I have a sanitizeStr() function that I need to run on EVERY property/subproperty that exists in an object like the one below:
const data = {
info: 'schools',
schools: [
{ name: 'Johnson Elementary', type: 'elementary' },
{ name: 'Iselin Middle School', type: 'middle' }
],
bestStudent: {
name: 'John',
grade: 'sixth'
}
};
The issue is that for every single one of these properties, they may or may not exist. Right now, I'm having to do multiple if checks for each property and manually running the function:
// Is there a better way to do this rather than what I have here:
if (data.info) {
data.info = sanitizeStr(data.info);
}
if (data.bestStudent) {
if (data.bestStudent.name) {
data.bestStudent.name = sanitizeStr(data.bestStudent.name);
}
if (data.bestStudent.grade) {
data.bestStudent.grade = sanitizeStr(data.bestStudent.grade);
}
}
if (data.schools) {
data.schools.forEach((school, i) => {
if (school.name) {
data.schools[i].name = sanitizeStr(school.name);
}
if (school.grade) {
data.schools[i].grade = sanitizeStr(school.grade);
}
});
}
If anyone knows of a cleaner/less manual way of doing this, it would be appreciated.
You could use an iterative and recursive approach for objects and call the function for non objects only.
function sanitizeStr(s) {
return '#' + s;
}
function iterAll(object) {
Object.keys(object).forEach(function (k) {
if (object[k] && typeof object[k] === 'object') {
iterAll(object[k]);
return;
}
object[k] = sanitizeStr(object[k]);
})
}
var data = { info: 'schools', schools: [{ name: 'Johnson Elementary', type: 'elementary' }, { name: 'Iselin Middle School', type: 'middle' }], bestStudent: { name: 'John', grade: 'sixth' } };
iterAll(data);
console.log(data);
.as-console-wrapper { max-height: 100% !important; top: 0; }
You must me looking for this
const sanitizeObject = (obj, callBack, isClone = false) => {
let tempObj = obj;
if(typeof callBack === 'function' && (typeof tempObj === 'string' || typeof tempObj === 'number')){
return callBack(tempObj)
}else if(typeof tempObj === 'object' && tempObj !== null){
tempObj = isClone ? (Array.isArray(tempObj) ? [...tempObj] : {...tempObj}) : tempObj;
Object.keys(tempObj).forEach(objKey => {
const valueOfobject = tempObj[objKey]
if(typeof valueOfobject === 'string' || typeof valueOfobject === 'number'){
tempObj[objKey] = callBack(tempObj[objKey])
}else {
tempObj[objKey] = sanitizeObject(valueOfobject, callBack, isClone)
}
})
}
return tempObj;
}
const data = {
test1: {
test2: [{
property: "any string",
property2: null
}]}
}
console.log(sanitizeObject(data, function (stringValue){
return stringValue + " apend"
}))
Related
This question already has answers here:
foreach return object property javascript
(4 answers)
Closed 1 year ago.
var OBJ = {
code: 42,
item1: [{
id: 1,
name: 'foo'
}, {
id: 2,
city: 'NY'
name: 'bar'
}],
thing: [{
id: 14,
name: 'foo'
}, {
id: 5,
street: 'E43'
name: 'pub'
}]
};
Javascript object(OBJ)
I need a method that returns VALUE of KEY I pass as an argument if KEY is not present in OBJ method should return undefined
getKeyValueFromObject(OBJ , 'street') // should return 'E43'
getKeyValueFromObject(OBJ , 'dog') // should return undefined
I tried this(not working)
getKeyValueFromObject(obj: any, search: string) {
const notFound = {};
Object.keys(obj).forEach(key => {
if (key !== null && key !== undefined && !(obj[key] === undefined || obj[key] === null)) {
if (key === search) {
return obj[key];
} else if (obj[key].constructor === {}.constructor) {
const result = this.getKeyValueFromObject(obj[key], search);
if (result !== notFound) return result;
} else if (Array.isArray(obj[key])) {
obj[key].forEach(element => {
const result = this.getKeyValueFromObject(element, search);
if (result !== notFound) return result;
});
}
}
});
return {};
}
Your code was almost working, but the return statements in your forEach code were not working as you expected. Look here: Grab the return value and get out of forEach in JavaScript?. Instead I used a variable resultKey to store a match.
