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I'm trying to fill a rectangle with diagonal lines at 30 degrees that don't get clipped by the canvas. Each line should start and end on the edges of the canvas, but do not go outside the canvas.
I've gotten somewhat of a result but is struggling to understand how I can fix the ends so the lines become evenly distributed:
Here is the code I got so far:
const myCanvas = document.getElementById("myCanvas");
const _ctx = myCanvas.getContext("2d");
const canvasWidth = 600;
const canvasHeight = 300;
// Helper function
const degToRad = (deg) => deg * (Math.PI / 180);
const angleInDeg = 30;
const spaceBetweenLines = 16;
const lineThickness = 16;
_ctx.fillStyle = `black`;
_ctx.fillRect(0, 0, canvasWidth, canvasHeight);
const step = (spaceBetweenLines + lineThickness) / Math.cos(angleInDeg * (Math.PI / 180));
for (let distance = -canvasHeight + step; distance < canvasWidth; distance += step) {
let x = 0;
let y = 0;
if(distance < 0) {
// Handle height
y = canvasHeight - (distance + canvasHeight);
} else {
// Handle height
x = distance;
}
const lineLength = canvasHeight - y;
const slant = lineLength / Math.tan(degToRad((180 - 90 - angleInDeg)));
const x2 = Math.min(x + slant, canvasWidth);
const y2 = y + lineLength;
_ctx.beginPath();
_ctx.moveTo(x, y);
_ctx.lineTo(x2, y2);
_ctx.lineWidth = lineThickness;
_ctx.strokeStyle = 'green';
_ctx.stroke();
}
and a JSFiddle for the code.
What I'm trying to achieve is drawing a pattern where I can control the angle of the lines, and that the lines are not clipped by the canvas. Reference photo (the line-ends don't have flat):
Any help?
My example is in Javascript, but it's more the logic I'm trying to wrap my head around. So I'm open to suggestions/examples in other languages.
Update 1
If the angle of the lines is 45 degree, you will see the gutter becomes correct on the left side. So I'm suspecting there is something I need to do differently on my step calculations.
My current code is based on this answer.
Maybe try something like this for drawing the lines
for(var i = 0; i < 20; i++){
_ctx.fillrect(i * spaceBetweenLines + lineThickness, -100, canvas.height + 100, lineThickness)
}
I have some js code that i copied from a youtube tutorial and adapted for my own project to fill the header, the code works as intended and it works when the viewport is smaller than around 1200px, however when i put firefox into full screen the animation does not play & the image is being stretched, not retaining its aspect ratio. I do have a 10/15 year old gpu so i'm guessing thats half my issue. The script uses a png image file of 100x100 pixels, which it then converts into particle color values. Can this be optimized or made to run better. it seems that the wider the viewport the longer the animation takes to kick in, until it finally stops & doesn't work. full screen= [2550x1440]...
The original tutorial is here: Pure Javascript Particle Animations & to convert an image to base64 encoding is here: Image to base64.
HTML:
<html>
<body>
<canvas id="CanV"></canvas>
</body>
</html>
CSS:
#Canv{
position:absolute;
top:-1px;left:-2px;
z-index:67;
width:100vw !important;
max-height: 264px !important;
min-height: 245px !important;
filter:blur(2.27px);
}
Javascript:
window.addEventListener("DOMContentLoaded",(e)=>{
const canv = document.getElementById('Canv');
const ctx = canv.getContext('2d');
canv.width = window.innerWidth;
canv.height = window.innerHeight/ 3.85;
let particleArray = [];
let mouse = {
x: null,
y: null,
radius: 74
}
window.addEventListener('mousemove',(e)=>{
mouse.x = event.x + canv.clientLeft/2;
mouse.y = event.y + canv.clientTop/1.2;
});
function drawImage(){
let imageWidth = png.width; //These to values crop if / sum no.
let imageHeight = png.height;
const data = ctx.getImageData(0, 0, imageWidth, imageHeight); //Gets img data for particles
ctx.clearRect(0,0, canv.width, canv.height); // Clears the original img as its now being stored in the variable data.
class Particle {
constructor(x, y, color, size){
this.x = x + canv.width/2 - png.width * 174, //Chngd Ok:74
this.y = y + canv.height/2 - png.height * 32, //Ch<2 Ok:16
this.color = color,
this.size = 2.28, // Particle Size > Changed this value. from 2 i think!.
this.baseX = x + canv.width/1.8 - png.width * 3.1, //Chngd ok:5.1
this.baseY = y + canv.height/1.2 - png.height * 2.8,
this.density = (Math.random() * 14) + 2;
}
draw() {
ctx.beginPath(); // this creates the sort of force field around the mouse pointer.
ctx.arc(this.x, this.y, this.size, 0, Math.PI * 2);
ctx.closePath();
ctx.fill();
}
update() {
ctx.fillStyle = this.color;
// Collision detection
let dx = mouse.x - this.x;
let dy = mouse.y - this.y;
let distance = Math.sqrt(dx * dx + dy * dy);
let forceDirectionX = dx / distance;
let forceDirectionY = dy / distance;
// Max distance, past that the force will be 0
const maxDistance = 144;
let force = (maxDistance - distance) / maxDistance;
if (force < 0) force = 0;
let directionX = (forceDirectionX * force * this.density * 0.6);
let directionY = (forceDirectionY * force * this.density * 8.7); //Ch.this
if (distance < mouse.radius + this.size) {
this.x -= directionX;
this.y -= directionY;
} else {
if (this.x !== this.baseX){
let dx = this.x - this.baseX;
this.x -= dx/54; // Speed Particles return to ori
} if (this.y !== this.baseY){
let dy = this.y - this.baseY;
this.y -= dy/17; // Speed Particles return to ori
}
}
this.draw();
}
}
function init(){
particleArray = [];
for(let y = 0, y2 = data.height; y<y2; y++){
for(let x =0, x2 = data.width; x<x2; x++){
if(data.data[(y * 4 * data.width) + (x*4) + 3] > 128){
let positionX = x + 25;
let positionY = y + 45; // Co-ords on Canv
let color = "rgb(" + data.data[(y * 4 * data.width) + (x * 4)] + "," +
data.data[(y * 4 * data.width) + (x * 4) + 1] + "," +
data.data[(y * 4 * data.width) + (x * 4) + 2] + ")";
particleArray.push(new Particle(positionX * 2, positionY * 2, color));
} /* These number effect png size but its to high */
}
}
}
function animate(){
requestAnimationFrame(animate);
ctx.fillStyle = 'rgba(0,0,0,.07)';
ctx.fillRect(0,0, innerWidth, innerHeight);
for(let i =0; i < particleArray.length; i++){
particleArray[i].update();
}
}
init();
animate();
}
const png = new Image();
png.src = "RemovedBase64StringToBig";
window.addEventListener('load',(e)=>{
console.log('page has loaded');
ctx.drawImage(png, 0, 0);
drawImage();
})
});
have managed to shorten it by about 100 characters by shortening all the variable names > PartArr, ImgWidth, DirX, DirY etc, but apart from minifying it is there any other ways to optimize this? and fix the full screen issue?
