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How can I transition between two divs without seeing the background of the page during the transition. In this example, I would expect just to see the numbers change:
https://jsfiddle.net/j2td4hd7/15/
The transition easing is set to linear.
This doesn't have anything to do with the easing, it's that you're unnecessarily transitioning both elements.
It's easy to overcomplicate this -- instead think of the two images as a stack: the one on the bottom can stay visible the whole time, only the one on the top needs to fade in and out.
Compare below:
goodswap = function() {
$('#div2').fadeToggle(); // transitions the top element in and out
}
badswap = function() {
$('#div1, #div2').fadeToggle(); // transitions both elements in and out
}
.block-div {
position: absolute;
height: 200px;
width: 400px;
color: #fff;
font-size: 40px;
text-align: center;
}
.container { position: relative }
#div1 { background-color: red;}
#div2 { background-color: brown; display: none;}
#div3 { background-color: blue }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<button onclick="goodswap()">Good fade</button>
<button onclick="badswap()">Bad fade</button>
<div class="container">
<div class="block-div" id="div3">(This is the page background)</div>
<div class="block-div" id="div1">1</div>
<div class="block-div" id="div2">2</div>
</div>
If the images are different sizes, this technique still works so long as the larger one is stacked with the higher z-index. To keep the rest of the page from jumping around, set the container's size to that of the larger image.
goodswap = function() {
$('#div2').fadeToggle(); // transitions the top element in and out
}
badswap = function() {
$('#div1, #div2').fadeToggle(); // transitions both elements in and out
}
.block-div {
position: absolute;
height: 200px;
width: 400px;
color: #fff;
font-size: 40px;
text-align: center;
}
.container { position: relative }
#div1 { background-color: red;}
#div2 { background-color: brown; width: 500px; display: none;}
#div3 { background-color: blue }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<button onclick="goodswap()">Good fade</button>
<button onclick="badswap()">Bad fade</button>
<div class="container">
<div class="block-div" id="div3">(This is the page background)</div>
<div class="block-div" id="div1">1</div>
<div class="block-div" id="div2">2</div>
</div>
If you have two elements with black background and opacity of 50% on each of them - they are not combined into 100% black :)
Check the following:
div {
background: black;
width: 150px;
height: 150px;
position: absolute;
}
div.half {
opacity: 0.5;
left: 0;
top: 0;
}
div.full {
top: 0;
left: 150px;
}
<div class="half"></div>
<div class="half"></div>
<div class="full"></div>
During the animation - the opacity of the two elements is changing from 0 to 100 and from 100 to 0, but the background color is not "combined".
I think the following will provide what you are looking for:
window.swap = function(divId){
if(divId === 'div1'){
jQuery('#div1').css('zIndex', 1);
jQuery('#div2').css('zIndex', 2);
jQuery('#div2').fadeIn({easing: 'linear', complete: function() {
jQuery('#div1').fadeOut({easing: 'linear'})
} }
);
}else{
jQuery('#div2').css('zIndex', 1);
jQuery('#div1').css('zIndex', 2);
jQuery('#div1').fadeIn({easing: 'linear', complete: function() {
jQuery('#div2').fadeOut({easing: 'linear'})
}
});
}
}
.block-div {
position: absolute;
height: 200px;
width: 400px;
color: #fff;
font-size: 40px;
text-align: center;
}
#div2{ display: none; background-color: brown; }
#div1{ background-color: red; }
html, body{
background-color: #fff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="block-div" onclick="swap('div1')" id="div1">1</div>
<div class="block-div" onclick="swap('div2')" id="div2">2</div>
Note regarding comments from the OP:
In case you want the same effect with two elements that has different height, you can create two dummy div, one for each div you have. The dummy1 will be in the size of div1, but contain the bg of div2, and same for dummy2. now you can use these dummy divs to do the transition.
Related
using only css and html, is it possible to scroll away the inner div (overlay red div) completely before scrolling down the rest of the page? Essentially, wondering if overlay scrolling while freezing the behind div is possible in only css? Then once the red div is gone, unfreeze the background scrolling and continue on. Similar to this site here: https://humaan.com/ . Or would some sort of JavaScript need to be used?
.headervideo{background-color:blue; width:100%; height:900px;}
.headerbreak{width:100%; height:300px;}
.headervideo #inner-box {
background-color: red;
height: 90%;
width: 100%;
}
<div class="headervideo">
<div id="inner-box"></div>
</div>
<div class="headerbreak">
<div>
position:sticky can approximate this:
.headervideo {
background: url(https://picsum.photos/id/1064/800/800) center/cover;
height: 100vh;
position: relative;
z-index: 2;
}
.nextsection {
background: url(https://picsum.photos/id/107/800/800) center/cover;
height: 100vh;
margin-top: -100vh;
position: sticky;
top: 0;
}
.container {
height:200vh;
}
body {
margin: 0;
}
<div class="container">
<div class="headervideo"></div>
<div class="nextsection"></div>
</div>
<div style="height:150vh"> more content later </div>
With CSS, you could use the hover event to detect a certain scroll position (e.g. on something just after the red div), but this would not work on touch only devices like mobile phones. It also wouldn't be reliable, as the cursor could be anywhere on the screen.
