Develop Reference

Submitting form set all null inputs and their associated hidden input fields to disabled

I have a form with multiple input fields where users may choose to enter a value or not. Next to each input field is a hidden input field that will send a specific id unique to the previous input field. On form submission, all blank input fields are disabled. This I got to work using this code.
function disableEmptyInputs(form) {
var controls = form.elements;
for (var i = 0, iLen = controls.length; i < iLen; i++) {
controls[i].disabled = controls[i].value == '';
}
}
I now want to also disable the hidden inputs if their primary visible input field is null
<div class="col-md-4">
<div class="input-group mb-3">
<div class="input-group-prepend">
<span class="input-group-text">$</span>
</div>
<input name="Pay" placeholder="Amount for A" class="form-control" type="text" />
<input type="hidden" name="PayId" value="A" />
</div>
</div>
<div class="col-md-4">
<div class="input-group mb-3">
<div class="input-group-prepend">
<span class="input-group-text">$</span>
</div>
<input name="Pay" placeholder="Amount for B" class="form-control" type="text" />
<input type="hidden" name="PayId" value="B" />
</div>
</div>
Any help will be really appreciated. The form submits to a c# backend where I am able to filter out all blanks If I allowed all blanks to be submitted but I felt if I could filter all blanks by making them disabled at the client side in addition to server side that will be better.

You can use .each loop to iterate through your form elements and then compare if the value of input is "" simply disable that input and also the input next to it using .next().
Demo Code :
$("form").on("submit", function() {
//loop through input(exclude hidden input)..select..etc
$("form").find("input:not(:hidden),select").each(function() {
//if the value is empty
if ($(this).val() == "") {
$(this).prop("disabled", true) //disable
$(this).next().prop("disabled", true) //also next field (hidden) disable
}
})
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form>
<div class="col-md-4">
<div class="input-group mb-3">
<div class="input-group-prepend">
<span class="input-group-text">$</span>
</div>
<input name="Pay" placeholder="Amount for A" class="form-control" type="text" value="abc" />
<input type="hidden" name="PayId" value="A" />
</div>
</div>
<div class="col-md-4">
<div class="input-group mb-3">
<div class="input-group-prepend">
<span class="input-group-text">$</span>
</div>
<input name="Pay" placeholder="Amount for B" class="form-control" type="text" />
<input type="hidden" name="PayId" value="B" />
</div>
</div>
<button>Click me ..</button>
</form>

Change submit onclick based on a checkbox

I have a form that is being used as a basic contact form. I have added a checkbox that adds some fields if selected. How can I change the onclick action of the submit button based on if this box is checked or not. Here is what I have currently.
<form class="homeContact">
<label for="chkJob">
Interested in a career? Check to apply
<input type="checkbox" id="chkJob" />
</label>
<div id="dvApply" style="display: none">
Download Application
Download the application. Fill it out and upload below:
<input type="file" name="fileToUpload" id="fileToUpload">
</div>
<div id="popErr"></div>
<input type="hidden" name="nospam">
<div class="field">
<div class="label-form">
<input type="text" placeholder="Name *" value="" name="name" id="popName">
<span class="form-icon fa fa-user"></span>
</div>
</div>
<div class="field">
<div class="label-form">
<input type="text" placeholder="Email *" value="" name="email" id="popEmail">
<span class="form-icon fa fa-envelope"></span>
</div>
</div>
<div class="field">
<div class="label-form">
<input type="text" placeholder="Phone *" value="" name="phone" id="popTel">
<span class="form-icon fa fa-phone"></span>
</div>
</div>
<div id="submit_button">
<input type="button" class="button submit" id="contact-submit" onclick="submitForm()" value="Request Information">
</div>
</form>
<script>
jQuery(document).ready(function($) {
$("#chkJob").click(function () {
if ($(this).is(":checked")) {
$("#dvApply").show();
} else {
$("#dvApply").hide();
}
});
});
</script>

You can implement this login into your submitForm function:
function submitForm()
{
if ($('#chkJob').is(":checked")) {
$("#dvApply").show();
} else {
$("#dvApply").hide();
}
}
But if you want dvApply to be toggled every time checkbox button is clicked without waiting for submit button to be clicked you can do something like:
jQuery(document).ready(function($) {
$('#chkJob').change(function() {
$('#dvApply').toggle();
});
});

Show Added Values on same page before submitting in form with multiple entry

I would like to add functionality to my existing form.So far my form allows only entries on per submit bases, meaning is if the user wants to add another entry, he/she has to go back to the form and add and click to submit again.I would like to show all added values on same page, cause I am planning to add a Javascript print function that will print the add entries before saving to database.I need all values in fields to be printed
<form method="POST" name="myForm" action="saveto.php">
<label> Speed Rating:</label>
<select name="speed_rating" required class="form-control" id="speed_rating" ></select>
<div class="form-group col-sm-8">
<label> Description:</label>
<select name="description" required class="form-control" id="description" >
</select>
</div>
<div class="form-group col-sm-4">
<label> Load Index:</label>
<select name="load_index" required class="form-control" id="load_index" >
</select>
</div>
<div class="form-group col-sm-6">
<label> Vendor:</label>
<select name="vendor" required class="form-control" id="vendor" >
</select>
<div class="note"> Recommended Vendor : <span id="recomvend"> </span> </div>
</div>
<div class="form-group col-sm-6">
<label> Quantity:</label>
<input type="text" required name="qty" class="form-control" id="qty"></div>
<div style="clear:both"> </div>
<input type="submit" name="submit" class="btn btn-primary smp" value="Submit">
<button id="clear" type="button" class="btn btn-primary smp smp2" > Reset </button>
</div>
<input type="submit" value="submit" name="submit">
</form>
entry 1
speed rating -- 46
description ---'the discription'
------
entry 2
speed rating --56
description ---'another description'
submit
The saveto.php is just a normal script that will process the submitted data to database, one entry in a per submit bases.

