I have been tring to set img at same position as another using jquery .position() and .css()
Here is the code:
function setImgsToSamePosition() {
var position = $('#img1').position();
$('#img2').css({ 'left': position.left + 'px', 'top': position.top + 'px' });
$('#img3').css({ 'left': position.left + 'px', 'top': position.top + 'px' });
}
$(document).ready(function () {
// Set imgs pos to be equal to img1 pos
setImgsToSamePosition();
})
Any thoughts?
You can overlap images this way. I set the position to fixed then set the left and top values for both other images. I'm not entirely sure why'd you want this; so, if it's not the desired result, just comment.
function setImgsToSamePosition() {
var position = $('#img1').position();
$('#img2, #img3').css({ 'left': position.left + 'px', 'top': position.top + 'px' });
}
$(document).ready(function () {
// Set imgs pos to be equal to img1 pos
setImgsToSamePosition();
})
img {
width:100px;
height:100px;
border:1px solid black;
}
#img1, #img2, #img3 {
position:fixed;
}
#img1 {
left:50px;
top:50px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img id="img1" src="http://neil.computer/stack/bg.jpg" />
<img id="img2" src="http://neil.computer/stack/bg2.jpg" />
<img id="img3" src="http://neil.computer/stack/bg3.jpg" />
For the translation of an element to work in this way
position: relative;
left: 20px;
I dont exactly know what ur upto but i just corrected your code.
$(function(){
var position = $('#img1').position();
var x = $("#img2").position();
$("#pos").text("top: "+x.top+" "+"left: "+x.left);
$('#img3').css({ 'left': x.left + 'px', 'top': x.top + 'px' });
});
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
</head>
<body>
<img src="https://www.w3schools.com/css/img_fjords.jpg" id="img1" style="height:100px;width:100px;"/>
<img src="https://www.w3schools.com/howto/img_mountains.jpg" id="img2" style="height:100px;width:100px;"/>
<p id="pos"></p>
</body>
</html>
Related
I am using lazyYT to load youtube video's faster. The loaded lazyYT videos are then placed in the slick slider. What then happens is that the video's are sticking together instead of a nice margin between every video. So I manually added a class to the video div
<div class="js-lazyYT" id="video-slide" data-youtube-id="<?php echo $video['video_link']; ?>" data-width="500" data-height="425"></div>
and gave it a margin which is working fine until the first video comes loaded back again. They paste together until all three first video's are visible again.
#video-slide{
width: 500px !important;
height: 425px !important;
margin-right: 10px;
-webkit-border-radius: 15px;
-moz-border-radius: 15px;
border-radius: 15px;
}
It looks like the first 3 entries in the slider reload the slider again when they are visible. Any idea?
;(function ($) {
'use strict';
function setUp($el) {
var width = $el.data('width'),
height = $el.data('height'),
ratio = $el.data('ratio'),
id = $el.data('youtube-id'),
aspectRatio = ['16', '9'],
paddingTop = 0,
youtubeParameters = $el.data('parameters') || '';
if (typeof width === 'undefined' || typeof height === 'undefined') {
height = 0;
width = '100%';
aspectRatio = (ratio.split(":")[1] / ratio.split(":")[0]) * 100;
paddingTop = aspectRatio + '%';
}
$el.css({
'position': 'relative',
'height': height,
'width': width,
'padding-top': paddingTop,
'background': 'url(http://img.youtube.com/vi/' + id + '/hqdefault.jpg) center center no-repeat',
'cursor': 'pointer',
'background-size': 'cover'
})
.html('<p id="lazyYT-title-' + id + '" class="lazyYT-title"></p><div class="lazyYT-button"></div>')
.addClass('lazyYT-image-loaded');
$.getJSON('https://gdata.youtube.com/feeds/api/videos/' + id + '?v=2&alt=json', function (data) {
$('#lazyYT-title-' + id).text(data.entry.title.$t);
});
$el.on('click', function (e) {
e.preventDefault();
if (!$el.hasClass('lazyYT-video-loaded') && $el.hasClass('lazyYT-image-loaded')) {