There were some commas missing in your OBJ json, but I think that was not the main problem.
var OBJ = {
code: 42,
item1: [{
id: 1,
name: 'foo'
}, {
id: 2,
city: 'NY',
name: 'bar'
}],
thing: [{
id: 14,
name: "foo"
}, {
id: 5,
street: "E43",
name: "pub"
}]
};
function getKeyValueFromObject(obj, search) {
let resultKey = undefined;
const notFound = {};
Object.keys(obj).forEach(key => {
if (key !== null && key !== undefined && !(obj[key] === undefined || obj[key] === null)) {
if (key === search) {
resultKey = obj[key];
} else if (obj[key].constructor === {}.constructor) {
const result = this.getKeyValueFromObject(obj[key], search);
if (result !== notFound) resultKey = result;
} else if (Array.isArray(obj[key])) {
obj[key].forEach(element => {
const result = this.getKeyValueFromObject(element, search);
if (result !== notFound) resultKey = result;
});
}
}
return;
});
return resultKey;
}
console.log(getKeyValueFromObject(OBJ, "street"));
console.log(getKeyValueFromObject(OBJ , "dog"));
I have some attributes from a nested object that is inside the parent object but I would like to merge nested object with the parent object to be flatten.
Original object:
enrollment = {
user: {
id: 'string',
name: 'string'
},
finished: 'boolean',
path: 'string'
}
expected flatten object:
user: {
id: 'string',
name: 'string',
finished: 'boolean',
path: 'string'
}
You can recursively build object any number of nested objects. So, this function is not your case dependent:
var enrollment = {
user: {
id: 'string',
name: 'string'
},
finished: 'boolean',
path: 'boolean'
}
var enrollment2 = {
user: {
id: 'string',
name: 'string'
},
test: {
test1: {
test2: {
val0:'val0',
test4: { //3rd level nested object for example
val1: 'val1',
val2: 'val2'
}
}
}
},
finished: 'boolean',
path: 'boolean'
}
const flat = (obj, out) => {
Object.keys(obj).forEach(key => {
if (typeof obj[key] == 'object') {
out = flat(obj[key], out) //recursively call for nesteds
} else {
out[key] = obj[key] //direct assign for values
}
})
return out
}
console.log(flat(enrollment, {}))
console.log(flat(enrollment2, {}))
I needed something that avoids rewriting keys with the same name that were in different levels in the original object. So I wrote the following:
const flattenObject = (obj, parentKey = '') => {
if (parentKey !== '') parentKey += '.';
let flattened = {};
Object.keys(obj).forEach((key) => {
if (typeof obj[key] === 'object' && obj[key] !== null) {
Object.assign(flattened, flattenObject(obj[key], parentKey + key))
} else {
flattened[parentKey + key] = obj[key]
}
})
return flattened;
}
var test = {
foo: 'bar',
some: 'thing',
father: {
son1: 'son1 value',
son2: {
grandchild: 'grandchild value',
duplicatedKey: 'note this is also used in first level',
},
},
duplicatedKey: 'note this is also used inside son2',
}
let flat = flattenObject(test);
console.log(flat);
// how to access the flattened keys:
let a = flat['father.son2.grandchild'];
console.log(a);
Also checks if the object is null, as I was having some problems with that in my usage.
Here's a quick and dirty way to flatten your object:
var enrollment = {
user: {
id: 'string',
name: 'string',
},
fineshed: true,
path: false,
};
var user = Object.assign(enrollment.user);
user.fineshed = enrollment.fineshed;
user.path = enrollment.path;
For a generic method with a couple of caveats of no shared key names and only flattening 1 level of depth:
var enrollment = {
user: {
id: 'string',
name: 'string',
},
fineshed: true,
path: false,
};
const flatten = (object) => {
let value = {};
for (var property in object) {
if (typeof object[property] === 'object') {
for (var p in object[property]) {
value[p] = object[property][p];
}
} else {
value[property] = object[property];
}
}
return value;
};
let user = flatten(enrollment);
console.log(user);
using recursion and reduce.
