For example:
<div class="div1">
<div class="div2">
</div>
<div class="div3">
</div>
<div class="div4">
</div>
<div class="div5">
</div>
...
</div>
Imaging that the blocks are big ones, and the browser view cannot hold all of them at the same time. Is there a way if I can get idea that a particular block get displayed and viewed by user?
Related
I am trying to create a sliding tile structure in Sharepoint.
I have already succeeded in having the tile slide open once when it is clicked on the basis of a parent and child tile. Now I would like it to be able to slide open again, so three-part drop menu
<div class="tile largeTile green" onclick="DropDown(this)" Parent="tegel">
<div class="tileFront" title="S2">
<div class="title">
Tegel
</div>
</div>
</div>
<!--Start Child containers for tegel-->
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<div class="tile green DocumentChild" Parent="tegel">
<div class="tileFront" title="test" onclick="window.open('link','_blank')">
<div class="title">
schuif
</div>
</div>
</div>
<!--End of child containers tegel-->
I tried putting a child after a child but it doesn't work, and I have no idea how to use the 'element' code. I read somewhere about an element as 3rd menu but I have no idea how to insert it in the code.
There are still 2 files, 1 .css file containing the layout of the tiles and Javascript for the operation of the tiles. I will probably need to add code to this as well.
Hopefully someone can help me with this
Good evening,
I have a question regarding the Bootstrap 4.1 Grid. I built a normal website with multiple "containers" and "columns".
<div class"container">
<div class"row">
<div class="col-12">
CONTENT
</div>
</div>
</div>
<div class"container">
<div class"row">
<div class="col-12">
CONTENT
</div>
</div>
</div>
On normal displays, this works perfectly fine as both containers are showed underneath each other.
But on very large screens the containers are besides each other.
How can I adjust my code, so that independently of the screen size, the containers are always showed below each other.
Thank you in advance!
I can't really reproduce your issue but you might be missing an equal sign in your classes.
class="container"
class="row"
You are missing equals
<div class="container">
<div class="row">
<div class="col-12">
CONTENT
</div>
</div>
</div>
<div class="container">
<div class="row">
<div class="col-12">
CONTENT
</div>
</div>
</div>
I'm currently building a website and have an image as the header, but when I load the page it will jump half way down the page, load the image and then jump back up. How can I make the image load in first to prevent it from jumping?
HTML:
<div class="refocus" id="hero-header">
<div class="refocus-img-bg"></div>
<div class="refocus-img focus-in">
HTML:
</div>
<div class="refocus-text-container">
<div class="t">
<div class="tc">
</div>
</div>
</div>
</div>
<div class="row">
<div class=".col-md-6">
<div id="section1">
<div id = "sub-text">
<h1>Hello</h1>
<br>
<h2>Hello</h2>
<h3><br>Hello.</h3>
</div>
<div id="image">
<img src="images/aboutme.png"/>
</div>
</div>
<div id="buttoncontainer">
<div id="totimeline">▼</div>
</div>
</div>
</div>
Here's a JSFiddle to replicate this.
Thank you in advance.
You can do one of two things for this.
1) Set the dimensions of your image inline. This is actually a recommended method of preventing the very thing you are experiencing where the page jumps around after images load in. By setting the dimensions inline, the browser will already know how tall the image needs to be and will reserve the space for it before it even finishes loading in.
Example:
<img src="http://placehold.it/350x150" height="150" width="350">
2) If you don't prefer to set the dimensions inline, it seems you could also just set the height in your styles ahead of time and that would do the trick as well.
Example:
.refocus-img{
height:150px;
}
I'm trying to automate a clicking of a link within a class list. Currently I have a working script that will pick the first item in the container using the querySelector(), one line of code wrapped in a function.
To have more usability, I was wondering if I could modify the code so that the script searches within each item in the container trying to match a title of the listing or name with a defined variable, to the users desire, and once found, clicks the link for that particular item.