$el.html('<iframe width="' + width + '" height="' + height + '" src="//www.youtube.com/embed/' + id + '?autoplay=1&' + youtubeParameters + '" style="position:absolute; top:0; left:0; width:100%; height:100%;" frameborder="0" allowfullscreen></iframe>')
.removeClass('lazyYT-image-loaded')
.addClass('lazyYT-video-loaded');
}
});
}
$.fn.lazyYT = function () {
return this.each(function () {
var $el = $(this).css('cursor', 'pointer');
setUp($el);
});
};
}(jQuery));
I was looking at the lazyYT site and found their example:
<div class="container">
<div class="js-lazyYT" data-youtube-id="_oEA18Y8gM0" data-width="560" data-height="315" data-parameters="rel=0"></div>
</div>
Given that, you might try:
.myclass {
margin-left: 5px;
}
<div class="container">
<div class="js-lazyYT myclass" data-youtube-id="_oEA18Y8gM0" data-width="560" data-height="315" data-parameters="rel=0"></div>
</div>
or
<div class="container">
<div class="js-lazyYT" data-youtube-id="_oEA18Y8gM0" data-width="560" data-height="315" data-parameters="rel=0"> style='margin-left: 5px'</div>
</div>
or
.myclass div {
margin-left: 5px;
}
<div class="container myclass">
<div class="js-lazyYT" data-youtube-id="_oEA18Y8gM0" data-width="560" data-height="315" data-parameters="rel=0"></div>
</div>
I'm trying to set the min-height of each of these sections to the the height of the window. This is the current code...
HTML
<section id="hero">
</section>
<section id="services">
</section>
<section id="work">
</section>
jQuery
jQuery(document).ready(function() {
$("#hero").css('min-height':($(window).height())+'px');
$(window).resize(function() {
$("#hero").css('min-height':($(window).height())+'px');
});
$("#services").css('min-height':($(window).height())+'px');
$(window).resize(function() {
$("#services").css('min-height':($(window).height())+'px');
});
$("#work").css('min-height':($(window).height())+'px');
$(window).resize(function() {
$("#work").css('min-height':($(window).height())+'px');
})
});
Here's a FIDDLE
$(function() {
$("#hero").css({ minHeight: $(window).innerHeight() + 'px' });
$(window).resize(function() {
$("#hero").css({ minHeight: $(window).innerHeight() + 'px' });
});
$("#services").css({ minHeight: $(window).innerHeight() + 'px' });
$(window).resize(function() {
$("#services").css({ minHeight: $(window).innerHeight() + 'px' });
});
$("#work").css({ minHeight: $(window).innerHeight() + 'px' });
$(window).resize(function() {
$("#work").css({ minHeight: $(window).innerHeight() + 'px' });
});
});
or shorter version
$(function() {
$("#hero, #services, #work").css({ minHeight: $(window).innerHeight() + 'px' });
$(window).resize(function() {
$("#hero, #services, #work").css({ minHeight: $(window).innerHeight() + 'px' });
});
});
for jQuery CSS you can use e.g
$("#element").css( minHeight, $(window).innerHeight() + 'px' ); // When you target single property
or
$("#element").css({ minHeight: $(window).innerHeight() + 'px' }); // When you target single or multiple properties comma delmited
also you can use 'min-height' or minHeight
Changed : to ,
Try this:
jQuery(document).ready(function () {
$("#hero").css('min-height': ($(window).height()) + 'px');
$(window).resize(function () {
$('#hero').css("min-height", $(window).height() + "px");
});
$("#services").css('min-height': ($(window).height()) + 'px');
$(window).resize(function () {
$('#services').css("min-height", $(window).height() + "px");
});
$("#work").css('min-height': ($(window).height()) + 'px');
$(window).resize(function () {
$('#work').css("min-height", $(window).height() + "px");
})
});
Hi You don't need for that jquery, just css please see here : http://jsbin.com/filoru/3
CSS:
section {
width:33%%;
float:left;
display:block;
height:100%
}
html, body {
height:100%;
padding : 0;
margin:0;
}
#hero {
background-color:red;
}
#services {
background-color:green;
}
#work {
background-color:orange;
}
html:
<body>
<section id="hero">
hero
</section>
<section id="services">
service
</section>
<section id="work">
work
</section>
</body>
</html>
I have this markup.