I tried to add it to a JSfiddle, So I could link to it here, but I don't think this is allowing the base64 string, its not loading anything anyway. The canvas loads, with the bg just no image or animation.
I've found out what part of the problem is with full screen, the cursor position is actually about 300px to the right of where the actual cursor is, but I still have no idea how to fix this or fix the major lagging performance issues. Guessing its alot to compute even just with 100x100.
One option I can think of to make this perform better would be to move it & its calculations, into its own dedicated web worker & convert the image to Webp but i'm still not very clued up about web workers or how to implement them properly.. Will play around & see what I can put together using All the suggestions in the comments & answers.
I'm adding these links only for future reference, when I come back to this later on:
MDN Canvas Optimizations
Html5Rocks Canvas Performance
Stack Question. Canv ~ Opti
Creating A blob From A Base 64 String in Js
Secondary bonus Question,
is there a maximum file size or max px dimensions,
that can be base64 encoded? only asking this as someone on facebook has recently sent me a question regarding another project with multiple base64 encoded images and I was unsure of the answer..
Shortening your code doesn't help much with performance. I'm using Firefox. To check what's taking your time up the most during browser runs in Firefox, you can read Performance from MDN.
The problem with your solution is your fps is dropping hard. This happens because you are painting each Particle every frame. Imagine how laggy it will be when there are thousands of Particles that you need to paint every frame. This paint call is called from your function Particle.draw (which calls the following: ctx.beginPath, ctx.arc, and ctx.closePath). This function, as said, will be called because of Particle.update for each frame. This is an extremely expensive operation. To improve your fps drastically, you can try to not draw each Particle individually, but rather gather all the Particles' ImageData wholly then placing it in the canvas only once in rAQ (thus only one paint happens). This ImageData is an object that contains the rgba for each pixel on canvas.
In my solution below, I did the following:
For each Particle that is dirty (has been updated), modify the ImageData that is to be put in the canvas
Then, after the whole ImageData has been constructed for one frame, only draw once to the canvas using putImageData. This saves a lot of the time needed to call your function Particle.update to draw each Particle individually.
One other obvious solution is to increase the size of Particles so that there are fewer Particles' pixels that are needed to be processed (to alter ImageData). I've also tweaked the code a little so that the image will always be at least 100px high; you can tweak the maths so that the image will always maintain your aspect ratio and respond to window size.
Here's a working example:
const canvas = document.querySelector('#canvas1')
const ctx = canvas.getContext('2d')
canvas.width = window.innerWidth
canvas.height = window.innerHeight
let canvasWidth = canvas.width
let canvasHeight = canvas.height
let particleArray = []
let imageData = []
// mouse
let mouse = {
x: null,
y: null,
radius: 40
}
window.addEventListener('mousemove', e => {
mouse.x = event.x
mouse.y = event.y
})
function drawImage(width, height) {
let imageWidth = width
let imageHeight = height
const data = ctx.getImageData(0, 0, imageWidth, imageHeight)
class Particle {
constructor(x, y, color, size = 2) {
this.x = Math.round(x + canvas.width / 2 - imageWidth * 2)
this.y = Math.round(y + canvas.height / 2 - imageHeight * 2)
this.color = color
this.size = size
// Records base and previous positions to repaint the canvas to its original background color
this.baseX = Math.round(x + canvas.width / 2 - imageWidth * 2)
this.baseY = Math.round(y + canvas.height / 2 - imageHeight * 2)
this.previousX = null
this.previousY = null
this.density = (Math.random() * 100) + 2
}
stringifyColor() {
return `rgba(${this.color.r}, ${this.color.g}, ${this.color.b}, ${this.color.a}`
}
update() {
ctx.fillStyle = this.stringifyColor()
// collision detection
let dx = mouse.x - this.x
let dy = mouse.y - this.y
let distance = Math.sqrt(dx * dx + dy * dy)
let forceDirectionX = dx / distance
let forceDirectionY = dy / distance
// max distance, past that the force will be 0
const maxDistance = 100
let force = (maxDistance - distance) / maxDistance
if (force < 0) force = 0
let directionX = (forceDirectionX * force * this.density)
let directionY = (forceDirectionY * force * this.density)
this.previousX = this.x
this.previousY = this.y
if (distance < mouse.radius + this.size) {
this.x -= directionX
this.y -= directionY
} else {
// Rounded to one decimal number to as x and y cannot be the same (whole decimal-less integer)
// as baseX and baseY by decreasing using a random number / 20
if (Math.round(this.x) !== this.baseX) {
let dx = this.x - this.baseX
this.x -= dx / 20
}
if (Math.round(this.y) !== this.baseY) {
let dy = this.y - this.baseY
this.y -= dy / 20
}
}
}
}
function createParticle(x, y, size) {
if (data.data[(y * 4 * data.width) + (x * 4) + 3] > 128) {
let positionX = x
let positionY = y
let offset = (y * 4 * data.width) + (x * 4)
let color = {
r: data.data[offset],
g: data.data[offset + 1],
b: data.data[offset + 2],
a: data.data[offset + 3]
}
return new Particle(positionX * 4, positionY * 4, color, size)
}
}
// Instead of drawing each Particle one by one, construct an ImageData that can be
// painted into the canvas at once using putImageData()
function updateImageDataWith(particle) {
let x = particle.x
let y = particle.y
let prevX = particle.previousX
let prevY = particle.previousY
let size = particle.size
if (prevX || prevY) {
let prevMinY = Math.round(prevY - size)
let prevMaxY = Math.round(prevY + size)
let prevMinX = Math.round(prevX - size)
let prevMaxX = Math.round(prevX + size)
for (let y = prevMinY; y < prevMaxY; y++){
for (let x = prevMinX; x < prevMaxX; x++) {
if (y < 0 || y > canvasHeight) continue
else if (x < 0 || x > canvasWidth) continue
else {
let offset = y * 4 * canvasWidth + x * 4
imageData.data[offset] = 255
imageData.data[offset + 1] = 255
