I am trying to provide a default value for a TimePicker object. But the that value I have is a string e.g "12:00 PM" And the picker needs a Date object.
I tried parsing the time directly into a Date object like shown below, but it does not work
let startTime = new Date("12:00 PM");
How can i convert this time string into a Date object so that i can provide the default value to the TimePicker.
Ive been able to create a function that can do the conversion, since I did not find any solution to this.
const dateFromTime = ({ timeString }) => {
const dateTime = new Date();
let timeHours = parseInt(timeString.substring(0, 2));
let timeMinutes = parseInt(timeString.substring(3, 5));
let timeAMPM = timeString.substring(6,
if (timeAMPM === "PM") {
timeHours += 12;
dateTime.setHours( timeHours, timeMinutes, 0, 0);
return dateTime;
}
const dateTime = dateFromTime({ timeString: "12:00 PM" });
This get the current date and time and instead sets the time to the specified time. and returns that
For any improvements, please suggest the right way to do this.
HTML:
<input id="appt-time" type="time" name="appt-time" value="13:30">
JS
const timeFrom12hto24h = time12h => {
const [time, meridiem] = time12h.split(" ");
let [hours, minutes] = time.split(":");
if (hours === "12") hours = "00";
if (meridiem === "PM") hours = parseInt(hours, 10) + 12;
return {hours, minutes}
};
const getMyObjectTime= timeFrom12hto24h('12:00 PM');
// apply the time to the HTML element
document.getElementById("appt-time").value = getMyObjectTime.hours + ':' + getMyObjectTime.minutes;
// one way to generate the needed time object
const dateInMiliseconds = new Date().setHours(getMyObjectTime.hours, getMyObjectTime.minutes, 0)
console.log(dateInMiliseconds);
In case there is moment.js already used in the project it would be like this:
HTML:
<input id="appt-time" type="time" name="appt-time" value="13:30">
JS:
// apply the time to the HTML element
document.getElementById("appt-time").value = moment("01:00 PM", 'hh:mm A').format('HH:mm')
// one way to generate the needed time object
let [hour, minutes] = moment("01:00 PM", 'hh:mm A').format('HH,mm').split(',');
const dateInMiliseconds = new Date().setHours(hour,minutes, 0)
console.log(dateInMiliseconds);
You just need to give the correct format to the Date object.
solution 1
If you don't care about date then you can simply convert like this.
let startTime = new Date(`2022/01/01 12:00 PM`);
solution 2
If you need today's date then you can simply convert like this.
let startTime = new Date(`${new Date().toDateString()} 12:00 PM`)
I used date-and-time package to format current time. It's worked for me.
npm install date-and-time
Controller
const date = require("date-and-time");
const now = new Date();
const startTime = date.format(now, "HH:mm:ss");
I have a list of array exdate which has some date. I want to exclude those dates and suggest the next available date from today. Date should not be random.
const exdate = ["24/08/2020", "8/8/2020"] //dates needs to be excluded [DD/MM/YYYY]
The newly generated date would be "25/08/2020" which is the closest one and not in the array.
This post has a question that is generating a random date using math.random function but my scenario is different.
Iterate inside a while loop and check if exdate contains the current date. If it doesnt contain the date, add 1 day to the current date and check it again. If the current date is not present inside the exdate array, exit the while loop and print the value.
A thing you might consider: What is the expected format of your dates? You should make sure it stays consistent. e.g. dont use leading 0s in front of months. My answer should point you into the right direction.
exdate = ['24/8/2020', '8/8/2020'];
let currDate = new Date();
let dd = currDate.getDate();
let mm = currDate.getMonth() + 1;
let y = currDate.getFullYear();
let dateFormat = dd + '/' + mm + '/' + y;
while (true) {
dd = currDate.getDate();
mm = currDate.getMonth() + 1;
y = currDate.getFullYear();
dateFormat = dd + '/' + mm + '/' + y;
if (!exdate.includes(dateFormat)) break;
currDate.setDate(currDate.getDate() + 1);
}
console.log(dateFormat);
I think this code does what you are after and is quite simple:
import moment from "moment";
// Constants
const dateFormat = 'DD/MM/YYYY'
// Utils
const strToDate = (date) => moment(date, dateFormat)
const dateToStr = (date) => date.format(dateFormat)
const sortByMoment = (a, b) => b.diff(a)
const incrementDate = (date) => date.add(1, 'day')
const isToday = (date) => moment().isSame(date, 'day')
// Data
const exdate = ["17/08/2020", "24/08/2020", "8/8/2020"];
// Implementation
const sortNewestToOldest = (data) => data
.map(strToDate)
.sort(sortByMoment)
const nextAvailableDate = ([head]) => isToday(head) ? [dateToStr(incrementDate(head))] : [dateToStr(moment())]
nextAvailableDate check if todays date is in the exdate list, if yes return tomorrow, else return today. If you also had future dates in there that you need to accomodate for you could expand isToday to be isTodayOrInTheFuture. The moment functions you would need can all be found here.
