how to merge two array objects in javascript - javascript

Just wondering what is my best approach to merge these two arrays together.
example
var a = [{"ID":11021,"ASSET_NAME":"panda","SERVICE_NAME":"Open Ticket"}]
var b = [{"ID":11021,"ASSET_NAME":"panda","SERVICE_NAME":"open requests"}]
Looking to merge them into:
var c = ["ID":11021, ASSET_NAME:"panda", service_name: ['open requests','open tickets']]
any help would be great.
Thanks

You can use one object to store ID's and reduce() to create new array of merged objects.
var a = [{"ID":11021,"ASSET_NAME":"panda","SERVICE_NAME":"Open Ticket"}]
var b = [{"ID":11021,"ASSET_NAME":"panda","SERVICE_NAME":"open requests"}]
var obj = {}
var result = a.concat(b).reduce(function(r, e) {
if (!obj[e.ID]) {
obj[e.ID] = {
ID: e.ID,
ASSET_NAME: e.ASSET_NAME,
service_name: []
}
r.push(obj[e.ID])
}
obj[e.ID].service_name.push(e.SERVICE_NAME)
return r
}, [])
console.log(JSON.stringify(result, 0, 4))

You can utilize the map method of arrays, like so:
var a = [{'eprid':112}, {'asset_name':'panda'}, {'service_name': 'open tickets'}];
var b = [{'eprid':112}, {'asset_name':'panda'}, {'service_name': 'open requests'}];
var c = a.map((obj, i) => {
for (key in obj) {
if(obj[key] !== b[i][key]) {
obj[key] = [obj[key], b[i][key]]
}
return obj;
}
})
console.log(c) // [{'eprid':112}, {'asset_name':'panda'}, {'service_name': ['open ticket', 'open requests']}]

Related

Convert array of structured string into multi-level object in Javascript [duplicate]

This question already has answers here:
Create an object based on file path string
(3 answers)
Closed 1 year ago.
I have an array of structured strings with have connection | as a format which self-divided into levels. I want to convert it into a structured object with multiple levels.
Input:
[
"clothes|tshirt|tshirt-for-kids",
"clothes|coat|raincoat",
"clothes|coat|leather-coat",
"clothes|tshirt|tshirt-for-men",
"clothes|tshirt|tshirt-for-men|luxury-tshirt",
]
Expected output:
{
clothes: {
tshirt: {
tshirt-for-kids: {},
tshirt-for-men: {
luxury-tshirt: {}
}
},
coat: {
raincoat: {}
leather-coat: {}
}
}
}
Very simple task - just enumerate the array and create the relevant object keys:
var myArray = [
"clothes|tshirt|tshirt-for-kids",
"clothes|coat|raincoat",
"clothes|coat|leather-coat",
"clothes|tshirt|tshirt-for-men",
"clothes|tshirt|tshirt-for-men|luxury-tshirt",
]
var result = {}, levels, current, temp;
while(myArray.length > 0)
{
levels = myArray.pop().split('|');
temp = result;
while(levels.length > 0)
{
current = levels.shift();
if(!(current in temp)) temp[current] = {};
temp = temp[current];
}
}
console.log(result);
You could try this:
const input = [
"clothes|tshirt|tshirt-for-kids",
"clothes|coat|raincoat",
"clothes|coat|leather-coat",
"clothes|tshirt|tshirt-for-men",
"clothes|tshirt|tshirt-for-men|luxury-tshirt",
];
function convertStrToObject(str, sep, obj) {
const sepIndex = str.indexOf(sep);
if (sepIndex == -1) {
obj[str] = obj[str] || {};
} else {
const key = str.substring(0, sepIndex);
obj[key] = obj[key] || {};
convertStrToObject(str.substring(sepIndex + 1), sep, obj[key]);
}
}
const all = {};
for (let i = 0; i < input.length; ++i) {
convertStrToObject(input[i], "|", all);
}
console.log(all);
Assuming you intend to collect properties, all having an empty object as leaf node.
// input
const input = [
"clothes|tshirt|tshirt-for-kids",
"clothes|coat|raincoat",
"clothes|coat|leather-coat",
"clothes|tshirt|tshirt-for-men",
"clothes|tshirt|tshirt-for-men|luxury-tshirt",
];
// Here, we collect the properties
const out = {};
// map the input array, splitting each line at |
input.map(i => i.split('|'))
.filter(a => a.length > 0) // lets not entertain empty lines in input
.forEach(a => { // process each array of property names
// start at outermost level
let p = out;
// iterate properties
for(const v of a){
// create a property if it is not already there
if(!p.hasOwnProperty(v)){
p[v] = {};
}
// move to the nested level
p = p[v];
}
});
// lets see what we have created
console.log(out);
A number of solutions have been suggested already, but I'm surprised none involves reduce() - which would seem the more idiomatic solution to me.
var array = [
"clothes|tshirt|tshirt-for-kids",
"clothes|coat|raincoat",
"clothes|coat|leather-coat",
"clothes|tshirt|tshirt-for-men",
"clothes|tshirt|tshirt-for-men|luxury-tshirt",
]
var object = array.reduce(function (object, element) {
var keys = element.split("|")
keys.reduce(function (nextNestedObject, key) {
if (!nextNestedObject[key]) nextNestedObject[key] = {}
return nextNestedObject[key]
}, object)
return object
}, {})
console.log(object)
One Liner With eval
Used eval to evaluate strings like the following:
'o["clothes"]??={}'
'o["clothes"]["tshirt"]??={}'
'o["clothes"]["tshirt"]["tshirt-for-kids"]??={}'
const
data = ["clothes|tshirt|tshirt-for-kids", "clothes|coat|raincoat", "clothes|coat|leather-coat", "clothes|tshirt|tshirt-for-men", "clothes|tshirt|tshirt-for-men|luxury-tshirt"],
arr = data.map((d) => d.split("|")),
res = arr.reduce((r, a) => (a.forEach((k, i) => eval(`r["${a.slice(0, i + 1).join('"]["')}"]??={}`)), r), {});
console.log(res)
One Liner Without eval
const
data = ["clothes|tshirt|tshirt-for-kids", "clothes|coat|raincoat", "clothes|coat|leather-coat","clothes|tshirt|tshirt-for-men", "clothes|tshirt|tshirt-for-men|luxury-tshirt"],
res = data.reduce((r, d) => (d.split("|").reduce((o, k) => (o[k] ??= {}, o[k]), r), r), {});
console.log(res)

