City Area onchange in magento2 - javascript

I am using magento 2.1.0. I created two dropdown on customer registration form ,where the data is fetching from database.
There are two databases :
city database which contain city_id and city column.
send is area table which contain area_id, city_id and area column.
on frontend data is sucessfully fetch, and even onchange is also working on city.
City dropdown:
<select name="city" onchange="getArea()" id="city">
<?php
$objectManager = \Magento\Framework\App\ObjectManager::getInstance();
$model = $objectManager->create('/city')->serviceCity();
foreach ($model as $d)
{ ?>
<option id="<?php echo $d['city_id']; ?>" value="<?php echo $d['city_id']; ?>"><?php echo $d['city']; ?></option>
<?php } ?>
</select>
Area dropdown:
<div class="field area required">
<label for="area" class="label"><span><?php /* #escapeNotVerified */
echo __('Area') ?></span></label>
<select name="area" id="area">
<?php
$objectManager = \Magento\Framework\App\ObjectManager::getInstance();
$model = $objectManager->create('\Area')->serviceArea();
foreach ($model as $a)
{ ?>
<option value="<?php echo $a['area']; ?>"><?php echo $a['area']; ?></option>
<?php } ?>
</select>
</div>
Onchange script:
<script>
function getArea(){
alert(document.getElementById('city').value);
}
</script>
Now my question is, what should I do, when I change the city, in second dropdown related area will display only?
Thanks in advance

Related

OnChange with javascript/ajax result, also with a php foreach loop

I have this interesting setup that I hope someone can help me fix. I've searched and found some solutions but nothing that comes close to what I'm trying to achieve, so nothing really lead me in a direction that could get me to a solution for what I'm doing
I have a dropdown of litters. You select a litter, onchange happens, it gets the available pick spots from the database, then echos out the results with another foreach to another dropdown menu
The problem is, these dropdown menus are inside of a foreach loop (for each client available to the site user). So the first client works as expected, but because it has the same ID, the second client's dropdowns don't do anything since it's still on the same page
Hopefully someone has some insight on how to make this work :(
Here's the dropdown:
<select class="form-control mb-3" name="the_chosen_litter" id="litter" required>
<option disabled selected>First, Choose A Litter...</option>
<?php
foreach($labradoodle_two as $litter_waitlist_form){
?>
<option id="<?php echo $litter_waitlist_form['litter_id']; ?>" value="<?php echo $litter_waitlist_form['litter_id']; ?>" style="<?php if($litter_waitlist_form['status']=='LITTER CLOSED'){ echo 'color:red;'; }else{ echo 'color:green;'; } ?>" >
<?php echo $litter_waitlist_form['litter_names']; ?>
</option>
<?php } ?>
</select>
<select class="form-control mb-3" name="buyer_pick_gender" id="pick_list" required> <!-- uses jquery to fill in this field -->
<option disabled selected>Litter Selection Required...</option>
</select>
Here's the javascript/ajax:
$(document).ready(function() {
$("#litter").on("change", function() {
var litterID = document.getElementById("litter").value;
$.post('secure/litter_list_dropdown.php', { littersubmit: litterID }, function(result) {
$('#pick_list').html(result);
}
);
});
});
And for reference, here's my "litter_list_dropdown" code that pulls from the database and echos out the available "pick spots":
<?php
session_start();
include '../../database/dbh.class.php';
$litter_id = $_REQUEST['littersubmit'];
$femalespickedquery = $dbpdo->query("SELECT * FROM pick_assignment WHERE litter_id=? AND gender_id=?",$litter_id,"1")->fetchAll();
$malespickedquery = $dbpdo->query("SELECT * FROM pick_assignment WHERE litter_id=? AND gender_id=?",$litter_id,"2")->fetchAll();
?>
<option disabled="disabled" selected="selected">Choose A Pick</option>
<?php foreach ($femalespickedquery as $pick){
$picktaken=$pick['user_id'];
$pickcustom=$pick['custom_name'];
$pickposition=$pick['pick_id'];
$suffix=ordinal($pickposition);
?>
<option value="<?php echo $pickposition.' 1'; ?>" <?php if($picktaken!="0" OR $pickcustom==true){ echo "disabled"; } ?>>
<?php echo "FEMALE - " .$pickposition.$suffix. " Pick"; if($picktaken!="0" OR $pickcustom==true){ echo " *RESERVED*"; }?>
</option>
<?php } ?>
<?php
foreach ($malespickedquery as $pick){
$picktaken=$pick['user_id'];
$pickcustom=$pick['custom_name'];
$pickposition=$pick['pick_id'];
$suffix=ordinal($pickposition);
?>
<option value=<?php echo $pickposition.' 2'; ?>" <?php if($picktaken!="0" OR $pickcustom==true){ echo "disabled"; } ?>>
<?php echo "MALE - " .$pickposition.$suffix. " Pick"; if($picktaken!="0" OR $pickcustom==true){ echo " *RESERVED*"; }?>
</option>
<?php } ?>