I need difference of two timestamp in seconds. But when calculate it gave wrongly. How to calculate the seconds from difference of two timestamp? Thanks in advance.
Here,
First timestamp = 20180104113612
Second timestamp = 20180104113954
Difference = First timestamp - Second timestamp
It results as 342. But actually it should be 222. So please anyone help to find the difference in seconds?
You need to parse out year, month, day, hour, minutes and seconds from your date and create a date object and then subtract both dates to get the difference.
var firstTimestamp = 20180104113612,
secondTimestamp = 20180104113954,
getDate = (time) => {
time = time.toString();
var year = time.substring(0,4),
month = time.substring(4,6),
day = time.substring(6,8),
hour = time.substring(8,10),
minutes = time.substring(10,12),
seconds = time.substring(12,14);
return new Date(year, month, day, hour, minutes, seconds);
},
getTimeDifference = (firstTime, secondTime) => {
return Math.floor((getDate(secondTime) - getDate(firstTime))/1000);
};
console.log(getTimeDifference(firstTimestamp, secondTimestamp));
Try this
let startDate = new Date();
let endDate = new Date();
let differenceInSecond = (endDate - startDate) / 1000; //since it's originally in milliseconds
first you have to format your date in proper format something like this. "2018-01-04T11:36:12";
for formatting you can use make some function like this
function getFormat(dateString) {
var txt = dateString.slice(0, 4)
+ "-"
+ dateString.slice(4, 6)
+ "-"
+dateString.slice(6,8)
+"T"
+dateString.slice(8,10)
+":"
+dateString.slice(10,12)
+":"
+dateString.slice(12,14);
return txt;
}
and then convert it into javascript Date object.
const First_timestamp = 20180104113612;
const Second_timestamp = 20180104113954;
const FirstDate = new Date(getFormat(First_timestamp.toString()));
const SecondDate = new Date(getFormat(Second_timestamp.toString()));
const TimeDiffInSeconds = (SecondDate.getTime() - FirstDate.getTime()) / 1000;
I've got a string from an input field which I use for date with a format like this 25-02-2013. Now I want to compare the string with today's date. I want to know if the string is older or newer then today's date.
Any suggestions?
<script type="text/javascript">
var q = new Date();
var m = q.getMonth()+1;
var d = q.getDay();
var y = q.getFullYear();
var date = new Date(y,m,d);
mydate=new Date('2011-04-11');
console.log(date);
console.log(mydate)
if(date>mydate)
{
alert("greater");
}
else
{
alert("smaller")
}
</script>
Exact date comparsion and resolved bug from accepted answer
var q = new Date();
var m = q.getMonth();
var d = q.getDay();
var y = q.getFullYear();
var date = new Date(y,m,d);
mydate=new Date('2011-04-11');
console.log(date);
console.log(mydate)
if(date>mydate)
{
alert("greater");
}
else
{
alert("smaller")
}
You can use a simple comparison operator to see if a date is greater than another:
var today = new Date();
var jun3 = new Date("2016-06-03 0:00:00");
if(today > jun3){
// True if today is on or after June 3rd 2016
}else{
// Today is before June 3rd
}
The reason why I added 0:00:00 to the second variable is because without it, it'll compare to UTC (Greenwich) time, which may give you undesired results. If you set the time to 0, then it'll compare to the user's local midnight.
Using Javascript Date object will be easier for you. But as the Date object does not supports your format i think you have to parse your input string(eg: 25-02-2013) with '-' to get date month and year and then use Date object for comparison.
var x ='23-5-2010';
var a = x.split('-');
var date = new Date (a[2], a[1] - 1,a[0]);//using a[1]-1 since Date object has month from 0-11
var Today = new Date();
if (date > Today)
alert("great");
else
alert("less");
If your date input is in the format "25-02-2013", you can split the string into DD, MM and YYYY using the split() method:
var date_string="25-02-2013";
var day = parseInt(date_string.split("-")[0]);
var month= parseInt(date_string.split("-")[1]);
var year = parseInt(date_string.split("-")[2]);
The parseInt() function is used to make the string into an integer. The 3 variables can then be compared against properties of the Date() object.
