I Am trying to send value from ajax to php and retrieve it just to test that everything is work, when i click in a button to test i got error and alert('Failed') Appears , how can i fix it in order to get success? thanks
Ajax :
var a = "test";
$.ajax({
url: "search.php",
dataType: "json",
data: a ,
success: function(data) {
alert('Successfully');
},
error: function(data) {
alert('Failed');
}
})
PHP :
<?php
$pictures = "img1";
echo json_encode($pictures);
?>
I refined your code slightly and it works.
var a = "test";
$.ajax({
type: 'POST',
url: 'search.php',
data: 'a=' + a,
dataType: 'json',
cache: false,
success: function (result) {
alert('Successful');
},
error: function (result) {
alert('Failed');
}
});
If you're requesting a JSON, use the $.getJSON from jQuery, it's aready parse the JSON into a JSON object for you.
Seems that you're not return an actual JSON from server, maybe this is what is causing the error.
If you're seeing the 'Failed' message probably the problem is a 500 error which is a server error.
Try this code above.
Javascript:
var a = "test";
$.getJSON("search.php", {
a: a
}, function (json) {
console.log(json);
});
PHP:
<?php
$pictures = ["img1"];
echo json_encode($pictures);
The only way to this not work, is if you have a huge mistake on you webserver configuration.
Your ajax is wrong, it should be:
var a = "test";
$.ajax({
type: "POST",
url: "search.php",
dataType: "json",
data: {a:a},
success: function(data) {
alert('Successfully');
},
error: function(data) {
alert('Failed');
}
});
Related
I'm stuck here when passing or sending multiple parameters on Ajax. It only works when I pass one. Here the Ajax code:
$.ajax({
type: "POST",
url: "dataCartas.php",
data: {valorXY: valorXY,
CentroX: CentroX},
success: function(msg){
// return value stored in msg variable
console.log(valorXY + CentroX)
}
});
And the PHP code:
$valorXY = $_POST['valorXY'];
$CentroX = $_POST['CentroX'];
include "configX.php";
if ($conn){
$sql="EXEC sp_InsertaComID #ComID = '".$valorXY."', #DR =
'".$CentroX."'";
if ($rs=sqlsrv_query($conn,$sql)){
}else{
echo (print_r(sqlsrv_errors(), true));
}
}else{
die(print_r(sqlsrv_errors(), true));
}
Sorry for my bad english :(
You can serialize a form
$.ajax({
type: 'post',
url: 'include/ajax.php',
data: $('#form').serialize(),
success: function (response) {
// do something
},
error: function(jqxhr,textStatus,errorThrown){
console.log(jqxhr);
console.log(textStatus);
console.log(errorThrown);
}
});
you can also use form data https://stackoverflow.com/a/8244082/3063429
I'm trying to make a PHP connection, but I keep getting this error. I am hoping someone can help.
My code gives the following error:
{
"readyState": 0,
"status": 0,
"statusText": "NetworkError: Failed to execute 'send' on 'XMLHttpRequest': Failed to load 'http://localhost/php/busca.php'."
}
My code is:
SendSQL.onclick = function() {
var dataString='a=hello&b=world';
$.ajax({
type: "POST",
url:"http://localhost/php/busca.php",
data: dataString,
async: false,
dataType:'html',
success: function(data){
alert(data);
},
error: function(data){
alert(JSON.stringify(data)); //Better diagnostics
}
});
};
And the file busca.php is:
<?php
$a = $_POST['a'];
$b = $_POST['b'];
echo "$a, $b";
?>
Try this approach...
SendSQL.onclick = function() {
var dataString='a=hello&b=world';
$.ajax({
type: "POST",
url:"http://localhost/php/busca.php",
data: {
"a":"hello",
"b":"world"
},
async: false,
dataType:'text',
success: function(data){
alert(data);
},
error: function(data){
console.log(data);
}
});
};
Your dataString is the way for sending parameter of GET request.