imageData.data[offset + 2] = 255
imageData.data[offset + 3] = 255
}
}
}
}
let minY = Math.round(y - size)
let maxY = Math.round(y + size)
let minX = Math.round(x - size)
let maxX = Math.round(x + size)
for (let y = minY; y < maxY; y++){
for (let x = minX; x < maxX; x++) {
if (y < 0 || y > canvasHeight) continue
else if (x < 0 || x > canvasWidth) continue
else {
let offset = y * 4 * canvasWidth + x * 4
imageData.data[offset] = particle.color.r
imageData.data[offset + 1] = particle.color.g
imageData.data[offset + 2] = particle.color.b
imageData.data[offset + 3] = particle.color.a
}
}
}
}
function init() {
particleArray = []
imageData = ctx.createImageData(canvasWidth, canvasHeight)
// Initializing imageData to a blank white "page"
for (let data = 1; data <= canvasWidth * canvasHeight * 4; data++) {
imageData.data[data - 1] = data % 4 === 0 ? 255 : 255
}
const size = 2 // Min size is 2
const step = Math.floor(size / 2)
for (let y = 0, y2 = data.height; y < y2; y += step) {
for (let x = 0, x2 = data.width; x < x2; x += step) {
// If particle's alpha value is too low, don't record it
if (data.data[(y * 4 * data.width) + (x * 4) + 3] > 128) {
let newParticle = createParticle(x, y, size)
particleArray.push(newParticle)
updateImageDataWith(newParticle)
}
}
}
}
function animate() {
requestAnimationFrame(animate)
for (let i = 0; i < particleArray.length; i++) {
let imageDataCanUpdateKey = `${Math.round(particleArray[i].x)}${Math.round(particleArray[i].y)}`
particleArray[i].update()
updateImageDataWith(particleArray[i])
}
ctx.putImageData(imageData, 0, 0)
}
init()
animate()
window.addEventListener('resize', e => {
canvas.width = innerWidth
canvas.height = innerHeight
canvasWidth = canvas.width
canvasHeight = canvas.height
init()
})
}
const png = new Image()
png.src = " 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"
window.addEventListener('load', e => {
// Ensuring height of image is always 100px
let pngWidth = png.width
let pngHeight = png.height
let divisor = pngHeight / 100
let finalWidth = pngWidth / divisor
let finalHeight = pngHeight / divisor
ctx.drawImage(png, 0, 0, finalWidth, finalHeight)
drawImage(finalWidth, finalHeight)
})
#canvas1 {
position: absolute;
top: 0;
left: 0;
width: 100%;
height: 100%;
}
<canvas id="canvas1"></canvas>
UPDATE 2: I have managed to optimize further. Now it can render FullHD image (1920x1080) without downgrading quality (on my PC it runs at about 20fps).
Take a look this code on JSFiddle (you can also tweak values).
Thanks also goes to #Richard (check out his answer) for idea to put all data in ImageData and make a single draw call. Code on JSFiddle is combination of his and mine optimizations (code below is my old code).
EDIT: Updated JSFiddle link, optimized more by spreading work of stationary particles across multiple frames (for given settings it improves performance for about 10%).
Regarding optimization, you won't achieve much by minifying code (in this case) because code that eats up CPU is runtime intensive (executes each frame). Minification is good for optimizing loading, not runtime execution.
Most of time is spent on drawing, and after some investigation I have found few performance optimizations but these are not enough to make big difference (eg. ctx.closePath() can be omitted and this saves some milliseconds).
What you can do is to either reduce resolution of image or skip some pixels in image in order to reduce work.
Additionally you could spread work across multiple frames to improve frame rate (but keep in mind if you spread it on more than few frames you might start seeing flickering).
Fullscreen issue can be solved by simply re-initializing everything on resize event.
Below is code with mentioned optimizations and fullscreen fix. Sample image is 375x375 pixels.
UPDATE: I played a little with code and I managed to improve further performance by optimizing calls (things I mentioned below code snippet). Code is updated with these changes.
var canv
var ctx
//performance critical parameters
const pixelStep = 2 //default 1; increase for images of higher resolution
const maxParticlesToProcessInOneFrame = 20000
//additional performance oriented paramteres
// Max distance, past that the force will be 0
const maxDistance = 144
const mouseRadius = 74
//customization parameters
const ctxFillStyle = 'rgba(0,0,0,.07)'
const speedOfActivatingParticle = 1
const speedOfRestoringParticle = 0.1
const png = new Image();
const mouse = {
x: null,
y: null
}
window.addEventListener('mousemove', (e) => {
mouse.x = event.x + canv.clientLeft;
mouse.y = event.y + canv.clientTop;
})
class Particle {
constructor(x, y, size) {
this.x = x
this.y = y
this.size = pixelStep
this.baseX = x
this.baseY = y
this.density = (Math.random() * 14) + 2
}
draw() {
//ctx.beginPath(); // this creates the sort of force field around the mouse pointer.
//ctx.arc(this.x, this.y, this.size, 0, Math.PI * 2);
ctx.rect(this.x, this.y, this.size * 2, this.size * 2)
//ctx.closePath();
}
update() {
// Collision detection
let dx = mouse.x - this.x;
let dy = mouse.y - this.y;
let distance = Math.sqrt(dx * dx + dy * dy);
if (distance < mouseRadius + this.size) {
let forceDirectionX = dx / distance;
let forceDirectionY = dy / distance;
let force = (maxDistance - distance) / maxDistance;
if (force < 0)
force = 0;
const forceTimesDensity = force * this.density * speedOfActivatingParticle
let directionX = (forceDirectionX * forceTimesDensity);
let directionY = (forceDirectionY * forceTimesDensity); //Ch.this
this.x -= directionX;
this.y -= directionY;
} else {
if (this.x !== this.baseX) {
let dx = this.x - this.baseX;
this.x -= dx * speedOfRestoringParticle; // Speed Particles return to ori
}
if (this.y !== this.baseY) {
let dy = this.y - this.baseY;
this.y -= dy * speedOfRestoringParticle; // Speed Particles return to ori
}
}
this.draw();
}
}
window.addEventListener('resize', initializeCanvas)
window.addEventListener("load", initializeCanvas, {
once: true
})
let animationFrame = null
function initializeCanvas(e) {
cancelAnimationFrame(animationFrame)
canv = document.getElementById('Canv');
ctx = canv.getContext('2d');
canv.width = window.innerWidth;
canv.height = window.innerHeight;
let particles = {}
function drawImage() {
let imageWidth = png.width; //These to values crop if / sum no.
