I submit a form manually via jQuery. I use FormData with all input elements from this form.
See code below:
$("#submit-form").on('submit', function (event) {
event.preventDefault();
var form = $('#submit-form')[0];
var data = new FormData(form);
$.ajax({
type: "POST",
url: "my-best-handler",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 60000
});
});
One of input elements is file and it's optional to set it. When it's not set, I don't need to use it in FormData and be sent with other elements to request handler.
The problem is that currently it will be sent even if it's not set.
I'm curious how I can exclude it from FormData if it's not set.
In worst case I can create FormData manually like here.
But I hope there is "black list" like approach by removing just not set file from FormData OR any other elegant way.
Update:
I came with the following solution:
if (!$("#input-file").val()) {
data.delete('input-file');
}
You can use the delete() function to remove your field
var form = $('#submit-form')[0];
var data = new FormData(form);
if (!$("#input-file").val()) {
data.delete('input-file');
}
Disabling input approach.
Disabled form controls never get submitted
$("#submit-form").on('submit', function (event) {
event.preventDefault();
// disable before creating FormData
$(this).find(':file').prop('disabled', function(){
return !this.files.length;
});
var form = $('#submit-form')[0];
var data = new FormData(form);
As mentioned in comments should re-enable in ajax success callback
Running into a bit of trouble trying to upload multiple files through a single AJAX request into a Laravel 5 back-end.
In the front-end, I am using the following code to prep the FormData object:
var fd = new FormData();
fd.append("data", JSON.stringify(values));
fd.append("page_id", page_id);
files.forEach(function(file, index){
fd.append("file_"+index, file);
});
Then this is my AJAX call:
$.ajax({
type: 'POST',
url: '/file_test',
data: fd,
contentType: false,
processData: false,
success: function(response){
alert(response);
},
failure: function(response){
alert(response);
}
});
In the back-end, I've tried to retrieve with $request->allFiles() and $request->file('file_0') as well as $_FILES but they are all turning up empty.
After #Pavel mentioned that the $_FILES array was empty, I went and checked what was being sent up in the XHRRequest. What I realized was that I was not appending the file itself to the FormData object and instead was appending the whole input containing the file.
var files = [];
if(this.type == "file"){
if(this.files.length == 1){
values[$(this).attr('name')] = this.files[0].name;
//files.push(this); // ORIGINAL CODE
files.push(this.files[0]); // WORKING CODE!
}
}
Alright guys I'm trying to make a filter system for posts using ajax and a select box. I am able to get the value from the select box no problem. But my issue is that when I try to include the selected value in my PHP file it doesn't do anything. I have a file called public_wall.php. This file contains PHP, Javascript, and HTML. How can I refresh this div whenever a user selects a different filter option? Basically I need the selected value to be passed onto my public_wall.php file and then I want to plug it into the PHP function that fetches the posts thats's in the same file and then I want to refresh that same file to display the filtered results. Here is my Javascript code.
$("#postRatings").on("click", function(e) {
selectedRatingFilter = $("#postRatings option:selected").val();
var dataString = "timeFilter="+selectedRatingFilter;
jQuery.ajax({
type: "POST",
url: site_url+"public_wall.php",
data: dataString,
dataType: "json",
cache: false,
success: function(response){
hideSpinner();
jQuery('#postsPagingDiv').remove();
jQuery('#wsc_midbox').html(jQuery(response.htmls).fadeIn(400));
setpost_ids(response.all_post_id);
jQuery('#paging_in_process').val(0);
}
});
});
When the dataType is set to "json" nothing happens. But when it is set to html it prints some javascript code. Please help. The PHP file is too large to include here, but it basically contains PHP, HTML, and Javascript and some PHP functions that do sql queries. What is the best way to achieve a filter mechanism for my setup?
And on the public_wall.php file I want to get the value like so:
$ratingFilter = isset($_REQUEST['timeFilter']) ? intval($_REQUEST['timeFilter']) : 0;
And then plug it into the PHP function that fetches the posts which is in the public_wall.php file also so that I can filter the posts based on the selected value. And then finally I want to refresh the public_wall.php file with the new results. I hope that makes sense. Please help.