Create new array with Average of same keys in an array of objects

I have an array of object as follows:
var arr=[ {"jan":2},{"jan":5},{"feb":3},{"feb":1}];
Their will be N number of objects with any combination keys jan & feb is just an example.
I need to find average of objects with similar keys so that resultant array looks like this :
var newArr=[{"jan":3.5},{"feb":2}];
Looking to achieve this without reduce method in JavaScript.
I tried to seperate out objects with similar keys so that ic an sum and average them and push in to a new aray. something like this :
arr.forEach(a=>{
console.log(Object.keys(a))
console.log(arr.filter(ar=>ar.hasOwnProperty(Object.keys(a)[0])))
})
But it creates multiple groups for same keys like this in console.
[ {"jan":2},{"jan":5} ]
[ {"jan":2},{"jan":5} ]
[ {"feb":3},{"feb":1} ]
[ {"feb":3},{"feb":1} ]
A code without using reduce . A bit length though but easy to understand
We are using two objects , one is to store the count of the keys and other is for storing the total of the keys.
result object has the average.
var arr=[ {"jan":2},{"jan":5},{"feb":3},{"feb":1}];
var count = {};
var total = {};
arr.forEach(obj => {
var key = Object.keys(obj)[0];
if(count.hasOwnProperty(key)){
count[key]=count[key]+1;
} else {
count[key]=1;
}
if(total.hasOwnProperty(key)){
total[key]=total[key]+obj[key];
} else {
total[key]=obj[key];
}
})
var result = {}
Object.keys(total).forEach(key => {
result[key] = total[key]/count[key];
})
console.log(result)
Similar to the answer above, but makes use of a map:
var arr=[ {"jan":2},{"jan":5},{"feb":3},{"feb":1}];
let map = new Map();
let keyCount = {};
arr.forEach(e => {
let key = Object.keys(e)[0];
let value = Object.values(e)[0];
if (map.get(key) !== undefined) {
map.set(key, map.get(key) + value);
keyCount[key] = keyCount[key] + 1;
} else {
map.set(key, value);
keyCount[key] = 1;
}
});
let newArr = [];
for (let e of map.entries()) {
let obj = {};
obj[e[0]] = e[1] / keyCount[e[0]];
newArr.push(obj);
}
console.log(newArr);

How do I merge two dictionaries in Javascript? [duplicate]