<div class="row">
<div class="col-md-4">
<img src="imgsrc.jpg" />
</div>
</div>
<div class="row">
<div class="col-md-4">
<img src="imgsrc.jpg" />
</div>
</div>
With .col-md-4 has relative position, when I try to attach mouseover event to the .col-md-4 and get position of its offset it's return wrong offset for second .col-md-4 in second row. Here is the script
$('.col-md-4').hover(function(){
var offset = $(this).position();
var height = $(this).height();
console.log(offset); // this gives the wrong offset when hovering over second col-md-4 in second row
$('#shadow2').stop(true, true).animate({
'left': offset.left,
'top': offset.top + height + 10
});
}, function(){
$('#shadow2').animate({
'left': '-350px'
});
});
try using .offset(), it gives position of element relative to document, change
var offset = $(this).position();
to
var offset = $(this).offset();
Update::
$('.col-md-4').hover(function(){
var childPosition = $(this).offset();
var parentPosition = $(this).parent().offset();
var actualOffset = {
top: childPosition.top - parentPosition.top,
left: childPosition.left - parentPosition.left
}
var height = $(this).height();
console.log(offset);
$('#shadow2').stop(true, true).animate({
'left': actualOffset.left,
'top': actualOffset.top + height + 10
});
....
I have the following code which serves to open an image in an overlay div. For some reason whenever I try to add a border to the image object it doesn't work. It only comes out the raw image with no border. How can I implement a border on this and also a close button on top right?
This is my code.
$(document).ready(function(){
$('a.lightbox').click(function(e){
$('body').css('overflow-y',' hidden');
$('<div id="overlay"></div>')
.css('top', $(document).scrollTop())
.css('opacity', '0')
.animate({'opacity': '0.6'}, 'slow')
.appendTo('body');
$('<div id= "lightbox"></div>')
.hide()
.appendTo('body');
$('<img>', {
src: $(this).attr('href'),
load: function() {
positionLightboxImage();
},
click : function() {
removeLightbox();
}
}).appendTo('#lightbox');
return false;
});
});
function positionLightboxImage() {
var top = ($(window).height() - $('#lightbox').height()) / 2;
var left = ($(window).width() - $('#lightbox').width()) / 2;
$('#lightbox')
.css({
'top': top + $(document).scrollTop(),
'left': left
})
.fadeIn();
}
function removeLightbox() {
$('#overlay, #lightbox')
.fadeOut('slow', function() {
$(this).remove();
$('body').css('overflow-y', 'auto'); // show scrollbars!
});
}
<a class="lightbox" href="<?php echo $row_searchHH['imageURL']; ?>"><img src="<?php echo $row_searchHH['imageURL']; ?>" width="90" height="90" style="margin-left:10px" /></a>
Add your border to this chunk:
$('#lightbox')
.css({
'top': top + $(document).scrollTop(),
'left': left
})
For example:
$('#lightbox')
.css({
'top': top + $(document).scrollTop(),
'left': left,
'border': '2px solid white'
})
Check this fiddle for demo
If you have the img inside the div
then probably you can set the style of the image
CSS
.imageclass{
width:98%;
height:98%;
position:absolute;
left:1%;
top:1%;
}
.parentdivclass{
background:rgba(15, 15, 15, .5);
width:200px;
height:200px;
position:absolute;
}
.closebuttonclass
{
left:95%;
top:0.2%;
width:5%;
height:5%;
position:absolute;
}
You can position your close button image on the top right of your div !!
so the final div structure should be something like this
HTML
<div class='parentdivclass'>
<img class='imageclass' src='' />
<img class='closebuttonclass' src='' />
</div>
How to create circular animation with different objects using jQuery. I have tried myself but the issue is that my scrip is not running smoothly.
