i need send mi post in this format
{
"elements" : ["elem1", "elem2","elem3" ]
}
and i have created this array :
var miElem=["elem1", "elem2","elem3" ]
$.post({
url: 'url',
data: {"elements" : miElem} ,
dataType: 'json',
success: function(data) {
console.log(data)
}.bind(this),
error: function(xhr, status, err) {
console.log(err)
}.bind(this)
});
but dont work, the data send well, but the format is incorrect
Use $.ajax() like this.The use of $.post is not correct.Check the syntax for $.post.here https://api.jquery.com/jquery.post/
var miElem=["elem1", "elem2","elem3"];
$.ajax({
url: 'url',//give your url here
type:'POST',
data: {elements : miElem} ,
dataType: 'json',
success: function(data) {
alert('success');//test for successful ajax request
console.log(data);
},
error: function(xhr, status, err) {
alert('error');//test for unsuccessful ajax request
console.log(err);
}
});
You should used $.ajax instead of $.post.
In $.ajax don't use success and error parameters. Use .done(), .fail(), .. (http://api.jquery.com/jquery.ajax/) it's more comprehensive. You can use .then() if you want to use promise.
Datatype parameter is for response type.
Your request is failing because
you passed incorrect arguments to $.post() method.
you did not set type:'POST' if you intended to use $.ajax.
for $.post() do the following:
$.post('url', {elements: miElem}).done(function(data) {
console.log(data);
}).fail(function (error)
console.error(error);
});
for $.ajax do the following:
$.ajax({
type: 'POST',
url: 'url',
data: {elements: miElem},
success: function (data) {
console.log(data);
},
dataType: 'json'
});
Related
Hi I am currently learning php and I am trying to get data from php file using the below script but i am not getting any response
$.ajax({
type: 'POST',
url: "mark_mod.php",
data: data_set,
dataType: "JSON",
success: function(data) {
alert("Response : " ); // not triggering
}
});
my php return stmt
There might be problems with File URL or file access. You can use complete callback to check request for errors like that:
$.ajax({
type: 'POST',
url: "mark_mod.php",
data: data_set,
dataType: "JSON",
success: function(data) {
alert("Response : " );
},
// This method will be fired when request completes
complete: function(xxhr, status) {
alert("Status code: " + status);
}
});
If the status code is not success that means there is something wrong with your request.
You can check more callback options here.
It doesn't matter whether you use return or echo in your PHP file.
The success method must get a call if it's fine. However, if you use
return instead of echo, nothing will append to your request's data.
On the other hand, The PHP response will include in your 'data' variable in the function success.
You need use data in the assync function success
success: function(data) {
alert("Response : " + data);
},
Thanks for your Responses. I got the Solution to my problem. It seems since Ajax is asynchronous... its taking time to receive the resultant echo value from my php file. so I had to synchronize my Jquery using async : False.
$(function(){
$('#formID').on('submit',function(){
const data_set={
name:"Nipu chakraborty",
"phone":"01783837xxx"
}
$.ajax({
type: 'POST',
url: "mark_mod.php",
data: data_set,
dataType: "JSON",
success: function(data) {
alert(data);
}
});
});
});
I want all the ajax params before sending an ajax request in JSON format and I need to encrypt each value in JSON and again pass to the ajax request.
I get data in URI format as see in below code, not in JSON. How can I get that?
Around 200 Ajax in this format:
$.ajax({
type: "POST",
url: site_url + "user/user/login_action",
data: login_parms,
success: function (data) {
},
error: function (xhr, textStatus, errorThrown) {
}
});
Before Ajax Call:
$(document).ajaxSend(function(event, jqxhr, settings) {
console.log("settings :",settings.data);
});
Console log:
settings : vEmail=disha.c1%40grr.la&vPassword=123456789
Also if in AJAX use formData then how we can get each value of form data?
If you want to send a AJAX JSON CALL you must to use:
$.ajax({
type: "POST",
url: site_url + "user/user/login_action",
dataType: "json",
async: false,
contentType: "application/json",
data: JSON.stringify(login_parms),
success: function (data) {
},
error: function (xhr, textStatus, errorThrown) {
}
});
if you want to modify the param:
$.ajax({
beforeSend: function(xhr){
this.data
}
});
Here is My ajax call
$.ajax({
url:'http://localhost:8081/organizations/',
data: JSON.stringify({"name":"karthik"}),
type: 'POST',
dataType :'json',
processData : true,
success: (function(response){ alert("response "+response);}),
error: (function(err){ console.log(err); })
});
In the api, when i tried to print request.data, why i am getting like this {u'{"name":"karthik"}': [u'']}
Replace below line
success: (function(response){ alert("response "+response);}),
by newone
success: (function(response){ alert(JSON.stringify(response));}),
In your code and then try it will work.