This is the output when I set my dataType to "html"
<script>
function refreshPosts() {/* only posts comments likes and count updated. */
var posts = jQuery("#all_post_id").val();
var arrays = posts.split(',');
var dataString = "postids="+posts;
jQuery.ajax({
type: "POST",
url: site_url+"includes/update_wall.php",
data: dataString,
dataType: "json",
cache: false,
success: function(response) {
var x = response;
//############ skip posts whose comments are being read by users
var ExemptedPostsIDs = jQuery("#exemptedPostsID").val();
var ExemptedArray = ExemptedPostsIDs.split(',');
ExemptedArray = ExemptedArray.sort();
//////////////
for (i=0; i<arrays.length; i++) {
var val = 'row'+arrays[i];
if(x[val]) {
if(!inArray(arrays[i], ExemptedArray))
jQuery("#ajax_wall_"+arrays[i]).html(x[val]);
} else {
jQuery('#PostBoxID'+arrays[i]).parent().fadeOut(500);
}
}
}
});
}
function inArray(needle, haystack) {
var length = haystack.length;
for (var i = 0; i < length; i++) {
if(haystack[i] == needle) return true;
}
return false;
}
function refreshWall() {/* loads new posts real time */
var posts = jQuery("#all_post_id").val();
var pageUsing = jQuery('#pageUsing').val();
var dataString = "update_posts=1&postids="+posts+'&pagex='+pageUsing;
jQuery.ajax({
type: "POST",
url: site_url+"public_wall.php",
data: dataString,
dataType: "json",
cache: false,
success: function(response) {
if(response.all_post_id) {
jQuery('#wsc_midbox').prepend(jQuery(response.htmls).fadeIn(400));
setpost_ids(response.all_post_id);
}
}
});
}
</script>
I suggest you keep the form with select element and any JavaScript on the outer frame.
Via ajax, only load the results to a seperate DIVision below that.
When you put an Ajax response to a div, any JavaScript inside it will not be executed.
For the best throughput with Ajax, you should consider loading a json response via Ajax and create HTML elements on the client side. That way it becomes much easier to pull additional variables to front-end JS from server side along with the same request/response.
But that becomes bit difficult when you have a template engine in the back-end. You can still send the HTML content in a json value, so you can easily pass the "all_post_id" as well..
I would like to get a form object and submit the data to server with a button click in Asp.net MVC.
This is my HTML code:
<form method="post" form-sync="ajax">
#Html.Hidden("InvtId", item.InvtId)
</form>
This is my JS code:
$(document).on("click", "[form-sync='ajax']", function() {
var formdata = new FormData($(this).closest("form")),
url = $(this).data("url");
$.ajax({
url: url,
type: "POST",
data: formdata,
processData: false,
contentType: false,
success: function(response) {
alert(response.message);
return false;
},
});
});
This is my MVC code:
var data = Request["InvtId"];
The problem is the data variable is empty
Any help would be greatly appreciated, thanks.
Your form-sync attribute is non standard so your HTML is invalid. You should make that a data attribute.
You need to hook to the submit event of the form, not click.
The FormData constructor expects a DOMElement, not a jQuery object as you are currently passing to it. You can just give the this reference as that is the DOMElement.
The form has no data-url attribute. I assume you want the action property instead, which will default to the current page as you haven't provided one explicitly.
The return statement in your success handler is redundant.
You need to stop the standard form submission (as you're submitting via AJAX instead) by calling preventDefault() on the passed submit event.
Here's a complete example with all the above fixes:
<form method="post" data-form-sync="ajax">
#Html.Hidden("InvtId", item.InvtId)
</form>
$(document).on('submit', '[data-form-sync="ajax"]', function(e) {
e.preventDefault();
$.ajax({
url: this.action,
type: 'post',
data: new FormData(this),
processData: false,
contentType: false,
success: function (result) {
alert(result.message);
},
});
})
The problem is that you are passing in a jQuery element and NOT a DOM element.
For the FormData to actually return what you expect, you need to pass in a DOM element to its constructor.
Here, try this instead:
var formdata = new FormData($(this).closest("form")[0]);
Another problem is that the form has no data-url attribute.
Use the action property instead, it will return the url of the current page if you have not given a url yourself.
Here, use this instead:
var url = this.action; // or $(this).prop('action');
HTML
< button type="button" class="btn btn-primary"
onclick="saveData()">Save</button>
JS Code
Inside of function saveData()
var formData = new FormData();
get values with serializeArray
var formulario = $("#miFormulario").serializeArray();
if there are extra data or files
formulario.push({ "name": fileName, "value": file });
add information to formData
formulario.forEach((d) => {
formData.append(d.name, d.value); });
ajax request
$.ajax({
timeout: 0,
url: "/InfoController/savingInfo",
method: "post",
data: formData,
contentType: false,
processData: false,
success: function (result) { //do something }
});
Controller
[HttpPost] public JsonResult savingInfo() {
if (Request.Files.Count > 0)
{ ... }
var data = Request.Form;
var valor1 = data["dato1"];
return Json(true);
}
I've got a problem sending a file to a serverside PHP-script using jQuery's ajax-function.
It's possible to get the File-List with $('#fileinput').attr('files') but how is it possible to send this Data to the server? The resulting array ($_POST) on the serverside php-script is 0 (NULL) when using the file-input.
I know it is possible (though I didn't find any jQuery solutions until now, only Prototye code (http://webreflection.blogspot.com/2009/03/safari-4-multiple-upload-with-progress.html)).
