How to declare associative array of regex?
This is not working
var Validators = {
url : /^http(s?)://((\w+\.)?\w+\.\w+|((2[0-5]{2}|1[0-9]{2}|[0-9]{1,2})\.){3}(2[0-5]{2}|1[0-9]{2}|[0-9]{1,2}))(/)?$/gm
};
EDITED: Now working!
This will be valid in JS (like # operator in C#)
url : `/^http(s?)://((\w+\.)?\w+\.\w+|((2[0-5]{2}|1[0-9]{2}|[0-9]{1,2})\.){3}(2[0-5]{2}|1[0-9]{2}|[0-9]{1,2}))(/)?$/gm`
However, will still not work due to double escape, one in JS and other in Regex. If expression is small, perhaps naked eye can manually escape for both JS and Regex. My brain just can't :)
In order to use strings as tested on regex101.com for example, all required strings should be declared as 'row' like this:
var exp = String.raw`^(http(s?):\/\/)?(((www\.)?[a-zA-Z0-9\.\-\_]+(\.[a-zA-Z]{2,3})+)|(\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b))(\/[a-zA-Z0-9\_\-\s\.\/\?\%\#\&\=]*)?$`;
var strings = [
String.raw`http://www.goo gle.com`,
String.raw`http://www.google.com`,
];
Wrap it with new RegExp() and escape slashes
var Validators = {
url : new RegExp( /^http(s?):\/\/((\w+\.)?\w+\.\w+|((2[0-5]{2}|1[0-9]{2}|[0-9]{1,2})\.){3}(2[0-5]{2}|1[0-9]{2}|[0-9]{1,2}))(\/)?$/gm )
};
Your regex has forward slashes in it. This symbol needs to be escaped because it is supposed to indicate the start and end of the expression. Try \/.
Related
I'm trying to write my regex as string (it's part of my S-Expression tokenizer that first split on string, regular expressions and lisp comments and then tokenize stuff between), it works in https://regex101.com/r/nH4kN6/1/ but have problem to write it as string for php.
My JavaScript regex look like this:
var pre_parse_re = /("(?:\\[\S\s]|[^"])*"|\/(?! )[^\/\\]*(?:\\[\S\s][^\/\\]*)*\/[gimy]*(?=\s|\(|\)|$)|;.*)/g;
I've tried to write this regex in php (the one from Regex101 was inside single quote).
$pre_parse_re = "%(\"(?:\\[\\S\\s]|[^\"])*\"|/(?! )[^/\\]*(?:\\[\\S\\s][^/\\]*)*/[gimy]*(?=\\s|\\(|\\)|$)|;.*)%";
My input
'(";()" /;;;/g baz); (baz quux)'
when called:
$parts = preg_split($pre_parse_re, $str, -1,
PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
it should create same array as in Regex101 (3 matches and stuff between) but it keep splitting on first semicolon inside regex /;;;/g
I think your escaping might be incorrect. Try this regex instead:
$pre_parse_re = "%(\"(?:\\\\[\\\\S\\\\s]|[^\"])*\"|\/(?! )[^\/\\\\]*(?:\\\\[\S\s][^\/\\\\]*)*\/[gimy]*(?=\s|\(|\)|$)|;.*)%";
Using preg_split might also return more than the capturing groups that you want, so you could also change to use this if you just want the 3 matches.
$parts;
preg_match_all($pre_parse_re, $str, $parts, PREG_SET_ORDER, 0);
I have a regular expression that I have been using in notepad++ for search&replace to manipulate some text, and I want to incorporate it into my javascript code. This is the regular expression:
Search
(?-s)(.{150,250}\.(\[\d+\])*)\h+ and replace with \1\r\n\x20\x20\x20
In essence creating new paragraphs for every 150-250 words and indenting them.
This is what I have tried in JavaScript. For a text area <textarea name="textarea1" id="textarea1"></textarea>in the HTML. I have the following JavaScript:
function rep1() {
var re1 = new RegExp('(?-s)(.{150,250}\.(\[\d+\])*)\h+');
var re2 = new RegExp('\1\r\n\x20\x20\x20');
var s = document.getElementById("textarea1").value;
s = string.replace(re1, re2);
document.getElementById("textarea1").value = s;
}
I have also tried placing the regular expressions directly as arguments for string.replace() but that doesn't work either. Any ideas what I'm doing wrong?
Several issues:
JavaScript does not support (?-s). You would need to add modifiers separately. However, this is the default setting in JavaScript, so you can just leave it out. If it was your intention to let . also match line breaks, then use [^] instead of . in JavaScript regexes.
JavaScript does not support \h -- the horizontal white space. Instead you could use [^\S\r\n].