This question already has answers here:
How can I merge properties of two JavaScript objects dynamically?
(69 answers)
Closed 1 year ago.
var a = {};
a['fruit'] = "apple";
var b = {};
b['vegetable'] = "carrot";
var food = {};
The output variable 'food' must include both key-value pairs.
You could use Object.assign.
var a = { fruit: "apple" },
b = { vegetable: "carrot" },
food = Object.assign({}, a, b);
console.log(food);
For browser without supporting Object.assign, you could iterate the properties and assign the values manually.
var a = { fruit: "apple" },
b = { vegetable: "carrot" },
food = [a, b].reduce(function (r, o) {
Object.keys(o).forEach(function (k) { r[k] = o[k]; });
return r;
}, {});
console.log(food);
Ways to achieve :
1. Using JavaScript Object.assign() method.
var a = {};
a['fruit'] = "apple";
var b = {};
b['vegetable'] = "carrot";
var food = Object.assign({}, a, b);
console.log(food);
2. Using custom function.
var a = {};
a['fruit'] = "apple";
var b = {};
b['vegetable'] = "carrot";
function createObj(obj1, obj2){
var food = {};
for (var i in obj1) {
food[i] = obj1[i];
}
for (var j in obj2) {
food[j] = obj2[j];
}
return food;
};
var res = createObj(a, b);
console.log(res);
3. Using ES6 Spread operator.
let a = {};
a['fruit'] = "apple";
let b = {};
b['vegetable'] = "carrot";
let food = {...a,...b}
console.log(food)
You could use the spread operator in es6, but you would need to use babel to transpile the code to be cross browser friendly.
const a = {};
a['fruit'] = "apple";
const b = {};
b['vegetable'] = "carrot";
const food = { ...a, ...b }
console.log(food)
Create a Utility function which can extend Objects, like:
function extendObj(obj1, obj2){
for (var key in obj2){
if(obj2.hasOwnProperty(key)){
obj1[key] = obj2[key];
}
}
return obj1;
}
And then extend this food object with the another Objects. Here is example:
food = extendObj(food, a);
food = extendObj(food, b);

convert serialized form to individual post items [duplicate]

