I have requirement to converting integer value to time format using javascript.
My requirement is that the result should be in time format.
Example 08:55 and 09:55
If I add these two as numbers then I will get 18.10 but I need 18:50
Try this: (My solution assumes the sum of times is not more than 24 hours)
function pad(str) {
return ("00"+str).slice(-2);
}
var str1 = "08:55";
var str2 = "09:55";
var token1 = str1.split(":");
var token2 = str2.split(":");
var result = token1[0] * 60 + + token1[1] + + token2[0] * 60 + + token2[1];
var newTime = pad(Math.floor(result/60)) + ":" + pad(result % 60);
console.log(newTime);
Does anyone how can I do a time difference count in Javascript?
Example:
If I have the following time (24H format)
startTime = 0615
endTime = 1530
breakTime = 0030
how can I get the following output?
diffB4Break = 7.15 hours
afterBreak = 6.45 hours
There are complications here, for example you would need to know what the maximum shift was, and whether it is possible for a worker to be scheduled to work over the threshold of a day, i.e. start work at 2300 and finish at 0900.
It very quickly becomes clear why it's better to use a Date/Time object to handle dates and time-deltas.
In Javascript have a look at Date
Based on #Guffa's answer here:
function parseTime(s) {
var c = s.split(':');
return parseInt(c[0]) * 60 + parseInt(c[1]);
}
var startTime = '6:45';
var endTime = '15:30';
var diff = parseTime(endTime) - parseTime(startTime);
var min = diff % 60;
var hrs = parseInt(diff / 60);
alert(hrs + ":" + min);
I trying to create a very simple time difference calculation. Just "endtime - starttime". I'm getting +1 hour though. I suspect it has with my timezone to do, since I'm GMT+1.
Regardless, that should not affect the difference, since both start and end times are in the same timezone.
Check my running example-code here:
http://jsfiddle.net/kaze72/Rm3f3/
$(document).ready(function() {
var tid1 = (new Date).getTime();
$("#tid").click(function() {
var nu = (new Date).getTime();
var diff = new Date(nu - tid1);
console.log(diff.getUTCHours() + ":" +
diff.getUTCMinutes() + ":" +
diff.getUTCSeconds());
console.log(diff.toLocaleTimeString());
});
})
You must understand what Date object represent and how it stores dates. Basically each Date is a thin wrapper around the number of milliseconds since 1970 (so called epoch time). By subtracting one date from another you don't get a date: you just get the number of milliseconds between the two.
That being said this line doesn't have much sense:
var diff = new Date(nu - tid1);
What you really need is:
var diffMillis = nu - tid1;
...and then simply extract seconds, minutes, etc.:
var seconds = Math.floor(diffMillis / 1000);
var secondsPart = seconds % 60;
var minutes = Math.floor(seconds / 60);
var minutesPart = minutes % 60;
var hoursPart = Math.floor(minutes / 60);
//...
console.log(hoursPart + ":" + minutesPart + ":" + secondsPart);
Working fiddle.
lol sorry i posted it accidentally
I'm new to JavaScript and i'm trying to make a simple countdown script that should show the difference between the end date and today's server date.
here is a great example of what i'm trying to do http://moblog.bradleyit.com/2009/06/javascripting-to-find-difference.html
The only thing i want to add is another variable with a calculated seconds. How can i do that?
Here is the code:
var today = new Date();
var Christmas = new Date("12-25-2009");
var diffMs = (Christmas - today); // milliseconds between now & Christmas
var diffDays = Math.round(diffMs / 86400000); // days
var diffHrs = Math.round((diffMs % 86400000) / 3600000); // hours
var diffMins = Math.round(((diffMs % 86400000) % 3600000) / 60000); // minutes
alert(diffDays + " days, " + diffHrs + " hours, " + diffMins + " minutes until Christmas 2009 =)");
You have two issues with this code:
1: You need to use a date that will be accepted across browsers so it needs to be formatted with / instead of -.
2: You are rounding, which when rounding up will give you inaccurate numbers. All numbers need to be rounded down. Here is a function do do so:
var roundDown = function(num){
var full = num.toString();
var reg = /([\d]+)/i;
var res = reg.exec(full);
return res[1];
}
So your final code should look like this:
var roundDown = function(num){
var full = num.toString();
var reg = /([\d]+)/i;
var res = reg.exec(full);
return res[1];
}
var today = new Date(); // date and time right now
var goLive = new Date("06/01/2013"); // target date
var diffMs = (goLive - today); // milliseconds between now & target date
var diffDays = roundDown(diffMs / 86400000); // days
var diffHrs = roundDown((diffMs % 86400000) / 3600000); // hours
var diffMins = roundDown(((diffMs % 86400000) % 3600000) / 60000); // minutes
var diffSecs = roundDown((((diffMs % 86400000) % 3600000) % 60000) / 1000 ); // seconds
var endDate = new Date(year, month, day, hours, minutes, seconds, milliseconds);
var today = Date.now()
var timeLeft = endDate - today // timeLeft would be in milliseconds
// Parse this into months, days, hours, ...
