I want to make an array of all numbers. Here is my code:
$(function(){ // dom ready
$('tr').each(function() {
var nums = $(this).map(function() {
return (this).find('td:nth-child(3)').text()
}).get();
console.log(nums);
})
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>760</td>
<td>John</td>
</tr>
<tr>
<td>532</td>
<td>Peter</td>
</tr>
<tr>
<td>201</td>
<td>Martin</td>
</tr>
<tr>
<td>12</td>
<td>Barman</td>
</tr>
</tbody>
</table>
What's wrong with it and how can I fix it?
Firstly you're missing a $ prefix on the (this) in the map() handler. Then to get the numbers use :nth-child(1), not :nth-child(3). Also you can just use map() directly, no need for each(). Finally, assuming you want the values to actually be numerical and not strings, use parseInt() on them, like this:
$(function() { // dom ready
var nums = $('tr').map(function() {
return parseInt($(this).find('td:nth-child(1)').text(), 10)
}).get();
console.log(nums);
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>760</td>
<td>John</td>
</tr>
<tr>
<td>532</td>
<td>Peter</td>
</tr>
<tr>
<td>201</td>
<td>Martin</td>
</tr>
<tr>
<td>12</td>
<td>Barman</td>
</tr>
</tbody>
</table>
Small Mistake,
change return (this).find('td:nth-child(3)') to return $(this).find('td:nth-child(1)')
$(function(){ // dom ready
$('tr').each(function() {
var nums = $(this).map(function() {
return $(this).find('td:nth-child(1)').text()
}).get();
console.log(nums);
})
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>760</td>
<td>John</td>
</tr>
<tr>
<td>532</td>
<td>Peter</td>
</tr>
<tr>
<td>201</td>
<td>Martin</td>
</tr>
<tr>
<td>12</td>
<td>Barman</td>
</tr>
</tbody>
</table>
Change like this parseInt($(this).find('td:nth-child(1)').text()).parseInt() its used to change the string to number
Whats Wrong?
Missing $in return statement
And numbers column is a first cell find('td:nth-child(1)')
But you are trying to create a array with 3rd cell .but is not there.only two column is available
$(function(){ // dom ready
$('tr').each(function() {
var nums = $(this).map(function() {
return parseInt($(this).find('td:nth-child(1)').text())
}).get();
console.log(nums);
})
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>760</td>
<td>John</td>
</tr>
<tr>
<td>532</td>
<td>Peter</td>
</tr>
<tr>
<td>201</td>
<td>Martin</td>
</tr>
<tr>
<td>12</td>
<td>Barman</td>
</tr>
</tbody>
</table>
I think this is ist a 'lighter' version:
var nums=[];
$('td:nth-child(1)').each(function(){
nums.push(parseInt(this.innerHTML));
});
console.log(nums);
//[760, 532, 201, 12]
Related
I have an HTML table and I need to define a function that should grab the data from the table and build an array of objects that contains table data. Outside the function I have to declare a variable and assign the returned value from the function.
Thanks in advance.
HTML
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
JS
function buildTableData() {
let tbody = document.getElementsByTagName("tbody")[0];
let rows = tbody.children;
let people = [];
for (let row of rows) {
let person = {};
let cells = row.children;
person.rating = cells[0].textContent;
person.review = cells[1].textContent;
person.favoriteFood = cells[2].textContent;
people.push(person);
return people;
}
let data = people;
console.log(data);
}
You can get all the elements by using querySelectorAll('td'). Then use map to to get only the text of it and return this.