This question already has answers here:
How can I get query string values in JavaScript?
(73 answers)
Closed 1 year ago.
I have a string like this:
abc=foo&def=%5Basf%5D&xyz=5
How can I convert it into a JavaScript object like this?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
In the year 2021... Please consider this obsolete.
Edit
This edit improves and explains the answer based on the comments.
var search = location.search.substring(1);
JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
Example
Parse abc=foo&def=%5Basf%5D&xyz=5 in five steps:
decodeURI: abc=foo&def=[asf]&xyz=5
Escape quotes: same, as there are no quotes
Replace &: abc=foo","def=[asf]","xyz=5
Replace =: abc":"foo","def":"[asf]","xyz":"5
Suround with curlies and quotes: {"abc":"foo","def":"[asf]","xyz":"5"}
which is legal JSON.
An improved solution allows for more characters in the search string. It uses a reviver function for URI decoding:
var search = location.search.substring(1);
JSON.parse('{"' + search.replace(/&/g, '","').replace(/=/g,'":"') + '"}', function(key, value) { return key===""?value:decodeURIComponent(value) })
Example
search = "abc=foo&def=%5Basf%5D&xyz=5&foo=b%3Dar";
gives
Object {abc: "foo", def: "[asf]", xyz: "5", foo: "b=ar"}
Original answer
A one-liner:
JSON.parse('{"' + decodeURI("abc=foo&def=%5Basf%5D&xyz=5".replace(/&/g, "\",\"").replace(/=/g,"\":\"")) + '"}')
2022 ES6/7/8 and on approach
Starting ES6 and on, Javascript offers several constructs in order to create a performant solution for this issue.
This includes using URLSearchParams and iterators
let params = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
params.get("abc"); // "foo"
Should your use case requires you to actually convert it to object, you can implement the following function:
function paramsToObject(entries) {
const result = {}
for(const [key, value] of entries) { // each 'entry' is a [key, value] tupple
result[key] = value;
}
return result;
}
Basic Demo
const urlParams = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
const entries = urlParams.entries(); //returns an iterator of decoded [key,value] tuples
const params = paramsToObject(entries); //{abc:"foo",def:"[asf]",xyz:"5"}
Using Object.fromEntries and spread
We can use Object.fromEntries, replacing paramsToObject with Object.fromEntries(entries).
The value pairs to iterate over are the list name-value pairs with the
key being the name and the value being the value.
Since URLParams, returns an iterable object, using the spread operator instead of calling .entries will also yield entries per its spec:
const urlParams = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5');
const params = Object.fromEntries(urlParams); // {abc: "foo", def: "[asf]", xyz: "5"}
Note: All values are automatically strings as per the URLSearchParams spec
Multiple same keys
As #siipe pointed out, strings containing multiple same-key values will be coerced into the last available value: foo=first_value&foo=second_value will in essence become: {foo: "second_value"}.
As per this answer: https://stackoverflow.com/a/1746566/1194694 there's no spec for deciding what to do with it and each framework can behave differently.
A common use case will be to join the two same values into an array, making the output object into:
{foo: ["first_value", "second_value"]}
This can be achieved with the following code:
const groupParamsByKey = (params) => [...params.entries()].reduce((acc, tuple) => {
// getting the key and value from each tuple
const [key, val] = tuple;
if(acc.hasOwnProperty(key)) {
// if the current key is already an array, we'll add the value to it
if(Array.isArray(acc[key])) {
acc[key] = [...acc[key], val]
} else {
// if it's not an array, but contains a value, we'll convert it into an array
// and add the current value to it
acc[key] = [acc[key], val];
}
} else {
// plain assignment if no special case is present
acc[key] = val;
}
return acc;
}, {});
const params = new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5&def=dude');
const output = groupParamsByKey(params) // {abc: "foo", def: ["[asf]", "dude"], xyz: 5}
One liner. Clean and simple.
const params = Object.fromEntries(new URLSearchParams(location.search));
For your specific case, it would be:
const str = 'abc=foo&def=%5Basf%5D&xyz=5';
const params = Object.fromEntries(new URLSearchParams(str));
console.log(params);
2023 One-Liner Approach
For the general case where you want to parse query params to an object:
Object.fromEntries(new URLSearchParams(location.search));
For your specific case:
Object.fromEntries(new URLSearchParams('abc=foo&def=%5Basf%5D&xyz=5'));
Split on & to get name/value pairs, then split each pair on =. Here's an example:
var str = "abc=foo&def=%5Basf%5D&xy%5Bz=5"
var obj = str.split("&").reduce(function(prev, curr, i, arr) {
var p = curr.split("=");
prev[decodeURIComponent(p[0])] = decodeURIComponent(p[1]);
return prev;
}, {});
Another approach, using regular expressions:
var obj = {};
str.replace(/([^=&]+)=([^&]*)/g, function(m, key, value) {
obj[decodeURIComponent(key)] = decodeURIComponent(value);