let imageHeight = png.height;
const data = ctx.getImageData(0, 0, imageWidth, imageHeight); //Gets img data for particles
ctx.clearRect(0, 0, canv.width, canv.height); // Clears the original img as its now being stored in the variable data.
function init() {
particles = {}
for (let y = 0, y2 = data.height; y < y2; y += pixelStep) {
for (let x = 0, x2 = data.width; x < x2; x += pixelStep) {
if (data.data[(y * 4 * data.width) + (x * 4) + 3] > 128) {
let positionX = x
let positionY = y
let color = "rgb(" + data.data[(y * 4 * data.width) + (x * 4)] + "," +
data.data[(y * 4 * data.width) + (x * 4) + 1] + "," +
data.data[(y * 4 * data.width) + (x * 4) + 2] + ")";
let particlesArray = particles[color]
if (!particlesArray)
particlesArray = particles[color] = []
particlesArray.push(new Particle(positionX * 2, positionY * 2))
} /* These number effect png size but its to high */
}
}
}
let particlesProcessed = 0
let animateGenerator = animate()
function* animate() {
particlesProcessed = 0
ctx.fillStyle = ctxFillStyle;
ctx.fillRect(0, 0, innerWidth, innerHeight);
let colors = Object.keys(particles)
for (let j = 0; j < colors.length; j++) {
let color = colors[j]
ctx.fillStyle = color
let particlesArray = particles[color]
ctx.beginPath()
for (let i = 0; i < particlesArray.length; i++) {
particlesArray[i].update()
if (++particlesProcessed > maxParticlesToProcessInOneFrame) {
particlesProcessed = 0
ctx.fill()
yield
ctx.beginPath()
}
}
ctx.fill()
}
}
init();
function animateFrame() {
animationFrame = requestAnimationFrame(() => {
if (animateGenerator.next().done) {
animateGenerator = animate()
}
animateFrame()
})
}
animateFrame()
}
console.log('page has loaded');
ctx.drawImage(png, 0, 0, png.width, png.height);
drawImage();
}
png.src = 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";
body {
margin: 0;
padding: 0;
}
#Canv {
width: 100vw;
height: 100vh;
filter: blur(1.5px);
}
<canvas id="Canv"></canvas>
If you still need to optimize, you could do some optimization regarding ctx.beginPath(), ctx.fill() and ctx.rect() calls. For example, try to combine sibling pixels (pixels that are next to each other) and render them all in one call. Furthermore, you could merge similar colors in single color, but downside is that image will loose quality (depending on how much colors are merged).
Also (if this is option) you might want to set fixed canvas size rather than dynamically sized.
Disclosure: On my PC given code works nicely, but on others it might still have performance issues. For that reason try to play with pixelStep and maxParticlesToProcessInOneFrame variable values.
I'm making an HTML5 canvas hexagon grid based system and I need to be able to detect what hexagonal tile in a grid has been clicked when the canvas is clicked.
Several hours of searching and trying my own methods led to nothing, and porting implementations from other languages has simply confused me to a point where my brain is sluggish.
The grid consists of flat topped regular hexagons like in this diagram:
Essentially, given a point and the variables specified in this image as the sizing for every hexagon in the grid (R, W, S, H):
I need to be able to determine whether a point is inside a hexagon given.
An example function call would be pointInHexagon(hexX, hexY, R, W, S, H, pointX, pointY) where hexX and hexY are the coordinates for the top left corner of the bounding box of a hexagonal tile (like the top left corner in the image above).
Is there anyone who has any idea how to do this? Speed isn't much of a concern for the moment.
Simple & fast diagonal rectangle slice.
Looking at the other answers I see that they have all a little over complicated the problem. The following is an order of magnitude quicker than the accepted answer and does not require any complicated data structures, iterators, or generate dead memory and unneeded GC hits. It returns the hex cell row and column for any related set of R, H, S or W. The example uses R = 50.
Part of the problem is finding which side of a rectangle a point is if the rectangle is split diagonally. This is a very simple calculation and is done by normalising the position of the point to test.
Slice any rectangle diagonally
Example a rectangle of width w, and height h split from top left to bottom right. To find if a point is left or right. Assume top left of rectangle is at rx,ry
var x = ?;
var y = ?;
x = ((x - rx) % w) / w;
y = ((y - ry) % h) / h;
if (x > y) {
// point is in the upper right triangle
} else if (x < y) {
// point is in lower left triangle
} else {
// point is on the diagonal
}
If you want to change the direction of the diagonal then just invert one of the normals
x = 1 - x; // invert x or y to change the direction the rectangle is split
if (x > y) {
// point is in the upper left triangle
} else if (x < y) {
// point is in lower right triangle
} else {
// point is on the diagonal
}
Split into sub cells and use %
The rest of the problem is just a matter of splitting the grid into (R / 2) by (H / 2) cells width each hex covering 4 columns and 2 rows. Every 1st column out of 3 will have diagonals. with every second of these column having the diagonal flipped. For every 4th, 5th, and 6th column out of 6 have the row shifted down one cell. By using % you can very quickly determine which hex cell you are on. Using the diagonal split method above make the math easy and quick.
And one extra bit. The return argument retPos is optional. if you call the function as follows
var retPos;
mainLoop(){
retPos = getHex(mouse.x, mouse.y, retPos);
}
the code will not incur a GC hit, further improving the speed.
Pixel to Hex coordinates
From Question diagram returns hex cell x,y pos. Please note that this function only works in the range 0 <= x, 0 <= y if you need negative coordinates subtract the min negative pixel x,y coordinate from the input
// the values as set out in the question image
var r = 50;
var w = r * 2;
var h = Math.sqrt(3) * r;
// returns the hex grid x,y position in the object retPos.
