I've been searching the net net for a while now trying to find a way to aggregate json array values with handlebars using +=, or -= if the condition is met. however i can't seem to find any guidelines on how to properly do so. can anyone guide me on how to convert this iteration into a handlebars helper?
var table = $("#table tbody");
$.getJSON("front-end/ajax/bethistory.php", function(data) {
var value = 0;
$.each(data, function(a, b) {
if (b.action == "win") {
value += parseFloat(b.coins);
} else if (b.action == "lose") {
value -= parseFloat(b.coins);
}
var tbody = $("<tr/>").append($("<td/>").html(b.action), $("<td/>").html(value))
table.append(tbody);
});
});
something like this?
var value = 0;
Handlebars.registerHelper("this_val", function(a,b) {
if (a == "win") {
value += parseFloat(b);
} else if (a == "lose") {
value -= parseFloat(b);
}
return value;
});
for anyone who needs this. i was able to figure it out thanks to this post
Handlebars.registerHelper("compute", function(array, options) {
var new_array = "",
value = 0,
count = array.length;
for (var i = 0; i < array.length; i++) {
var coins = Number(array[i]['coins']),
action = array[i]['action'];
if (action == "win") {
if (coins > 0) {
value += coins;
}
} else if (action == "lose") {
if (coins > 0) {
value -= coins;
}
}
array[i]['running'] = value;
new_array += options.fn(array[i]);
}
return new_array;
});
Related
I want to create a function that is able to determine if a number is same or palindrome. if a given number is palindrome or same then return 2 otherwise if it is not palindrome or same then i need check it twice by increment the given number by 1. after that if it palindrome or same then return 1. if no palindrome or same number found then return 0. i write the function which is giving me the exact result when i give the number as 11211 but the function don't show any response if i enter 1122 or other random value. please help me to find where the error of my function.
function sameOrPalindrome(num) {
var c = 0;
var al = 0;
var normalArray = num.toString().split("");
var revArray = num.toString().split("").reverse();
for (var i = 0; i < normalArray.length; i++) {
if (normalArray[i] != revArray[i]) {
c++;
}
}
if (c == 0) {
return 2;
} else {
num++;
al = sameOrPalindrome(num);
if (al == 2) {
return 1;
} else {
num++;
al = sameOrPalindrome(num);
if (al == 2) {
return 1;
}
}
}
return 0;
}
console.log("1233",sameOrPalindrome(1233))
here is my solution to this problem:
function reversedNum(num) {
return (
parseFloat(
num
.toString()
.split('')
.reverse()
.join('')
) * Math.sign(num)
)
}
function sameOrPalindrome(num) {
if (num === reversedNum(num)) {
return 2;
} else {
num++;
if (num === reversedNum(num)) {
return 1;
} else {
num++;
if (num === reversedNum(num)) {
return 1;
}
}
}
return 0;
}
console.log("1233",sameOrPalindrome(1233))
Perhaps not using recurse - I think your function loops
const allEqual = arr => arr.every( v => v === arr[0] )
const sameOrPalin = num => {
const str = String(num);
let arr = str.split("")
if (allEqual(arr)) return 2
arr.reverse();
if (arr.join("") === str) return 1;
return 0
};
console.log("1111",sameOrPalin(1111));
console.log("2111",sameOrPalin(2111));
console.log("2112",sameOrPalin(2112));
console.log("1234",sameOrPalin(1234));
for (let i = 2111; i<=2113; i++) console.log(i,sameOrPalin(i));
Question: I assumed if palindrome test is true at first time then return 2. if not try incrementing by one and test the palindrome again . if true return 1 else try incrementing for last time and check the palindrome if true return 1 else 0.
