I am trying to submit the login request using Jquery Ajax. But the form is not submitting. I am tried to find the issue but can not. the code is vey simple but as I have started learning javascript so I am failing to find the problem in my code. Below is the code Please find the problem with it......
$(function() {
//get form by id
var form = $('#login_form');
//get message container by is
var message = $('#message');
//prevent default on form submit
$(form).submit(function(event) {
event.preventDefault();
//serialize form data
var form_data = $(form).serialize();
$.ajax({
type: 'post',
url: $(form).attr('action'),
data: form_data
}).done(function(response) {
//set the class of message container to success
$(message).removeClass('error');
$(message).addClass('success');
//put data received from server
$(message).html(response);
//clear form
$('#email').val('');
$('#password').val('');
}).fail(function(data) {
//set the class of message container to error
$(message).removeClass('success');
$(message).addClass('error');
//put the error message
if (data.responseText !== '') {
$(message).html(data.responseText);
} else {
$(message).text('Sorry...! an unexpected error has occured...!');
}
});
});
});
<html>
<head>
<meta charset="UTF-8">
<title>Ajax Practice</title>
<link href="assets/css.css" rel="stylesheet" type="text/css" />
<script src="assets/jquery.js" type="text/javascript"></script>
<script src="assets/ajax_code.js" type="text/javascript"></script>
</head>
<body>
<div class="login_form_div">
<form action="login.php" method="POST" name="login_form" id="login_form" class="login_form">
<div class="label">
<label>Email:</label>
</div>
<div class="form_input">
<input type="text" name="email" id="email">
</div>
<div class="label">
<label>Password:</label>
</div>
<div class="form_input">
<input type="password" name="password" id="password">
</div>
<div class="form_input">
<button type="submit" name="submit_form" id="submit_form">Login</button>
</div>
</form>
<span class="message1 error success" id="message">
</span>
</div>
</body>
</html>
your html and javascript is working perfectly.
can you post your php code?.
otherwise try put this code in your login.php file:
<?php
echo "form submitted";
?>
If you are using js fiddle then import the jquery js file on the dropdown on the left side of the panel.
$(function () {
//get form by id
var form = $('#login_form');
//get message container by is
var message = $('#message');
//prevent default on form submit
$(form).submit(function (event) {
event.preventDefault();
//serialize form data
var form_data = $(form).serialize();
$.ajax({
type: 'post',
url: $(form).attr('action'),
data: form_data
}).done(function (response) {
//set the class of message container to success
$(message).removeClass('error');
$(message).addClass('success');
//put data received from server
$(message).html(response);
//clear form
$('#email').val('');
$('#password').val('');
}).fail(function (data) {
//set the class of message container to error
$(message).removeClass('success');
$(message).addClass('error');
//put the error message
if (data.responseText !== '') {
$(message).html(data.responseText);
} else {
$(message).text('Sorry...! an unexpected error has occured...!');
}
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<html>
<head>
<meta charset="UTF-8">
<title>Ajax Practice</title>
<link href="assets/css.css" rel="stylesheet" type="text/css"/>
<script src="assets/jquery.js" type="text/javascript"></script>
<script src="assets/ajax_code.js" type="text/javascript"></script>
</head>
<body>
<div class="login_form_div">
<form action="login.php" method="POST" name="login_form" id="login_form" class="login_form">
<div class="label">
<label>Email:</label>
</div>
<div class="form_input">
<input type="text" name="email" id="email">
</div>
<div class="label">
<label>Password:</label>
</div>
<div class="form_input">
<input type="password" name="password" id="password">
</div>
<div class="form_input">
<button type="submit" name="submit_form" id="submit_form">Login</button>
</div>
</form>
<span class="message1 error success" id="message">
</span>
</div>
</body>
</html>
Actually the problem was here. as the default form submission is prevented through javascript and I was looking for the message.
if (isset($_POST['submit_form'])) {
$email = mysqli_real_escape_string($_POST['email']);
$password = mysqli_real_escape_string($_POST['password']);
if (!empty($email) && !empty($password)) {
echo "Login Must be Successful...!";
} else {
echo "Login Failed....!";
}
}
Related
i got something weird in my code. honestly, i got this from someone and i try to adapt it for my needs. So the problem is when i click fetch button, the data is not display. can any body here tell me what is wrong with the code?