});
This is adapted from John Resig's "Search and Don’t Replace".
The proposed solutions I found so far do not cover more complex scenarios.
I needed to convert a query string like
https://random.url.com?Target=Offer&Method=findAll&filters%5Bhas_goals_enabled%5D%5BTRUE%5D=1&filters%5Bstatus%5D=active&fields%5B%5D=id&fields%5B%5D=name&fields%5B%5D=default_goal_name
into an object like:
{
"Target": "Offer",
"Method": "findAll",
"fields": [
"id",
"name",
"default_goal_name"
],
"filters": {
"has_goals_enabled": {
"TRUE": "1"
},
"status": "active"
}
}
OR:
https://random.url.com?Target=Report&Method=getStats&fields%5B%5D=Offer.name&fields%5B%5D=Advertiser.company&fields%5B%5D=Stat.clicks&fields%5B%5D=Stat.conversions&fields%5B%5D=Stat.cpa&fields%5B%5D=Stat.payout&fields%5B%5D=Stat.date&fields%5B%5D=Stat.offer_id&fields%5B%5D=Affiliate.company&groups%5B%5D=Stat.offer_id&groups%5B%5D=Stat.date&filters%5BStat.affiliate_id%5D%5Bconditional%5D=EQUAL_TO&filters%5BStat.affiliate_id%5D%5Bvalues%5D=1831&limit=9999
INTO:
{
"Target": "Report",
"Method": "getStats",
"fields": [
"Offer.name",
"Advertiser.company",
"Stat.clicks",
"Stat.conversions",
"Stat.cpa",
"Stat.payout",
"Stat.date",
"Stat.offer_id",
"Affiliate.company"
],
"groups": [
"Stat.offer_id",
"Stat.date"
],
"limit": "9999",
"filters": {
"Stat.affiliate_id": {
"conditional": "EQUAL_TO",
"values": "1831"
}
}
}
I compiled and adapted multiple solutions into one that actually works:
CODE:
var getParamsAsObject = function (query) {
query = query.substring(query.indexOf('?') + 1);
var re = /([^&=]+)=?([^&]*)/g;
var decodeRE = /\+/g;
var decode = function (str) {
return decodeURIComponent(str.replace(decodeRE, " "));
};
var params = {}, e;
while (e = re.exec(query)) {
var k = decode(e[1]), v = decode(e[2]);
if (k.substring(k.length - 2) === '[]') {
k = k.substring(0, k.length - 2);
(params[k] || (params[k] = [])).push(v);
}
else params[k] = v;
}
var assign = function (obj, keyPath, value) {
var lastKeyIndex = keyPath.length - 1;
for (var i = 0; i < lastKeyIndex; ++i) {
var key = keyPath[i];
if (!(key in obj))
obj[key] = {}
obj = obj[key];
}
obj[keyPath[lastKeyIndex]] = value;
}
for (var prop in params) {
var structure = prop.split('[');
if (structure.length > 1) {
var levels = [];
structure.forEach(function (item, i) {
var key = item.replace(/[?[\]\\ ]/g, '');
levels.push(key);
});
assign(params, levels, params[prop]);
delete(params[prop]);
}
}
return params;
};
A concise solution:
location.search
.slice(1)
.split('&')
.map(p => p.split('='))
.reduce((obj, pair) => {
const [key, value] = pair.map(decodeURIComponent);
obj[key] = value;
return obj;
}, {});
This is the simple version, obviously you'll want to add some error checking:
var obj = {};
var pairs = queryString.split('&');
for(i in pairs){
var split = pairs[i].split('=');
obj[decodeURIComponent(split[0])] = decodeURIComponent(split[1]);
}
For Node JS, you can use the Node JS API querystring:
const querystring = require('querystring');
querystring.parse('abc=foo&def=%5Basf%5D&xyz=5&foo=b%3Dar');
// returns the object
Documentation: https://nodejs.org/api/querystring.html
I found $.String.deparam the most complete pre built solution (can do nested objects etc.). Check out the documentation.
Another solution based on the latest standard of URLSearchParams (https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams)
function getQueryParamsObject() {
const searchParams = new URLSearchParams(location.search.slice(1));
return searchParams
? _.fromPairs(Array.from(searchParams.entries()))
: {};
}
Please note that this solution is making use of
Array.from (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/from)
and _.fromPairs (https://lodash.com/docs#fromPairs) of lodash for the sake of simplicity.
It should be easy to create a more compatible solution since you have access to searchParams.entries() iterator.
I had the same problem, tried the solutions here, but none of them really worked, since I had arrays in the URL parameters, like this:
?param[]=5&param[]=8&othr_param=abc&param[]=string
So I ended up writing my own JS function, which makes an array out of the param in URI:
/**
* Creates an object from URL encoded data
*/
var createObjFromURI = function() {
var uri = decodeURI(location.search.substr(1));
var chunks = uri.split('&');
var params = Object();
for (var i=0; i < chunks.length ; i++) {
var chunk = chunks[i].split('=');
if(chunk[0].search("\\[\\]") !== -1) {
if( typeof params[chunk[0]] === 'undefined' ) {
params[chunk[0]] = [chunk[1]];
} else {
params[chunk[0]].push(chunk[1]);
}
} else {
params[chunk[0]] = chunk[1];
}
}
return params;
}
One of the simplest way to do this using URLSearchParam interface.
Below is the working code snippet:
let paramObj={},
querystring=window.location.search,
searchParams = new URLSearchParams(querystring);
//*** :loop to add key and values to the param object.
searchParams.forEach(function(value, key) {
paramObj[key] = value;
});
There is quite simple and incorrect answer with ES6:
console.log(
Object.fromEntries(new URLSearchParams(`abc=foo&def=%5Basf%5D&xyz=5`))
