I'm making a little mini game and I have to put multiple switches inside of themselves, so I really need to know how to put a switch into a few words so I can make this game. I have tried it so that it's fully written out but it takes FOREVER and it is very confusing as to what is what. please help!
EDIT: im sorry i made this so confusing... let me say that again in english (: what i need to do is make it so when they either choose one of the cases or if they choose none of them (default) it would reactivate the switch. the way the person would choose is through a prompt. so what i thought i could do was make a switch into a variable then use that variable inside the switch basicly creating an endless thing that if they choose default it asks them again. here is an example i will post it in one minute
here you go!:
//this is the variable holding the switch
/*I I I I I*/
/*V V V V V*/
var switch1 = {
var choice = prompt("do you choose EXAMPLE or EXAMPLE").toUpperCase()
switch(choice) {
case 'EXAMPLE':
//this will repeat the whole prompt
switch1
break;
default:
//this will repeat it too
switch1
break; }
}
So how would i do this and make java accept this #ajaysinghdav10d?
JavaScript allows you to nest switch statements.
Have a look at this dummy example in which a service returns the location of the customer and his choice of product. Based on the combination of Choice and Location, a function to return the co-ordinates of the nearest store is called; I have used dummy values where ever necessary and alerts to explain the flow of control within the nested switch statements:
var choice = "CHO2"; /* call getChoice() function returning values from {CHO1, CHO2, ...}*/
var location = "LOC1"; /*call getLocality() function returning values from {LOC1, LOC2, ...}*/
switch (location) {
case "LOC1":
switch (choice) {
case "CHO1":
/* redirectToCHO1ofLOC1() is a function returning co-ordinates of the store*/
alert("redirectToCHO1ofLOC1");
break;
case "CHO2":
alert("redirectToCHO2ofLOC1");
break;
default:
alert("redirectToRegret");
break;
}
break;
case "LOC2":
switch (choice) {
case "CHO1":
/* redirectToCHO1ofLOC2() is a function returning co-ordinates of the store*/
alert("redirectToCHO1ofLOC2");
break;
case "CHO2":
alert("redirectToCHO1ofLOC2");
redirectToCHO2ofLOC2();
break;
default:
alert("redirectToRegret");
break;
}
break;
default:
alert("redirectToRegret");
break;
}
Updated answer based on the new context :
You must use recursion for that matter. Put your switch inside a function and call that function from the case statement of your switch, please have a look at this:
function recursiveSwitch() {
var choice = prompt("do you choose EXAMPLE or EXAMPLE").toUpperCase()
switch (choice) {
case 'EXAMPLE':
//this will repeat the whole prompt
recursiveSwitch();
break;
default:
//this will repeat it too
recursiveSwitch();
break;
}
}
Now just call the recursiveSwitch function from where ever you want and an endless loop would start.
I'm trying to develop a simplified poker game through Javascript. I've listed all possible card combinations a given player might have in its hand ordered by its value, like this:
switch(sortedHand)
{
//Pair
case [1,1,4,3,2]: sortedHand.push(1,"Pair"); break;
case [1,1,5,3,2]: sortedHand.push(2,"Pair"); break;
case [1,1,5,4,2]: sortedHand.push(3,"Pair"); break;
case [1,1,5,4,3]: sortedHand.push(4,"Pair"); break;
case [1,1,6,3,2]: sortedHand.push(5,"Pair"); break;
case [1,1,6,4,2]: sortedHand.push(6,"Pair"); break;
case [1,1,6,4,3]: sortedHand.push(7,"Pair"); break;
case [1,1,6,5,2]: sortedHand.push(8,"Pair"); break;
case [1,1,6,5,3]: sortedHand.push(9,"Pair"); break;
case [1,1,6,5,4]: sortedHand.push(10,"Pair"); break;
Even though the "sortedHand" array stores values succesfully (as I've seen through console.log), the switch() statement always returns the default case, and everyone gets an straight flush. I fear this is a matter of the literal approach I've used to declare possible array values to be compared with the whole of "sortedHand", but I don't know any better. Is it even possible to use switch() in such a manner?
You can try switching on a textual representation of the array.
switch(sortedHand.join(' '))
{
//Pair
case '1 1 4 3 2': sortedHand.push(1,"Pair"); break;
case '1 1 5 3 2': sortedHand.push(2,"Pair"); break;
case '1 1 5 4 2': sortedHand.push(3,"Pair"); break;
case '1 1 5 4 3': sortedHand.push(4,"Pair"); break;
// etc.