Using JavaScript to detect scroll position would be necessary. However, you could use the JavaScript only to add a class at different scroll positions and then do the rest with CSS. Here's a simple example:
var red = document.querySelector('#inner-box');
var begin = red.scrollTop;
var end = begin + red.clientHeight;
console.log(begin)
document.body.classList.add('in');
window.addEventListener("scroll", (event) => {
if(this.scrollY < begin) {
document.body.classList.add('before');
document.body.classList.remove('after');
document.body.classList.remove('in');
} else if(end < this.scrollY) {
document.body.classList.remove('before');
document.body.classList.add('after');
document.body.classList.remove('in');
} else {
document.body.classList.remove('before');
document.body.classList.remove('after');
document.body.classList.add('in');
};
});
.headervideo {
background-color: blue;
width: 100%;
height: 900px;
}
.headerbreak {
width: 100%;
height: 300px;
}
.headervideo #inner-box {
background-color: red;
height: 90%;
width: 100%;
}
body {
}
body.before {
background-color: lightgreen;
}
body.in {
background-color: lightpink;
}
body.after {
background-color: lightblue;
}
<body>
<div class="headervideo">
<div id="inner-box"></div>
</div>
<div class="headerbreak">
<div>
</body>
I'm trying to make something where I need to duplicate all the entries (multiple times) and then later I would like to make it spin and land on a colour slowly, etc. I'm now just getting stuck at duplicating the colours, how can I make it so the new colours are overflowing, without doubling the width?
I want it so that the colours go out of the wrapper div. Now they are just distributing themselves.
Any ideas?
$(document).on("click", ".duplicate", function() {
var $wrapper = $('.wrapper .inner');
$wrapper.find('.color').each(function() {
$wrapper.append($(this).clone());
});
});
.wrapper {
width: 75%;
margin: 12px auto;
height: 26px;
border-radius: 6px;
overflow: hidden;
position: relative;
}
.wrapper .inner {
width: 100%;
height: 100%;
position: absolute;
display: flex;
}
.wrapper .color {
width: 100%;
height: 100%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="wrapper">
<div class="inner">
<div class="color" style="background:red;width:231%"></div>
<div class="color" style="background:purple;width:111%"></div>
<div class="color" style="background:orange;width:91%"></div>
</div>
</div>
<button class='duplicate'>
Duplicate
</button>
In order to have two items in the same position in document flow you need to wrap them in a parent with position:relative and give one of them position:absolute; top:0;left:0. Also note that if your element doesn't have any content, you might need to define it's height and width. To make it same size as parent, you can give it top:0;bottom:0;left:0;right:0;.
Here's a demo started from your fiddle. You might want to inspect DOM after you press "Duplicate". I made it revert to original, so you can do it multiple times.
But do note your question is currently unclear. I'm afraid you lost me at "to make it spin and land on a colour slowly". It's truly poetic, but won't get you very far on SO...
I guess you are simply over complicating this. All what you need is a reapeated linear-gradient like this:
.wrapper {
width: 75%;
margin: 12px auto;
position: relative;
}
.wrapper .inner {
width: 100%;
height: 25px;
display: flex;
border-radius: 6px;
overflow: hidden;
}
.wrapper .color {
width: 100%;
height: 100%;
}
.new {
margin-top:5px;
height:25px;
border-radius: 6px;
background-image:linear-gradient(to right,red,red 54%,purple 54%, purple 80%,orange 0);
background-size:100% 100%;
animation:change 5s linear infinite alternate;
}
#keyframes change {
from {
background-position:0 0;
}
to {
background-position:-1000px 0;
}
}
<div class="wrapper">
<div class="inner">
<div class="color" style="background:red;width:231%"></div>
<div class="color" style="background:purple;width:111%"></div>
<div class="color" style="background:orange;width:91%"></div>
</div>
<div class="new"></div>
</div>
So I have 2 divs children of a display block parent. I would like to make div #2 (green) be on top of div #1 (red). With "on top" I'm not talking about z-index, I'm talking about literally being on top of the other. And then I was wondering if there could be a way to make div #2 slideDown()
As far as I tested, jQuery slideDown() or slideUp() works differently.
In the demo I made, when I run
$('.item-1').slideUp();
The item 2 is sliding up instead of item 1, why is that? I'm getting confused.