);
But this one line code do not cover multiple same keys, you have to use something more complicated:
function parseParams(params) {
const output = [];
const searchParams = new URLSearchParams(params);
// Set will return only unique keys()
new Set([...searchParams.keys()])
.forEach(key => {
output[key] = searchParams.getAll(key).length > 1 ?
searchParams.getAll(key) : // get multiple values
searchParams.get(key); // get single value
});
return output;
}
console.log(
parseParams('abc=foo&cars=Ford&cars=BMW&cars=Skoda&cars=Mercedes')
)
Code will generate follow structure:
[
abc: "foo"
cars: ["Ford", "BMW", "Skoda", "Mercedes"]
]
Using ES6, URL API and URLSearchParams API.
function objectifyQueryString(url) {
let _url = new URL(url);
let _params = new URLSearchParams(_url.search);
let query = Array.from(_params.keys()).reduce((sum, value)=>{
return Object.assign({[value]: _params.get(value)}, sum);
}, {});
return query;
}
ES6 one liner (if we can call it that way seeing the long line)
[...new URLSearchParams(location.search).entries()].reduce((prev, [key,val]) => {prev[key] = val; return prev}, {})
One simple answer with build in native Node module.(No third party npm modules)
The querystring module provides utilities for parsing and formatting URL query strings. It can be accessed using:
const querystring = require('querystring');
const body = "abc=foo&def=%5Basf%5D&xyz=5"
const parseJSON = querystring.parse(body);
console.log(parseJSON);
Pretty easy using the URLSearchParams JavaScript Web API,
var paramsString = "abc=foo&def=%5Basf%5D&xyz=5";
//returns an iterator object
var searchParams = new URLSearchParams(paramsString);
//Usage
for (let p of searchParams) {
console.log(p);
}
//Get the query strings
console.log(searchParams.toString());
//You can also pass in objects
var paramsObject = {abc:"forum",def:"%5Basf%5D",xyz:"5"}
//returns an iterator object
var searchParams = new URLSearchParams(paramsObject);
//Usage
for (let p of searchParams) {
console.log(p);
}
//Get the query strings
console.log(searchParams.toString());
##Useful Links
URLSearchParams - Web APIs | MDN
Easy URL Manipulation with URLSearchParams | Web
| Google Developers
NOTE: Not Supported in IE
There is no native solution that I'm aware of. Dojo has a built-in unserialization method if you use that framework by chance.
Otherwise you can implement it yourself rather simply:
function unserialize(str) {
str = decodeURIComponent(str);
var chunks = str.split('&'),
obj = {};
for(var c=0; c < chunks.length; c++) {
var split = chunks[c].split('=', 2);
obj[split[0]] = split[1];
}
return obj;
}
edit: added decodeURIComponent()
/**
* Parses and builds Object of URL query string.
* #param {string} query The URL query string.
* #return {!Object<string, string>}
*/
function parseQueryString(query) {
if (!query) {
return {};
}
return (/^[?#]/.test(query) ? query.slice(1) : query)
.split('&')
.reduce((params, param) => {
const item = param.split('=');
const key = decodeURIComponent(item[0] || '');
const value = decodeURIComponent(item[1] || '');
if (key) {
params[key] = value;
}
return params;
}, {});
}
console.log(parseQueryString('?v=MFa9pvnVe0w&ku=user&from=89&aw=1'))
see log
There's a lightweight library called YouAreI.js that's tested and makes this really easy.
YouAreI = require('YouAreI')
uri = new YouAreI('http://user:pass#www.example.com:3000/a/b/c?d=dad&e=1&f=12.3#fragment');
uri.query_get() => { d: 'dad', e: '1', f: '12.3' }
If you are using URI.js, you can use:
https://medialize.github.io/URI.js/docs.html#static-parseQuery
var result = URI.parseQuery("?foo=bar&hello=world&hello=mars&bam=&yup");
result === {
foo: "bar",
hello: ["world", "mars"],
bam: "",
yup: null
};
console.log(decodeURI('abc=foo&def=%5Basf%5D&xyz=5')
.split('&')
.reduce((result, current) => {
const [key, value] = current.split('=');
result[key] = value;
return result
}, {}))
This seems to be the best solution as it takes multiple parameters of the same name into consideration.
function paramsToJSON(str) {
var pairs = str.split('&');
var result = {};
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = pair[0]
var value = pair[1]
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result );
}
something
paramsToJSON("x=1&x=2&x=3&y=blah");
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
I later decided to convert it to a jQuery plugin too...
$.fn.serializeURLParams = function() {
var result = {};
if( !this.is("a") || this.attr("href").indexOf("?") == -1 )
return( result );
var pairs = this.attr("href").split("?")[1].split('&');
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = decodeURI(pair[0])
var value = decodeURI(pair[1])
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result )
}
something
$("a").serializeURLParams();
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
Now, the first will accept the parameters only but the jQuery plugin will take the whole url and return the serialized parameters.
Here's one I use:
var params = {};
window.location.search.substring(1).split('&').forEach(function(pair) {
