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JavaScript to remove string in OBX 5.1 starting with first occurance of "\\." till the end

I am trying to write a JavaScript to remove string in OBX 5.1 after "\."
Here is the inbound OBX segment:
OBX|2|NM|WBC^White Blood Cell Count^WinPath||3.2\\.br\\This result could indicate your patient might have\\.br\\sepsis. Take into consideration the absolute\\.br\\neutrophil and lymphocyte counts when making your|x 10^9/l|4 - 10|L|||F|||||
Here is the expected outbound OBX segment:
OBX|2|NM|WBC^White Blood Cell Count^WinPath||3.2|x 10^9/l|4 - 10|L|||F|||||
I have written this Javascript code. It is compiling but not removing the unwanted text.
Here is what I have written:
var RegExp_pattern = "\\.";
function indexOf(stringToTrim) {
return stringToTrim.indexOf(RegExp_pattern);
}
function substring(ssstringToTrim) {
return ssstringToTrim.substring(indexOf(OBX_TestValue), -1);
}
/* Single input message case */
var next = output.append(input[0]);
// loop through Order Group (OBR) & Result Group (OBX)
//
var cntObs = next.getRepeatCount("ObservationMessage");
for (var i = 0; i < cntObs; i++) {
var cntOrders = next.getRepeatCount("ObservationMessage[" + i + "]/Order");
for (var j = 0; j < cntOrders; j++) {
var cntResults = next.getRepeatCount("ObservationMessage[" + i + "]/Order[" + j + "]/Results");
for (var k = 0; k < cntResults; k++) {
var OBX_TestValue = next.getField("ObservationMessage[" + i + "]/Order[" + j + "]/Results[" + k + "]/OBX/ObservationValue");
if (OBX_TestValue.indexOf(OBX_TestValue) > 0) {
OBX_TestValue = substring(OBX_TestValue);
}
}
}
}

To remove everything from the first occurance of "\." until the end of the string you should use a regular expression.
var str = "OBX|2|NM|WBC^White Blood Cell Count^WinPath||3.2\\.br\\This result could indicate your patient might have\\.br\\sepsis. Take into consideration the absolute\\.br\\neutrophil and lymphocyte counts when making your|x 10^9/l|4 - 10|L|||F|||||";
var mtch = str.replace(/\\\..*/, '');
console.log(mtch);

creating a for-loop that prints # signs instead of number values [duplicate]

This question already has answers here:
How to print a half pyramid in javascript
(9 answers)
How to print star pattern in JavaScript in a very simple manner? [closed]
(22 answers)
Closed 1 year ago.
im trying to write a code that outputs lines of '#' signs that increase by one for each value until the input number is reached.
for example, when triangles(3) is called my desired output is:
'#'
'##'
'###'
ive learned how to create this sequence with number values instead of the '#' signs but not sure how to achieve this output displayed above. thanks!
function triangles(num) {
let number = '';
for (let i = 1; i <= num; i++) {
console.log(number += i);
}
}
triangles(5)
this outputs:
'1'
'12'
'123'
'1234'
'12345'

You can use String.prototype.repeat() to repeat the pound (#) character as specified by the current value of i, without needing to declare a new variable to store it:
function triangles(num) {
for (let i = 1; i <= num; i++) {
console.log('#'.repeat(i));
}
}
triangles(5);

function triangles(num) {
let symbol = "#";
for (let i = 1; i <= num; i++) {
console.log(Array(i).fill(symbol).join(""));
}
}
triangles(5);

function triangles(num) {
const c = "#";
for (let i = 1; i <= num; i++) {
console.log(c.repeat(i));
}
}
triangles(5)

You don't have to use console.log to print number += i specifically. If you want to print '#' multiple times, you can use #Terry's answer (which is shorter) or you can use another for loop in your code (this approach could be simpler for beginners).
function triangles(num) {
let number = '';
for (let i = 1; i <= num; i++) {
number++;
let poundkeys = '';
// dont use i again, name it something else (like j or k)
for (let j = 1; j <= number; j++) {
// just like you do number += i, add a pound symbol to poundkeys
poundkeys += '#';
}
// now, log poundkeys
console.log(poundkeys);
}
}
triangles(5);
Also, a quick tip. Generally, it is better not to log number += i. Instead of:
console.log(number += i);
It is encouraged and more readable if you separate them:
number += i;
console.log(number);

draw a Triangle in numbers (javascript) [duplicate]

This question already has answers here:
How to display pyramid using JavaScript?
(34 answers)
Closed 4 years ago.
I wrote this method that draw a Triangle. For example if you call drawTriangle(5) you get the following output:
this is my code :-
function drawTriangle(t){
for (let i=1; i <= t; i++)
{
for (let j=1; j<=i; j++)
{
console.log(j+" ");
}
console.log("\n");
}
}
let t = 5 ;
drawTriangle(t);
and i get this output
I can not make them in a line I don't Know where is the problem .

console.log() will print a new line every time, store each line in a variable and print it at the end of innerLoop
function drawTriangle(t){
for (let i=1; i <= t; i++)
{
let eachLine = ''
for (let j=1; j<=i; j++)
{
eachLine += j + " "
}
eachLine = eachLine.trim();
console.log(eachLine);
}
}
let t = 5 ;
drawTriangle(t);

Refer to this. You can use string concatenation in your inner for loop.