Any related answer will be appreciated. Thanks in advance.
and here are my code
<script type="text/javascript">
$(document).ready(function() {
function myrequest(e) {
var name = $('.username').val();
$.ajax({
method: "GET",
url: "http://localhost/spdb/debug/autofill.php", /* online, change this to your real url */
data: {
username: name
},
success: function( responseObject ) {
alert('success');
$('#posts').val(responseObject.level);
$('#joindate').val(responseObject.last_login);
},
failure: function() {
alert('fail');
}
});
}
$('#fetchFields').click(function(e) {
e.preventDefault();
myrequest();
});
});
</script>
<html xml:lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1/themes/redmond/jquery-ui.css" type="text/css" rel="stylesheet">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js" type="text/javascript"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1/jquery-ui.min.js" type="text/javascript"></script>
</head>
<body>
<form method="POST" action="?act=proc">
<fieldset>
<legend>Form</legend>
<label for="username">Username: </label>
<input type="text" name="username" id="username">
<button id="fetchFields">fetch</button>
<label for="posts">Posts: </label>
<input type="text" size="20" name="posts" id="posts">
<label for="joindate">Joindate: </label>
<input type="text" size="20" name="joindate" id="joindate">
<p><input type="submit" value="Submit" name="submitBtn"></p>
</fieldset>
</form>
</body>
</html>
and this is the PHP code :
$return = mysqli_query($konek, "SELECT * FROM tb_auth WHERE username ='admin' LIMIT 1");
$rows = mysqli_fetch_array($return);
$formattedData = json_encode($rows);
print $formattedData;`
here are the result from PHP Code :
{
"0":"1",
"id_auth":"1",
"1":"TRC-US001",
"auth_code":"TRC-US001",
"2":"admin",
"username":"admin",
"3":"5f4dcc3b5aa765d61d8327deb882cf99",
"password":"5f4dcc3b5aa765d61d8327deb882cf99",
"4":"1",
"level":"1",
"5":"2018-07-05 13:55:19.200878",
"last_login":"2018-07-05 13:55:19.200878",
"6":"1",
"status":"1"
}
this is the picture :
result
Hope this can help you
first we need to do some modification on html, and php code :
<!-- doctype is mandatory -->
<!DOCTYPE html>
<!-- language en -->
<html lang="en">
<head>
<!-- title also is mandatory -->
<title>tilte of your project</title>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1/themes/redmond/jquery-ui.css" type="text/css" rel="stylesheet" />
</head>
<body>
<form method="POST" action="?act=proc">
<fieldset>
<legend>Form</legend>
<label for="username">Username: </label>
<input type="text" name="username" id="username">
<button id="fetchFields">fetch</button>
<label for="posts">Posts: </label>
<input type="text" size="20" name="posts" id="posts">
<label for="joindate">Joindate: </label>
<input type="text" size="20" name="joindate" id="joindate">
<p><input type="submit" value="Submit" name="submitBtn"></p>
</fieldset>
</form>
<!-- put all your javascript before the end of the body -->
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1/jquery-ui.min.js"></script>
<script>
$(document).ready(function() {
function myrequest(e) {
// use $('#username') to select by id instead of $('.username') used to select by class
var name = $('#username').val();
$.ajax({
method: "GET",
url: "http://localhost/spdb/debug/autofill.php", /* online, change this to your real url */
data: {
username: name
},
dataType: 'json', /* this is not mandatory */
success: function( responseObject ) {
console.log('success');
$('#posts').val(responseObject.level);
$('#joindate').val(responseObject.last_login);
},
failure: function() {
alert('fail');
}
});
}
$('#fetchFields').click(function(e) {
e.preventDefault();
myrequest();
});
});
</script>
</body>
</html>
php code :
// this line is very important, by using this line
// the browser can recognize that the data sent from
// the server as a json object.