I want this animate but in smooth way:
Efforts :
http://jsfiddle.net/eT7SD/
Html Code
<div id="apDiv1"><p><img src="http://4.bp.blogspot.com/_UkDBPY_EcP4/TUr43iCI-FI/AAAAAAAADR0/o9rAgCt9d-U/s1600/1242796868203109724Number_1_in_green_rounded_square_svg_med.png" width="200" height="115" id="img-1"/></p></div>
<div id="apDiv2"><p><img src="https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcRZv4hqGcyV6OqP0hI3uAiQVwHHgPuqcTl2NppFRyvbxXLVokbs" width="200" height="115" id="img-2"/></p></div>
<div id="apDiv3"><p><img src="https://encrypted-tbn2.gstatic.com/images?q=tbn:ANd9GcQaplzZIaF-uTQKnvfK9N9i-Rg27F6aHtSchQZaGR-DITgO1bDwzA" width="200" height="115" id="img-3"/></p></div>
<div id="apDiv4"><p><img src="https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcQjTbe5WfEnT840gIChKfbzlVnoPPoZsyrT4zjMReym9YpsRdOFvA" width="200" height="115" id="img-4"/></p></div>
<div id="apDiv5"><p><img src="https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcRWtiMAcxGe-RQw2gRwUUiyB5aRTMeVMG5LSCPF0Qpzes-USpgyTw" width="200" height="115" id="img-5"/></p></div>
<div id="apDiv6"><p><img src="https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcTXDhOygDcNsNVsv0eIXLYdBx4C-tmedIRhFfxGlCoCfNy04YU_" width="200" height="115" id="img-6"/></p></div>
<div id="apCenterDiv"><img src="https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcR42cgsKsYMWey79jT0XsTkMOyxc9oej9fVt-udxQvnVFOadpPQ" width="200" height="115" /></div>
Css Code
<style type="text/css">
#apCenterDiv {
position:absolute;
width:200px;
height:115px;
z-index:1;
left: 571px;
top: 209px;
}
#apDiv1 {
position:absolute;
width:200px;
height:115px;
z-index:2;
left: 570px;
top: 4px;
}
#apDiv2 {
position:absolute;
width:200px;
height:115px;
z-index:3;
left: 821px;
top: 134px;
}
#apDiv3 {
position:absolute;
width:200px;
height:115px;
z-index:4;
left: 822px;
top: 328px;
}
#apDiv4 {
position:absolute;
width:200px;
height:115px;
z-index:5;
left: 572px;
top: 385px;
}
#apDiv5 {
position:absolute;
width:200px;
height:115px;
z-index:6;
left: 319px;
top: 329px;
}
#apDiv6 {
position:absolute;
width:200px;
height:115px;
z-index:7;
left: 319px;
top: 135px;
}
</style>
Script
<script>
$(document).ready(function(e) {
setInterval(function() {
var imgfirstSrc = $("#img-1").attr("src");
var imgSecSrc = $("#img-2").attr("src");
var imgthirdSrc = $("#img-3").attr("src");
var imgfourthSrc = $("#img-4").attr("src");
var imgfifthSrc = $("#img-5").attr("src");
var imgsixthSrc = $("#img-6").attr("src");
$("#img-2").attr("src",imgfirstSrc);
$("#img-3").attr("src",imgSecSrc);
$("#img-4").attr("src",imgthirdSrc);
$("#img-5").attr("src",imgfourthSrc);
$("#img-6").attr("src",imgfifthSrc);
$("#img-1").attr("src",imgsixthSrc);
},1000);
});
</script>
EDIT
I have to add more animation with click/stop events. When user click the red image place of 270 they have to replace the place of 90 and animation will be stop; for more clarification you have to see the image below. I have tried #Cristi Pufu code but I want more modification
Efforts
http://jsfiddle.net/SaNtf/
