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Actually, i have created form using php i have to form fields pass to google spreadsheet how to pass ? please help me.
I have to store all the Form data to Google Spreed sheet How to Implement this one . I have blow put my code please check it. Kindly any one help me. Blow is my
I can't add comment so I am posting it as answer:
you might check this out, it's GIT source from heaversm :
https://github.com/heaversm/google-custom-form.
I hope this will help .
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I use translation to talk to you because I got tired of searching a lot in Arabic explanations and did not find a solution. I have a chat site programmed with "node.js" with a mysql database and there is a security vulnerability that some users do (check element > control panel) that puts this code "socket.emit('broadcasting', {cmd: 'send'});" is restarting the entire site. I want a solution to this problem. Is there a way to prevent users from placing this code in (check element > console)or any other solution? Thank you.
I tried obfuscating the code but it didn't work
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I am using bootstrap-table by wenzhixin on Github it is this one
I want to do a button that would toggle filter, Filtering works but when I try do display all the Data again In does not Work, I have struggled with this issue in two days but I can't figure out how to do it.
I tried
$('#table').bootstrapTable('load', $('#table').bootstrapTable('getData')); but It doesn't work it seems that getData gives the already filtered data
$('#table').bootstrapTable('load', data);
where data is the array of my Data but it does not change anything
I wanted to use $('#table').bootstrapTable('refresh') ,but It does not support local data.
Here is my JSFiddler https://jsfiddle.net/pacitwizere/4y3079s7/2/
Your data variable will not be updated by bootstrapTable filterBy feature. Adding the following line to your click functions will make it work.
$('#table').bootstrapTable("filterBy", )
$('#table').bootstrapTable("filterBy", {"forks_count": ["11","4"]})
How about this?
https://jsfiddle.net/4y3079s7/4/
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I realise this might look like a duplicate but I don't think it is. I've looked everywhere.
What I'm attempting to do is get the URL of the page the user is currently on, but I'm attempting to do this in a separately loaded page.
$('#siteStatus').load('/_backend/account/accountStatus.php');
I want to load a script into this div that works out the current page of the url.
At the moment I am doing $url = "{$_SERVER['REQUEST_URI']}"; but this just returns /_backend/account/ and I'm unsure why.
Any help is appreciated.
Thanks to #prasad using print_r($_SERVER); showed an array of what I could use and it turns out $_SERVER['HTTP_REFERER'] was what I needed.
Thanks.
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I'm trying to replicate this: https://tympanus.net/codrops/2014/01/07/shape-hover-effect-with-svg/
It works on my localhost but not on WordPress. Any advice is greatly appreciated.
Many Thanks!
When you say not on Wordpress could you clarify? Is this wordpress.com, your web hosted version of Wordpress or a localhost version?
The first thing to do is check the mime type if you have posted the svg to a web server.
Could you post a url so I can see what the issue is first off, then I can help you figure what to do next to fix it.
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I'm trying to get eBay suggested values for searching purposes against the given keyword. A prototype can be found here. Can anyone help me to figure out the problem in code?
The problem is due to the Same Origin Policy - you cannot make an AJAX call to any domain other than the current, unless the format of the request is JSONP.
The workaround is to use a server-side proxy on your domain (such as in this example) to get the XML file, and then have your jQuery load that.