I have been working on a piece of code and I was wondering if there is a inbuilt JavaScript method which allows a function to be runned every 4 seconds for seconds and 5 times for example.
Your question is ambiguous in the sense that it is unclear whether you want to call the function five times each interval, or call it with intervals until it has been called five times.
5 times each time interval
You can easily write a higher order function for this:
function multi_repeat(f,dmsec,times) {
function foo() {
setTimeout(foo,dmsec);
for(var i = 0; i < times; i++) {
f();
}
}
setTimeout(foo,dmsec);
}
Now if your function is:
function the_alert() {
alert("Hi");
}
You can run this with:
multi_repeat(the_alert,4000,5);
where 4000 is the number of milliseconds (so 4 seconds is 4000 milliseconds) and 5 the number of times the function should be called.
Stop after 5 calls
In case the procedure should stop after 5 calls, you can define another higher order function:
function repeat_stop(f,dmsec,times) {
var count = 0;
function foo() {
f();
count++;
if(count < times) {
setTimeout(foo,dmsec);
}
}
setTimeout(foo,dmsec);
}
you are looking at the setInverval function.
var counter = 0;
function someFunction(){
console.log('hello world')
}
var interVal = setInterval(function(){
conter++;
if (counter < 5) {
someFunction();
}
else {
clearInterval(interVal );
}
}, 4000);
setInterval will run a function repeatedly with a custom delay between them. To run it five times, you'll have to handle that yourself, e.g.
setInterval(function(){
for (var i = 0; i < 5; i++){
myFunction();
}
},4000);
https://developer.mozilla.org/en-US/docs/Web/API/WindowOrWorkerGlobalScope/setInterval
Related
So from what I have understood, setInterval() is used to call a function on repeat on regular intervals.
So basically it is a loop that executes a function forever periodically.
I am confused as to if I had to stop this execution at one point what would be the way to do it
for eg I am trying to print the message "hey" 3 times after 1 second each, but somehow it is printing it 3 times every second and is going on forever.
What can I do to stop it after a set number of times.
This is the code that I've been trying
var i = 3;
function message() {
console.log("hey");
}
while(i > 0) {
setInterval(message, 1000);
i = i - 1;
}
Your code is executing the setInterval thrice in the while loop, which is not needed.
Actually, setInterval does not work as a function call but actually registers a function to be called at some interval.
The setInterval() method will continue calling the function until clearInterval() i.e it is deregistered or the process is killed.
It should work like this
var i = 3;
var interval = setInterval(message, 1000);
function message() {
if (i === 0) {
clearInterval(interval);
}
console.log("hey");
i = i - 1;
}
To clear a setInterval, use global clearInterval method.
Example:
var timerId = setInterval(func, 500);
.... some code here....
clearInterval(timerId);
What can I do to stop it after a set number of times.
usually you don't use setInterval() for this, you use setTimeout().
Something like
var counter = 0;
function message() {
console.log("hey");
// we trigger the function again after a second, if not already done 3 times
if (counter < 3) {
setTimeout(message, 1000);
}
counter++;
}
// initial startup after a second, could be faster too
setTimeout(message, 1000);
The setInterval function calls the function indefinitely, whereas setTimeout calls the function once only.
Simply use clearInterval once the count runs out.
var i = 3;
function message(){
console.log("hey");
if (--i < 0) {
clearInterval(tmr);
}
}
var tmr = setInterval(message, 1000);
you have to assign that setInterval to a javascript variable to name it what for this setInterval, like this
var messageLog = setInterval(message, 1000);
After, in setInterval message function add this condition to clear the inverval whenever you want to clear.
function message(){
if(i>3) {
clearInterval(messageLog); // clearInterval is a javascript function to clear Intervals.
return null;
}
console.log("hey");
}
You can retrieve the timer when creating and clear it if needed.
var i=3;
var timer = setInterval(message,1000);
function message(){
console.log("hey");
i—-;
if(i==0)
clearInterval(timer)
}
a beginner here too,look for clearInterval method ...
Learning some basic concepts in JavaScript "asynchronicity" from Frontendmasters course JavaScript: The Hard Parts, v2
I am given the exercise (Challenge 5):
Create a function limitedRepeat that console logs "hi for now" every second, but only for 5 seconds. Research how to use clearInterval() if you are not sure how to do this.
And following placeholder was given for this function:
function limitedRepeat() {
//CODE HERE
}
I was able to solve it as following (2 versions):
Version 1
function limitedRepeat() {
var totalLogs = 0;
var logFunc = setInterval(myTimer, 1000)
function myTimer() {
if(totalLogs < 5){
console.log("hi for now");
totalLogs++;
} else {
clearInterval(logFunc);
}
}
}
limitedRepeat(); // should log (every second, for 5 seconds): hi for now
Version 2
function limitedRepeat(totalLogs) {
console.log("hi for now");
var timery = setTimeout(timerable,1000);
function timerable() {
totalLogs++;
if(totalLogs >= 5){
clearTimeout(timery);
} else {
limitedRepeat(totalLogs);
}
}
}
limitedRepeat(0); // should log (every second, for 5 seconds): hi for now
Obviously, I have changed the signature of function in Version 2, so I am curious if there is solution that leverages setTimeout() and clearTimeout() and possibly recursion, that doesn't require signature of function to be changed - in other words for that recursive call set by timeout to somehow memorize how many times was the log printed to console?