Using jQuery Animation: http://jsfiddle.net/eT7SD/6/
Using mathand jQuery : http://jsfiddle.net/eT7SD/7/
Using CSS3 Rotation (just for fun): http://jsfiddle.net/dMnKX/
Just add a class 'box' to your animating divs like in the fiddle and use this js:
$(document).ready(function(e) {
var animate = function(){
var boxes = $('.box');
$.each(boxes, function(idx, val){
var coords = $(boxes[idx+1]).position() || $(boxes[0]).position();
$(val).animate({
"left" : coords.left,
"top" : coords.top
}, 1500, function(){})
});
}
animate();
var timer = setInterval(animate, 2000);
});
EDIT:
$(document).ready(function(e) {
var angles = [90, 45, 315, 270, 225, 135];
var unit = 215;
var animate = function(){
$.each($('.box'), function(idx, val){
var rad = angles[idx] * (Math.PI / 180);
$(val).css({
left: 550 + Math.cos(rad) * unit + 'px',
top: unit * (1 - Math.sin(rad)) + 'px'
});
angles[idx]--;
});
}
var timer = setInterval(animate, 10);
});
You have to change the left, top, width, height properties of boxes, standardize them, set the correct unit (circle radius) and initial angles. But for a preview, i think this is what you want (just needs a little more work).
Example: http://jsfiddle.net/eT7SD/7/
Visual understanding of angles:
Just use CSS3 to rotate the image:
html
<div id='container'>
... (all your images here)
</div>
javascript:
<script type='text/javascript'>
window.myRotation=0;
$(document).ready(function(e) {
setInterval(function() {
$("#container").css("transform","rotate(" + window.myRotation + "deg)");
$("#container").css("-ms-transform","rotate(" + window.myRotation + "deg)");
$("#container").css("-webkit-transform","rotate(" + window.myRotation + "deg)");
window.myRotation +=20;
},50);
});
</script>
Well I tried out something, I think it could work
NOTE: this is not the complete code and only an example of how it could work
FIDDLE: http://jsfiddle.net/Spokey/eT7SD/2/
NEW FIDDLE http://jsfiddle.net/Spokey/eT7SD/3/ (6 images)
I used .position() from jQuery to get the positions of div1 - div6.
Then moved the image there using .animate().
http://api.jquery.com/position/
http://api.jquery.com/animate/
HTML
<img src="http://4.bp.blogspot.com/_UkDBPY_EcP4/TUr43iCI-FI/AAAAAAAADR0/o9rAgCt9d-U/s1600/1242796868203109724Number_1_in_green_rounded_square_svg_med.png" width="200" height="115" id="img-1"/>
<img src="http://4.bp.blogspot.com/_UkDBPY_EcP4/TUr43iCI-FI/AAAAAAAADR0/o9rAgCt9d-U/s1600/1242796868203109724Number_1_in_green_rounded_square_svg_med.png" width="200" height="115" id="img-2"/>
<div id="apDiv1"></div>
<div id="apDiv2"></div>
<div id="apDiv3"></div>
<div id="apDiv4"></div>
<div id="apDiv5"></div>
<div id="apDiv6"></div>
<div id="apCenterDiv"></div>
JavaScript
$(document).ready(function(e) {
var i = 1;
var j = 2;
setInterval(function() {
if(i===7){i=1;}
if(j===7){j=1;}
var divd = $("#apDiv"+i).position();
var divds = $("#apDiv"+j).position();
$("#img-1").stop().animate({left:(divd.left), top:(divd.top)});
$("#img-2").stop().animate({left:(divds.left), top:(divds.top)});
i++;j++;
},1000);
});