Develop Reference

why ajax post method return empty alert box when i tried to return data from controller file in codeigniter

This is my ajax function
$(function(){
$("#myform").submit(function(){ //i want to get data from my form after submittingit
dataString = $("#myform").serialize();
alert(dataString);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
success: function(data){
alert(data);
}
});
return false;
});
});
this is my controller class function
function viewCustomerData(){
if($_POST){
$name = $_POST['name'];
return 'name';
}
else {
return false;
}
}
other thing is i tried to alert data string taken from form serialize, but it also empty. I want to return data set from database after sending key word from javascript file. i tried if the javascript file connect correctly with my controller function. so i tried to return some value and display it using alert box. but it gives empty result.

This is better way to submit a form with ajax
$(document).on("submit", "#myform", function(event)
{
event.preventDefault();
$.ajax({
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData"
type: "POST",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
alert(data);
},
error: function (xhr, desc, err)
{
}
});
});

try this
$(function(){
$("#myform").submit(function(){
dataString = $("#myform").serialize();
alert(dataString);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
cache: false,
datatype: 'json',
success: function(data){
alert(data.result);
}
});
});
});
in controller
function viewCustomerData(){
if($this->input->post('name'){
$result = $this->input->post('name');
} else {
$result = false;
}
header('Content-Type: application/json');
echo json_encode(array('result' => $result));
}

you cant alert $("#myform").serialize(); because this is an object instead of alert it try console.log($("#myform").serialize();)
then open browser console and see what is printed
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
})
.done(function( data ) {
if ( console && console.log ) {
console.log( "Sample of data:", data);
}
});

Problems with $_POST["var"] in Yii Controller

i am having problems with $_POST["var"] on controller. It seems to be empty. How can i receive the string being typed on my textFiled?
View
<?php Yii::app()->clientScript->registerCoreScript("jquery"); ?>
<script type="text/javascript">
$(document).ready(function(){
$("#hhmm").change(function(){
$.ajax({
url: "<?php echo CController::createUrl('reqTest01Loading'); ?>",
data: $(this).serialize(),
type: "post",
dataType: "json",
success: function(data) {
if (data.status === 'failure') {
$('#impatto').val('Error request failed.');
} else {
$("#impatto").html(data.total);
}
}
});
});
});
</script>
Controller
public function actionReqTest01Loading() {
$result = array("total" => $_POST['hhmm'], "status"=>"OK");
echo CJSON::encode($result);
}
rules on Controller
array('allow', // allow all users to perform 'index' and 'view' actions
'actions'=>array('reqTest01Loading','index','view','admin'),
'users'=>array('#'),
),
thanks in advance

This is because you dont tell ajax call to send parameters.
Try:
$.ajax({
url: "<?php echo CController::createUrl('reqTest01Loading'); ?>",
data: {data:$(this).serialize()},
type: "post",
dataType: "json",
success: function(data) {
if (data.status === 'failure') {
$('#impatto').val('Error request failed.');
} else {
$("#impatto").html(data.total);
}
}
});
And it controller:
public function actionReqTest01Loading() {
// var_dump(Yii::app()->request->getPost('data'));
$result = array("total" => Yii::app()->request->getPost('data'), "status"=>"OK");
echo CJSON::encode($result);
}

How can i redirect page JavaScript/PHP?

I want to redirect page to URL that return from PHP script.
That when user created a post i want to return value of mysql_insert_id() for post_id.
$('input#submitButton').click( function() {
$.ajax({
url: 'newpost.php',
type: 'post',
dataType: 'json',
data: $('form#myForm').serialize(),
success: function(data) {
window.location.replace("http://localhost/?post_id=...");
}
});
});
I looked here but not found what i want.
Link

In your php script do :
echo json_encode(array(
'id' => $THE_ID
));
then here do:
$('input#submitButton').click( function() {
$.ajax({
url: 'newpost.php',
type: 'post',
dataType: 'json',
data: $('form#myForm').serialize(),
success: function(data) {
window.location = "http://localhost/?post_id=" + data.id;
}
});
});
});

How do i send multiple requests for the same file and get the required response back in php using jquery ajax

var postID = $post->ID;
$.ajax({
type: "POST",
url: "<?php echo get_template_directory_uri();?>/b.php",
data:{postID:postID},
dataType: 'json',
success: function(result){
if(result!=''){
r = $.parseJSON(result);
final_rating = get_final_rating(r);
set_stars(final_rating);
}
}
});
var arr = [a,b,c,d,e,f];
$.ajax({
type: "POST",
url: "<?php echo get_template_directory_uri();?>/b.php",
data:{star:arr, postID:postID},
async :false,
cache: false,
success: function(result){
if(result === '1')
{
final_rating = result;
set_stars(final_rating);
}
}
});

You can do something like this with jQuery:
var postID = <?php echo $post->ID; ?>,
arr = [a,b,c,d,e,f],
req1, req2;
req1 = $.ajax({
type: "POST",
url: "<?php echo get_template_directory_uri();?>/b.php",
data: {postID:postID},
dataType: 'json'
});
req2 = $.ajax({
type: "POST",
url: "<?php echo get_template_directory_uri();?>/b.php",
data: {star:arr, postID:postID},
async: false,
cache: false
});
$.when(req1, req2).then(function (data1, data2) {
// data1[0] = result
if(data1[0] !== '') {
r = $.parseJSON(result);
final_rating = get_final_rating(r);
set_stars(final_rating);
}
// data2[0] = result
if(data2[0] === '1') {
final_rating = result;
set_stars(final_rating);
}
});

var postID = $post->ID; should be replaced by:
var postID = <?php echo $post->ID; ?>;
You're also doing Ajax wrong. You should make all requests on admin-ajax.php - http://codex.wordpress.org/AJAX_in_Plugins
You then use different action parameters to differentiate between different Ajax calls.

