Send array of files using AJAX - javascript

Say I have an array which contains a few images:
var images = [image1, image2, image3]
How do I send these images to a php file using AJAX in a single request?
The following code did not work:
$.ajax({
url: 'PHP/posts.php',
type: 'post',
data: {data: images},
success: function(data) {
alert(data);
location.reload();
}
});
My HTML:
<div id="newPostFile">
<label for="newPostFiles"><i class="fa fa-file-text-o" id="newPostFileIcon" aria-hidden="true"></i></label>
<input type="file" name="newPostFiles" id="newPostFiles">
</div>
Endgoal:
Whenever a file is selected, the file is added to the array and when the submit button is clicked, all the files are uploaded at once.

You have to send files as formData
var images = [image1, image2, image3]
var data = new FormData();
images.forEach(function(image, i) {
data.append('image_' + i, image);
});
$.ajax({
url: 'PHP/posts.php',
type: 'post',
data: data,
contentType: false,
processData: false,
success: function(data) {
console.log(data);
location.reload();
}
});
But as you're reloading the page anyway, why use ajax at all ?

You can pass a JSON object to PHP, which would be the convenient solution here
var data ={'image1':image1,'image2':image2};
You can pass this object to the php code and then parse it:
Pass the object as a string:
AJAX call:
$.ajax({
type : 'POST',
url : 'PHP/posts.php',
data : {result:JSON.stringify(data)},
success : function(response) {
alert(response);
}
});
You can handle the data passed to the result.php as :
$data = $_POST["result"];
$data = json_decode("$data", true);
//just echo an item in the array
echo "image1 : ".$data["image1"];
Another option would be serializing the array before sending, or convert it into a comma separated string using array.join, then parse/split on the posts.php
array.join(",")

you can just use the list symbol after the input name [i]
for example:
let formData = new FormData();
let files = fileInput.prop('files');
for (let i = 0; i < TotalFiles; i++) {
formData.append('file['+i+']', files[i]);
}

Use FormData Object to send files using ajax.new FormData($('#your_form_id')[0]) automatically appends all form input in FormData object which we can be done by manually formData.append('file1',file1);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
let formData = new FormData($('#your_form_id')[0]);
$.ajax({
url: 'PHP/posts.php',
type: 'POST',
data: formData,
dataType:'json',
processData: false,
contentType: false,
success: function(response) {
console.log(response);
location.reload();
},
error: function() {
console.log('fail');
}
});
</script>

Related

file upload serialize jquery without form

how to send image file data with jquery ajax in a table without using a form attribute
i am using serialize this but file data is not in payload
$('.upload').on('click', function() {
var mdata = $(this).closest('tr').find("input, select, textarea").serialize();
$.ajax({
url: "../../../uploadimage",
data:mdata,
timeout:false,
type:'POST',
dataType:'JSON',
success:function(res){
...
}
});
});
while for other text input attributes run normally
You need to use formData to post images with ajax.
If you have to use closest, then you should use both together.
Here is an example :
$(document).ready(function(){
$(".upload").submit(function(e){
e.preventDefault();
var [form] = $(this).closest('form');
var formData = new FormData(form);
$.ajax({
url:'../../../uploadimage',
type: 'POST',
data: formData,
cache: false,
contentType: false,
processData: false,
success: function(data) {
...
}
});
});
});
If you dont have to use closest, then this is your answer : how to do file upload using jquery serialization

FormData in multiple ajax request files

I'm trying to do a Ajax's loops requests for send files to an API but i don't not what I send at Ajax's data. When I do only file in upload I use the own formdata object and works very well. I tried use loop and each row send an individual file but it's doesn't works too:
Multiple files:
var form_data = new FormData();
for(i=0;i<3;i++){ // 3 length just for tests
form_data.append('file', $('#myfile').prop('files')[i]);
}
for (var value of form_data.values()) {
$.ajax({
url: 'URI',
data: value,
processData: false,
contentType: false,
type: 'POST',
success: function (data) {
alert("Success!")
},
error: function(e){
alert("Error")
}
});
}

how to append formdata in ajax call with image in php?