Store string into array first and do arr.reverse().join("") to compare
let arr=num.toString().split("");
if(num.toString() == arr.reverse().join(""))
function sameOrPalindrome(num, times) {
let arr = num.toString().split("");
if (num.toString() == arr.reverse().join("")) {
if (times == 3) return 2
else return 1;
} else if (times > 0) {
num++; times--;
return sameOrPalindrome(num, times);
} else return 0
}
console.log(sameOrPalindrome(123321, 3));
console.log(sameOrPalindrome(223321, 3));
console.log(sameOrPalindrome(323321, 3));
Your function needs to know if it should not call itself any more, e.g. when it's doing the second and third checks:
function sameOrPalindrome(num,stop) { // <-- added "stop"
var c = 0;
var al = 0;
var normalArray = num.toString().split("");
var revArray = num.toString().split("").reverse();
for (var i = 0; i < normalArray.length; i++) {
if (normalArray[i] != revArray[i]) {
c++;
}
}
if (c == 0) {
return 2;
} else if(!stop) { // <-- check of "stop"
num++;
al = sameOrPalindrome(num,true); // <-- passing true here
if (al == 2) {
return 1;
} else {
num++;
al = sameOrPalindrome(num,true); // <-- and also here
if (al == 2) {
return 1;
}
}
}
return 0;
}
for(let i=8225;i<8230;i++)
console.log(i,sameOrPalindrome(i));
function check_palindrom(num){
var c1 = 0;
var normalArray = num.toString().split("");
var revArray = num.toString().split("").reverse();
for (var i = 0; i < normalArray.length; i++) {
if (normalArray[i] == revArray[i]) {
c1++;
}
}
if(c1==0){
return 2;
}else{
return 1;
}
}//check_palindrom
function my_fun_check_palindrome(mynum){
//console.log(mynum);
var num = mynum;
var c2 = 0;
var al = 0;
var normalArray = mynum.toString().split("");
var revArray = mynum.toString().split("").reverse();
for (var j = 0; j < normalArray.length; j++) {
if (normalArray[j] == revArray[j]) {
c2++;
}
}
if(c2==0){
console.log('Number is palindrome. Return Value :'+ 2);
}
if(1){
console.log('checking again with incremeting value my one');
num = parseInt(num)+1;
al = check_palindrom(num);
if(al==2){
console.log('Number is palindrome. Return Value :'+ 1);
}else{
console.log('Number is not palindrome. Return Value :'+ 0);
}
}
}//my_fun_check_palindrome
console.log(my_fun_check_palindrome(1122));
console.log(my_fun_check_palindrome(11221));
We should always strive to make function more effiecient... you dont need to run full loop. plus actual checking of palindrome can me modularized
function isSameOrPalindrome(num) {
var normalArray = num.toString().split("");
var revArray = num.toString().split("").reverse(),
i;
for (i = 0; i < normalArray.length / 2; i++) {
if (normalArray[i] !== revArray[i]) {
break;
}
}
if (i >= normalArray.length/2) {
return "Palindrome";
} else {
return "Not Palindrome";
}
}
function doCheck(num) {
var isPalindrome = isSameOrPalindrome(num);
console.log(isPalindrome);
if(isPalindrome === "Palindrome") {
return 2;
} else {
num++;
isPalindrome = isSameOrPalindrome(num);
if(isPalindrome === "Palindrome") {
return 1;
} else {
return 0
}
}
}
console.log("100",doCheck(100));
I am making a custom registration page with only 2 values Email and Password, later I will add confirm password as well, for my password field I have some restrictions and I am using some regex and also some custom made code to make the validation.
this is my validateField:
validateField(fieldName, value) {
let fieldValidationErrors = this.state.formErrors;
let emailValid = this.state.emailValid;
let passwordValid = this.state.passwordValid;
//let passwordValidConfirm = this.state.passwordConfirmValid;
switch(fieldName) {
case 'email':
emailValid = value.match(/^([\w.%+-]+)#([\w-]+\.)+([\w]{2,})$/i);
fieldValidationErrors.email = emailValid ? '' : ' is invalid';
break;
case 'password':
passwordValid = (value.length >= 5 && value.length <= 32) && (value.match(/[i,o,l]/) === null) && /^[a-z]+$/.test(value) && this.check4pairs(value) && this.check3InRow(value);
fieldValidationErrors.password = passwordValid ? '': ' is not valid';
break;
default:
break;
}
this.setState({formErrors: fieldValidationErrors,
emailValid: emailValid,
passwordValid: passwordValid,
//passwordValidConfirm: passwordValidConfirm
}, this.validateForm);
}
as you can see for
passwordValid
I have made some methods, this one
check3InRow
doesnt work the way I want it to work, this one makes sure, you have at least 3 letters in your string that are in a row so like "abc" or "bce" or "xyz".
check3InRow(value){
var counter3 = 0;
var lastC = 0;
for (var i = 0; i < value.length; i++) {
if((lastC + 1) === value.charCodeAt(i)){
counter3++;
if(counter3 >= 3){
alert(value);
return true;
}
}
else{
counter3 = 0;
}
lastC = value.charCodeAt(i);
}
return false;
}
this doesnt work correctly so it should accept this:
aabcc
as a password but not:
aabbc
You are starting your counter from 0 and looking for greater than equal to 3 which will never be 3 for 3 consecutive characters. Rest everything is fine with your code.
check3InRow(value) {
var counter3 = 1;
var lastC = 0;
for (var i = 0; i < value.length; i++) {
if ((lastC + 1) === value.charCodeAt(i)) {
counter3++;
if (counter3 >= 3) {
alert(value);
return true;
}
} else {
counter3 = 1;
}
lastC = value.charCodeAt(i);
}
return false;
}
Can we not do a simple version of that function? Like
function check3InRow2(value){
for (var i = 0; i < value.length-2; i++) {
const first = value.charCodeAt(i);
const second = value.charCodeAt(i+1);
const third = value.charCodeAt(i+2);
if(Math.abs(second - first) === 1 && Math.abs(third-second) === 1){
return true;
}
}
return false;
}
I mean complexity wise it is O(N) so maybe we can give this a try
Also adding the your function. When you are AT a char then you should consider counter with 1. Because if another one matches it will be 2 consecutive values.