Any hints would be appreciated,
Thanks in advance.
window.slide = function() {
$('.item-1').slideUp();
}
.items-container {
height: 400px;
width: 240px;
background-color: #c3c3c3;
display: block;
/* overflow: hidden; */
}
.item {
height: 100%;
width: 240px;
position: relative;
font-size: 30px;
text-align: center;
vertical-alignment: middle;
}
.item-1 {
background-color: red;
}
.item-2 {
float: left;
position: relative;
background-color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button onclick="slide()">
Click me!
</button>
<div class="items-container">
<div class="item item-1">
1
</div>
<div class="item item-2">
2
</div>
</div>
jQuery's slideUp() and slideDown() methods animate the height of the matched elements, not position as you seemed to want: http://api.jquery.com/slideUp/.
What you seem to want is to translate the div it so that it moves on top of the first one.
http://www.w3schools.com/css/css3_2dtransforms.asp
window.slideUp = function() {
$('.item-2').addClass('slideUp');
}
window.slideDown = function() {
$('.item-2').removeClass('slideUp');
}
.items-container {
height: 100px;
width: 240px;
background-color: #c3c3c3;
display: block;
/* overflow: hidden; */
}
.item {
height: 100%;
width: 240px;
position: relative;
font-size: 30px;
text-align: center;
vertical-alignment: middle;
}
.item-1 {
background-color: red;
}
.item-2 {
position: relative;
transition: transform linear 1s;
background-color: green;
}
.slideUp
{
transform: translate(0,-100%);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button onclick="slideUp()">
SlideUp!
</button>
<button onclick="slideDown()">
SlideDown!
</button>
<div class="items-container">
<div class="item item-1">
1
</div>
<div class="item item-2">
2
</div>
</div>
.slideUp() works by changing the height of the element. As that element gets shorter, following elements will move up the page.
As seen in the documentation:
The .slideUp() method animates the height of the matched elements. This causes lower parts of the page to slide up, appearing to conceal the items.
In your fiddle, item1 slides up as expected and as defined by the doc :
Description: Hide the matched elements with a sliding motion.
So your div slides up and disappears, and item2 doesn't "move", just fills the space in the DOM after item1 has been hidden.
I am trying to figure out how I can trigger a waypoints function. Right now this function starts when my info div is at the very top of the screen. Ideally, I want this to start when the user's bottom of the screen just gets to the info-box section. I am unsure of how I can even modify when the event triggers.
Also, for some reason the info-boxes aren't transitions to the right like I am attempting. They just transition into a fade with now horizontal movement. What is wrong with what I am trying?
var $info_show = $('#info');
$info_show.waypoint(function () {
$('.info-box').addClass("fadeShow");
});
#info {
max-width: 100%;
height: auto;
padding: 300px 20%;
}
.info-box {
border: 1px solid black;
padding: 50px;
background: #00f;
color: #fff;
display: inline;
margin: 0 100px;
transition: 1s;
opacity: 0;
}
.info-box.fadeShow {
opacity: 1;
transform: translateX(150px);
}
<script src="https://leaverou.github.io/prefixfree/prefixfree.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="info">
<div class="info-box">Red</div>
<div class="info-box">Blue</div>
<div class="info-box">Green</div>
</div>
I am using a `.toggle("slide") function to try and get a piece of text I have to appear as if each letter is sliding in. Unfortunately, it looks as if the text is flying in instead. I tried to squeeze the margins in tight, so that it would start at a closer place, but it still looks as if it is flying in from the left side.
Is there a better way to do this, so it looks as if the letters are sliding in without "flying in"?
$("#home-learn").toggle("slide");
#blue {
background-color: #0085A1;
width: 100%;
height: 300px;
}
#home-learn {
color: #FFF;
display: none;
text-align: center;
position: relative;
margin: 0 40%;
top: 50%;
font-size: 2.3em;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="blue">
<div id="home-learn">Learn more...</div>
</div>
For the effect you want, put a div inside your container. Make the div position absolute, make it 100% the height and width of the container, and make it the same background color as the main background. Make the div's z index higher than the container so the div sits over the text like a curtain. Then use toggle() to slide the curtain to the right exposing the text underneath.
Note that this uses jQuery UI, without it, you can't make toggle() slide to the right like this needs.(at least to my knowledge you cant). If you dont want to use jquery UI, you could use .animate() instead of toggle()
$("#curtain-div").toggle("slide", {
direction: "right"
}, 3000);
#blue {
background-color: #0085A1;
position: relative;
width: 100%;
height: 300px;
}
#home-learn {
color: #FFF;
text-align: center;
position: relative;
top: 50%;
font-size: 2.3em;
}
#curtain-div {
width: 100%;
height: 100%;
position: absolute;
background-color: #0085A1;
top: 0;
left: 0;
z-index: 10;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
<div id="blue">
<div id="home-learn">
<div id="curtain-div"></div>
Learn more...
</div>
</div>