I am trying to submit this for without using a submit button. Here I have used javascript and once the form has submitted user should be directed to the B.php.
html code
<form id="jsform" action="B.php" method="POST" target="_blank">
<input type="hidden" value="test" name="title"/>
</form>
java-script code
<script type="text/javascript">
document.getElementById('jsform').submit();
</script>
These 2 code lines run separately but not running together. Any mistakes have I done.
In javascript you can do this:
window.onload=function() {
document.getElementById("jsform").submit(); // using ID
}
And with jQuery
$(function() {
$("#jsform").submit(); // using ID
});
I write my comment as an actual answer this time.
Drop target="_blank" and it should work just fine. Otherwise your browser might see it as a popup.
Also make sure your JS is run after your form.
Use form name to submit
document.myform.submit();
Related
I am new to javascript so it might be a simple question for many.
I have used form sumbit in thymeleaf and am trying to add a JS validation before the form is submitted to the spring mvc controller. I can perform these two actions separately (individual tasks). However I could not really make them work one after the other (js function and form submit). Submit action is triggered by a button inside the form.
<form th:action="#{/user/trigger}" th:object="${triggers}" method="post">
<input type="hidden" name="tradeDate" th:value="${trigger.id.tradeDate}">
<button type="submit" id="ignore" name="action" value="ignoreOrder" class="btn btn-primary btn-sm">Ignore</button>
</form>
The js function is like below:
$(".ignore").click(function() {
//do some processing;
return false;
});
So can someone can help me to rewrite this code which will first call the JS function and submit the form to the java spring mvc controller? Thanks in advance.
The issue with your approach is that after your java-script is validating the code, your html 'submit' button is submitting the form as they're executing one after another. You haven't done anything to prevent the form submission after the validation is getting failed.
To overcome this issue, what you can do is to submit the form through your JavaScript code manually only when your validation is successful.
So your code will look something like this -
1.) Changes in Html code, instead of creating the button type as 'submit', make it as a normal button and run your javascript validation function on its click -
<form th:action="#{/user/trigger}" th:object="${triggers}" id="myForm" method="post">
<input type="hidden" name="tradeDate" th:value="${trigger.id.tradeDate}">
<button type="button" id="ignore" name="action" onclick="myValidationFunction()" value="ignoreOrder" class="btn btn-primary btn-sm">Ignore</button>
</form>
2.) Changes in Javascript code, now after clicking on the above button your javascript validation function will execute and after the validation is successful submit the form manually using the form id, something like this -
function myValidationFunction(){
if( some_condition ){
//validation failed
return;
}
//validation success , when above mentioned if condition is false.
$("#myForm").submit(); // Submit the form
}
For more information about using submit in jquery, refer the official documentation -
https://api.jquery.com/submit/
for jquery, it return a list, so:
$('#search_form')[0].submit();
<form id="login" method='post' action='membership.php'>
<b>Email</b><br><br>
<input class="form" type='text' name='email2' id='email2'><br><br>
<b>Password</b><br><br>
<input class="form" type='password' name='password2' id='password2'><br><br>
<input class="submitborder" id='submit2' type='submit' name='submit2' value='Submit'>
</form>
<script>
$(document).ready(function () {
$("#submit2").on("click", function() {
$(this).attr("disabled", "disabled");
Submitting();
});
});
function Submitting() {
setTimeout('$("#submit2").removeAttr("disabled")', 10000);
}
function PreventDouble(event) {
event.preventDefault();
}
</script>
<?php
echo "<a href='construction.php' onclick='PreventDouble(this)'></a>";
?>
I've read a few forum pages etc ... and they suggest disabling using jQuery or AJAX. When I disable though, I doesn't submit the form data anymore. But will disable the button accordingly.
For the hyperlink, because it sends user to another page, then disables, it's hard to judge if onclick='PreventDouble(this);' is working.
I also would like to apologize as I am a newb when it comes to Javascript, jQuery, or AJAX.
UPDATE: May I also mention I'm newb at this forum posting. Um. One last note is the disabling of form button. I use this code in another area of my website that doesn't click properly on computer. As if it seems to be on a wait before it processes my Javascript/jQuery/AJAX scripts? I dunno.