With recursion;
function limitedRepeat(count = 0) {
if(count >= 5) return;
console.log('hi')
setTimeout(() => limitedRepeat(++count), 1000)
}
limitedRepeat()
Just make sure you increment before recalling the function.
This is my approach:
var count = 1,
timer = setInterval(limitedRepeat,1000)
function limitedRepeat() {
console.log('Hi for now');
count++;
if(count > 5) clearInterval(timer)
}
Using an inner named IIFE with recursion.
EDIT: We don't even need the closure to memoize the times executed if we pass the parameter to the inner function.
function limitedRepeat() {
const maxTimes = 5;
return (function _limitedRepeat(current) {
console.log("hi for now");
var timery = setTimeout(timerable, 1000);
function timerable() {
current++;
if (current >= maxTimes) {
return
}
_limitedRepeat(current);
}
})(0);
}
limitedRepeat();
I'm trying to develop a function that repeats a function x amount of times, just once, not based on settimerinterval or settimeout or anything based on time. I don't want to use a while/for loop directly, I want to use this repeat function.
I've tried something like this:
function repeat(func, times) {
for (x = 0; x < times; x++) {
eval(func)
}
}
But eval doesn't work on a function.
const func = () => console.log("hi");
const times = 3;
Array.from({length: times}, () => func());
I define a function.
I set the number of times to repeat function.
I make an array the size of times to repeat function.
I run the "defined function" on each element of the array.
Just call func and decrement counter and call the function repeat again.
function repeat(func, times) {
func();
times && --times && repeat(func, times);
}
repeat(function () { document.write('Hi<br>'); }, 5);
If Lodash is an option, then _.times
You can also define a reusable function, utilizing setInterval and clearInterval
function runFunctionXTimes(callback, interval, repeatTimes) {
let repeated = 0;
const intervalTask = setInterval(doTask, interval)
function doTask() {
if ( repeated < repeatTimes ) {
callback()
repeated += 1
} else {
clearInterval(intervalTask)
}
}
}
function sayHi() {
console.log("Hi")
}
The following line will run sayHi 5 times without wasting any time between completion of one and the beginning of another.
runFunctionXTimes(sayHi, 0, 5)
It is also possible to pass function arguments to setInerval, you can read more about it here https://developer.mozilla.org/en-US/docs/Web/API/WindowOrWorkerGlobalScope/setInterval
Using recursion:
function repeat(fn, times) {
var loop = function (times) {
if (times) {
fn(times);
loop(--times);
}
}
loop(times);
}
repeat(function (times) {
console.log(times);
}, 5);
You may not be able to eval() a function, but you can call it. Here's the fix:
function repeat(func, times) {
for (x = 0; x < times; x++) {
func()
}
}
I've got this Problem here, that this function is not working and I cant figure out why..
This function should count to 10 (in 10 seconds). For this purpose I'm using a for loop with setTimeout function - duration set to 1000ms.
It should go on and on for what i took the setInterval function.
function timer() {
var time=10;
for(i=0; i<time; i++){
setTimeout(console.log(i+1), 1000);
}
}
setInterval(timer, 10000);
The Problem is, that it isnt working and I dont understand why ... I have found another working solution but would like to know the issue of this one. :)
The reason that nothing appears to happen is the way that you use setTimeout. Instead of providing an event handler you are calling console.log and try to use the return value from that call as event handler.
The closest thing that would at least do something would be to make a function that calls console.log:
setTimeout(function(){ console.log(i+1) }, 1000);
However, you will notice that it will just log the value 11 ten times at once, every ten seconds, indefinitely.
Eventhough the loop counts from 0 to 9, you start a timeout in each iteration that will be triggered one second from when it was created. As all ten timeouts are created at the same time, they will be triggered at the same time. There isn't a separate variable i for each handler, so they will all show the value in the variable at the time that they are triggered, and as the loop has completed before any of them can be called they will all show the final value 10 + 1.
You are using both an interval and timeouts, you should use one or the other.
You can start timeouts in a loop, but then you should only do it once, not in an interval, and you should specify the time from start to when you want it to be triggered:
var time = 10;
for (var i = 1; i <= time; i++){
setTimeout(function() { console.log('tick'); }, 1000 * i);
}
If you want to use the variable in the event handler, then you need to create a copy of the variable for each iteration:
var time = 10;
for (var i = 1; i <= time; i++){
(function(copy){
setTimeout(function() { console.log(copy); }, 1000 * i);
})(i);
}
You can use an interval, but then you don't have a loop, it's the interval that is the loop. Use clearInterval to stop it when you reach the end of the loop:
var i = 1, time = 10, handle;
function timer() {
console.log(i);
i++;
if (i > time) clearInterval(handle);
}
handle = setInterval(timer, 1000);
First, it's not working because setTimeout call is wrong. Even if your setTimeout call worked, there's another issue here. Your code will actually print 11 every 10 seconds.
function timer() {
var time = 10;
for (i = 0; i < time; i++) {
setTimeout(function() {
console.log(i + 1)
}, 1000);
}
}
setInterval(timer, 10000);
Because, you have sequential setTimeout calls to be effected every second and you are forming a closure on the variable i.
