Hello everyone I want to parse array to Codeigniter controller but my code is not working can you please tell me where is a mistake in this code. I am a new in jQuery I know it is a very basic mistake.
jQuery Code:
$("#add_state").click(function(){
var addstate = {
State: $.trim($('#statename').val()
}
$.ajax({
type: "POST",
url: "<?php echo base_url()?>/index.php/geo/add_state",
data: addstate,
success: function(response){
alert(response);
}
});
event.preventDefault();
});
HTML Code:
<form role="form">
<div class="form-group">
<label for="exampleInputEmail1">State Name</label>
<input type="text" name="State" class="form-control" id="statename" placeholder="Enter State Name">
</div>
<button type="submit" class="btn btn-info" id="add_state">Submit</button>
</form>
trim is not closed properly
it suppose to be like this
$("#add_state").click(function(){
var addstate = {
State: $.trim($('#statename').val())
}
$.ajax({
type: "POST",
url: "<?php echo base_url()?>/index.php/geo/add_state",
data: addstate,
success: function(response){
alert(response);
}
});
event.preventDefault();
});
Missing ) in State: $.trim($('#statename').val(). Change it to State: $.trim($('#statename').val()).
Use $(document).on('click', '#add_state', function() { instead$("#add_state").click(function(){. Because first solution will work, if you add script before dom element was created.
Check url, maybe it's incorrect.
Related
Have no idea what it could be. Please help me release this ajax commentaries. I have never done this before. HTML form for input text and some ids:
<form id="send_comment" method="POST" action="write_comment.php">
<input hidden type="text" id="c_post_id" name="c_post_id" value="<?=$_GET["id"]?>">
<input hidden type="text" id="c_user_id" name="c_user_id" value="<?=$user_id?>">
<div class="form-group shadow-textarea">
<textarea class="form-control z-depth-1" type="text" id="c_text" rows="3" placeholder="Write comment here..." name="c_text" required pattern="^[a-zA-Z0-9\s]+$"></textarea>
</div>
<div class="col-md-12 text-center">
<button id="make_comment" class="btn btn-default" name="make_comment" type="submit" value="Submit"><i class="fas fa-check" style="font-size: 35px;"></i></button>
</div>
</form>
PHP processing:
if($_POST["make_comment"]) {
$c_post_id = $_POST["c_post_id"];
$c_user_id = $_POST["c_user_id"];
$c_text = $_POST["c_text"];
$date = date("m/d/y G:i:s<br>", time());
$sql = "INSERT INTO `comments` VALUES ('$c_post_id','$c_user_id',null,'$c_text','$date')";
if ($connect->query($sql) === TRUE) {
header("Location: http://thecobnmod.com/post.php?id=$c_post_id");
}
else {
exit( "Error: " . $sql . "<br>" . $conn->error);
}
}
JS ajax:
function funcSuccess (data) {
$("#comment_ajax").text(data);
}
function funcBefore (){
$("#comment_ajax").text("Loading comment...");
}
$(document).ready(function(){
$("#make_comment").bind("click", function () {
event.preventDefault();
$.ajax({
post: $("#c_post_id").val(),
user: $("#c_user_id").val(),
text: $("#c_text").val(),
url: "write_comment.php",
type: "POST",
data: {
c_post_id:post,
c_user_id:user,
c_text:text
},
dataType: "html",
beforeSend: funcBefore,
success: funcSuccess
});
});
});
Post id comes fro GET request to input field. I thought it could be a problem but not. now I really do not know what's wrong. Please help.
I strongly recommend consulting the documentations: Ajax doc
Ajax doesn't have post property AFAIK!
I'm not sure what you wanted to do, but here is a simple ajax example:
$.ajax({
url: 'here/is/some/url',
type: 'post',
data: {
some_key: 'value1',
other_key: 'value2',
/*...*/
},
dataType: 'html',
beforeSend: function() {/*...*/}
success: function(result) {/*...*/},
error: function(error) {/*...*/}
});
i new to use laravel framework,,
i want to passing datepicker value after user select the date
i try to give button, to submit that value, but i got error.
Anybody have idea to passing value without button ?
this is my blade :
<form id="myform" name="myform">
<input type="text" id="datepicker" name="datepicker" value="Date"/>
<input placeholder="Submit" type="button" id="submitMe" style="width:
100px;"/>
//can i passing this value without button?
<script>
$('#datepicker').datepicker({
format : 'yyyy-mm-dd'
});
</script>
</form>
<script>
$("#submitMe").click(function() {
$.ajax({
type: 'POST',
url: "/index/getDate",
method: "POST",
dataType: "json",
data: $('#myform').serialize(),
success: function(data) {
console.log("Done");
}
});
return false;
})
</script>
this is my route :
Route::post('index/getDate', 'UserController#getDate')-
>name('Usercontroller.getDate');
this is my controller :
function getDate(Request $request){
$date = urldecode ($_GET['datepicker']);
echo "chosen date is: ".$date;
}
i try to get output like this :
thankyou so much, if somebody want to help me :))
try this in your controller:
function getDate(Request $request){
$date = $request->datepicker;
return "chosen date is: ".$date;
}
then in your view:
<input type="text" id="datepicker" name="datepicker" value="Date"/>
<label id="dateSelected"></label>
<script>
$("#submitMe").click(function() {
$.ajax({
type: 'POST',
url: "/index/getDate",
method: "POST",
data: $('#myform').serialize(),
success: function(data) {
console.log(data);
$('#dateSelected').text(data);
}
});
return false;
})
</script>
you pass the form data with POST method, so you can get the parameter with
$request->input('datepicker');
I don't know how to write a proper question. But please let me explain this. I sent from with ajax and return with json. Each json value contain its status. So I need to test/evaluate the status and do something with it.