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 7 years ago.
I am new to AJAX and I need to find a way to return an AJAX JSON response back to the calling function. Is there any way to achieve this.
My code snippet:
function requestAjaxWebService(webServiceName, method, jsonData) {
var returnData;
$.ajax({
url: webServiceName,
type: method,
data : jsonData,
dataType: "json",
success: function (data) {
returnData = data;
},
error: function(error){
returnData = "Server error";
}
});
return returnData;
}
jQuery.ajax() performs asynchronous HTTP request. Hence, you can't return its response synchronously (which your code is trying to do).
If the request succeeds, the success(data, textStatus, jqXHR) handler will get called at some point (you don't know when).
Here is one way you could modify your code:
function requestAjaxWebService(webServiceName, method, jsonData, callback) {
$.ajax({
url: webServiceName,
type: method,
data : jsonData,
dataType: "json",
success: function (data, textStatus, jqXHR) {
callback(true, data); // some method that knows what to do with the data
},
error: function(jqXHR, textStatus, errorThrown){
callback(false, errorThrown);
}
});
}
callback should be a reference to a method like:
function onData(isSuccess, dataOrError)
{
if (isSuccess) {
// do something with data
} else {
console.error(dataOrError);
}
}
Update If the settings object is needed in the callback for some reason:
function onData(isSuccess, settings, jqXHR, errorThrown)
{
if (isSuccess) {
// do something with the data:
// jqXHR.responseText or jqXHR.responseXML
} else {
// do something with error data:
// errorThrown, jqXHR.status, jqXHR.statusText, jqXHR.statusCode()
}
}
function requestAjaxWebService(webServiceName, method, jsonData, callback) {
var settings = {
url: webServiceName,
type: method,
data : jsonData,
dataType: "json"
};
settings.success = function(data, textStatus, jqXHR){
callback(true, settings, jqXHR);
};
settings.error = function(jqXHR, textStatus, errorThrown){
callback(false, settings, jqXHR, errorThrown);
};
$.ajax(settings);
}
requestAjaxWebService("name", "POST", "json", onData);
You can also use .done() and .fail() callbacks of jqxhr object instead of callbacks in settings object, as obiTheOne's answer suggests. It may look neater, but is not actually important here.
jQuery.ajax is an asynchronous function, so normally it doesn't return anything.
You can anyway return a value to the original function by setting the async option to false, but is not recommended, because a synchronous request will block the rest execution of the rest of your code until a response will be returned.
function requestAjaxWebService(webServiceName, method, onSuccess, onFail) {
var returnData;
$.ajax({
url: webServiceName,
type: method,
async: false,
data : jsonData,
dataType: "json",
success: function (data) {
returnData = data;
},
error: function(error){
returnData = "Server error";
}
});
}
take a look at this example: jsbin sync ajax example
You should instead use a callback (the standard way) to handle the response
function onSuccess (data) {
console.log(data);
}
function onFail (error) {
console.log('something went wrong');
}
function requestAjaxWebService(webServiceName, method, onSuccess, onFail) {
$.ajax({
url: webServiceName,
type: method,
data : jsonData,
dataType: "json",
success: onSuccess,
error: onError
});
}
Or you can return a Promise (a sort of async object) that will change value as soon as the request will be fullfilled
function requestPromise (webServiceName, method) {
return $.ajax({
url: webServiceName,
type: method,
data : jsonData,
dataType: "json"
});
}
requestPromise('...', 'GET').done(function (data) {
console.log(data);
});
refs:
jquery.ajax params
I use $.ajax to send some data to testajax.phpenter code here where data are processing. Result of this proces is link. How to get access to this? I think about sessions or cookies. Set in session $test and get access in another files.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: console.log('success');
data: { json : jsonObj }
});
In testajax.php I have someting like this
echo "PDF: <a href=images/test.pdf>$dir.pdf</a>";
$test = "PDF: <a href=images/test.pdf>$dir.pdf</a>";
How to get the $test or output the echo after call $.ajax
You can use success' function to get request from PHP.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'html',
data: { json : jsonObj }
success: function(data) {
var request = data;
console.log(data);
$('#link_container').html(data);
}
});
Your console now holds PDF: <a href=images/test.pdf>($dir content).pdf</a>.
Also the variable request holds the same result that you can use anywhere in the script.
Result is appended to #link_container.
Use the success() method for display the result.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: function (data){ // <= define handler for manupulate the response
$('#result').html(data);
}
data: { json : jsonObj }
});
Use below code It may help you.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
data: { json : jsonObj },
onSuccess: successFunc,
onFailure: failureFunc
});
function successFunc(response){
alert(response);
}
function failureFunc(response){
alert("Call is failed" );
alert(response);
}