function check3InRow(value) {
var counter3 = 1;
var lastC = value.charCodeAt(0);
for (var i = 1; i < value.length; i++) {
if ((lastC + 1) === value.charCodeAt(i)) {
counter3++;
if (counter3 >= 3) {
return true;
}
} else {
counter3 = 1;
}
lastC = value.charCodeAt(i);
}
return false;
}
I am using bubbleSort, and I can get the array to toggle from its original order to descending, but I am having trouble getting it to go from descending back to ascending. Should I just copy the bubbleSort code and flip the greater than/less than signs? Any help is appreciated!
var myStuff = [];
function myfunctionA() {
var enteredvalue = document.getElementById("numbers").value;
// alert(typeof Number(document.getElementById('numbers').value));
if (enteredvalue == "") {
alert("Input is not a number");
} else if (isNaN(enteredvalue)) {
alert('You need to enter a valid number!');
}
var elementExists = false;
var x = document.getElementById('numbers').value;
for (var i = 0; i < myStuff.length; i++) {
if (myStuff[i] == Number(x)) {
elementExists = true;
}
}
if(elementExists != true) {
myStuff.push(Number(enteredvalue));
alert('Thank You for entering a valid number.');
} else {
alert('Element is here');
}
}
function myfunctionB() {
window.alert(myStuff.length);
}
function myfunctionC() {
var sum = 0;
for(var i = 0; i < myStuff.length; i++) {
sum+=myStuff[i];
}
alert(sum);
}
function myfunctionD() {
if (myStuff.length == 0) {
alert("already empty");
} else {
myStuff = [];
}
alert("Array Empty");
}
function myfunctionE() {
alert(myStuff.join('\n'));
{
if (myStuff == []) {
alert("Enter something into Array")
}
}
}
function bubbleSort() {
var sorted = true;
var temp;
while(sorted) {
sorted = false;
for(var i = 0; i < myStuff.length-1; i++) {
if(myStuff[i] < myStuff[i+1]) {
temp = myStuff[i];
myStuff[i] = myStuff[i+1];
myStuff[i+1] = temp;
sorted = true;
}
}
}
}
First you'll need a toggle to tell which way you are going.
var isAscending = false;
Then in your bubbleSort function inside the for-statement, above the if-statement.
var sortComparison;
if (isAscending) sortComparison = myStuff[i] > myStuff[i];
if (!isAscending) sortComparison = myStuff[i] < myStuff[i];
Then replace your if-statement with:
if (sortComparison)
Finally, once you have finished sorting, you can toggle your variable:
isAscending = !isAscending;
Though, I'd recommend using a toggled variable and simply using sort() and reverse() instead.
https://jsfiddle.net/ytcax0qc/
I have this piece of code
$scope.addToOrder = function(index) {
var tempItem = $scope.item;
if (tempItem[index].validate == true){
if (_.isEmpty($scope.item2) == true) {
$scope.item2.push(tempItem[index]);
} else {
for (var i = 0; i < $scope.item2.length; i++) {
if ($scope.item2[i] == tempItem[index]) {
break;
}
if (i == $scope.item2.length - 1) {
$scope.item2.push(tempItem[index]);
}
}
}
}
}
I want to push data from one object to other (item to item2), it works well, but when i change data from item also item2 updates i dont want this.
What i missing?
As is, you are using an object reference. Then if modify one, the othes one is modified too.
You could use angular.copy
$scope.addToOrder = function(index) {
var tempItem = $scope.item;
var itemCopy = angular.copy(tempItem[index]);
if (tempItem[index].validate == true){
if (_.isEmpty($scope.item2) == true) {
$scope.item2.push(itemCopy);
} else {
for (var i = 0; i < $scope.item2.length; i++) {
if ($scope.item2[i] == tempItem[index]) {
break;
}
if (i == $scope.item2.length - 1) {
$scope.item2.push(itemCopy);
}
}
}
}
}
use angular.copy to cope by value
angular.copy($scope.item1, $scope.item2);
or
$scope.item1 = angular.copy($scope.item2);
I'm using dropdowncheckboxlist, where we can select multiple values and my question is how to again check the checkbox inside dropdownCheckList based on database values. That is, I have to check multiple values while editing or updating the values. I'm using this script:
<script type="text/javascript">
$(document).ready(function () {
$("#ContentPlaceHolder1_dropdown").dropdownchecklist({
forceMultiple: true
, onComplete: function (selector) {
var values = "";
for (i = 0; i < selector.options.length; i++) {
if (selector.options[i].selected && (selector.options[i].value != "") ) {
if (values != "") values += ",";
values += selector.options[i].value;
}
}
// alert(values);
$('#<%= hidVisitorID.ClientID %>').val(values);
}
, onItemClick: function (checkbox, selector) {
var justChecked = checkbox.prop("checked");
var checkCount = (justChecked) ? 1 : -1;
for (i = 0; i < selector.options.length; i++) {
if (selector.options[i].selected) checkCount += 1;
}
if (checkCount > 9) {
alert("Industry Limit is 9");
throw "too many";
}
}
}
</script>