<div class="item-wall">
<div class="grid-item" data-column-index="0" data-pdpurl="http://www.LINK1.com">
<div class="grid-item"> … </div>
<div class="content">
<div class="grid-item-details-wrapper">
<div class="grid-item-image"> … </div>
<div class="grid-item-info-wrapper no-chipper">
<a href="http://www.LINK1.com">
<div class="product-name">
<p class="griditem-display-name nsg-font-size--regular nsg-text--dark-grey">
PRODUCT1
</p>
<p class="griditem-subtitle nsg-font-size--regular nsg-text--medium-grey"> … </p>
</div>
<div class="product-price-wrapper"> … </div>
</a>
</div>
<div class="grid-item-extras"> … </div>
</div>
</div>
</div>
<div class="grid-item" data-column-index="1" data-pdpurl="http://www.LINK2.com">
<div class="grid-item"> … </div>
<div class="content">
<div class="grid-item-details-wrapper">
<div class="grid-item-image"> … </div>
<div class="grid-item-info-wrapper no-chipper">
<a href="http://www.LINK2.com">
<div class="product-name">
<p class="griditem-display-name nsg-font-size--regular nsg-text--dark-grey">
PRODUCT2
</p>
<p class="griditem-subtitle nsg-font-size--regular nsg-text--medium-grey"> … </p>
</div>
<div class="product-price-wrapper"> … </div>
</a>
</div>
<div class="grid-item-extras"> … </div>
</div>
</div>
</div>
<div class="paging-bar hidden"> … </div>
<div class="spacer"></div>
</div>
Sorry for being so verbose. The web page has an 'item-wall' with several items, 2 are only shown here. I wish to be able to set a variable as a string in the script and be able to use something along the lines of .contain() to find an instance of the matching product name in the wall and then have it open the link corresponding to the selection.
Thanks for any input!
/////////////////////////////////////////////////////////////////////////////////////////////
EDIT: Thanks to #Barmar for the working console function:
function product_click(product) {
$(".griditem-display-name:contains("+product+")").closest("a").click();
}
product_click("Desirable here")
Now I am at a loss as to how to make this function operational in an script. I've tried with scriptish in firefox and have tried writing this to a .js file and loading it as an unpacked extension in chrome to no avail. It seems as though the function/script won't load. If anyone has any thoughts, they'd be greatly appreciated.
Thanks again!
If I understand you correctly, I think this is it:
function product_click(product) {
$(".griditem-display-name:contains("+product+")").closest("a").click();
}
Can someone please explain the structure of this line of a script for me? Another user on here has written it as part of a function that I know want to edit and change to use elsewhere on my site.
$('#main_content .img-wrapper').empty().append($(this).find('img').clone());
This one takes an image from one div and copies it to another with the class="img-wrapper"
I want to do exactly the same but with text. I tried this
$('#main_content .text-wrapper').empty().append($(this).find('.info').clone());
where ('.info') is the class name of the div I want to copy. Its not working.
I don't fully understand the syntax as this is my first day using javascript. Please can someone explain where I'm going wrong?
This is the HTML - There are four different images and when the user clicks on each of the image I want it to load the same image and associated text in the main content div
<div class="row">
<div class="card-container">
<div class="card">
<div class="back">
<img src="images1.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#cc99cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images2.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#9966cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images3.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#6666cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images4.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#3366cc;"></div>
</div>
</div>
This is the main content div
<div id="main_content">
<!-- main content -->
<div class="img-wrapper">
</div>
<div class="text-wrapper">
</div>
</div>
The javascript in question is using jQuery.
$('#main_content .img-wrapper')
returns the element(s) with class 'img-wrapper' inside the element with id 'main_content'
.empty()
empties this element (removes all it's HTML contents)
.append(
inserts the argument (the bit that comes next) into this element
$(this).find('img')
finds all 'img' tags within the element referred to by this (i.e. if this was triggered from a .click() handler then the element that was clicked)
.clone()
clones these elements so that there are two versions - one in their original location and one being inserted into the #main_content img-wrapper element.
);
Do you definitely have a #main_content .text-wrapper element?
Without seeing the html structure, my guess would be the context in which you're trying to find .info is incorrect.
I'm assuming this block of code is within an event handler like a click or mouseover or something. In that case the $(this) is referring to the element that triggered that event. So the following snippet:
$(this).find('.info')
is looking for elements with a classname of info within the element referred to by $(this).
Make sure the context is correct - change $(this) to the element that you need to search within.
Try this:
$('#main_content .text-wrapper').empty().append($(this).find('.info').html());