Using gulp, what is a proper way to inject one js file into another?
I know about gulp-browserify, but that wraps each require'd file in it's own IIFE so variables are no longer global and, unfortunately, I need them to be global.
I know I can also concat all JS files into one, but I would like to generate separate JS files.
Is there a way to simply include the contents of one file within another where I can specify the concatenation in the JS file itself instead of in Gulp's configuration file?
Related
A javascript file containing import statements referencing Firebase browser modules embedded in an HTML file needs to be declared as type="module". But after conversion to ES6 modules, this qualifier seems to be optional.
Is a "bundled" javascript file no longer regarded as a module? It certainly still behaves like a module, at least in the sense that a Javascript function in your bundled file remains unavailable to the DOM (eg, an "onclick" reference to a bundled function won't work).
Examples of tags in Google documents seem to confirm the pattern - scripts using browser modules should be declared type="module", bundled scripts should be left unqualified. But what exactly is going on here?
Advice would be much appreciated
Yes, before you build an app, i.e. before you do npm run build, remove type="module" from all the script tags.
What happens under the hood is that the bundler puts all the code from your .js files into one big file.
You can find that file inside you dist folder.
If you're using Webpack or Parcel or any other bundler, they convert JS from ES6+ to ES5, and ES5 does not support import statements, that is why it puts all the js code into one big file.
I'm pretty new to Typescript. I'm about to work on a Js project and I want to use Typescript because provides modularity features which helps me to maintain and develop the project more easily.
I put each class inside one single ts file and imported all of them in the main.ts file. I used --outFile flag to compile all of them into a single js file
but the problem is I want to finally compile them into a single js file and easily attach it to HTML file without any other preliminaries such as importing require.js! is there any way to do it without importing any other js files to the HTML document? if not, please suggest me an alternative way!
because I want to just compile all the stuff into one file like jquery.js file.
I used --outFile
Use outFile only if your code doesn't depend on any other library as it is straight concatenation.
the problem is I want to finally compile them into a single js file and easily attach it to HTML file without any other preliminaries such as importing require.js
This will only happen if you used a module aka import/export statement in your code. These require a module loader. outFile should not be used if you are using modules.
Thoughts
Personally I recommend commonjs with webpack
This is what I was looking for
https://www.typescriptlang.org/docs/handbook/gulp.html
I am trying to require files dynamically with Webpack like so:
this.svg = require(`resources/assets/images/svg/${this.name}.svg`);
Of course because this code only runs in NodeJS, Webpack has no clue what this.name is and creates a context.
With the context it grabs all the files from that particular directory and jams them into my javascript bundle. I do not want all of the files from this directory though I just want the ones want this exact name.
Since this can't be achieved at runtime is there a way to provide a static list of files which Webpack can run through?
Sort of like a forEach with require.
The Answer is below the question:
Maybe I don't understand the whole RequireJS thing fully,
but here is my problem:
I got a set of files like that:
sub
sub1.js
sub2.js
main.js
In all of the files in sub, i use the define() function to define modules. In the main.js, i use the require() function to load all modules. All of this works.
Now when i run the optimizer (r.js) on the main.js, it just takes the content of all files and puts it into one file. Yes, i can then use this optimized file to do the same as what i could do with the multiple files.
All good, no error.
Now my question: In that optimized file, it still uses RequireJS. Can i optimize it to the point, where it doesn't use RequireJS, where it's just the functions put together?
Answer
You can only include RequireJS into your optimized file by setting the include option to "requireLib".
Are you trying to load the file in the script tag w/o using data-main + require.js? OR, are you trying to render the file so that RequireJS is no longer used at all? I suspect it's the latter, which is not possible. If the former, that is achieved by bundling Require in via a build file option: http://youtu.be/m6VNhqKDM4E?t=12m44s
No you cant. The point of the r.js is to compile all your dependencies situated in multiple files into one. So even after compiling the modules are still AMD modules, but now without the need to load them separately. And the modules still need an AMD loader to get work. The only thing you can do after compiling is to use a more lightweight loader loader like Almond
after optimizing a require.js project (pushing everything into one "big" .js file), is there any way to circumstance the need to include the require.js file (which then only loads one single .js file) and load the compiled file directly instead?
You can use a light weight AMD loader like Almond. You will still need a loader anyway as your compiled JavaScript still use define and require.