header("Content-type: application/json");
$formattedData = [];
if (isset($_GET['username'])) {
$username = trim($_GET['username']);
// to be sure that the username is not empty
if(empty($username)) {
print json_encode($formattedData);
exit;
}
$konek = mysqli_connect($sql_db_host, $sql_db_user, $sql_db_pass, $sql_db_name, 3306);
$return = mysqli_query($konek, "SELECT * FROM tb_auth WHERE username = '" . $username . "' LIMIT 1");
// use mysqli_fetch_assoc instead of mysqli_fetch_array
// $rows = mysqli_fetch_array($return);
$rows = mysqli_fetch_assoc($return);
$formattedData = json_encode($rows);
// very important every connection created need to be closed
mysqli_close($konek);
}
print $formattedData;
In your html code, there is an input with an id username. In Javascript, search for this line of code var name = $('.username').val();. Change . to #. It should be var name = $('#username').val();.
.username is for any tag that have a class username.
#username will search for a tag that have an id username.
try to parse responseObject to json using
responseObject=JSON.parse(responseObject);
in you success function
I have login form, it is as follows, this will be let me login. I don't have experience with HTML and javascript.
<!DOCTYPE html>
<html lang="en">
<body>
<div class="container">
<h1> <b> Please sign in</b></h1>
<div id="login">
<form name="salesForm" id="submit_form">
<div class="form-group" id="UserNameD" >
<label for="UserName">Username</label>
<input id="UserName" type="text" name="UserName" class="form-control" required style="color:black">
</div>
<div class="form-group" id="passwordD" >
<label for="password">password</label>
<input id="password" type="password" name="password" class="form-control" required style="color:black">
</div>
<input id="submit" type="submit" class="btn btn-primary" value="submit">
</form>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<script src="https://netdna.bootstrapcdn.com/bootstrap/3.0.0/js/bootstrap.min.js"></script>
<script src="static/js/login.js?233"> </script>
</body>
</html>
I have following javascript file as follows:
$(document).ready(function() {
$('#submit_form').submit(function(ev) {
var form_data = $('#submit_form').serializeArray()
console.log(form_data);
$.ajax({
"type": "POST",
"async": false,
"url":'xxxx',
"data": form_data,
"cache": false,
"processData": false,
"contentType": false,
success: function ( res ) {
successcallback(res);
},
error: function( err ) {
alert("Login Fail");
}
});
function successcallback( res ) {
window.location.replace("xxxx");
}
});
});
It is not working, it is making get request at / not url that I put in login.js.
Thanks for your help
try to add:
$('#submit_form').submit(function(ev) {
ev.preventDefault(); // prevent default form behavior
to prevent page reload after sumbit clicked
I am using laravel 5.2,my question is:
How to show validation errors when submitting form with ajax ?
For example:
When ajax is not used,if the title field is not filled in, when submitting,there is an information :
"The title field is required."
And, when ajax is used,how to show the information above.
View:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<meta http-equiv="x-ua-compatible" content="ie=edge">
<meta name="csrf-token" content="{{ csrf_token() }}">
<link href="https://cdn.bootcss.com/bootstrap/4.0.0-alpha.2/css/bootstrap.min.css" rel="stylesheet">
<link href="https://cdn.bootcss.com/tether/1.1.1/css/tether.min.css" rel="stylesheet">
</head>
<body>
<div class="container">
<form id="formArticle" class="form-horizontal" role="form">
<fieldset class="row form-group">
<label class="col-xs-2 control-label">Title:</label>
<div class="col-xs-10">
<input id="title" name="title" type="text" class="form-control"
value="{{ old('title') }}">
<span class="help-block"><strong></strong></span>
</div>
</fieldset>
<fieldset class="row form-group">
<label class="col-xs-2 control-label">Content:</label>
<div class="col-xs-10">
<input id="content" name="content" type="text" class="form-control"
value="{{ old('content') }}">
<span class="help-block"><strong></strong></span>
</div>
</fieldset>
<fieldset class="row form-group">
<label class="col-xs-2 control-label" for="photo">Photo：</label>
<div class="col-xs-10">
<input id="photo" name="photo" type="file" class="form-control-file">
<span class="help-block"><strong></strong></span>
</div>
</fieldset>
<fieldset class="form-group">
<div class="col-xs-12">
<button id="submit" type="submit" class="btn btn-primary">Submit</button>
</div>
</fieldset>
</form>
<div class="alert alert-success" role="alert" hidden>