// retPos is created if not supplied;
// argument x,y is pixel coordinate (for mouse or what ever you are looking to find)
function getHex (x, y, retPos){
if(retPos === undefined){
retPos = {};
}
var xa, ya, xpos, xx, yy, r2, h2;
r2 = r / 2;
h2 = h / 2;
xx = Math.floor(x / r2);
yy = Math.floor(y / h2);
xpos = Math.floor(xx / 3);
xx %= 6;
if (xx % 3 === 0) { // column with diagonals
xa = (x % r2) / r2; // to find the diagonals
ya = (y % h2) / h2;
if (yy % 2===0) {
ya = 1 - ya;
}
if (xx === 3) {
xa = 1 - xa;
}
if (xa > ya) {
retPos.x = xpos + (xx === 3 ? -1 : 0);
retPos.y = Math.floor(yy / 2);
return retPos;
}
retPos.x = xpos + (xx === 0 ? -1 : 0);
retPos.y = Math.floor((yy + 1) / 2);
return retPos;
}
if (xx < 3) {
retPos.x = xpos + (xx === 3 ? -1 : 0);
retPos.y = Math.floor(yy / 2);
return retPos;
}
retPos.x = xpos + (xx === 0 ? -1 : 0);
retPos.y = Math.floor((yy + 1) / 2);
return retPos;
}
Hex to pixel
And a helper function that draws a cell given the cell coordinates.
// Helper function draws a cell at hex coordinates cellx,celly
// fStyle is fill style
// sStyle is strock style;
// fStyle and sStyle are optional. Fill or stroke will only be made if style given
function drawCell1(cellPos, fStyle, sStyle){
var cell = [1,0, 3,0, 4,1, 3,2, 1,2, 0,1];
var r2 = r / 2;
var h2 = h / 2;
function drawCell(x, y){
var i = 0;
ctx.beginPath();
ctx.moveTo((x + cell[i++]) * r2, (y + cell[i++]) * h2)
while (i < cell.length) {
ctx.lineTo((x + cell[i++]) * r2, (y + cell[i++]) * h2)
}
ctx.closePath();
}
ctx.lineWidth = 2;
var cx = Math.floor(cellPos.x * 3);
var cy = Math.floor(cellPos.y * 2);
if(cellPos.x % 2 === 1){
cy -= 1;
}
drawCell(cx, cy);
if (fStyle !== undefined && fStyle !== null){ // fill hex is fStyle given
ctx.fillStyle = fStyle
ctx.fill();
}
if (sStyle !== undefined ){ // stroke hex is fStyle given
ctx.strokeStyle = sStyle
ctx.stroke();
}
}
I think you need something like this~
EDITED
I did some maths and here you have it. This is not a perfect version but probably will help you...
Ah, you only need a R parameter because based on it you can calculate H, W and S. That is what I understand from your description.
// setup canvas for demo
var canvas = document.getElementById('canvas');
canvas.width = 300;
canvas.height = 275;
var context = canvas.getContext('2d');
var hexPath;
var hex = {
x: 50,
y: 50,
R: 100
}
// Place holders for mouse x,y position
var mouseX = 0;
var mouseY = 0;
// Test for collision between an object and a point
function pointInHexagon(target, pointX, pointY) {
var side = Math.sqrt(target.R*target.R*3/4);
var startX = target.x
var baseX = startX + target.R / 2;
var endX = target.x + 2 * target.R;
var startY = target.y;
var baseY = startY + side;
var endY = startY + 2 * side;
var square = {
x: startX,
y: startY,
side: 2*side
}
hexPath = new Path2D();
hexPath.lineTo(baseX, startY);
hexPath.lineTo(baseX + target.R, startY);
hexPath.lineTo(endX, baseY);
hexPath.lineTo(baseX + target.R, endY);
hexPath.lineTo(baseX, endY);
hexPath.lineTo(startX, baseY);
if (pointX >= square.x && pointX <= (square.x + square.side) && pointY >= square.y && pointY <= (square.y + square.side)) {
var auxX = (pointX < target.R / 2) ? pointX : (pointX > target.R * 3 / 2) ? pointX - target.R * 3 / 2 : target.R / 2;
var auxY = (pointY <= square.side / 2) ? pointY : pointY - square.side / 2;
var dPointX = auxX * auxX;
var dPointY = auxY * auxY;
var hypo = Math.sqrt(dPointX + dPointY);
var cos = pointX / hypo;
if (pointX < (target.x + target.R / 2)) {
if (pointY <= (target.y + square.side / 2)) {
if (pointX < (target.x + (target.R / 2 * cos))) return false;
}
if (pointY > (target.y + square.side / 2)) {
if (pointX < (target.x + (target.R / 2 * cos))) return false;
}
}
if (pointX > (target.x + target.R * 3 / 2)) {
if (pointY <= (target.y + square.side / 2)) {
if (pointX < (target.x + square.side - (target.R / 2 * cos))) return false;
}
if (pointY > (target.y + square.side / 2)) {
if (pointX < (target.x + square.side - (target.R / 2 * cos))) return false;
}
}
return true;
}
return false;
}
// Loop
setInterval(onTimerTick, 33);
// Render Loop
function onTimerTick() {
// Clear the canvas
canvas.width = canvas.width;
// see if a collision happened
var collision = pointInHexagon(hex, mouseX, mouseY);
// render out text
context.fillStyle = "Blue";
context.font = "18px sans-serif";
context.fillText("Collision: " + collision + " | Mouse (" + mouseX + ", " + mouseY + ")", 10, 20);
// render out square
context.fillStyle = collision ? "red" : "green";
context.fill(hexPath);
}
// Update mouse position
canvas.onmousemove = function(e) {
mouseX = e.offsetX;
mouseY = e.offsetY;
}
#canvas {
border: 1px solid black;
}
<canvas id="canvas"></canvas>
Just replace your pointInHexagon(hexX, hexY, R, W, S, H, pointX, pointY) by the var hover = ctx.isPointInPath(hexPath, x, y).