Well other answer has already specified what you missed in your code.
I am adding it in case you want to see a alternate solution
let n = 1;
let op = ''
while(n<=5){
op+=new Array(n).fill(0).map( (e,i) => i+1 ).join(' ') + '\n'
n++
}
console.log(op)

Here's a solution with linear time complexity--just console.log(draw(n)), where n is an integer, to see the result:
function draw(n) {
let triangle = '';
let prev;
for (let i = 1; i <= n; i++) {
if (prev) {
triangle += '\n';
prev = prev + ' ' + i;
} else {
prev = i;
}
triangle += prev;
}
return triangle;
}

JavaScript - Printing from Array of Objects Not Working

I have this array of objects here that I am traversing and want to display a match if the person at the current index has an age within +/- 10 years of anyone else in the array. However, when I run it, it says "Cannot read property 'age' of undefined." Where did I go wrong?
function findmatches() {
var n = USERS.length;
for (var i = 0; i < n; i++) {
var currName = USERS[i].firstName;
var currAge = USERS[i].age;
var currGender = USERS[i].gender;
for (var c = 0; c < 10; c++) {
if (((USERS[c].age) + 10) <= currAge) {
document.getElementById("showmatches").innerHTML += currName + " matched to >> " + USERS[i].firstName + " " + USERS[i].lastName + " \n";
break;
}
}
}
}

What exactly is your second for loop supposed to do?
In the code you posted, it iterates through first 10 users in the USERS array. I assume it has less users than that, so at some point USERS[c] is undefined, and you're trying to access USERS[c].age.

Need for/while/do while loops to repeat asterisks

I have this problem, to repeat 30 asterisks for 3 lines. I made this example code but it repeats 30 numbers (1..30) from 1 number for first line, up to 30 numbers for the last line. So, I'd need the code to repeat 30 asterisks, for 3 lines each but not quite like within this code.
Sorry for bad elaboration.
var text = "";
var max = 30;
for(i = 0; i < max; i++)
{
for(j = 0; j <= i; j++)
{
text += (j+1)+" ";
}
text += "<br />";
}

A more re-usable solution will be to make a generic repeatString function that simply makes multiple copies of any string.
function repeatString(s, times) {
for (var i = 0, r = ''; i < times; i++) {
r += s;
}
return r;
}
var line = repeatString('*', 30) + '<br />',
content = repeatString(line, 3);
http://jsfiddle.net/611y2vmz/1/

Repeat the loop three times, like this:
for ( var i = 0; i < 3; i++ ) { // this is the line loop
for ( var j = 0; j < 30; j++ ) { //this is the asterix loop
document.write('*');
}
document.write('<br>');
}
Here's a simple demo

If you are using ES2015 (ES6) syntax you can leverage repeat function and string templating. Using those features your code will look like this
let text = (`${'*'.repeat(30)}<br/>`).repeat(3);
Here is an example of ES2015 (ES6) code
if you are using ES5 then you can do this way:
String.prototype.repeat = function(count) {
return count < 1 ? '' : new Array(count + 1).join(this);
};
var text = ('*'.repeat(30) + '<br/>').repeat(3);
Here is an example of ES5 code

You need your outer loop to iterate 3 times, and your inner loop to iterate 30 times. Each iteration of your inner loop should add an asterisk (instead of adding j+1 like you are doing now). This will produce 3 rows of 30 asterisks.

var TEXT = "*";
var LINE_SEPARATOR = "<br/>";
var TEXT_COUNT = 30;
var LINE_COUNT = 3;
var output = "";
for (line = 1; line <= LINE_COUNT; ++line) {
for (text = 1; text <= TEXT_COUNT; ++text) {
output += TEXT;
}
output += LINE_SEPARATOR;
}
document.write(output);

An alternative would be to use recursion:
function stars(num) {
return num > 0 ? stars(num - 1) + '*' : '';
}
var content = stars(30) + '<br/>' + stars(30) + '<br/>' + stars(30);
DEMO