upload successfully
</div>
</div>
<script src="https://cdn.bootcss.com/jquery/2.1.4/jquery.min.js"></script>
<script src="https://cdn.bootcss.com/tether/1.1.1/js/tether.min.js"></script>
<script src="https://cdn.bootcss.com/bootstrap/4.0.0-alpha.2/js/bootstrap.min.js"></script>
</body>
</html>
Javascript:
<script>
$(function () {
var articleData = new FormData($('#formArticle')[0]);
$(document).on('submit', '#formArticle', function (e) {
e.preventDefault();
$('input+span>strong').text('');
$('input').parent().parent().removeClass('has-error');
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax({
type: "POST",
url: "{{ url('article/') }}",
dataType: 'json',
processData: false,
contentType: false,
cache: false,
data: articleData
})
.done(function (data) {
$(".alert-success").prop("hidden", false);
})
.fail(function (data) {
$.each(data.responseJSON, function (key, value) {
var input = '#formArticle input[name=' + key + ']';
$(input + '+span>strong').text(value);
$(input).parent().parent().addClass('has-error');
});
});
});
});
</script>
Controller:
public function store(Requests\StoreArticleRequest $request)
{
$article = new Article;
$article -> user_id = \Auth::id();
$article->title = $request->title;
$article->content = $request->content;
$photo = $request->photo;
$destinationPath = 'uploads/';
$extension = $photo->getClientOriginalExtension();
$photoName = \Auth::user()->id . '_' . time() . '.' . $extension;
$photo->move($destinationPath, $photoName);
$article -> photo = '/'.$destinationPath.$photoName;
$article->save();
}
StoreArticleRequest:
public function rules()
{
return [
'title'=>'required',
'content'=>'required',
'photo'=>'required'
];
}
Form data can be saved to database successfully if inputs are filled in completely.
But, when they are not filled in completely,or filled in nothing,
json message is shown in Chrome debugger's Preview and Response tags, like this:
{
"title":["The title field is required."],
"content":["The content field is required."],
...
}
But, the message can not be shown in html.
And ,at this time,".alert-success" is shown.
I don't know where the problems are in my code.
I think my understanding to done() and fail() is not right.
done() and fail() mean that ajax request is done or failed,
but not validation successful or failed,
no matter validation of laravel is successful or failed,
ajax request is done,
so,
even though I don't complete the inputs,
div class="alert alert-success" always appears .
You're getting the success message because done() is fired when a "good" response is received. While you're getting error messages, the actual response from the server is still a 200.
You'd want to check the data in done() to make sure it isn't an error. If title === "The title field is required.", you'd want to run the code that is currently in your fail().
.done(function (data) {
if(data.title[0] == 'The title field is required.' ) {
alert('Title is required');
}
else {
$(".alert-success").prop("hidden", false);
}
})
.fail(function (data) {
alert('The server failed somewhere');
});
Obviously, you'd want to do something other than alerts, and you'd want to check both fields, but that's the gist of it.
I am trying to understand the basics of using AJAX in conjunction with PHP in order to use php pages to provide functions, but not change my 'view' on my MVC design.
So I created this basic login page...
<!DOCTYPE html>
<head>
<title>learning Php</title>
<script src="//code.jquery.com/jquery-1.11.3.min.js"></script>
<!-- Latest compiled and minified JavaScript -->
<script type="text/javascript">
$(document).ready(function() {
$(#"login").click(function() {
var action = $("#form1").attr("action");
var form_data = {
username: $("#username").val(),
password: $("#password").val(),
is_ajax: 1
};
$.ajax({
type: "POST",
url: action,
data: form_data,
success: function(response)
{
if(response == 'success')
{
$("#form1").slideUp('slow', function() {
$("#message").html('<p class="success">You have logged in.</p>');
};
}
else
$("#message").html('<p class="error">Incorrect password or username.</p>');
}
});
return false;
});
});
</script>
</head>
<body>
<div>
<form name="form1" id="form1" method="post" action="loginForm.php">
<p>
<label for="username"> Username: </label>
<input type="text" id="username" name="username" />
</p>
<p>
<label for="password"> Password: </label>
<input type="text" id="username" name="username" />
</p>
<p>
<input type="submit" id="login" name="login" value="login" />
</p>
</form>
<div id="message"></div>
<div>
</body>
</html>
And this was my php page to "handle" to login...