Let's change to JSON like
var dataString = { "a":"hello", "b":"world" };
$.ajax({
type: "POST",
url:"http://localhost/php/busca.php",
data: {data: JSON.stringify(dataString)},
async: false,
dataType:'json',
success: function(data){
alert(data);
},
error: function(data){
alert(JSON.stringify(data)); //Better diagnostics
}
});
And in php code, use json_decode($_POST['data'])
I have the following Jquery code that sends a ajax request to add-to-cart.php.
var productData = {
"product_id": s_product_id,
"product_opties": s_product_opties,
"product_aantal": s_product_aantal
}
productData = JSON.stringify(productData);
$.ajax({
url: 'inc/add-to-cart.php',
dataType: "json",
contentType: "application/json; charset=utf-8",
data: productData,
type: 'POST',
success: function(response) {
alert(response.d);
},
error: function(e){
console.log(e);
}
});
Add-to-cart.php:
<?php
print $_POST['product_id'];
?>
I am having two problems, the first one is that the $_POST['product_id'] does not exists when i ask for it and secondly when the ajax response returns it goes directly to the error: function and not succes function
The console log says:
[object Object]{readyState: 4, responseText: "<br /> <b>N...", status: 200, statusText: "OK"}
If the status is OK why does it jump to the error: part?
Thanks!
Try with:
...
var productData = {
'product_id': s_product_id,
'product_opties': product_opties,
'product_aantal': product_aantal,
}
$.ajax({
url: 'inc/add-to-cart.php',
dataType: 'json',
data: productData,
type: 'POST',
success: function(response) {
console.log(response.d);
},
error: function(e){
console.log(e);
}
});
...
Omitting the AJAX contentType parameter and the part where you stringify your JSON, that's already ready to be sent to your url, so, isn't needed.
Remove the line
productData = JSON.stringify(productData);
Then do not return HTML <br> ... from add_to_cart.php, you need to return a JSON string created by the PHP function json_encode and NOTHING ELSE.
Like in:
<?php echo json_encode(array('d' => 'value of d'));
First: status Code from the Webserver is 200 cause he deliverd an existing site.
Second: You dont need to stringify the json object by urself
I use $.ajax to send some data to testajax.phpenter code here where data are processing. Result of this proces is link. How to get access to this? I think about sessions or cookies. Set in session $test and get access in another files.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: console.log('success');
data: { json : jsonObj }
});
In testajax.php I have someting like this
echo "PDF: <a href=images/test.pdf>$dir.pdf</a>";
$test = "PDF: <a href=images/test.pdf>$dir.pdf</a>";
How to get the $test or output the echo after call $.ajax
You can use success' function to get request from PHP.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'html',
data: { json : jsonObj }
success: function(data) {
var request = data;
console.log(data);
$('#link_container').html(data);
}
});
Your console now holds PDF: <a href=images/test.pdf>($dir content).pdf</a>.
Also the variable request holds the same result that you can use anywhere in the script.
Result is appended to #link_container.
Use the success() method for display the result.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: function (data){ // <= define handler for manupulate the response
$('#result').html(data);
}
data: { json : jsonObj }
});
Use below code It may help you.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
data: { json : jsonObj },
onSuccess: successFunc,
onFailure: failureFunc
});
function successFunc(response){
alert(response);
}
function failureFunc(response){
alert("Call is failed" );
alert(response);
}
That is my function, for exp.:
adId = 1, adTitle = test
function deleteAd(adId, adTitle) {
$.ajax({
dataType: 'json',
url: 'ajax.php',
type: 'POST',
data: {
adId : adId,
adTitle: adTitle
},
success: function(data) {
alert(data);
}
});
That is ajax.php:
echo $_POST['adId']; echo $_POST['adTitle'];
But echo only adId, don't have adTitle.
I try this:
data: {
adId : adId,
adTitle: "test"
},
And don't have result too. With HttpFox I found this post and postdata is: adId=1&&adTitle=test
If your variable test === undefined then it will not get posted to your PHP script therefore you will not see it on the server side.
If test is an empty string than you just might not be seeing it on the client due to it not having any visible length.
Try doing: var_dump($_POST['adTitle']);