The most significant points which needs to be remembered while doing date comparison
Both the dates should be in same format to get accurate result.
If you are using date time format and only wants to do date comparison then make sure you convert it in related format.
Here is the code which I used.
var dateNotifStr = oRecord.getData("dateNotif");
var today = new Date();
var todayDateFormatted = new Date(today.getFullYear(),today.getMonth(),today.getDate());
var dateNotif=new Date(dateNotifStr);
var dateNotifFormatted = new Date(dateNotif.getFullYear(),dateNotif.getMonth(),dateNotif.getDate());
Well, this can be optimized further but this should give you clear idea on what is required to make dates in uniform format.
Here's my solution, getDay() doesn't work like some people said because it grabs the day of the week and not the day of the month. So instead you should use getDate like I used below
var date = new Date();
var m = date.getMonth();
var d = date.getDate();
var y = date.getFullYear();
var todaysDate = formateDate(new Date(y,m,d));
console.log("Todays date is: " + todaysDate)
const formateDate = (assignmentDate) => {
const date = new Date(assignmentDate)
const formattedDate = date.toLocaleDateString("en-GB", {
day: "numeric",
month: "long",
year: "numeric"
})
return formattedDate
}
The function below is just to format the date into a legible format I could display to my users
<script type="text/javascript">
// If you set the timezone then your condition will work properly,
// otherwise there is a possibility of error,
// because timezone is a important part of date function
var todayDate = new Date().toLocaleString([], { timeZone: "Asia/Dhaka" }); //Today Date
var targetDate = new Date('2022-11-24').toLocaleString([], { timeZone: "Asia/Dhaka" });
console.log('todayDate ==', todayDate); // todayDate == 10/31/2022, 12:15:08 PM
console.log('targetDate ==', targetDate); // targetDate == 11/24/2022, 6:00:00 AM
if(targetDate >= todayDate)
{
console.log("Today's date is small");
}
else
{
console.log("Today's date is big")
}
</script>
I'm trying to use JS to turn a date object into a string in YYYYMMDD format. Is there an easier way than concatenating Date.getYear(), Date.getMonth(), and Date.getDay()?
Altered piece of code I often use:
Date.prototype.yyyymmdd = function() {
var mm = this.getMonth() + 1; // getMonth() is zero-based
var dd = this.getDate();
return [this.getFullYear(),
(mm>9 ? '' : '0') + mm,
(dd>9 ? '' : '0') + dd
].join('');
};
var date = new Date();
date.yyyymmdd();
I didn't like adding to the prototype. An alternative would be:
var rightNow = new Date();
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");
<!-- Next line is for code snippet output only -->
document.body.innerHTML += res;
You can use the toISOString function :
var today = new Date();
today.toISOString().substring(0, 10);
It will give you a "yyyy-mm-dd" format.
Moment.js could be your friend
var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');
new Date('Jun 5 2016').
toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');
// => '2016-06-05'
If you don't need a pure JS solution, you can use jQuery UI to do the job like this :
$.datepicker.formatDate('yymmdd', new Date());
I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.
Visit http://api.jqueryui.com/datepicker/ for more examples
This is a single line of code that you can use to create a YYYY-MM-DD string of today's date.
var d = new Date().toISOString().slice(0,10);
I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.
function yyyymmdd(dateIn) {
var yyyy = dateIn.getFullYear();
var mm = dateIn.getMonth() + 1; // getMonth() is zero-based
var dd = dateIn.getDate();
return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd
}
var today = new Date();
console.log(yyyymmdd(today));
Fiddle: http://jsfiddle.net/gbdarren/Ew7Y4/
In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.
Also, use concat() to ensure safe concatenation of variables
Date.prototype.yyyymmdd = function() {
var yyyy = this.getFullYear();
var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
return "".concat(yyyy).concat(mm).concat(dd);
};
Date.prototype.yyyymmddhhmm = function() {
var yyyymmdd = this.yyyymmdd();
var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();
var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();
return "".concat(yyyymmdd).concat(hh).concat(min);
};
Date.prototype.yyyymmddhhmmss = function() {
var yyyymmddhhmm = this.yyyymmddhhmm();
var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();
return "".concat(yyyymmddhhmm).concat(ss);
};
var d = new Date();
document.getElementById("a").innerHTML = d.yyyymmdd();
document.getElementById("b").innerHTML = d.yyyymmddhhmm();
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();
<div>
yyyymmdd: <span id="a"></span>
</div>
<div>
yyyymmddhhmm: <span id="b"></span>
</div>
<div>
yyyymmddhhmmss: <span id="c"></span>
</div>
Local time:
var date = new Date();
date = date.toJSON().slice(0, 10);
UTC time:
var date = new Date().toISOString();
date = date.substring(0, 10);
date will print 2020-06-15 today as i write this.
toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ
The code takes the first 10 characters that we need for a YYYY-MM-DD format.