function buildTableData() {
const elements = [...document.querySelectorAll('td')];
return elements.map(x => {
return {content : x.innerHTML}
});
}
console.log(buildTableData());
<body>
<h2>Product reviews</h2>
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
<script src="https://cdnjs.cloudflare.com/ajax/libs/acorn/7.3.1/acorn.js" integrity="sha512-4GRq4mhgV43mQBgKMBRG9GbneAGisNSqz6DSgiBYsYRTjq2ggGt29Dk5thHHJu38Er7wByX/EZoG+0OcxI5upg==" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/acorn-walk/7.2.0/walk.js" integrity="sha512-j5XDYQOKluxz1i4c7YMMXvjLLw38YFu12kKGYlr2+w/XZLV5Vg2R/VUbhN//K/V6LPKuoOA4pfcPXB5NgV7Gwg==" crossorigin="anonymous"></script>
<script src="index.js"></script>
</body>
You can try using querySelectorAll() and map() like the following way:
function buildTableData() {
let rows = document.querySelectorAll('tbody tr');
let data = Array.from(rows).map(function(tr){
return {
rating: tr.querySelectorAll('td:nth-child(1)')[0].textContent,
review: tr.querySelectorAll('td:nth-child(2)')[0].textContent,
favoriteFood: tr.querySelectorAll('td:nth-child(3)')[0].textContent
};
});
console.log(data);
}
buildTableData();
<h2>Product reviews</h2>
<table>
<thead>
<tr>
<th>Name</th>
<th>Rating</th>
<th>Review</th>
</tr>
</thead>
<tbody>
<tr>
<td>Bob</td>
<td>5/5</td>
<td>This product is so good, I bought 5 more!</td>
</tr>
<tr>
<td>Jane</td>
<td>4/5</td>
<td>Good value for the price.</td>
</tr>
<tr>
<td>David</td>
<td>1/5</td>
<td>Arrived broken :(</td>
</tr>
<tr>
<td>Fiona</td>
<td>5/5</td>
<td>I love it!</td>
</tr>
<tr>
<td>Michael</td>
<td>3/5</td>
<td>Doesn't live up to expectations.</td>
</tr>
</tbody>
</table>
You want a loop, and each review to be an object that is appended to an array of reviews is what I'm assuming
var reviews = [];
var tbody = document.querySelectorAll("tbody")[0];
var TRs = tbody.querySelectorAll("tr");
for (var a = 0; a < TRs.length; a++) {
var TDs = TRs[a].querySelectorAll("td");
var review = {
name: "",
rating: "",
review: ""
};
//These assume the order of your table columns don't change
review.name = TDs[0].innerHTML;
review.rating = TDs[1].innerHTML;
review.review = TDs[2].innerHTML;
reviews.push(review);
}
Your reviews array should have everything in there just as you wanted. I assumed the third column was "review" instead of "favorite food"
I have a table like below
<table id="categoriesTable">
<tr id=row_id1_dynamicdata>
<td>...</td>
<td>..</td>
</tr>
<tr id=row_id2_dynamicdata>
<td>...</td>
<td>..</td>
</tr>
<tr id=row_id3_dynamicdata>
<td>...</td>
<td>..</td>
</tr>
<tr id=row_id4_dynamicdata>
<td>...</td>
<td>..</td>
</tr>
</table>
I want to hide all rows except row whose id contains id4. I won't have full id.
I came up with below jQuery code, but as I don't have full id, it doesn't work.
var idValue = document.getElementById(someElement);
$('#categoreisTable').find('tr').not($('#row_' +idValue)).hide();
How to filter with only half the id?
You can use the "Attribute starts with" selector to find the rows which don't match the one with the specified idValue. For example:
$('#someElement').on('change', function() {
var idValue = this.value;
$('#categoriesTable')
.find('tr')
.show() // not needed if you only want to hide
.not('[id^="row_id' + idValue + '_"]')
.hide();
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id="categoriesTable">
<tr id=row_id1_dynamicdata>
<td>.1..</td>
<td>..</td>
</tr>
<tr id=row_id2_dynamicdata>
<td>.2..</td>
<td>..</td>
</tr>
<tr id=row_id3_dynamicdata>
<td>.3..</td>
<td>..</td>
</tr>
<tr id=row_id4_dynamicdata>
<td>.4..</td>
<td>..</td>
</tr>
</table>
<input type="text" id="someElement" />
You can use querySelectorall on the tr element and then run a loop to only show rows that include id4 in their id.
Run the snippet below:
var idValue = document.querySelectorAll('tr');
for (i = 0; i < idValue.length; i++) {
if (idValue[i].id.includes("id4")) {
idValue[i].style.display = "block";
} else {
idValue[i].style.display = "none"
}
}
<table id="categoriesTable">
<tr id=row_id1_dynamicdata>
<td>row1</td>
<td>..</td>
</tr>
<tr id=row_id2_dynamicdata>
<td>row2</td>
<td>..</td>
</tr>
<tr id=row_id3_dynamicdata>
<td>row3</td>
<td>..</td>
</tr>
<tr id=row_id4_dynamicdata>
<td>row 4</td>
<td>..</td>
</tr>
<tr id=anotherrow_id4_dynamicdata>
<td>another row with id4</td>
<td>..</td>
</tr>
</table>
You can use document.getElementsByTagName to get all id contain id4.
Then, just to hide them.
let ElementArray = Array.prototype.filter.call(document.getElementsByTagName('tr'), element => element.id.match('id4'));
let idArray = ElementArray.forEach(element => document.getElementById(element.id).style.display="none");
You can simply use:
$('#categoriesTable tr').not('[id^="row_id4_"]').hide();
I use the HTML code.
I have a table and I write in first tr td "A" and "B" in second tr td
I have these two rows
but I want to print "B" in first tr and "A" in second
!! But I don't want to change my th position!!
Is it possible with any script like js or Jquery or with any type js CDN....??