I admit defeat to Javascript/jQuery/AJAX x_x
I may be wrong as I am not familiar with PHP, but it doesn't look like the PreventDouble(this) method get called upon form submission. You can try putting the function inside the click event handler instead. Or better yet, just put the event.preventDefault() line there.
I am building a sort of page builder where the user can add blocks to the page and then save the layout. I have encountered a problem that I can't seem to figure out. I have a form that is dynamically added to the page with JavaScript containing a file input as so:
<form class="upload " action="" method="post">
<input id="" type="file" class="fill" name="upload">
<img src="/admin/img/default.png" alt="">
</form>
After adding the content I call the following function to add event listeners. $el corresponds to the file input.
function changeListen($el){
$el.addEventListener('change', function(){
$el.parentElement.submit();
});
$el.parentElement.addEventListener('submit', function(e){
e.preventDefault;
// call Ajax request...
});
}
I want to be able to update the database with an Ajax request when an image is selected, therefore I submit the form within the change event, so far so good, but for some reason the submit event is not taken into account and the page reloads. Any solutions or workaround appreciated, preferably not jQuery.
By using onsubmit event in HTML, you can call javascript function this way and do ajax calls.
Javascript sample
<script>
function doSomething() {
alert('Hello, World');
return false;
}
</script>
HTML Sample
<form onsubmit="return doSomething();">
<input type="submit" value="Submit" />
</form>
EDIT: return false in javascript so ? does not appear in URI after clicked
i am trying to load a html page with the results of a "get" from another link.The idea is when I open the page, I should see the results of the get displayed.
I tried the following with javascript but with no success. The problem is I always get a submit button on the page. I want the submit to be "pre" done!
Please help. Here is what I have:
<body onLoad ="subMe()">
<script>
function subMe(){
document.getElementById("formButton").submit();
}
</script>
<div align="center">
<div style="display: hidden;">
<form action="http://localhost:8000/getusers/" method="get">
<input type="submit" id="formButton" />
</form>
</div>
..
</body>
Any idea? This is linked to my previous post:Cgi C program return value to main HTML and display result
The problem is that you are submitting a button, not the form.
Try:
function subMe() {
document.getElementsByTagName('form')[0].submit();
}
Since you have no need for the submit button, there is also no harm in removing it from the html.
I believe that you have to submit the form, not the button.
document.getElementsByTagName('form')[0].submit();
submit() should be called on the form element, not on a submit button.
I got this code here:
It works fine as far as disabling and replacing the Submit button goes, but it will not submit the form. My form uses the 'get' method and submits data to another page.
<script type="text/JavaScript">
$('.button').click(function() {
$('.button').remove();
$('.holder').append("DONT DOUBLE CLICK ANYTHING IN A BROWSER");
$('.form').submit();
});
</script>
I have tried most things, including changing .form to the id of my form, still no joy, any ideas would be helpful.
HTML code
<form action="liftingConfirm.asp" method="get" id="frmArchiveConfirm">
<input name="con_id" type="hidden" id="con_id" value="<%=request.querystring("con_id")%>" />
<input name="sub_id" type="hidden" id="sub_id" value="1" />
<input name="liftingDate" type="hidden" id="liftingDate" value="<%=Session("currentUSDate")%>" />
<div class="holder"><input name="btnConfirm" type="submit" class="button" id="btnConfirm" value="Start New Lifting Gear Examination" /></div>
You're using the wrong selector, the .form is looking for a <form> with a class of form. Furthermore you should be using the on() syntax:
$('form').on('click', '.button', function() {
$('.holder').append("DONT DOUBLE CLICK ANYTHING IN A BROWSER");
$('#frmArchiveConfirm').submit();
$('.button').remove();
});
For your jQuery code to work you should include the frmArchiveConfirm to your jQuery code as below.
Replace $('.form').submit(); with $('#frmArchiveConfirm').submit();
else if you only having one form in the page just use $('form').submit();
When you come across bug like this don't forget to make use of the firebug or the browser development tools. You can easily figure out the bug and what's wrong in your code.