
The position() call returns values for the first selected element (it doesn't work on all selected elements as many other jQuery calls). Check Javadoc.
This is working for me:
$(function(){
$(".oddpost").each (function (idx, el) {
if ($(el).position().left < $(el).width()) {
$('.arrow', el).hide();
}
});
});
The modified jsfiddle: http://jsfiddle.net/Ek5Gy/54/
In your code, $('.arrow').hide() will always act on all DOM elements that match that particular selector (.arrow). Also, your calculations are only performed once, for the first .oddpost element, since that's the behavior of the position() jQuery function.
I just did not follow exactly what you meant by "near the left of content". I've altered your code a bit to reflect all these changes and prepared a little jsFiddle. Check it here.
Your example works fine.
In your example the value of:
$(".oddpost").position().left + $(".oddpost").width() // Equals 100
This is less the total of #content which is 270px. Your asking if it's greater than or equal too. If you want to hide the arrow when it's near the left try this:
if ($(".oddpost").position().left === 0) {
$('.arrow').hide();
}
EDIT:
$(function(){
$(".oddpost").each(function(){
var position = $(this).position().left;
alert (position);
if(position === 0){
// Do what you need to here.
}
});
});
This is what your looking for...
I want an array of all elements that have fixed position.
This is what I've got so far (mootools code)
$$('*').filter(function(aEl){ return aEl.getStyle('position')=='fixed' });
Is there a more direct way to do this?
not really, what you posted is the best way of doing it.
but if it's something you do more often, I'd consider abstracting it to a pseudo selector:
Selectors.Pseudo.fixed = function(){
return this.getStyle("position") == "fixed";
};
// can now use it as a part of a normal selector:
console.log(document.getElements("div:fixed"));
p.s. this will break in mootools 1.3 as slick uses a different selectors engine.
to make it work in 1.3 do:
Slick.definePseudo('fixed',function() {
return this.getStyle("position") == "fixed";
});
and finally, to make it more versatile so you can look up any CSS property as a part of the selector, you can do something like this:
Selectors.Pseudo.style = function(key) {
var styles = key.split("=");
return styles.length == 2 && this.getStyle(styles[0]) == styles[1];
};
and for mootools 1.3:
Slick.definePseudo('style', function(key) {
var styles = key.split("=");
return styles.length == 2 && this.getStyle(styles[0]) == styles[1];
});
how to use it:
console.log(document.getElements("div:style(position=fixed)"));
http://www.jsfiddle.net/h7JPS/3/
I would suggest you to make a css class
.fixed_pos
{
position: fixed;
}
apply this class to elements that you want and then
$$(".fixed_pos");
That will give you to all the element