<?php
$is_ajax = $_REQUEST['is_ajax'];
if(isset($is_ajax) && $is_ajax)
{
$username = $_REQUEST['username'];
$password = $_REQUEST['password'];
if($username == 'demo' && $password == 'demo')
{
echo 'success';
}
}
?>
The problem I am having is that whenever I submit my login, I am redirected to "/loginForm.php" instead of staying on my current page and having the message change underneath the login form.
I tried using Firebug to help me track down what I suspected to be a javascript error, but to no avail.
Any idea on why I am being redirected or why the form is not submitting via Ajax?
One more mistake here
if(response == 'success')
{
$("#form1").slideUp('slow', function() {
}); <--- You Missed ")" here
}
a small mistake
$(#"login").click(function() {
This should be
$("#login").click(function() {
^ // # inside quotes.
Besides the typo and Rocky's good catch on the }); <--- You Missed ")" here
Both your username and password fields are the same.
<label for="username"> Username: </label>
<input type="text" id="username" name="username" />
and
<label for="password"> Password: </label>
<input type="text" id="username" name="username" />
the 2nd one should read as
<input type="text" id="password" name="password" />
In using everyone's answer, you will have yourself a working script.
Remember to hash your password once you go LIVE.
Edit sidenote: I've made a note below about using a button, rather than an input.
Here's a rewrite, just in case. However that input needs to be a <button>.
<!DOCTYPE html>
<head>
<title>learning Php</title>
<script src="//code.jquery.com/jquery-1.11.3.min.js"></script>
<!-- Latest compiled and minified JavaScript -->
<script type="text/javascript">
$(document).ready(function() {
$("#login").click(function() {
var action = $("#form1").attr("action");
var form_data = {
username: $("#username").val(),
password: $("#password").val(),
is_ajax: 1
};
$.ajax({
type: "POST",
url: action,
data: form_data,
success: function(response)
{
if(response == 'success')
{
$("#form1").slideUp('slow', function() {
$("#message").html('<p class="success">You have logged in.</p>');
});
}
else
$("#message").html('<p class="error">Incorrect password or username.</p>');
}
});
return false;
});
});
</script>
</head>
<body>
<div>
<form name="form1" id="form1" method="post" action="loginForm.php">
<p>
<label for="username"> Username: </label>
<input type="text" id="username" name="username" />
</p>
<p>
<label for="password"> Password: </label>
<input type="text" id="password" name="password" />
<!--
Your original input
<input type="text" id="username" name="username" />
-->
</p>
<button type="submit" id="login" name="login" />LOGIN</button>
<!--
Your original submit input. Don't use it
<p>
<input type="submit" id="login" name="login" value="login" />
</p>
-->
</form>
<div id="message"></div>
</div>
</body>
</html>
Your last div just before </body> was unclosed </div>, I've changed that above.
Additional edit from comments.
It seems that there was probably a space inserted somewhere and the use of trim() was the final nail to the solution.
response.trim();
A special thanks goes out to Jay Blanchard to have given us a helping hand in all this, cheers Sam!