<table id='table1'>
<tr>
<th>name</th>
</tr>
<tr>
<td>A</td>
</tr>
<tr>
<td>B</td>
</tr>
</table>
Give this a try:
Your script
$(function(){
$("tbody").each(function(elem,index){
var arr = $.makeArray($("tr",this).detach());
arr.reverse();
$(this).append(arr);
});
});
The second way to do the same will be like this:
var tbody = $('table tbody');
tbody.html($('tr',tbody).get().reverse());
I hope this helps! Thanks!
You can swap the .textContent of the <td> children of the <tr> elements
const {rows:[{cells:[a]}, {cells:[b]}]} = table1;
[a.textContent, b.textContent] = [b.textContent, a.textContent];
<table id='table1'>
<tr>
<td>A</td>
</tr>
<tr>
<td>B</td>
</tr>
</table>
Since you can use reverse() with an array, you can use get() to convert this to an array first. If you have a dynamic number of rows you can use something like this:
$('tbody').each(function(){
var row = $(this).children('tr');
console.log(row)
$(this).html(row.get().reverse())
})
Use this below code:
$(function(){
$("tbody").each(function(elem,index){
var arr = $.makeArray($("tr",this).detach());
arr.reverse();
$(this).append(arr);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id='table1'>
<tbody>
<tr>
<td>A</td>
</tr>
<tr>
<td>B</td>
</tr>
<tr>
<td>C</td>
</tr>
</tbody>
</table>
You can loop through each row, starting at the bottom and add it to the bottom - this will reverse the rows.
This will mean you don't need to load all the rows into an array, but will mean additional DOM manipulation.
var tbl = $("#table1>tbody")
var l = tbl.find("tr").length;
for (var i=l; i>=0; --i)
{
tbl.find("tr").eq(i).appendTo(tbl);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id='table1'><tbody>
<tr> <td>A</td> </tr>
<tr> <td>B</td> </tr>
<tr> <td>C</td> </tr>
<tr> <td>D</td> </tr>
<tr> <td>E</td> </tr>
</tbody></table>
Problem Solved
<script type="text/javascript">
var trCount = $('#table1 tr').length;
var $rows = [];
for (var i = 0; i < trCount; i++)
$rows.push($('#table1 tr:last-child').remove());
$("#table1 tbody").append($rows);
</script>
Thanks to all
You can do that with pure vanilla JS, you don't need jquery or any other library for that.
function reverseOrder(table) {
const rows = table.querySelector('tbody').children;
const swaptemp = rows[0].children[0].innerHTML;
rows[0].children[0].innerHTML = rows[1].children[0].innerHTML;
rows[1].children[0].innerHTML = swaptemp;
}
const tableToReserveOrder = document.getElementById('table1');
reverseOrder(tableToReserveOrder);
<table id='table1'>
<tr>
<td>A</td>
</tr>
<tr>
<td>B</td>
</tr>
</table>
This is just a demonstration for your use case, you can play around with value of n which is 0 for this case where n+1 is 1.
I have a 2-column table and I would like to convert the cells into an array using jQuery. I currently have that working, but I would like the array to be "2-column" as well, not sure if that's the right terminology. But basically I want the 2 cells from each row to be part of the same "row" in the array. Currently I have this:
$(function() {
var arr = [];
$('tbody tr').each(function() {
var $this = $(this),
cell = $this.find('td');
if (cell.length > 0) {
cell.each(function() {
arr.push($(this).text());
});
}
});
console.log(arr);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
<thead>
<tr>
<td>Table heading</td>
</tr>
</thead>
<tbody>
<tr>
<td>Apples</td>
<td>Red</td>
</tr>
<tr>
<td>Bananas</td>
<td>Yellow</td>
</tr>
<tr>
<td>Oranges</td>
<td>Orange</td>
</tr>
<tr>
<td>Cucumbers</td>
<td>Green</td>
</tr>
</table>
How do I make it so that 0 would be Apples, Red and so on?
You can do something like this
$(function() {
var arr = $('tbody tr').get()//convert jquery object to array
.map(function(row) {
return $(row).find('td').get()
.map(function(cell) {
return cell.innerHTML;
}).join(',');
});
console.log(arr);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
<thead>
<tr>
<td>Table heading</td>
</tr>
</thead>
<tbody>
<tr>
<td>Apples</td>
<td>Red</td>
</tr>
<tr>
<td>Bananas</td>
<td>Yellow</td>
</tr>
<tr>
<td>Oranges</td>
<td>Orange</td>
</tr>
<tr>
<td>Cucumbers</td>
<td>Green</td>
</tr>
</table>
ok you can also do this.