Put this in a function and set it up to be called every second or so using setInterval.
This should get you started with the JavaScript date object and it's associated methods.
http://www.w3schools.com/jsref/jsref_obj_date.asp
Also, look up the setInterval() method, that will allow you to fire code in set intervals (for example, updating the countdown text).
It amazes me that JavaScript's Date object does not implement an add function of any kind.
I simply want a function that can do this:
var now = Date.now();
var fourHoursLater = now.addHours(4);
function Date.prototype.addHours(h) {
// How do I implement this?
}
I would simply like some pointers in a direction.
Do I need to do string parsing?
Can I use setTime?
How about milliseconds?
Like this:
new Date(milliseconds + 4*3600*1000 /* 4 hours in ms */)?
This seems really hackish though - and does it even work?
JavaScript itself has terrible Date/Time API's. Nonetheless, you can do this in pure JavaScript:
Date.prototype.addHours = function(h) {
this.setTime(this.getTime() + (h*60*60*1000));
return this;
}
Date.prototype.addHours= function(h){
this.setHours(this.getHours()+h);
return this;
}
Test:
alert(new Date().addHours(4));
The below code will add 4 hours to a date (example, today's date):
var today = new Date();
today.setHours(today.getHours() + 4);
It will not cause an error if you try to add 4 to 23 (see the documentation):
If a parameter you specify is outside of the expected range, setHours() attempts to update the date information in the Date object accordingly
It is probably better to make the addHours method immutable by returning a copy of the Date object rather than mutating its parameter.
Date.prototype.addHours= function(h){
var copiedDate = new Date(this.getTime());
copiedDate.setHours(copiedDate.getHours()+h);
return copiedDate;
}
This way you can chain a bunch of method calls without worrying about state.
The version suggested by kennebec will fail when changing to or from DST, since it is the hour number that is set.
this.setUTCHours(this.getUTCHours()+h);
will add h hours to this independent of time system peculiarities.
Jason Harwig's method works as well.
Get a date exactly two hours from now, in one line.
You need to pass milliseconds to new Date.
let expiryDate = new Date(new Date().setHours(new Date().getHours() + 2));
or
let expiryDate2 = new Date(Date.now() + 2 * (60 * 60 * 1000) );
let nowDate = new Date();
let expiryDate = new Date(new Date().setHours(new Date().getHours() + 2));
let expiryDate2 = new Date(Date.now() + 2 * (60 * 60 * 1000) );
console.log('now', nowDate);
console.log('expiry', expiryDate);
console.log('expiry 2', expiryDate2);
You can use the Moment.js library.
var moment = require('moment');
foo = new moment(something).add(10, 'm').toDate();
I also think the original object should not be modified. So to save future manpower here's a combined solution based on Jason Harwig's and Tahir Hasan answers:
Date.prototype.addHours= function(h){
var copiedDate = new Date();
copiedDate.setTime(this.getTime() + (h*60*60*1000));
return copiedDate;
}
If you would like to do it in a more functional way (immutability) I would return a new date object instead of modifying the existing and I wouldn't alter the prototype but create a standalone function. Here is the example:
//JS
function addHoursToDate(date, hours) {
return new Date(new Date(date).setHours(date.getHours() + hours));
}
//TS
function addHoursToDate(date: Date, hours: number): Date {
return new Date(new Date(date).setHours(date.getHours() + hours));
}
let myDate = new Date();
console.log(myDate)
console.log(addHoursToDate(myDate,2))
There is an add in the Datejs library.
And here are the JavaScript date methods. kennebec wisely mentioned getHours() and setHours();
Check if it’s not already defined. Otherwise, define it in the Date prototype:
if (!Date.prototype.addHours) {
Date.prototype.addHours = function(h) {
this.setHours(this.getHours() + h);
return this;
};
}
This is an easy way to get an incremented or decremented data value.
const date = new Date()
const inc = 1000 * 60 * 60 // an hour
const dec = (1000 * 60 * 60) * -1 // an hour
const _date = new Date(date)
return new Date(_date.getTime() + inc)
return new Date(_date.getTime() + dec)
Another way to handle this is to convert the date to unixtime (epoch), then add the equivalent in (milli)seconds, then convert it back. This way you can handle day and month transitions, like adding 4 hours to 21, which should result in the next day, 01:00.