This is for Creating and copying paths
This is about the Collision Detection
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var hexPath = new Path2D();
hexPath.lineTo(25, 0);
hexPath.lineTo(75, 0);
hexPath.lineTo(100, 43);
hexPath.lineTo(75, 86);
hexPath.lineTo(25, 86);
hexPath.lineTo(0, 43);
function draw(hover) {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.fillStyle = hover ? 'blue' : 'red';
ctx.fill(hexPath);
}
canvas.onmousemove = function(e) {
var x = e.clientX - canvas.offsetLeft, y = e.clientY - canvas.offsetTop;
var hover = ctx.isPointInPath(hexPath, x, y)
draw(hover)
};
draw();
<canvas id="canvas"></canvas>
I've made a solution for you that demonstrates the point in triangle approach to this problem.
http://codepen.io/spinvector/pen/gLROEp
maths below:
isPointInside(point)
{
// Point in triangle algorithm from http://totologic.blogspot.com.au/2014/01/accurate-point-in-triangle-test.html
function pointInTriangle(x1, y1, x2, y2, x3, y3, x, y)
{
var denominator = ((y2 - y3)*(x1 - x3) + (x3 - x2)*(y1 - y3));
var a = ((y2 - y3)*(x - x3) + (x3 - x2)*(y - y3)) / denominator;
var b = ((y3 - y1)*(x - x3) + (x1 - x3)*(y - y3)) / denominator;
var c = 1 - a - b;
return 0 <= a && a <= 1 && 0 <= b && b <= 1 && 0 <= c && c <= 1;
}
// A Hex is composite of 6 trianges, lets do a point in triangle test for each one.
// Step through our triangles
for (var i = 0; i < 6; i++) {
// check for point inside, if so, return true for this function;
if(pointInTriangle( this.origin.x, this.origin.y,
this.points[i].x, this.points[i].y,
this.points[(i+1)%6].x, this.points[(i+1)%6].y,
point.x, point.y))
return true;
}
// Point must be outside.
return false;
}
Here is a fully mathematical and functional representation of your problem. You will notice that there are no ifs and thens in this code other than the ternary to change the color of the text depending on the mouse position. This whole job is in fact nothing more than pure simple math of just one line;
(r+m)/2 + Math.cos(a*s)*(r-m)/2;
and this code is reusable for all polygons from triangle to circle. So if interested please read on. It's very simple.
In order to display the functionality I had to develop a mimicking model of the problem. I draw a polygon on a canvas by utilizing a simple utility function. So that the overall solution should work for any polygon. The following snippet will take the canvas context c, radius r, number of sides s, and the local center coordinates in the canvas cx and cy as arguments and draw a polygon on the given canvas context at the right position.
function drawPolgon(c, r, s, cx, cy){ //context, radius, sides, center x, center y
c.beginPath();
c.moveTo(cx + r,cy);
for(var p = 1; p < s; p++) c.lineTo(cx + r*Math.cos(p*2*Math.PI/s), cy + r*Math.sin(p*2*Math.PI/s));
c.closePath();
c.stroke();
}
We have some other utility functions which one can easily understand what exactly they are doing. However the most important part is to check whether the mouse is floating over our polygon or not. It's done by the utility function isMouseIn. It's basically calculating the distance and the angle of the mouse position to the center of the polygon. Then, comparing it with the boundaries of the polygon. The boundaries of the polygon can be expressed by simple trigonometry, just like we have calculated the vertices in the drawPolygon function.
We can think of our polygon as a circle with an oscillating radius at the frequency of number of sides. The oscillation's peak is at the given radius value r (which happens to be at the vertices at angle 2π/s where s is the number of sides) and the minimum m is r*Math.cos(Math.PI/s) (each shows at at angle 2π/s + 2π/2s = 3π/s). I am pretty sure the ideal way to express a polygon could be done by the Fourier transformation but we don't need that here. All we need is a constant radius component which is the average of minimum and maximum, (r+m)/2 and the oscillating component with the frequency of number of sides, s and the amplitude value maximum - minimum)/2 on top of it, Math.cos(a*s)*(r-m)/2. Well of course as per Fourier states we might carry on with smaller oscillating components but with a hexagon you don't really need further iteration while with a triangle you possibly would. So here is our polygon representation in math.
(r+m)/2 + Math.cos(a*s)*(r-m)/2;
Now all we need is to calculate the angle and distance of our mouse position relative to the center of the polygon and compare it with the above mathematical expression which represents our polygon. So all together our magic function is orchestrated as follows;
function isMouseIn(r,s,cx,cy,mx,my){
var m = r*Math.cos(Math.PI/s), // the min dist from an edge to the center
d = Math.hypot(mx-cx,my-cy), // the mouse's distance to the center of the polygon
a = Math.atan2(cy-my,mx-cx); // angle of the mouse pointer
return d <= (r+m)/2 + Math.cos(a*s)*(r-m)/2;
}
So the following code demonstrates how you might approach to solve your problem.
// Generic function to draw a polygon on the canvas
function drawPolgon(c, r, s, cx, cy){ //context, radius, sides, center x, center y
c.beginPath();
c.moveTo(cx + r,cy);
for(var p = 1; p < s; p++) c.lineTo(cx + r*Math.cos(p*2*Math.PI/s), cy + r*Math.sin(p*2*Math.PI/s));
c.closePath();
c.stroke();
}
// To write the mouse position in canvas local coordinates
function writeText(c,x,y,msg,col){
c.clearRect(0, 0, 300, 30);
c.font = "10pt Monospace";
c.fillStyle = col;
c.fillText(msg, x, y);
}
// Getting the mouse position and coverting into canvas local coordinates
function getMousePos(c, e) {
var rect = c.getBoundingClientRect();
return { x: e.clientX - rect.left,
y: e.clientY - rect.top
};
}
// To check if mouse is inside the polygone
function isMouseIn(r,s,cx,cy,mx,my){
var m = r*Math.cos(Math.PI/s),
d = Math.hypot(mx-cx,my-cy),
a = Math.atan2(cy-my,mx-cx);
return d <= (r+m)/2 + Math.cos(a*s)*(r-m)/2;
}
// the event listener callback
function mouseMoveCB(e){
var mp = getMousePos(cnv, e),
msg = 'Mouse at: ' + mp.x + ',' + mp.y,
col = "black",
inside = isMouseIn(radius,sides,center[0],center[1],mp.x,mp.y);
writeText(ctx, 10, 25, msg, inside ? "turquoise" : "red");
}
// body of the JS code
var cnv = document.getElementById("myCanvas"),
ctx = cnv.getContext("2d"),
sides = 6,
radius = 100,
center = [150,150];
cnv.addEventListener('mousemove', mouseMoveCB, false);
drawPolgon(ctx, radius, sides, center[0], center[1]);
#myCanvas { background: #eee;
width: 300px;
height: 300px;
border: 1px #ccc solid
}
<canvas id="myCanvas" width="300" height="300"></canvas>
At the redblog there is a full explanation with math and working examples.