pair = pair.split('=');
if (pair[1] !== undefined) {
var key = decodeURIComponent(pair[0]),
val = decodeURIComponent(pair[1]),
val = val ? val.replace(/\++/g,' ').trim() : '';
if (key.length === 0) {
return;
}
if (params[key] === undefined) {
params[key] = val;
}
else {
if ("function" !== typeof params[key].push) {
params[key] = [params[key]];
}
params[key].push(val);
}
}
});
console.log(params);
Basic usage, eg.
?a=aa&b=bb
Object {a: "aa", b: "bb"}
Duplicate params, eg.
?a=aa&b=bb&c=cc&c=potato
Object {a: "aa", b: "bb", c: ["cc","potato"]}
Missing keys, eg.
?a=aa&b=bb&=cc
Object {a: "aa", b: "bb"}
Missing values, eg.
?a=aa&b=bb&c
Object {a: "aa", b: "bb"}
The above JSON/regex solutions throw a syntax error on this wacky url:
?a=aa&b=bb&c=&=dd&e
Object {a: "aa", b: "bb", c: ""}
Here's my quick and dirty version, basically its splitting up the URL parameters separated by '&' into array elements, and then iterates over that array adding key/value pairs separated by '=' into an object. I'm using decodeURIComponent() to translate the encoded characters to their normal string equivalents (so %20 becomes a space, %26 becomes '&', etc):
function deparam(paramStr) {
let paramArr = paramStr.split('&');
let paramObj = {};
paramArr.forEach(e=>{
let param = e.split('=');
paramObj[param[0]] = decodeURIComponent(param[1]);
});
return paramObj;
}
example:
deparam('abc=foo&def=%5Basf%5D&xyz=5')
returns
{
abc: "foo"
def:"[asf]"
xyz :"5"
}
The only issue is that xyz is a string and not a number (due to using decodeURIComponent()), but beyond that its not a bad starting point.
//under ES6
const getUrlParamAsObject = (url = window.location.href) => {
let searchParams = url.split('?')[1];
const result = {};
//in case the queryString is empty
if (searchParams!==undefined) {
const paramParts = searchParams.split('&');
for(let part of paramParts) {
let paramValuePair = part.split('=');
//exclude the case when the param has no value
if(paramValuePair.length===2) {
result[paramValuePair[0]] = decodeURIComponent(paramValuePair[1]);
}
}
}
return result;
}
If you need recursion, you can use the tiny js-extension-ling library.
npm i js-extension-ling
const jsx = require("js-extension-ling");
console.log(jsx.queryStringToObject("a=1"));
console.log(jsx.queryStringToObject("a=1&a=3"));
console.log(jsx.queryStringToObject("a[]=1"));
console.log(jsx.queryStringToObject("a[]=1&a[]=pomme"));
console.log(jsx.queryStringToObject("a[0]=one&a[1]=five"));
console.log(jsx.queryStringToObject("http://blabla?foo=bar&number=1234"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry&a[1]=five&a[fruits][red][]=cherry&a[fruits][yellow][]=lemon&a[fruits][yellow][688]=banana"));
This will output something like this:
{ a: '1' }
{ a: '3' }
{ a: { '0': '1' } }
{ a: { '0': '1', '1': 'pomme' } }
{ a: { '0': 'one', '1': 'five' } }
{ foo: 'bar', number: '1234' }
{
a: { fruits: { red: { '0': 'strawberry' } } }
}
{
a: {
'1': 'five',
fruits: {
red: { '0': 'strawberry', '1': 'cherry' },
yellow: { '0': 'lemon', '688': 'banana' }
}
}
}
Note: it's based on locutus parse_str function (https://locutus.io/php/strings/parse_str/).
FIRST U NEED TO DEFINE WHAT'S A GET VAR:
function getVar()
{
this.length = 0;
this.keys = [];
this.push = function(key, value)
{
if(key=="") key = this.length++;
this[key] = value;
this.keys.push(key);
return this[key];
}
}
Than just read:
function urlElement()
{
var thisPrototype = window.location;
for(var prototypeI in thisPrototype) this[prototypeI] = thisPrototype[prototypeI];
this.Variables = new getVar();
if(!this.search) return this;
var variables = this.search.replace(/\?/g,'').split('&');
for(var varI=0; varI<variables.length; varI++)
{
var nameval = variables[varI].split('=');
var name = nameval[0].replace(/\]/g,'').split('[');
var pVariable = this.Variables;
for(var nameI=0;nameI<name.length;nameI++)
{
if(name.length-1==nameI) pVariable.push(name[nameI],nameval[1]);
else var pVariable = (typeof pVariable[name[nameI]] != 'object')? pVariable.push(name[nameI],new getVar()) : pVariable[name[nameI]];
}
}
}
and use like:
var mlocation = new urlElement();
mlocation = mlocation.Variables;
for(var key=0;key<mlocation.keys.length;key++)
{
console.log(key);
console.log(mlocation[mlocation.keys[key]];
}
I needed to also deal with + in the query part of the URL (decodeURIComponent doesn't), so I adapted Wolfgang's code to become:
var search = location.search.substring(1);
search = search?JSON.parse('{"' + search.replace(/\+/g, ' ').replace(/&/g, '","').replace(/=/g,'":"') + '"}',
function(key, value) { return key===""?value:decodeURIComponent(value)}):{};
In my case, I'm using jQuery to get URL-ready form parameters, then this trick to build an object out of it and I can then easily update parameters on the object and rebuild the query URL, e.g.:
var objForm = JSON.parse('{"' + $myForm.serialize().replace(/\+/g, ' ').replace(/&/g, '","').replace(/=/g,'":"') + '"}',
function(key, value) { return key===""?value:decodeURIComponent(value)});
objForm.anyParam += stringToAddToTheParam;
var serializedForm = $.param(objForm);