When passing a string literal to new RegExp be aware that backslashes are escape characters for the string literal notation, so they will not end up in the regex. So either double them, or else use JavaScript's regex literal notation
In JavaScript replace will only replace the first occurrence unless you provided the g modifier to the regular expression.
The replacement (second argument to replace) should not be a regex. It should be a string, so don't apply new RegExp to it.
The backreferences in the replacement string should be of the $1 format. JavaScript does not support \1 there.
You reference string where you really want to reference s.
This should work:
function rep1() {
var re1 = /(.{150,250}\.(\[\d+\])*)[^\S\r\n]+/g;
var re2 = '$1\r\n\x20\x20\x20';
var s = document.getElementById("textarea1").value;
s = s.replace(re1, re2);
document.getElementById("textarea1").value = s;
}
I've been trying to use Regex in my Javascript codes for to collapse indicated gaps like the below. But I couldn't manage that;
this works;
outputFile = outputFile.replace(/\s*<div/g, '<div');
these don't work;
htmlElements = [
"div",
"form",
"label",
"input"
];
var exp = new RegExp("\s*<"+htmlElements[0], 'g')
var str = "<"+htmlElements[0];
outputFile = outputFile.replace(exp, str);
Exactly the same expressions except using variable. Also I checked my expression on here https://regex101.com/r/eJ5kJ2/2 and here http://regexper.com/#%2F%5Cs*%3Cdiv%2F. And I tried both on Chrome and Firefox too.
Is there any chance to overcome this issue?
You have to escape all \s to \\ because you define your regex as string, not as regex literal
new RegExp("\\s*<"+htmlElements[0], 'g')
Beside that: you may want to use a html parser instead of regex to accomplish your task
I know there are many questions about variables in regex. Some of them for instance:
concat variable in regexp pattern
Variables in regexp
How to properly escape characters in regexp
Matching string using variable in regular expression with $ and ^
Unfortunately none of them explains in detail how to escape my RegExp.
Let's say I want to find all files that have this string before them:
file:///storage/sdcard0/
I tried this with regex:
(?:file:\/\/\/storage\/sdcard0\(.*))(?:\"|\')
which correctly got my image1.jpg and image2.jpg in certain json file. (tried with http://regex101.com/#javascript)
For the life of me I can't get this to work inside JS. I know you should use RegExp to solve this, but I'm having issues.
var findStr = "file:///storage/sdcard0/";
var regex = "(?:"+ findStr +"(.*))(?:\"|\')";
var re = new RegExp(regex,"g");
var result = <mySearchStringVariable>.match(re);
With this I get 1 result and it's wrong (bunch of text). I reckon I should escape this as said all over the web.. I tried to escape findStr with both functions below and the result was the same. So I thought OK I need to escape some chars inside regex also.
I tried to manually escape them and the result was no matches.
I tried to escape the whole regex variable before passing it to RegExp constructor and the result was the same: no matches.
function quote(regex) {
return regex.replace(/([()[{*+.$^\\|?])/g, '\\$1');
}
function escapeRegExp(str) {
return str.replace(/[\-\[\]\/\{\}\(\)\*\+\?\.\\\^\$\|]/g, "\\$&");
}
What the hell am I doing wrong, please?
Is there any good documentation on how to write RegExp with variables in it?
All I needed to do was use LAZY instead of greedy with
var regex = "(?:"+ findStr +"(.*?))(?:\"|\')"; // added ? in (.*?)
Im using this snippet to replace several characters in a string.
var badwords = eval("/foo|bar|baz/ig");
var text="foo the bar!";
document.write(text.replace(badwords, "***"));
But one of the characters I want to replace is '/'. I assume it's not working because it's a reserved character in regular expressions, but how can I get it done then?
Thanks!
You simply escape the "reserved" char in your RegExp:
var re = /abc\/def/;
You are probably having trouble with that because you are, for some reason, using a string as your RegExp and then evaling it...so odd.
var badwords = /foo|bar|baz/ig;
is all you need.
If you INISIST on using a string, then you have to escape your escape:
var badwords = eval( "/foo|ba\\/r|baz/ig" );
This gets a backslash through the JS interpreter to make it to the RegExp engine.
first of DON'T USE EVAL it's the most evil function ever and fully unnecessary here
var badwords = /foo|bar|baz/ig;
works just as well (or use the new RegExp("foo|bar|baz","ig"); constructor)
and when you want to have a / in the regex and a \ before the character you want to escape
var badwords = /\/foo|bar|baz/ig;
//or
var badwords = new RegExp("\\/foo|bar|baz","ig");//double escape to escape the backslash in the string like one has to do in java