note that if value itself is an array containing objects, you might want add another check like !Array.isArray(value) depending on your case
function flatObj(obj) {
return Object.entries(obj).reduce(
(flatted, [key, value]) =>
typeof value == "object"
? { ...flatted, ...flatObj(value) }
: { ...flatted, [key]: value },
{}
);
}
Just want a single Object:
const enrollment = {
user: {
id: 'string',
name: 'string'
},
finished: 'boolean',
path: 'boolean'
}
function propsToUser(enrollObj){
const u = {...enrollObj.user};
for(let i in enrollObj){
if(i !== 'user')u[i] = enrollObj[i];
}
return u;
}
const user = propsToUser(enrollment);
console.log(user);
Below code snippet takes nested input object like this :
{
name:'Namig',
surname:'Hajiyev',
address:{
city:'Sumgait',
country:'Azerbaijan',
geo: {
lat:'40.5897200',
long:'49.6686100'
}
}
}
and returns result flattened object like this:
{
"name": "Namig",
"surname": "Hajiyev",
"address.city": "Sumgait",
"address.country": "Azerbaijan",
"address.geo.lat": "40.5897200",
"address.geo.long": "49.6686100"
}
Here is my code :
function flattenObject(obj, newObj, prefix) {
newObj = newObj || {};
prefix = prefix || "";
for (var key in obj) {
if (obj.hasOwnProperty(key)) {
const type = typeof obj[key];
const newKey = !!prefix ? prefix + "." + key : key;
if (type === "string") {
newObj[newKey] = obj[key];
}
else if (type === "object") {
flattenObject(obj[key], newObj, newKey);
}
}
}
return newObj;
}
var obj = {
name:'Namig',
surname:'Hajiyev',
address:{
city:'Sumgait',
country:'Azerbaijan',
geo: {
lat:'40.5897200',
long:'49.6686100'
}
}
}
console.log(flattenObject(obj));
I need to replace every time value in a nested object with a momentJS element of its value.
const input = {
data: {
sub1: {
time: 1578857603218
}
sub2: {
some: 'thing,
foo: [{
value: 123,
time: 1578857603218
}]
}
}
}
Right now my code looks very ugly, as I'm doing this manually as there are specific fields with an optional time value.
if (data && data.sub2 && data.sub2.foo && data.sub2.foo[0].time) {
data.sub2.foo[0].time = moment(data.sub2.foo[0].time).toDate()
}
To do this in a more dynamic way, I see two options:
Pass something like an array/map with all optional time fields and replace them with a loop
Is there a better way to replace my if conditions to go through all relacing time fields?
Iterate through all keys
But this would not work for nested objects.
for (var prop in obj) {
if (Object.prototype.hasOwnProperty.call(obj, prop)) {
// do stuff
}
}
If you know the key value pair, then what you show as already in use is exactly what you should use. It is O(1), very quick, and essentially a single line.
Making that dynamic will require O(n) where n is the number of key value pairs, and will require several lines of code.
const renderTime = input => {
if (Array.isArray(input)) {
input.forEach(el => renderTime(el));
}
if (typeof input === 'object' && !!input) {
Object.keys(input).forEach(k => {
if (k === 'time') input[k] = 'moment(input[k]).toDate()';
else renderTime(input[k]);
});
}
};
const input = {
data: {
sub1: {
time: 1578857603218
},
sub2: {
some: 'thing',
foo: [{
value: 123,
time: 1578857603218
}]
}
}
};
renderTime(input);
console.log(input);
Whenever you want to deal with nested objects with an undetermined level of depth, think of recursivity
const setTime = (object, time) => {
for (let prop in object) {
if (!Object.prototype.hasOwnProperty.call(object, prop)) {
continue;
}
if (typeof (object[prop]) === 'object') {
setTime(object[prop], time);
}
if (prop === 'time') {
object.time = time;
}
}
return object;
};
const input = {
data: {
sub1: {
time: 1578857603218
},
sub2: {
some: 'thing',
foo: [{
value: 123,
time: 1578857603218
}]
}
}
}
setTime(input, 666);
Try this one:) The secret is recursive loop
const input = {
data: {
sub1: {
time: 1578857603218
},
sub2: {
some: 'thing',
foo: [{
value: 123,
time: 1578857603218
}]
}
}
};
function changeTime(obj) {
obj && Object.keys(obj).forEach(key => {
if(key === 'time') {
obj.time = moment(obj.time); // you have to use moment
}
if(typeof obj[key] === 'object'){
changeTime(obj[key]);
}
});
}
changeTime(input);
console.log(input);
This won't handle the case where the nested fields are in an array, but it should work for nested objects
function replaceNestedValues(obj, targetVal, nextVal) {
return Object.keys(obj).reduce((acc, key) => {
const value = obj[key];
if (typeof value === 'object' && value !== null) {
acc[key] = replaceNestedValues(value, targetVal, nextVal);
} else if (value === targetVal) {
acc[key] = nextVal;
} else {
acc[key] = value;
}
return acc;
}, {});
}
Example
const data = { a: { b: 10, c: null }, d: null };
replaceNestedValues(data, null, '');
// => { a: { b: 10, c: '' }, d: '' }
You can use this code to modify your property. The property can be present in deeply nested object or within array of objects.