References (TRIM):
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/Trim
http://php.net/manual/en/function.trim.php
I want to create a stripe.js form, first the data should be validated client-side then submitted to stripe.js to get token. Here is my full source code:
<!DOCTYPE html><html>
<head>
<?php
print_r($_POST);
?>
<meta charset="utf-8">
<link rel="stylesheet" type="text/css" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script type="text/javascript" src="https://js.stripe.com/v2/"></script>
<script type="text/javascript" src="jquery.payment.js"></script>
<style type="text/css" media="screen">
.has-error input {
border-width: 2px;
}
.validation.text-danger:after {
content: 'Validation failed';
}
.validation.text-success:after {
content: 'Validation passed';
}
</style>
<script type="text/javascript">
jQuery(function($) {
$('[data-numeric]').payment('restrictNumeric');
$('.cc-number').payment('formatCardNumber');
$('.cc-exp').payment('formatCardExpiry');
$('.cc-cvc').payment('formatCardCVC');
$.fn.toggleInputError = function(erred) {
this.parent('.form-group').toggleClass('has-error', erred);
return this;
};
$('button[type="submit"]').click(function(e){
e.preventDefault();
var cardType = $.payment.cardType($('.cc-number').val());
$('.cc-number').toggleInputError(!$.payment.validateCardNumber($('.cc-number').val()));
$('.cc-exp').toggleInputError(!$.payment.validateCardExpiry($('.cc-exp').payment('cardExpiryVal')));
$('.cc-cvc').toggleInputError(!$.payment.validateCardCVC($('.cc-cvc').val(), cardType));
$('.cc-brand').text(cardType);
$('.validation').removeClass('text-danger text-success');
if ($('.has-error').length) { $('.validation').addClass('text-danger') } else { $('form').submit(); }
});
});
Stripe.setPublishableKey('pk_test_***');
jQuery(function($) {
$('#payment-form').submit(function(event) {
var $form = $(this);
// Disable the submit button to prevent repeated clicks
$form.find('button').prop('disabled', true);
Stripe.card.createToken($form, stripeResponseHandler);
// Prevent the form from submitting with the default action
return false;
});
});
function stripeResponseHandler(status, response) {
var $form = $('#payment-form');
if (response.error) {
// Show the errors on the form
$form.find('.payment-errors').text(response.error.message);
$form.find('button').prop('disabled', false);
} else {
// response contains id and card, which contains additional card details
var token = response.id;
// Insert the token into the form so it gets submitted to the server
$form.append($('<input type="hidden" name="stripeToken" />').val(token));
// and submit
$form.get(0).submit();
}
};
</script>
</head>
<body>
<div class="container">
<form action="" method="post" id="payment-form" novalidate autocomplete="on">
<span class="payment-errors"></span>
<div class="form-group">
<label for="cc-number" class="control-label">Card number:<small class="text-muted">[<span class="cc-brand"></span>]</small></label>
<input id="cc-number" data-stripe="number" type="tel" class="input-lg form-control cc-number" autocomplete="cc-number" placeholder="•••• •••• •••• ••••" required class="col-md-2">
</div>
<div class="form-group">
<label for="cc-exp" class="control-label">Card expiry:</label>
<input id="cc-exp" type="tel" class="input-lg form-control cc-exp" autocomplete="cc-exp" placeholder="•• / ••" required class="col-md-2">
</div>
<div class="form-group">
<label for="cc-cvc" class="control-label">CVC:</label>
<input id="cc-cvc" data-stripe="cvc" type="tel" class="input-lg form-control cc-cvc" autocomplete="off" placeholder="•••" required class="col-md-2">
</div>
<button type="submit" class="btn btn-lg btn-primary">Submit</button>
<h4 class="validation"></h4>
</form>
</div>
</body>
</html>
This form for expiry uses just one field and it will be submitted as mm/yy to validator, validator works fine but after successfull validation, I want to split mm/yy separated and assign each of them to data-stripe="exp-month" and data-stripe="exp-year" respectively before submitting to stripe.js as those two data-stripe="exp-month" and data-stripe="exp-year" are required by stripe.js.
for validator I use this 3rd party script: https://github.com/stripe/jquery.payment/tree/master/lib
I see it has already a feature to split mm and yy here https://github.com/stripe/jquery.payment#paymentcardexpiryvalstring-and-fnpaymentcardexpiryval , but I have no idea how to use that function to split fom expiry date and assign them to data-stripe="exp-month" and data-stripe="exp-year"
Please advice how can I do this?
Stripe.js can accept expiry dates as a single argument: https://stripe.com/docs/stripe.js#passing-exp-dates
So you don't need to split the date. Just adding data-stripe="exp" to the cc-exp field should do the trick:
<input id="cc-exp" data-stripe="exp" type="tel" class="input-lg form-control cc-exp" autocomplete="cc-exp" placeholder="•• / ••" required class="col-md-2">