If you want format without '-' use:
var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;
In .join`` you can add space, dots or whatever you'd like.
Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:
var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');
This in response to #weberste's comment on #Pierre Guilbert's answer.
// UTC/GMT 0
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509
// Client local time
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509
Another way is to use toLocaleDateString with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:
date.toLocaleDateString('se')
To remove the delimiters (-) is just a matter of replacing the non-digits:
console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );
This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.
var someDate = new Date();
var dateFormated = someDate.toISOString().substr(0,10);
console.log(dateFormated);
dateformat is a very used package.
How to use:
Download and install dateformat from NPM. Require it in your module:
const dateFormat = require('dateformat');
and then just format your stuff:
const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');
Shortest
.toJSON().slice(0,10).split`-`.join``;
let d = new Date();
let s = d.toJSON().slice(0,10).split`-`.join``;
console.log(s);
Working from #o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.
Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
return format;
};
d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);
I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.
NB: I've kept the predefined class definition but you might wanna put that in a function or a custom class as per best practices.
A little variation for the accepted answer:
function getDate_yyyymmdd() {
const date = new Date();
const yyyy = date.getFullYear();
const mm = String(date.getMonth() + 1).padStart(2,'0');
const dd = String(date.getDate()).padStart(2,'0');
return `${yyyy}${mm}${dd}`
}
console.log(getDate_yyyymmdd())
This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format() function for the Javascript's Date object, so it can be used with familiar literal formats.
If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.
Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :
function toYYYYMMDD(d) {
var yyyy = d.getFullYear().toString();
var mm = (d.getMonth() + 101).toString().slice(-2);
var dd = (d.getDate() + 100).toString().slice(-2);
return yyyy + mm + dd;
}
You can simply use This one line code to get date in year
var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();
How about Day.js?
It's only 2KB, and you can also dayjs().format('YYYY-MM-DD').
https://github.com/iamkun/dayjs
Use padStart:
Date.prototype.yyyymmdd = function() {
return [
this.getFullYear(),
(this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
this.getDate().toString().padStart(2, '0')
].join('-');
};
This code is fix to Pierre Guilbert's answer:
(it works even after 10000 years)
YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")
Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:
function getDateInYYYYMMDD() {
let currentDate = new Date();
// year
let yyyy = '' + currentDate.getFullYear();
// month
let mm = ('0' + (currentDate.getMonth() + 1)); // prepend 0 // +1 is because Jan is 0
mm = mm.substr(mm.length - 2); // take last 2 chars
// day
let dd = ('0' + currentDate.getDate()); // prepend 0
dd = dd.substr(dd.length - 2); // take last 2 chars
return yyyy + "" + mm + "" + dd;
}
var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);
[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value
or
new Date().toJSON().slice(0,10).replace(/\/|-/g,'')
From ES6 onwards you can use template strings to make it a little shorter:
var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;
This solution does not zero pad. Look to the other good answers to see how to do that.
I usually use the code below when I need to do this.
var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
+ ('0' + (date.getMonth() + 1)).slice(-2)
+ '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written
To explain, .slice(-2) gives us the last two characters of the string.
So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.
So if the MyDate.getMonth() returns 9, it will be:
("0" + "9") // Giving us "09"
so adding .slice(-2) on that gives us the last two characters which is:
("0" + "9").slice(-2)
"09"
But if date.getMonth() returns 10, it will be:
("0" + "10") // Giving us "010"
so adding .slice(-2) gives us the last two characters, or:
("0" + "10").slice(-2)
"10"
It seems that mootools provides Date().format(): https://mootools.net/more/docs/1.6.0/Types/Date
I'm not sure if it worth including just for this particular task though.
If you don't mind including an additional (but small) library, Sugar.js provides lots of nice functionality for working with dates in JavaScript.
To format a date, use the format function:
new Date().format("{yyyy}{MM}{dd}")