}
As an alternative to specifying every case directly, perhaps build a function dispatch table using an object and get rid of the switch entirely.
var dispatch = {};
// Build the table however you'd like, for your application
for (var i = 0; i < 10; i++) {
(function(i) {
var hand = ...; // Add your hand logic here
dispatch[hand] = function() { sortedHand.push(i, "Pair"); };
})(i);
}
// Execute your routine
dispatch[sortedHand.join(' ')]();
the switch() statement always returns the default case
That's because the comparison doesn't check the array contents, but the array object itself. Objects are considered equal by their identity, so nothing will be equal to an object instantiated by a literal.
Is it even possible to use switch() in such a manner?
Yes, one can use objects in switch statements, but you would have to use references in the cases. Not applicable to your problem.
In your case, I'd suggest a stringification:
switch(sortedHand.join())
{
//Pair
case "1,1,4,3,2": sortedHand.push(1,"Pair"); break;
case "1,1,5,3,2": sortedHand.push(2,"Pair"); break;
case "1,1,5,4,2": sortedHand.push(3,"Pair"); break;
case "1,1,5,4,3": sortedHand.push(4,"Pair"); break;
case "1,1,6,3,2": sortedHand.push(5,"Pair"); break;
case "1,1,6,4,2": sortedHand.push(6,"Pair"); break;
case "1,1,6,4,3": sortedHand.push(7,"Pair"); break;
case "1,1,6,5,2": sortedHand.push(8,"Pair"); break;
case "1,1,6,5,3": sortedHand.push(9,"Pair"); break;
case "1,1,6,5,4": sortedHand.push(10,"Pair"); break;
but I guess there's an even better, arithmetic solution to detect the patterns you're after. That would be shorter and faster, but I'm not sure what exactly this snippet is supposed to do.
a faster, potentially reusable, and more flexible way of doing it is to use an object instead of case:
var ok= {
'1 1 4 3 2':1,
'1 1 5 3 2':2,
'1 1 5 4 2':3,
'1 1 5 4 3':4
}[ sortedHand.join(' ') ] ;
if(ok){ sortedHand.push( ok ,"Pair"); }
objects work great when one output is hinged on one input. if you need to do five things in each case, then you have to use case, but if you just need X to turn into Y, (a 1:1), Look Up Tables in the shape of Objects are ideal.
i imagine a RegExp can work here, i used them on a connect4 game to identify 4 in a row, but the above logic table should work as well or better than what you describe.
That will not quite work as you have it, but you can use sortedHand.join(',') and compare it with [1,1,1,2,5].join(',') which will compare the two arrays and should be true if their contents were the exact same (Be careful with numbers typed as strings!)
To be fair, though, I can't imagine why you would design your logic like that. Even a simple card game has hundreds of thousands of possible hands. You might do better using underscore.js's collection managing functions as it will be simpler, and just a better practice.
There are 1274 possible combinations of 5 cards in a regular deck. Listing them all out in a switch statement is completely ridiculous. Why not just have a function count any duplicates to check for 2,3,4-of-a-kinds and then check for straights? (Your array doesn't show suit so I'm assuming you are leaving it out).
But if you really want to do it that way, you could use a string. Strings work with switches, and you can even use them like arrays. e.g. "123"[0] == '1'. You can change them back and forth user functions like parseInt.
Since no one suggested this, use a for loop and count the number of cards with exactly the given value. Having such a function you can call 'cardCount = count(sortedHand, cardNumber)'. And of cause looping through all possible card-numbers will give you the hands.
Since a given player can only have 1x2, 2x2, 1x3, 1x3+1x2, 1x4 or straights/streets, you can return an array of all hits being arrays/objects stating the count and the cardNumber involved. So [{2, 5}, {3, 6}] for a full house.
I want to use switch condition in JavaScript code. but i dont know how? please help me to do this.. thanks in advance
switch(n)
{
case 1:
execute code block 1
break;
case 2:
execute code block 2
break;
default:
code to be executed if n is different from case 1 and 2
}
http://www.w3schools.com/js/js_switch.asp
You don't have a lot of detail in your question but I'll try to help regardless - but without knowing the full scenario its a bit hard to give you a definitive answer.
I'm going to assume you want to handle a redirection on a button click, but with some conditions?
Usually you would use a simple case statement to handle this (or an if/else if there is only two conditions), such as the following (using jQuery for event bindings):
<button id="button1">Button 1</button>
<button id="button2">Button 2</button>
<script type="text/javascript">
jQuery(function() {
jQuery("button1, button2").click(function(e) {
switch(jQuery(this).attr("id")) {
case "button1":
location.href = "http://clickedonbutton1.com";
break;
case "button2":
location.href = "http://clickedonbutton2.com";
break;
default:
alert("Dont know what happened here....");
}
});
});
</script>
Read switch
No restriction on case value type.
You can use "string" case value in JavaScript
You can add duplicate case value. The first matching case value is recognized, regardless of duplicates.
switch(youVariable)
{
case "test1":
break;
case "test2":
break;
default:
break;
}