$(function() {
var arr = [];
flag = 0;
$('tbody tr td').each(function() {
if(flag == 0){
arr1 = [];
arr1.push($(this).text());
arr.push(arr1);
flag = 1;
}else{
let arr1 = arr[arr.length-1];
arr1.push($(this).text());
arr[arr.length-1] = arr1;
flag = 0;
}
});
console.log(arr);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
<thead>
<tr>
<td>Table heading</td>
</tr>
</thead>
<tbody>
<tr>
<td>Apples</td>
<td>Red</td>
</tr>
<tr>
<td>Bananas</td>
<td>Yellow</td>
</tr>
<tr>
<td>Oranges</td>
<td>Orange</td>
</tr>
<tr>
<td>Cucumbers</td>
<td>Green</td>
</tr>
</table>
I'd suggest:
// using Array.from() to convert the Array-like NodeList returned
// from document.querySelectorAll() into an Array, in order to use
// Array.prototype.map():
let array = Array.from(document.querySelectorAll('tbody tr')).map(
// tr: a reference to the current array-element of the Array over
// which we're iterating; using Arrow function syntax:
(tr) => {
// here we return the result of the following expression;
// again using Array.from() to convert the NodeList of
// the <tr> element's children into an Array, again in order
// to utilise Array.prototype.map():
return Array.from(tr.children).map(
// cell is a reference to the current Node of the Array
// of Nodes over which we're iterating; here we implicitly
// return the textContent of each <td> ('cell') Node; after
// using String.prototype.trim() to remove leading/trailing
// white-space:
(cell) => cell.textContent.trim()
);
});
let array = Array.from(document.querySelectorAll('tbody tr')).map(
(tr) => {
return Array.from(tr.children).map(
(cell) => cell.textContent.trim()
);
});
console.log(array);
<table>
<thead>
<tr>
<td>Table heading</td>
</tr>
</thead>
<tbody>
<tr>
<td>Apples</td>
<td>Red</td>
</tr>
<tr>
<td>Bananas</td>
<td>Yellow</td>
</tr>
<tr>
<td>Oranges</td>
<td>Orange</td>
</tr>
<tr>
<td>Cucumbers</td>
<td>Green</td>
</tr>
</table>
References:
Array.from().
Array.prototype.map().
Arrow functions.
document.querySelectorAll().
ParentNode.children.
String.prototype.trim().
Here is my DOM:
...
<table>
<tbody>
<tr>
<td>1</td>
<td><img src="../first"></td>
<td>John</td>
<\tr>
<tr>
<td>2</td>
<td><img src="../second"></td>
<td>Peter</td>
<\tr>
</tbody>
</table>
...
Now I want to make this array: (to pass it to the server side and make a .CSV export of it)
var arr = array();
arr = array(array(1,'../first','John'),array(2,'../second','Peter'));
How can I make array above from the DOM ?
Note: I use jquery, So I can get the src attribute by using this:
$('img').attr('src');
Haven't tested yet. Basically you need to iterate through all <tr> and get each values.
BTW, array should be Array.
var arr = Array();
$('table tr').each(function(index) {
var id = $(this).children()[0].innerText;
var imageSrc = $(this).find('img').attr('src');
var name = $(this).children()[2].innerText;
arr.push_back(Array(id, imageSrc, name));
});
You can return array using map() and get().
var array = $('tr').map(function() {
return [$(this).find('td').map(function(i) {
return i == 1 ? $(this).find('img').attr('src') : $(this).text()
}).get()]
}).get()
console.log(array)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>1</td>
<td><img src="../first"></td>
<td>John</td>
</tr>
<tr>
<td>2</td>
<td><img src="../second"></td>
<td>Peter</td>
</tr>
</tbody>
</table>
First, add an id to your table, to make sure that you do not accidentally send rows from other table to the server:
<table id="request-rows">
<tbody>
<tr>
<td>1</td>
<td><img src="../first"></td>
<td>John</td>
<\tr>
<tr>
<td>2</td>
<td><img src="../second"></td>
<td>Peter</td>
<\tr>
</tbody>
</table>
Then build your array like this:
var arr = [];
$("#request-rows tr").each(function() {
var tds = $(this).find("td");
var newElement = [$(td[0]).text(), $(td[1]).find("img").attr("src")];
arr.push(newElement);
});
//Do something with arr
Try like this .create array of each tr and then push with main array
var res = []
var a = $('tbody tr')
a.each(function(a, b) {
a = [];
a[0] = $(this).children('td').eq(0).text();
a[1] = $(this).children('td').eq(1).children('img').attr('src');
a[2] = $(this).children('td').eq(2).text();
res.push(a);
})
console.log(res)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tbody>
<tr>
<td>1</td>
<td><img src="../first"></td>
<td>John</td>
<tr>
<tr>
<td>2</td>
<td><img src="../second"></td>
<td>Peter</td>
<\tr>
<\tbody>
<\table>