This seems to be relatively new, so please do not mention file upload would be impossible via XHR/Ajax, because it's definitely working.
I need the functionality in Safari 5, FF and Chrome would be nice but are not essential.
My code for now is:
$.ajax({
url: 'php/upload.php',
data: $('#file').attr('files'),
cache: false,
contentType: 'multipart/form-data',
processData: false,
type: 'POST',
success: function(data){
alert(data);
}
});
Starting with Safari 5/Firefox 4, it’s easiest to use the FormData class:
var data = new FormData();
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file-'+i, file);
});
So now you have a FormData object, ready to be sent along with the XMLHttpRequest.
jQuery.ajax({
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
});
It’s imperative that you set the contentType option to false, forcing jQuery not to add a Content-Type header for you, otherwise, the boundary string will be missing from it.
Also, you must leave the processData flag set to false, otherwise, jQuery will try to convert your FormData into a string, which will fail.
You may now retrieve the file in PHP using:
$_FILES['file-0']
(There is only one file, file-0, unless you specified the multiple attribute on your file input, in which case, the numbers will increment with each file.)
Using the FormData emulation for older browsers
var opts = {
url: 'php/upload.php',
data: data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(data){
alert(data);
}
};
if(data.fake) {
// Make sure no text encoding stuff is done by xhr
opts.xhr = function() { var xhr = jQuery.ajaxSettings.xhr(); xhr.send = xhr.sendAsBinary; return xhr; }
opts.contentType = "multipart/form-data; boundary="+data.boundary;
opts.data = data.toString();
}
jQuery.ajax(opts);
Create FormData from an existing form
Instead of manually iterating the files, the FormData object can also be created with the contents of an existing form object:
var data = new FormData(jQuery('form')[0]);
Use a PHP native array instead of a counter
Just name your file elements the same and end the name in brackets:
jQuery.each(jQuery('#file')[0].files, function(i, file) {
data.append('file[]', file);
});
$_FILES['file'] will then be an array containing the file upload fields for every file uploaded. I actually recommend this over my initial solution as it’s simpler to iterate over.
Look at my code, it does the job for me
$( '#formId' )
.submit( function( e ) {
$.ajax( {
url: 'FormSubmitUrl',
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
} );
e.preventDefault();
} );
Just wanted to add a bit to Raphael's great answer. Here's how to get PHP to produce the same $_FILES, regardless of whether you use JavaScript to submit.
HTML form:
<form enctype="multipart/form-data" action="/test.php"
method="post" class="putImages">
<input name="media[]" type="file" multiple/>
<input class="button" type="submit" alt="Upload" value="Upload" />
</form>
PHP produces this $_FILES, when submitted without JavaScript:
Array
(
[media] => Array
(
[name] => Array
(
[0] => Galata_Tower.jpg
[1] => 518f.jpg
)
[type] => Array
(
[0] => image/jpeg
[1] => image/jpeg
)
[tmp_name] => Array
(
[0] => /tmp/phpIQaOYo
[1] => /tmp/phpJQaOYo
)
[error] => Array
(
[0] => 0
[1] => 0
)
[size] => Array
(
[0] => 258004
[1] => 127884
)
)
)
If you do progressive enhancement, using Raphael's JS to submit the files...
var data = new FormData($('input[name^="media"]'));
jQuery.each($('input[name^="media"]')[0].files, function(i, file) {
data.append(i, file);
});
$.ajax({
type: ppiFormMethod,
data: data,
url: ppiFormActionURL,
cache: false,
contentType: false,
processData: false,
success: function(data){
alert(data);
}
});
... this is what PHP's $_FILES array looks like, after using that JavaScript to submit:
Array
(
[0] => Array
(
[name] => Galata_Tower.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpAQaOYo
[error] => 0
[size] => 258004
)
[1] => Array
(
[name] => 518f.jpg
[type] => image/jpeg
[tmp_name] => /tmp/phpBQaOYo
[error] => 0
[size] => 127884
)
)
That's a nice array, and actually what some people transform $_FILES into, but I find it's useful to work with the same $_FILES, regardless if JavaScript was used to submit. So, here are some minor changes to the JS:
// match anything not a [ or ]
regexp = /^[^[\]]+/;
var fileInput = $('.putImages input[type="file"]');
var fileInputName = regexp.exec( fileInput.attr('name') );
// make files available
var data = new FormData();
jQuery.each($(fileInput)[0].files, function(i, file) {
data.append(fileInputName+'['+i+']', file);
});
(14 April 2017 edit: I removed the form element from the constructor of FormData() -- that fixed this code in Safari.)
That code does two things.
Retrieves the input name attribute automatically, making the HTML more maintainable. Now, as long as form has the class putImages, everything else is taken care of automatically. That is, the input need not have any special name.