I want to send FirstName, LastName and Image through Ajax Call to PHP. I am able to send the data without image, and I am able to send the image without text using formdata but the problem is I am not able to do both at a time. Kindly check my code what I am doing wrong:
<script>
function createBasicInfo() {
// For Image Send
var formdata = new FormData();
var file = jQuery('#photo').prop('files')[0];
formdata.append('photo', file);
// For Text Send
var data = {
'firstname' : jQuery('#firstname').val(),
'lastname' : jQuery('#lastname').val(),
};
**//Here Is the Problem, I am not able to append the data with Text**
formdata.append(data);
//Ajax call Start Here
jQuery.ajax({
url: '/adminseller/parsers/sbasicinfo.php',
method: 'POST',
cache: false,
contentType: false,
processData: false,
data: formdata,
success: function(data) {
if (data != 'passed') {
jQuery('#modal_errors_1').html(data);
}
if (data == 'passed') {
jQuery('#modal_errors_1').html("");
location.reload();
}
},
error: function() {
alert("Something went wrong.");
},
});
}
</script>
In above code if I comment
//formdata.append(data); // Then only image will send to php
And If I use in Ajax Call
data: data, // Then only FirstName & LastName will send to php without Image
I am not able to send text data and image both at the same time to php file.
Any idea or suggestion would be welcome.
You could just do this insted of formdata.append(data):
formdata.firstname = jQuery('#firstname').val();
formdata.lastname = jQuery('#lastname').val();
Just append your firstname and lastname into formdata. Then send full formdata.
<script>
function createBasicInfo() {
var formdata = new FormData();
var file = jQuery('#photo').prop('files')[0];
formdata.append('photo', file);
formdata.append('firstname', jQuery('#firstname').val());
formdata.append('lastname', jQuery('#lastname').val());
//Ajax call Start Here
jQuery.ajax({
url: '/adminseller/parsers/sbasicinfo.php',
method: 'POST',
cache: false,
contentType: false,
processData: false,
data: formdata,
success: function(data) {
// ...
// ...
},
error: function() {
alert("Something went wrong.");
},
});
}
</script>

Ajax send array and Image in same request

I want to make an ajax call that sends both JSON and file data to my PHP backend. This is my ajax call currently:
$.ajax({
type: 'POST',
dataType: 'json',
data: jsonData,
url: 'xxx.php',
cache: false,
success: function(data) {
//removed for example
}
});
The data(jsonData) is a JSON array that also holds the input from a file select as well(I am assuming this is wrong due to the type mismatch). I tried using contentType: false, and processData: false, but when I try to access $_POST data in PHP there is nothing there. The data I am passing does not come from a form and there is quite a bit of it so I do not want to use FormData and append it to that object. I am hoping i will not have to make two ajax calls to accomplish this.
If you want to send data along with any file than you can use FormData object.
Send your jsonData as like that:
var jsonData = new FormData(document.getElementById("yourFormID"));
Than in PHP, you can check your data and file as:
<?php
print_r($_POST); // will return all data
print_r($_FILES); // will return your file
?>
Try Using formdata instead of normal serialized json
Here's an example:
var formData = new FormData();
formData.append("KEY", "VALUE");
formData.append("file", document.getElementById("fileinputID").files[0]);
then in your ajax
$.ajax({
type: 'POST',
url: "YOUR URL",
data: formData,
contentType: false,
processData: false,
dataType: 'json',
success: function (response) {
CallBack(response, ExtraData);
},
error: function () {
alert("Error Posting Data");
}
});
You can try like this also
You can visit this answer also
https://stackoverflow.com/a/35086265/2798643
HTML
<input id="fuDocument" type="file" accept="image/*" multiple="multiple" />
JS
var fd = new FormData();
var files = $("#fuDocument").get(0).files; // this is my file input in which We can select multiple files.
fd.append("kay", "value"); //As the same way you can append more fields
for (var i = 0; i < files.length; i++) {
fd.append("UploadedImage" + i, files[i]);
}
$.ajax({
type: "POST",
url: 'Url',
contentType: false,
processData: false,
data: fd,
success: function (e) {
alert("success");
}
})

How do file upload for Ajax

I'm trying to submit a form via ajax which has some images The following code returns an object (in console.form), "FormData", however how do I use it and or retrieve it, and whether it is right.
$("#form_galeria").unbind('submit').bind('submit', function(e) {
e.preventDefault();
var url = 'salvarGaleria.do';
var form;
form = new FormData();
form.append('fileUpload', e.target.files);
console.log(form);
$.ajax({
type: "POST",
url: url,
data: $("#form_galeria").serialize(),
processData: false,
contentType: false,
success: function(result) {
console.log(result);
},
error: function(err) {
console.log(err.status + ' - ' + err.statusText);
}
});
$('#multiplas').modal('hide');
return false;
});
Set the ajax data option to your FormData object. You will need to add whatever field values to the FormData object as well if you wish to send those along with the file upload. Also you have to append each indvidual file you cannot just append the e.target.files collection
for(var i=0; i<e.target.files.length; i++){
form.append("fileUpload[]",e.target.files[i]);
}
//or if you are only doing a single file
//form.append("fileUpload",e.target.files[0]);
form.append("someField",jQuery("#someField").val());
form.append("someOtherField",jQuery("#someOtherField").val());
$.ajax({
type: "POST",
url: url,
data: form,
processData: false,
contentType: false,
success: function(result){
console.log(result);
},
error: function(err){
console.log(err.status + ' - ' + err.statusText);
}
});

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