JSON
{url:"error",email:"ok",name:"ok"}
JS
//new port
$('#pflBtn').on('click',function(e){
e.preventDefault();
$.ajax({
type: 'POST',
url: 'inc/wcont8_port_db.php',
data :$(this).closest('form').serialize(),
dataType: 'json',
success: function(data){
if(data.url=="err"){//if url=error
$('#plf_url').addClass('error');//will add .error into #plf_url class
}else{
$('#plf_url').addClass('success');
}
}
})//ajax
})
html
<form class="pflForm">
<div class="form-group form-float">
<div class="form-line" id="pfl_url">
<input type="text" class="form-control" name="pfl_url" value="URL" required />
<label class="form-label">URL (www.domain.com)</label>
</div>
</div><!-- form-group form-float -->
<button type="submit" id="pflBtn">Save</button>
</form>
There are two mistakes you have made, check my comments with the code and try again by changing them:
$('#pflBtn').on('click',function(e){
e.preventDefault();
$.ajax({
type: 'POST',
url: 'inc/wcont8_port_db.php',
data :$(this).closest('form').serialize(),
dataType: 'json',
success: function(data){
if(data.url=="error"){// url has value 'error', but this was checking 'err'
$('#plf_url').addClass('error');//will add .error into #plf_url class but the class is not available in your html,
}else{
$('#plf_url').addClass('success');
}
}
})//ajax
})
So I have a target. It's to have a live area where you type in a username and every time you let a key go onkeyup() in the input area, I want it to send that data to a php file where that file will return what you just typed in and display it out where I want it. This isn't going as I like though :P. Please help, and thanks in advance.
JavaScript/jQuery/Ajax Code
function changeUsername() {
var user = $("#user").val();
$.ajax({
type: "GET",
url: "php/return.php",
data: user,
cache: false,
success: function(data){
$("#username-display").text(data);
}
});
}
HTML Code
<div class="container" title="Press enter to submit">
<label>What is your name: </label><input type="text" name="user" required="" maxlength="200" id="user" onkeyup="changeUsername();" /> <br />
You typed: <strong id="username-display"></strong>
<strong id="msg"></strong>
</div>
PHP Code
<?php
$username_vuln = $_GET["user"];
$username = htmlspecialchars($username_vuln);
echo $username;
?>
Please let me know if you need more info to help me solve this...
hey you can use following code
HTML CODE
<script type="text/javascript">
function changeUsername() {
// var user = $("#user").val();
$.ajax({
type: "GET",
url: "s.php",
data: {'user':$("#user").val()},
success: function(data){
$("#username-display").text(data);
}
});
}
</script>
<div class="container" title="Press enter to submit">
<label>What is your name: </label><input type="text" name="user" required="" maxlength="200" id="user" onkeyup="changeUsername();" /> <br />
You typed: <strong id="username-display"></strong>
<strong id="msg"></strong>
</div>
PHP CODE
<?php
$username_vuln = $_GET["user"];
$username = htmlspecialchars($username_vuln);
echo $_GET["user"];
?>
You need to correct your AJAX code also change type from GET to POST in php code so, final code will be like -
function changeUsername() {
var user = $("#user").val();
$.ajax({
url: "data.php",
data: {'user': user},
type : 'post',
success: function (data) {
$("#username-display").text(data);
}
});
}
PHP CODE :-
$username_vuln = $_POST["user"];
$username = htmlspecialchars($username_vuln);
echo json_encode($username);
Change Get to Post.
function changeUsername() {
var user = $("#user").val();
$.ajax({
type: "POST",
url: "php/return.php",
data: {'user': user},
cache: false,
success: function(data){
alert(data);
$("#username-display").text(data);
}
});
}
Php code first try to get response.
$username_vuln = $_POST["user"];
$username = htmlspecialchars($username_vuln);
echo $username; exit;
Try:
echo( json_encode( $username ) );
exit( 1 );
I looked now through a various number of StackOverflow pages and other websites - but can't find the correct solution for my problem. I try to post two values over to a php page via Post:
loginframe.php:
<form class="signin">
<input type="username" id="inputUsername" class="control" placeholder="Username" required autofocus>
<input type="password" id="inputPassword" class="control" placeholder="Password" required>
<div id="remember" class="checkbox">
<label>
<input type="checkbox" value="remember-me">Remember me
</label>
</div>
<button class="btn-login" type="submit" value="login" id="btn-login">Sign in</button>
</form>
My js:
$(document).ready(function(){
$("#btn-login").click(function(){
var username = $("#inputUsername").val();
var password = $("#inputPassword").val();
$.ajax(
{
type: "POST",
url: 'login.php',
data: {
user: username,
pass: password
},
success: function(result)
{
$("#result").html(result);
}
});
});
});
My login.php
<?php
if(isset($_POST['user']) && isset($_POST['pass']))
{
echo $_POST['user'];
echo $_POST['pass'];
} else {
include 'loginframe.php';
}
This login.php is just to check now if the data is passed. That is absolutely not the case. It always opens loginframe.php...
I can't find the error - I appreciate your help! Thank you a lot.
Use prevent default method.
$(document).ready(function(){
$("#btn-login").click(function(event){
event.preventDefault(); // this one prevents the default submission of the form
var username = $("#inputUsername").val();
var password = $("#inputPassword").val();
$.ajax(
{
type: "POST",
url: 'login.php',
data: {
user: username,
pass: password
},
success: function(result)
{
$("#result").html(result);
}
});
});
});