The main idea is that hexagons are horizontally spaced by $3/4$ of hexagons size, vertically it is simply $H$ but the column needs to be taken to take vertical offset into account. The case colored red is determined by comparing x to y at 1/4 W slice.
First I want to say that I made a lot of research and tries myself without any success.
I am working on a MSPaint-like application using Canvas, and I would like to create a pencil tool which looks realistic like handmade drawings... Here is an example in the link below with the default tool :
http://www.onemotion.com/flash/sketch-paint/
I tried to play with mousespeed and linewidth properties but it is not working well (the entire line enlarge and shrink as I move the mouse). I have no idea of an algorithm acting on pixel raw data.
Do you know something existing or a suitable algorithm to apply ? Thank you very much for your help
EDIT
I decided to add the solution I've chosen because it seems to interest lot of people.
So, the best thing I found so far is to draw an image onto the canvas, using the technique explained here : http://css.dzone.com/articles/sketching-html5-canvas-and.
It works like a charm, the result is really convincing and this is quite easy to implement. Try it out here : http://tricedesigns.com/portfolio/sketch/brush.html#
You could try something like the following demo
Live Demo
Your most likely using moveTo and lineTo to create the paths, if you do it that way the properties will be shared for the path until you close the path. So everytime you change the thickness youd need to call closePath and then beginPath again.
In my example I use Bresenham's line algorithm to plot the points. Basically onmousedown it starts painting. Then onmousemove it compares the current coordinates with the last coordinates and plots all of the points between. Its also using fillRect to paint. Based on how fast your moving the line will be thicker or thinner.
Heres the code for the drawing function
var canvas = document.getElementById("canvas"),
ctx = canvas.getContext("2d"),
painting = false,
lastX = 0,
lastY = 0,
lineThickness = 1;
canvas.width = canvas.height = 600;
ctx.fillRect(0, 0, 600, 600);
canvas.onmousedown = function(e) {
painting = true;
ctx.fillStyle = "#ffffff";
lastX = e.pageX - this.offsetLeft;
lastY = e.pageY - this.offsetTop;
};
canvas.onmouseup = function(e){
painting = false;
}
canvas.onmousemove = function(e) {
if (painting) {
mouseX = e.pageX - this.offsetLeft;
mouseY = e.pageY - this.offsetTop;
// find all points between
var x1 = mouseX,
x2 = lastX,
y1 = mouseY,
y2 = lastY;
var steep = (Math.abs(y2 - y1) > Math.abs(x2 - x1));
if (steep){
var x = x1;
x1 = y1;
y1 = x;
var y = y2;
y2 = x2;
x2 = y;
}
if (x1 > x2) {
var x = x1;
x1 = x2;
x2 = x;
var y = y1;
y1 = y2;
y2 = y;
}
var dx = x2 - x1,
dy = Math.abs(y2 - y1),
error = 0,
de = dy / dx,
yStep = -1,
y = y1;
if (y1 < y2) {
yStep = 1;
}
lineThickness = 5 - Math.sqrt((x2 - x1) *(x2-x1) + (y2 - y1) * (y2-y1))/10;
if(lineThickness < 1){
lineThickness = 1;
}
for (var x = x1; x < x2; x++) {
if (steep) {
ctx.fillRect(y, x, lineThickness , lineThickness );
} else {
ctx.fillRect(x, y, lineThickness , lineThickness );
}
error += de;
if (error >= 0.5) {
y += yStep;
error -= 1.0;
}
}
lastX = mouseX;
lastY = mouseY;
}
}
I guess it is not possible to set stroke property such as CSS which is quite easy. With CSS we have dashed, dotted, solid but on canvas when drawing lines/or strokes this doesn't seem to be an option. How have you implemented this?
I've seen some examples but they are really long for such a silly function.
For example:
http://groups.google.com/group/javascript-information-visualization-toolkit/browse_thread/thread/22000c0d0a1c54f9?pli=1
Fun question! I've written a custom implementation of dashed lines; you can try it out here. I took the route of Adobe Illustrator and allow you to specify an array of dash/gap lengths.
For stackoverflow posterity, here's my implementation (slightly altered for s/o line widths):
var CP = window.CanvasRenderingContext2D && CanvasRenderingContext2D.prototype;
if (CP && CP.lineTo){
CP.dashedLine = function(x,y,x2,y2,dashArray){
if (!dashArray) dashArray=[10,5];
if (dashLength==0) dashLength = 0.001; // Hack for Safari
var dashCount = dashArray.length;
this.moveTo(x, y);
var dx = (x2-x), dy = (y2-y);
var slope = dx ? dy/dx : 1e15;
var distRemaining = Math.sqrt( dx*dx + dy*dy );
var dashIndex=0, draw=true;
while (distRemaining>=0.1){
var dashLength = dashArray[dashIndex++%dashCount];
if (dashLength > distRemaining) dashLength = distRemaining;
var xStep = Math.sqrt( dashLength*dashLength / (1 + slope*slope) );
if (dx<0) xStep = -xStep;
x += xStep
y += slope*xStep;
this[draw ? 'lineTo' : 'moveTo'](x,y);
distRemaining -= dashLength;
draw = !draw;
}
}
}
To draw a line from 20,150 to 170,10 with dashes that are 30px long followed by a gap of 10px, you would use:
myContext.dashedLine(20,150,170,10,[30,10]);
To draw alternating dashes and dots, use (for example):
myContext.lineCap = 'round';
myContext.lineWidth = 4; // Lines 4px wide, dots of diameter 4
myContext.dashedLine(20,150,170,10,[30,10,0,10]);
The "very short" dash length of 0 combined with the rounded lineCap results in dots along your line.
If anyone knows of a way to access the current point of a canvas context path, I'd love to know about it, as it would allow me to write this as ctx.dashTo(x,y,dashes) instead of requiring you to re-specify the start point in the method call.
