I m trying to make my website social icon, refer to a link (when clicked) based on the platform being used on. like the following:
if The website is opened on ios phone, ipad... to launch a specific deep link.
if The website is opened on android phone ... to launch a specific deep link.
if The website is opened on desktop pc ... to launch a specific link.
Thank you!
You can use HTTP Header.
See: https://en.wikipedia.org/wiki/List_of_HTTP_header_fields
Through the User-Agent field you can get the browser version etc. Other header could be interesting for you, too.
Related
I have a question about how to make a website that supports Add to Homescreen in Google chrome.
That's mean some websites like web.whatsapp.com when clicking on the Add to home screen, Website shortcut add to my home screen but when I open it, it has different, It opens in fullscreen mode and hide Google chrome options.
please say how to create a website like that.
I think they are called PWA (Progressive Web App) you can find information online on how to create those apps from scratch.
I have a website which contains links to external websites, for example amazon product links. The links work just fine, but when I test my website on mobile (iOS in this case), I noticed that clicking the links in the mobile browsers would force open the Amazon app rather than just opening a new tab.
The links in my html are as follows:
I want to have these links open in the browser only, not in their respective apps. Is there any way in to prevent this behavior using html / javascript? Thanks!
No, you can't.
The reason is: you should not be able to impose your choice on the user. Maybe the user prefers the app? That's why iOS 9 introduced the app switcher on the top left hand corner if you switch apps.
Also, let's look from the other side of things if you are the app developer: If you go so far as to build an app and allow universal links (or generally deep links), you obviously would like the user to use that feature and rather open the site in the app. But again, you cannot force the user into opening that link in the app. That's a good thing, because it all depends on what the user wants to do and how he wants to do it.
Having the user choose is the best way to handle this from a UX point of view.
I'm trying to open the app from an HTML page. It's working well, but I need the app to open without asking the permission from the user.
Currently, Safari will ask the user that "Open this page in myapp". I don't want this message box.
How I can remove this message from Safari? I'm using an URI scheme to open the app. It looks something like myApp://domain.
You can't avoid the dialog you mentioned while using Custom URL schemes. This is iOS feature.
Instead you can use Universal Links to open your iOS App without additional dialog. You need to have control over iOS App to make this happens.
To simplify Universal Links setup, you can use one of the companies that can setup most of it for you. I am working in Firebase/Google https://firebase.google.com/docs/dynamic-links/ . Other answer mentioned company that will do this for you as well.
Try branch.io? It works with Android and iOS.
As the title says, I would like to show a small popup containing a button at the end of my web site to hint users to add my website to their phone's home screen. I found a tutorial here: https://codelabs.developers.google.com/codelabs/add-to-home-screen/#0, which solved my issue on Android but this way just works just only on Android and https method. I would prefer that this popup must work on Android, iOS, http and https. Would anyone here know how to solve this? Thank you very much for your help.
For Android, the Add To Home Screen prompt requires HTTPS (or localhost), so it's not possible to do it on HTTP.
For Safari on iOS, you can configure the home screen icon & launch appearance with meta tags, but a prompt system is not currently available, so users will need to add the app manually.
I have a customer that wants to launch a certain website from an icon on a tablet that runs Android. He's leasing out the tablets, so we have complete control over the hardware. The idea is that these tablets will only be used for his site (it's a type of slide show), so he wants the tablet home screen to have a single icon, and that icon will always launch his site in complete fullscreen. This works somewhat, but the statusbar does not go away without a user gesture. On Chrome the meta tag mobile-web-app-capable does the trick, but we can also use other browsers if this simplifies things. Is it possible to remove the statusbar without a second user gesture (the first being launching the website)?
And in response to the answers below, how can a WebLauncherActivity be useful when the user is just opening a browser?
On the page, element.requestFullscreen() displays the element in fullscreen mode.
Additional JS API and CSS selectors can provide other fullscreen specification in the following html5 article:
Building an Amazing Fullscreen Mobile Experience
Try using the WebappLauncherActivity that's used by the page shortcuts.
You should be able to launch the activity via adb with:
adb shell am start -n com.android.chrome/.webapps.WebappManager.ACTION_START_WEBAPP "url"
You can also add your own activity inheriting from FullscreenActivity which is the base for WebappActivity like mentioned by #tushar-pandey.