Bootstrap reset button onclick keep textbox as valid

I have used below code for bootstrap textbox and textarea and also in the last div I have used button type="reset" .But when I entered invalid shop name and valid Address and click on Reset button it reset it and after only entering invalid shop name and click on Add shop then it is successfully adding new shop.Both the textbox show green background-color and correct sign even after it is empty.
Please help me.
Please see below image after onclick of reset button:
<form id="defaultForm" method="post" class="form-horizontal"
data-bv-message="This value is not valid"
data-bv-feedbackicons-valid="glyphicon glyphicon-ok"
data-bv-feedbackicons-invalid="glyphicon glyphicon-remove"
data-bv-feedbackicons-validating="glyphicon glyphicon-refresh">
<div class="form-group">
<label class="col-xs-3 control-label">Shop Name</label>
<div class="col-xs-4">
<input type="text" class="form-control" pattern="^[a-zA-Z\s]+$"
data-bv-regexp-message="The shop name can consist of alphabetical characters only" name="shopName" placeholder="Shop Name" data-bv-trigger="blur" data-bv-notempty="true" data-bv-notempty-message="Shop name is required and cannot be empty" />
</div>
</div>
<div class="form-group">
<label class="col-xs-3 control-label">Shop Address</label>
<div class="col-xs-4">
<textarea id="id_txt_addr" type="text" class="form-control" name="shop_address" placeholder="Shop Address" style="height:100px" maxlength="200" data-bv-trigger="blur" data-bv-notempty="true" data-bv-notempty-message="Shop address is required and cannot be empty"></textarea>
</div>
</div>
<div class="form-group">
<div class="col-xs-9 col-xs-offset-3">
<input type="submit" name="add" class="btn btn-primary" value="Add Shop">
<button type="reset" class="btn btn-default">Reset</button>
</div>
</div>
</form>

On reset button click, remove all relevant validation classes and elements handling error message inside closest form. Here an example:
$(':reset').on('click', function(){
var $form = $(this).closest("form");
$form.find('*').removeClass('has-success has-error glyphicon-ok glyphicon-remove');
$form.find('.help-block').remove();
});
-DEMO-
Now maybe there is a bootstrap method to reset validation, you should check bootstrap DOC maybe.

$(document).ready(function () {
$("#ibtReset").on("click", function () {
$('#ShopName').val("");
$('#id_txt_addr').val("");
$('.glyphicon ').remove();
});
});
On reset button click both the values become empty.
It may help You.

AngularJS:how to disable all the form controls in a form?

I want to disable all the form components so that it can't be edited when view button is clicked.
this is my form
<form action="#" class="form-horizontal" >
<div class="form-group">
<label for="fieldname" class="col-md-3 control-label">Name</label>
<div class="col-md-6">
<input type="text" ng-model="newItem.customSelected" typeahead="name as name.name for name in members | filter:{name:$viewValue}" class="form-control" />
</div>
</div>
<div class="form-group">
<label for="fieldhname" class="col-md-3 control-label">House name</label>
<div class="col-md-6">
<input type="text" ng-model="newItem.customSelected1" typeahead="house_name as house_name.house_name for house_name in family | filter:{house_name:$viewValue}" class="form-control" />
</div>
</div>
<div class="form-group">
<label for="" class="col-md-3 control-label"><?php echo $this->lang->line('label_family_id'); ?></label>
<div class="col-md-6">
<input type="text" ng-model="newItem.customSelected2" typeahead="fm as fm.family_reg_no for fm in family | filter:{family_reg_no:$viewValue}" class="form-control" />
</div>
</div>
<div class="col-md-3"></div>
</form>
and this is my button
<input type="button" class="finish btn-success btn" ng-click="view(newItem)" value="view"/>

Rather than handling it at per-field level, you can put all form elements into fieldset and use ng-disabled to disable the whole fieldset.

you can use fieldset tag by surrounding your buttons with a fieldset and using ng-disabled attribute:
<form action="#" class="form-horizontal" >
<fieldset ng-disabled="isClicked">
<!--your form here --!>
</fieldset>
</form>
now all that left is in the view(newItem) function do:
$scope.view = function(newItem){
$scope.isClicked = true;
// Your code here and set it to false when your are done with it
}

You could use an overlay and have a ng-show on it or you could add to each input ng-disabled

Set a scope variable when the view button is clicked.
Use ng-disabled in combination with the scope variable to disable the fields.