How to get the ajax response from success and assign it in a variable using jQuery?

Hello guys I have a problem in getting the response from my ajax. If I display it in the console. I can view it. But How do I assign it in a variable?
Here's what I have.
In my PHP code I have this
public function checkPassword($password){
$username = $this->session->userdata('username');
$validate = $this->members_model->checkPassword($password,$username);
echo $validate;
}
In my jquery I have this
$('#existing').on('keyup',function(){
var id = '<?php echo $this->session->userdata("user_id"); ?>';
var password_url = '<?php echo site_url("member/checkPassword/' +id+ '"); ?>';
$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json',
success: function(response){
var g = response;
if(g == 1){
$('#existing_info').html('Password is VALID'); //Doesn't display the VALID if the response is 1. Why?
}else{
$('#existing_info').html('Password is INVALID!');
}
}
});
});

$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json',
success: function(response){
var k=response;
if(k.indexOf("1") != -1)
$('#existing_info').html('Password is VALID');
else
$('#existing_info').html('Password is INVALID!');
}
});
response is in response variable of success function.
indexof returns the index within the calling String object of the first occurrence of the specified value, starting the search at fromIndex,
returns -1 if the value is not found.

try something like this
<script>
var k = null;
$(function(){
$('#existing').on('keyup',function(){
var id = '<?php echo $this->session->userdata("user_id"); ?>';
var password_url = '<?php echo site_url("member/checkPassword/' +id+ '"); ?>';
$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json',
success: function(response){
if(response == 1){
k = response;
}
}
});
});
})
</script>

In your success response you will get what you are set to output in php.
If you want to get an array or data set you can encode it in json in your php script like
echo json_encode($validate);
Then in your jquery you can use this response like this
var responseData = jQuery.parseJSON(response);
console.log(responseData);
console.log will print json object in browser console.
You can use this json object like this
responseData.some_data

Ajax is asynch so you will have access to it after the ajax method returns:
$('#existing').on('keyup',function(){
var id = '<?php echo $this->session->userdata("user_id"); ?>';
var password_url = '<?php echo site_url("member/checkPassword/' +id+ '"); ?>';
$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json'
}).then(function(response){
var k;
if(response == 1){
k = response;
//call another function that needs k here
}
});
});

$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json',
success: function(response){
k=response;
}
});

var k = null;
$('#existing').on('keyup', function() {
var id = '<?php echo $this->session->userdata("user_id"); ?>',
password_url = '<?php echo site_url("member/checkPassword/' +id+ '"); ?>';
$.ajax({
type : 'POST',
url : password_url,
success : function(data) {
if(data === '1') {
k = data;
}
}
});
});

response parameter itself contain data so just assign that to variable and use it.
$.ajax({
type: 'POST',
url: password_url,
success: function(response){
if(parseInt(response) == 1){
var k = response;
}
}
});

Your response data is in response variable of success function. Since the response type is json you can assign it directly to javaScript variable.
Also you comparison is wrong try if(g == '1') instead if(g == 1). You are getting a string as response and your checking equality with a numeric type which won't be equal at any point.
ie:-
$.ajax({
type: 'POST',
url: password_url,
data: '',
dataType: 'json',
contentType:"application/json",// Add Content type too
success: function(response){
k=response;
}
});
if your json response is as shown below
{"menu": {
"id": "file",
"value": "File",
"popup": {
"menuitem": [
{"value": "New", "onclick": "CreateNewDoc()"},
{"value": "Open", "onclick": "OpenDoc()"},
{"value": "Close", "onclick": "CloseDoc()"}
]
}
}}
you can access menuitem array as
success: function(response){
k=response.menu.popup.menuitem;
}

File Name votepost.php
<?php
include("domain.php");
$csid=$_POST['CSID'];
$voteid=$_POST['VOTEID'];
$myid=$_POST['MYID'];
$usertype=$_POST['USERTYPE'];
$myurl =URL."putvote.php?csid=".$csid."&voterid=".$myid."&voteid=".$voteid."&usertype=".$usertype;
$myurl=str_replace(" ","%20",$myurl);
$jsondata = file_get_contents($myurl);
$data = json_decode($jsondata);
if($data->response=="true")
{
echo 'true';
}
else
{
echo 'false';
}
?>
ajax reponse use $.trim for IF ELSE
$.post("votepost.php", {CSID:csid,VOTEID:voteid,MYID:myid,USERTYPE:usertype}, function (data) {
if($.trim(data)=='true')
{
alert('ok');
}
else
{
alert('error');
}
});
I hope you will solve your problem

You can create the js blank array and assign it to the same array.
var resp = [];
jQuery.ajax({
dataType: "json",
method: 'post',
url: 'ajax.php',
async: false,
data: {postData: 'postData'},
success: function(data){
resp.push(data);
}
});