This simplified version of Phrogz's code utilises the built-in transformation functionality of Canvas and also handles special cases e.g. when dx = 0
var CP = window.CanvasRenderingContext2D && CanvasRenderingContext2D.prototype;
if (CP.lineTo) {
CP.dashedLine = function(x, y, x2, y2, da) {
if (!da) da = [10,5];
this.save();
var dx = (x2-x), dy = (y2-y);
var len = Math.sqrt(dx*dx + dy*dy);
var rot = Math.atan2(dy, dx);
this.translate(x, y);
this.moveTo(0, 0);
this.rotate(rot);
var dc = da.length;
var di = 0, draw = true;
x = 0;
while (len > x) {
x += da[di++ % dc];
if (x > len) x = len;
draw ? this.lineTo(x, 0): this.moveTo(x, 0);
draw = !draw;
}
this.restore();
}
}
I think my calculations are correct and it seems to render OK.
At the moment at least setLineDash([5,10]) works with Chrome and ctx.mozDash = [5,10] works with FF:
var c=document.getElementById("myCanvas");
var ctx=c.getContext("2d");
if ( ctx.setLineDash !== undefined ) ctx.setLineDash([5,10]);
if ( ctx.mozDash !== undefined ) ctx.mozDash = [5,10];
ctx.beginPath();
ctx.lineWidth="2";
ctx.strokeStyle="green";
ctx.moveTo(0,75);
ctx.lineTo(250,75);
ctx.stroke();
Setting to null makes the line solid.
Phroz's solution is great. But when I used it in my application, I found two bugs.
Following code is debugged (and refactored for readability) version of Phroz's one.
// Fixed: Minus xStep bug (when x2 < x, original code bugs)
// Fixed: Vertical line bug (when abs(x - x2) is zero, original code bugs because of NaN)
var CP = window.CanvasRenderingContext2D && CanvasRenderingContext2D.prototype;
if(CP && CP.lineTo) CP.dashedLine = function(x, y, x2, y2, dashArray){
if(! dashArray) dashArray=[10,5];
var dashCount = dashArray.length;
var dx = (x2 - x);
var dy = (y2 - y);
var xSlope = (Math.abs(dx) > Math.abs(dy));
var slope = (xSlope) ? dy / dx : dx / dy;
this.moveTo(x, y);
var distRemaining = Math.sqrt(dx * dx + dy * dy);
var dashIndex = 0;
while(distRemaining >= 0.1){
var dashLength = Math.min(distRemaining, dashArray[dashIndex % dashCount]);
var step = Math.sqrt(dashLength * dashLength / (1 + slope * slope));
if(xSlope){
if(dx < 0) step = -step;
x += step
y += slope * step;
}else{
if(dy < 0) step = -step;
x += slope * step;
y += step;
}
this[(dashIndex % 2 == 0) ? 'lineTo' : 'moveTo'](x, y);
distRemaining -= dashLength;
dashIndex++;
}
}
Mozilla has been working on an implementation of dashed stroking for canvas, so we may see it added to the spec in the near future.
There's a much simpler way to do this. According to http://www.w3.org/TR/2dcontext/#dom-context-2d-strokestyle strokeStyle accepts strings, CanvasGradients, or CanvasPatterns. So we just take an image like this:
<img src="images/dashedLineProto.jpg" id="cvpattern1" width="32" height="32" />
load it into a canvas, and draw our little rectangle with it.
var img=document.getElementById("cvpattern1");
var pat=ctx.createPattern(img,"repeat");
ctx.strokeStyle = pat;
ctx.strokeRect(20,20,150,100);
that doesnt result in a perfect dashed line, but it's really straightforward and modifiable. Results may of course become imperfect when you're drawing lines which arent horizontal or vertical, a dotted pattern might help there.
PS. keep in mind SOP applies when you're trying to use imgs from external sources in your code.
Looks like context.setLineDash is pretty much implemented.
See this.
" context.setLineDash([5])
will result in a dashed line where both the dashes and spaces are 5 pixels in size. "
There is currently no support in HTML5 Canvas specification for dashed lines.
check this out:
http://davidowens.wordpress.com/2010/09/07/html-5-canvas-and-dashed-lines/
or
Check out the Raphael JS Library:
http://raphaeljs.com/
There are support for it in Firefox at least
ctx.mozDash = [5,10];
seems like ctx.webkitLineDash worked before, but they removed it because it had some compabillity issues.
The W3C specs says ctx.setLineDash([5,10]); but it doesn't seem to be implemented yet anywhere.
I made modified the dashedLine function to add support for offsetting. It utilizes native dashed lines if the browser supports ctx.setLineDash and ctx.lineDashOffset.
Example: http://jsfiddle.net/mLY8Q/6/
var CP = window.CanvasRenderingContext2D && CanvasRenderingContext2D.prototype;
if (CP.lineTo) {
CP.dashedLine = CP.dashedLine || function (x, y, x2, y2, da, offset) {
if (!da) da = [10, 5];
if (!offset) offset = 0;
if (CP.setLineDash && typeof (CP.lineDashOffset) == "number") {
this.save();
this.setLineDash(da);
this.lineDashOffset = offset;
this.moveTo(x, y);
this.lineTo(x2, y2);
this.restore();
return;
}
this.save();
var dx = (x2 - x),
dy = (y2 - y);
var len = Math.sqrt(dx * dx + dy * dy);
var rot = Math.atan2(dy, dx);
this.translate(x, y);
this.moveTo(0, 0);
this.rotate(rot);
var dc = da.length;
var di = 0;
var patternLength = 0;
for (var i = 0; i < dc; i++) {
patternLength += da[i];
}
if (dc % 2 == 1) {
patternLength *= 2;
}
offset = offset % patternLength;
if (offset < 0) {
offset += patternLength;
}
var startPos = 0;
var startSegment = 0;
while (offset >= startPos) {
if (offset >= startPos + da[startSegment % dc]) {
startPos += da[startSegment % dc];
startSegment++;
} else {
offset = Math.abs(offset - startPos);
break;
}
if (startSegment > 100) break;
}
draw = startSegment % 2 === 0;
x = 0;
di = startSegment;
while (len > x) {
var interval = da[di++ % dc];
if (x < offset) {
interval = Math.max(interval - offset, 1);
offset = 0;
}
x += interval;
if (x > len) x = len;
draw ? this.lineTo(x, 0) : this.moveTo(x, 0);
draw = !draw;
}
this.restore();
};
}
I found properties mozDash and mozDashOffset in Mozilla specification:
http://mxr.mozilla.org/mozilla-central/source/dom/interfaces/canvas/nsIDOMCanvasRenderingContext2D.idl
They're probaly used to control dashes, but i haven't used them.