SPRBRN is correct. In order to account for the beginning/end of the month and year, you need to convert to Epoch and back.
Here's how you do that:
var milliseconds = 0; //amount of time from current date/time
var sec = 0; //(+): future
var min = 0; //(-): past
var hours = 2;
var days = 0;
var startDate = new Date(); //start date in local time (we'll use current time as an example)
var time = startDate.getTime(); //convert to milliseconds since epoch
//add time difference
var newTime = time + milliseconds + (1000*sec) + (1000*60*min) + (1000*60*60*hrs) + (1000*60*60*24*days);
var newDate = new Date(newTime); //convert back to date; in this example: 2 hours from right now
Or do it in one line (where variable names are the same as above:
var newDate =
new Date(startDate.getTime() + millisecond +
1000 * (sec + 60 * (min + 60 * (hours + 24 * days))));
For a simple add/subtract hour/minute function in JavaScript, try this:
function getTime (addHour, addMin){
addHour = (addHour ? addHour : 0);
addMin = (addMin ? addMin : 0);
var time = new Date(new Date().getTime());
var AM = true;
var ndble = 0;
var hours, newHour, overHour, newMin, overMin;
// Change form 24 to 12 hour clock
if(time.getHours() >= 13){
hours = time.getHours() - 12;
AM = (hours>=12 ? true : false);
}else{
hours = time.getHours();
AM = (hours>=12 ? false : true);
}
// Get the current minutes
var minutes = time.getMinutes();
// Set minute
if((minutes + addMin) >= 60 || (minutes + addMin) < 0){
overMin = (minutes + addMin) % 60;
overHour = Math.floor((minutes + addMin - Math.abs(overMin))/60);
if(overMin < 0){
overMin = overMin + 60;
overHour = overHour-Math.floor(overMin/60);
}
newMin = String((overMin<10 ? '0' : '') + overMin);
addHour = addHour + overHour;
}else{
newMin = minutes + addMin;
newMin = String((newMin<10 ? '0' : '') + newMin);
}
// Set hour
if((hours + addHour >= 13) || (hours + addHour <= 0)){
overHour = (hours + addHour) % 12;
ndble = Math.floor(Math.abs((hours + addHour)/12));
if(overHour <= 0){
newHour = overHour + 12;
if(overHour == 0){
ndble++;
}
}else{
if(overHour == 0){
newHour = 12;
ndble++;
}else{
ndble++;
newHour = overHour;
}
}
newHour = (newHour<10 ? '0' : '') + String(newHour);
AM = ((ndble + 1) % 2 === 0) ? AM : !AM;
}else{
AM = (hours + addHour == 12 ? !AM : AM);
newHour = String((Number(hours) + addHour < 10 ? '0': '') + (hours + addHour));
}
var am = (AM) ? 'AM' : 'PM';
return new Array(newHour, newMin, am);
};
This can be used without parameters to get the current time:
getTime();
Or with parameters to get the time with the added minutes/hours:
getTime(1, 30); // Adds 1.5 hours to current time
getTime(2); // Adds 2 hours to current time
getTime(0, 120); // Same as above
Even negative time works:
getTime(-1, -30); // Subtracts 1.5 hours from current time
This function returns an array of:
array([Hour], [Minute], [Meridian])
If you need it as a string, for example:
var defaultTime: new Date().getHours() + 1 + ":" + new Date().getMinutes();
I think this should do the trick
var nextHour = Date.now() + 1000 * 60 * 60;
console.log(nextHour)
You can even format the date in desired format using the moment function after adding 2 hours.
var time = moment(new Date(new Date().setHours(new Date().getHours() + 2))).format("YYYY-MM-DD");
console.log(time);
A little messy, but it works!
Given a date format like this: 2019-04-03T15:58
//Get the start date.
var start = $("#start_date").val();
//Split the date and time.
var startarray = start.split("T");
var date = startarray[0];
var time = startarray[1];
//Split the hours and minutes.
var timearray = time.split(":");
var hour = timearray[0];
var minute = timearray[1];
//Add an hour to the hour.
hour++;
//$("#end_date").val = start;
$("#end_date").val(""+date+"T"+hour+":"+minute+"");
Your output would be: 2019-04-03T16:58
The easiest way to do it is:
var d = new Date();
d = new Date(d.setHours(d.getHours() + 2));
It will add 2 hours to the current time.
The value of d = Sat Jan 30 2021 23:41:43 GMT+0500 (Pakistan Standard Time).
The value of d after adding 2 hours = Sun Jan 31 2021 01:41:43 GMT+0500 (Pakistan Standard Time).