foo(entry: any | any[]) {
if (Array.isArray(entry)) {
entry.forEach(ent => this.foo(ent));
} else if (typeof entry === 'object' && entry !== null) {
for (let [key, value] of Object.entries(entry)) {
if (typeof value === 'object' && value !== null) {
this.foo(value);
} else if (Array.isArray(value)) {
this.foo(value);
}
if (key === "time") {
entry[key] = "changed"; // modified value
}
}
return entry;
}
}
this.foo(data); // your object
I would like to filter my data depending on a typed keyword.
https://jsfiddle.net/LeoCoco/e96L8akn/
let keyword = '-pre';
let data = {
'Basic': [{
name: 'a-basic'
}, {
name: 'b-basic'
}, {
name: 'c-basic'
}],
'Premium': [{
name: 'a-pre'
}, {
name: 'b-pre'
}, {
name: 'c-pre'
}],
'Extra': [{
name: 'a-ext'
}, {
name: 'b-ext'
}, {
name: 'c-ext'
}],
};
Output
'Premium': [{name: 'a-pre'}, { name: 'b-pre'}, { name: 'c-pre'}]
My try
lodash.forEach(data, (card) => {
card = card.filter(o => {
return Object.keys(o).some(k => {
return typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase());
});
});
})
But it does not work.The difficulty for me is that the filtering must happen on the nested object keys contained in each array.
var result={};
Object.keys(data).forEach(key => {
result[key] = data[key].filter(o => {
return Object.keys(o).some(k =>typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase()));
});
})
Because this is object you can use reduce() on Object.keys() instead and then inside use every() to check for keyword.
let keyword = '-pre';
let data = {"Basic":[{"name":"a-basic"},{"name":"b-basic"},{"name":"c-basic"}],"Premium":[{"name":"a-pre"},{"name":"b-pre"},{"name":"c-pre"}],"Extra":[{"name":"a-ext"},{"name":"b-ext"},{"name":"c-ext"}]}
var result = Object.keys(data).reduce(function(r, e) {
var check = data[e].every(o => o.name.indexOf(keyword) != -1);
if(check) r[e] = data[e]
return r;
}, {})
console.log(result)
Have a small question:
p: {
s: {
name: 'demo'
}
},
x: {
'something': 'me'
}
}
How do I get name without knowing exactly where it is in the object tree ?
Edit: How do I get to 'me' ?
You can iterate recursively:
function findByKeyName(obj, keyName) {
for (var key in obj) {
if (key === keyName) {
return obj[key];
} else {
if (typeof obj[key] === "object" && obj[key] !== null) {
return findByKeyName(obj[key], keyName);
}
}
}
}
findByKeyName(obj, "name") //returns "demo"
Ugly but true...
var getValue = (o,p) => JSON.stringify(o).replace(new RegExp('.*?' + p + '":"([^"]*).+'),"$1"),
obj = {
p: {
s: {
name: 'demo'
}
}
};
document.write(getValue(obj,"name"));
Well despite my ugly solution works perfectly i just would like to add my version of recursive approach for the public welfare.
The following will find the first appearance of the searched property.
p = {
s: {
name: 'demo',
},
x: {
'something': 'me'
},
y: null,
z: {
'something': 'you'
}
};
var getValue = (o,v) => {
var ok = Object.keys(o),
f = false,
i = 0;
while (!f && i < ok.length) {
o[ok[i]] !== null && typeof o[ok[i]] === "object" && (f = getValue(o[ok[i]],v));
i++;
}
return o[v] || f;
};
document.write(getValue(p,"something"));
And the following will find the last appearance of the searched property
p = {
s: {
name: 'demo',
},
x: {
'something': 'me'
},
y: null,
z: {
'something': 'you'
}
};
var getValue = (o,v) => {
var ok = Object.keys(o),
f = false,
i = 0;
while (!o[v] && i < ok.length) {
o[ok[i]] !== null && typeof o[ok[i]] === "object" && (f = getValue(o[ok[i]],v));
i++;
}
return o[v] || f;
};
document.write(getValue(p,"something"));