The array format that normal HTML submits is recreated by the JavaScript in the data.append line. Note the brackets.
With these changes, submitting with JavaScript now produces precisely the same $_FILES array as submitting with simple HTML.
I just built this function based on some info I read.
Use it like using .serialize(), instead just put .serializefiles();.
Working here in my tests.
//USAGE: $("#form").serializefiles();
(function($) {
$.fn.serializefiles = function() {
var obj = $(this);
/* ADD FILE TO PARAM AJAX */
var formData = new FormData();
$.each($(obj).find("input[type='file']"), function(i, tag) {
$.each($(tag)[0].files, function(i, file) {
formData.append(tag.name, file);
});
});
var params = $(obj).serializeArray();
$.each(params, function (i, val) {
formData.append(val.name, val.value);
});
return formData;
};
})(jQuery);
If your form is defined in your HTML, it is easier to pass the form into the constructor than it is to iterate and add images.
$('#my-form').submit( function(e) {
e.preventDefault();
var data = new FormData(this); // <-- 'this' is your form element
$.ajax({
url: '/my_URL/',
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
...
Devin Venable's answer was close to what I wanted, but I wanted one that would work on multiple forms, and use the action already specified in the form so that each file would go to the right place.
I also wanted to use jQuery's on() method so I could avoid using .ready().
That got me to this:
(replace formSelector with your jQuery selector)
$(document).on('submit', formSelecter, function( e ) {
e.preventDefault();
$.ajax( {
url: $(this).attr('action'),
type: 'POST',
data: new FormData( this ),
processData: false,
contentType: false
}).done(function( data ) {
//do stuff with the data you got back.
});
});
If the file input name indicates an array and flags multiple, and you parse the entire form with FormData, it is not necessary to iteratively append() the input files. FormData will automatically handle multiple files.
$('#submit_1').on('click', function() {
let data = new FormData($("#my_form")[0]);
$.ajax({
url: '/path/to/php_file',
type: 'POST',
data: data,
processData: false,
contentType: false,
success: function(r) {
console.log('success', r);
},
error: function(r) {
console.log('error', r);
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="my_form">
<input type="file" name="multi_img_file[]" id="multi_img_file" accept=".gif,.jpg,.jpeg,.png,.svg" multiple="multiple" />
<button type="button" name="submit_1" id="submit_1">Not type='submit'</button>
</form>
Note that a regular button type="button" is used, not type="submit". This shows there is no dependency on using submit to get this functionality.
The resulting $_FILES entry is like this in Chrome dev tools:
multi_img_file:
error: (2) [0, 0]
name: (2) ["pic1.jpg", "pic2.jpg"]
size: (2) [1978036, 2446180]
tmp_name: (2) ["/tmp/phphnrdPz", "/tmp/phpBrGSZN"]
type: (2) ["image/jpeg", "image/jpeg"]
Note: There are cases where some images will upload just fine when uploaded as a single file, but they will fail when uploaded in a set of multiple files. The symptom is that PHP reports empty $_POST and $_FILES without AJAX throwing any errors. Issue occurs with Chrome 75.0.3770.100 and PHP 7.0. Only seems to happen with 1 out of several dozen images in my test set.
Nowadays you don't even need jQuery:) fetch API support table
let result = fetch('url', {method: 'POST', body: new FormData(document.querySelector("#form"))})
The FormData class does work, however in iOS Safari (on the iPhone at least) I wasn't able to use Raphael Schweikert's solution as is.
Mozilla Dev has a nice page on manipulating FormData objects.
So, add an empty form somewhere in your page, specifying the enctype:
<form enctype="multipart/form-data" method="post" name="fileinfo" id="fileinfo"></form>
Then, create FormData object as:
var data = new FormData($("#fileinfo"));
and proceed as in Raphael's code.
One gotcha I ran into today I think is worth pointing out related to this problem: if the url for the ajax call is redirected then the header for content-type: 'multipart/form-data' can be lost.
For example, I was posting to http://server.com/context?param=x
In the network tab of Chrome I saw the correct multipart header for this request but then a 302 redirect to http://server.com/context/?param=x (note the slash after context)
During the redirect the multipart header was lost. Ensure requests are not being redirected if these solutions are not working for you.
Older versions of IE do not support FormData ( Full browser support list for FormData is here: https://developer.mozilla.org/en-US/docs/Web/API/FormData).
Either you can use a jquery plugin (For ex, http://malsup.com/jquery/form/#code-samples ) or, you can use IFrame based solution to post multipart form data through ajax: https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript
All the solutions above are looks good and elegant, but the FormData() object does not expect any parameter, but use append() after instantiate it, like what one wrote above:
formData.append(val.name, val.value);
get form object by jquery-> $("#id")[0]
data = new FormData($("#id")[0]);
ok,data is your want