merging two array of objects with custom compare function with javascript

I have two array of objects like:
var A = [{title:"name1",count:5},{title:"name2",count:1},{title:"name3",count:3}];
and:
var B = [{title:"name2",count:7},{title:"name3",count:2},{title:"name4",count:3},{title:"name5",count:8}];
I need to merge this two array in one array and sum the "count" values in returned array when the "title" properties is same:
the last answer must be:
[{title:"name1",count:5},{title:"name2",count:8},{title:"name3",count:5},{title:"name4",count:3},{title:"name5",count:8}]
how can i do this???
You can use Array#forEach and Array#some to achieve a result
var M = A.concat(B)
var C = [];
M.forEach(function(a) {
var index;
if (C.some(function(c, i) { index = i; return a.title == c.title; })) {
C[index].count += a.count;
} else {
C.push(a);
}
});
console.log(C); // as you expect
Solution with Array.concat and Array.map functions:
var merged = A.concat(B), titles = [], result = [];
merged.map(function(obj){
if (titles.indexOf(obj.title) === -1) {
titles.push(obj.title);
result.push(obj);
} else {
result[titles.indexOf(obj.title)]['count'] += obj['count'];
}
});
console.log(result); // will output the expected array of objects
It can be done like this https://jsfiddle.net/menm9xeo/
var noMatch;
var A = [{title:"name1",count:5},{title:"name2",count:1},{title:"name3",count:3}];
var B = [{title:"name2",count:7},{title:"name3",count:2},{title:"name4",count:3},{title:"name5",count:8}];
//for each A, loop through B's. If a match is found combine the Counts in A.
for(var i=0;i<A.length;i++){
for(var j=0;j<B.length;j++){
if(A[i].title == B[j].title){
A[i].count += B[j].count;
}
}
}
//find all B's that were not combined with A in the previous step, and push them into A.
for(var i=0;i<B.length;i++){
noMatch = true;
for(var j=0;j<A.length;j++){
if(B[i].title == A[j].title){
B[i].count += A[j].count;
noMatch = false;
}
}
if(noMatch){A.push(B[i]);}
}
Heres a simple 3 line answer (minus the A/B vars); utilizes the fact that objects must have unique keys
var A = [{title:"name1",count:5},{title:"name2",count:1},{title:"name3",count:3}];
var B = [{title:"name2",count:7},{title:"name3",count:2},{title:"name4",count:3},{title:"name5",count:8}];
var o = {};
A.concat(B).forEach(function(a){o[a.title] = o.hasOwnProperty(a.title)? o[a.title]+a.count: a.count});
var AB = Object.keys(o).map(function(j){ return {title:j,count:o[j]} });
This proposal is merging and counting with a temporary object and Array#forEach()
The forEach() method executes a provided function once per array element.
var arrayA = [{ title: "name1", count: 5 }, { title: "name2", count: 1 }, { title: "name3", count: 3 }],
arrayB = [{ title: "name2", count: 7 }, { title: "name3", count: 2 }, { title: "name4", count: 3 }, { title: "name5", count: 8 }],
result = function (array) {
var o = {}, r = [];
array.forEach(function (a) {
if (!(a.title in o)) {
o[a.title] = { title: a.title, count: 0 };
r.push(o[a.title]);
}
o[a.title].count += a.count;
});
return r;
}(arrayA.concat(arrayB));
document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');
Using lodash ._concat function :
var result = _.concat(A, B);
Fiddle

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