You need to take care of the closure and calls must be done after the second has been printed.
function timer() {
var p = Promise.resolve();
for (var i = 0; i < 10; i++) {
p = p.then(closure(i));
}
}
function closure(i) {
return (function () {
return new Promise(function (resolve) {
setTimeout(function () {
document.getElementById('results').innerHTML = (i + 1) + '\n';
resolve();
}, 1000);
})
});
}
timer();
setInterval(timer, 10000);
<pre id="results"></pre>
When I run your code in the Firebug debugger, I see:
TypeError: can't convert console.log(...) to string
I added a comment to your code about that error:
function timer() {
var time=10;
for(i=0; i<time; i++){
// The source of error is the line below
// Type error: setTimeout needs a function as first argument!
setTimeout(console.log(i+1), 1000);
}
}
setInterval(timer, 10000);
A corrected version might be
function timer() {
var time=10;
for(i=0; i<time; i++){
setTimeout(function() { console.log(i+1); }, 1000);
}
}
setInterval(timer, 10000);
However, the above change fixes the type error but not the logic.
You probably wanted to do this:
var counter = 0;
var count = function() {
console.log(++counter);
if (counter >= 10) {
clearInterval(timer);
}
};
var timer = setInterval(count, 1000);
Once the callback function count notices the counter passed the value 10 it will stop the periodic timer whose ID was saved in the variable timer when setting it up.
I have this code:
for (i = 0; i < 3; i++) {
var interval = setInterval(function(){
alert(i);
}, 2000);
}
What I would like to achieve is to have an alert every 2 sec displaying first 0, then 1 and lastly 2.
Instead I have to wait for quite long before I have 3 alerts all displaying the number 3. Where is my code wrong?
Well, there is (yet again) more than one solution to this problem. But, lets first talk why your code doesn't work properly.
Your code:
for (i = 0; i < 3; i++) {
var interval = setInterval(function(){
alert(i);
}, 2000);
}
..basically means that it will assign three setInterval calls to be executed after 2 seconds as fast as the for loop is placing them to the queue. So basically, all your calls runs really fast after 2 seconds, only few milliseconds or less between them. Moreover, setInterval means that it will be called as long as clearInterval is called to the variable it is assigned with. In other words, your code never stops executing the alert, because you are never calling clearInterval. Finally, your alert(i) will always display value of 3, because it is the last value of i when execution moves away from the for loop.
To improve your code, you could remove the for loop entirely and just let setInterval run as long as the value of i is alerted three times; At that point, you just call clearInterval to the value which has handle to setInterval and the job is finished.
Working code:
// value to output
var i = 0,
// starting setInterval and assigning its handle to variable interval,
// it is used to clear the interval when execution should be finished
interval = setInterval(function () {
// alert value of i and increase it by 1
alert(i++);
// if i is equals to 3, no more calls
if(i === 3) {
// clear the interval so method won't be called in the future
clearInterval(interval);
}
}, 2000);
JS FIDDLE EXAMPLE
Cheers, hopefully you learnt something new today.
Without forloop:
var number = 0;
var interval = setInterval(function(){
alert(number);
number++;
if(number === 3) {
clearInterval(interval);
}
}, 2000);
JSFIDDLE
1.1 Without for loop + without initial delay (demo):
var i = 0;
var showAlert = function(){
alert(i);
i++;
if(i < 3){
setTimeout(function(){
showAlert();
}, 2000);
}
};
showAlert();
1.2 Without for loop + with initial delay (demo):
var i = 0;
var showAlert = function(){
if(i < 3){
setTimeout(function(){
alert(i);
i++;
showAlert();
}, 2000);
}
};
showAlert();
2.1 With for loop + without initial delay (demo):
function setAlert(k){
setTimeout(function(){
alert(k);
},k * 2000);
}
for(var i = 0; i < 3; i++) {
setAlert(i);
}
2.2 With for loop + with initial delay (demo):
function setAlert(k){
setTimeout(function(){
alert(k);
},(k + 1) * 2000);
}
for(var i = 0; i < 3; i++) {
setAlert(i);
}
First of all, I would go with setTimout, you know that you want 3 alerts.
Second problem is a bit stranger. You are calling async function, setTimeout/setInterval and referring to the original i of the for loop inside of the setTimeout callback. That will not work because at the time of the timeout invocation the for loop has already finished and i var will be 3. One solution is to wrapp the async function in a self invoking anonymous function with params that you need inside async function. In our case we call it with i.
Solution:
for (i = 0; i < 3; i++) {
(function(i) {
setTimeout(function(){
alert(i);
}, 2000 * i);
})(i);
}
JS fiddle