Keep the selected options after submitting the form

Good morning, I have a problem that is: I can not keep several options selected after submitting the form and I would like someone to help me.
<select name="utilizadores[]" id="utilizadores" multiple="multiple" class="selectpicker" data-live-search="true" data-actions-box="true" title="Utilizadores">
<?php while ($reg_sql=mysqli_fetch_array($res_sql)){?>
<option value="<?php echo $reg_sql['ID_USER']; ?>"><?php echo $reg_sql['NOMEUSER']; ?></option>
<?php } ?>
</select>
<script type="text/javascript">
document.getElementById('utilizadores').value = "<?php echo $_POST['utilizadores[]'];?>";
</script>
this is my code to have the various options in the select box
You have to check if $_POST['utilizadores'] or $_GET['utilizadores'] it depends on your request type. I will use $_POST in here for explain my answer.
your select is multiple, you can use in_array function for checking that if result from db record is in array of $_POST['utilizadores']
<select name="utilizadores[]" id="utilizadores" multiple="multiple" class="selectpicker" data-live-search="true" data-actions-box="true" title="Utilizadores">
<?php while ($reg_sql=mysqli_fetch_array($res_sql)){?>
**<option value="<?php echo $reg_sql['ID_USER']; ?>"
<?php
if(isset($_POST['utilizadores'])){
if(in_array($reg_sql['ID_USER'], $_POST['utilizadores'])){
echo 'selected';
}else{
echo '';
}
}
?>
>**<?php echo
$reg_sql['NOMEUSER']; ?></option>
<?php } ?>
</select>
You may be able to do it more efficiently if your database result also contains which rows are selected, but when you loop through, just add the selected="selected" attribute to the <option> tag.
Assuming your $_POST array exists in this scope, you can use the in_array function in PHP to determine if the option has been selected (docs).
The ternary based operation is as follows:
in_array($reg_sql['ID_USER'],$_POST['utilizadores']) ? 'selected="selected"' : ''
Which says "if the ID_USER is in the post array, then print the selected attribute, otherwise, print a blank string"
Putting it all together:
<select name="utilizadores[]" id="utilizadores" multiple="multiple" class="selectpicker" data-live-search="true" data-actions-box="true" title="Utilizadores">
<?php while ($reg_sql=mysqli_fetch_array($res_sql)){?>
<option value="<?php echo $reg_sql['ID_USER']; ?>" <?= in_array($reg_sql['ID_USER'],$_POST['utilizadores']) ? 'selected="selected"' : '' $?>>
<?php echo $reg_sql['NOMEUSER']; ?>
</option>
<?php } ?>
</select>
An example of how you can do this. Either add the "selected" string if yes or leave blank if no. You can also write selected="selected". You can do the same thing to set disabled or readonly.
<select name="utilizadores[]" id="utilizadores" multiple="multiple" class="selectpicker" data-live-search="true" data-actions-box="true" title="Utilizadores">
<?php while ($reg_sql=mysqli_fetch_array($res_sql)){?>
<?php $selected = isset($reg_sql["mi_variable"]) ? "selected" : ""; ?>
<option value="<?php echo $reg_sql['ID_USER'];?>" <?php echo $selected; ?> >
<?php echo $reg_sql['NOMEUSER']; ?>
</option>
<?php } ?>
</select>
<script type="text/javascript">
document.getElementById('utilizadores').value = "<?php echo $_POST['utilizadores[]'];?>";
</script>

Selectize js submitting only last selected item

I'm currently using Selectize.js with a 'select' item and multiple options. My html is something like:
<div class="form-group">
<label for="record-genre">Genre(s):</label>
<select name="record_genre" id="record-genre" class="form-control multi-selectize" multiple="multiple" placeholder="Enter genre(s)">
<?php foreach ($record_genre_opts as $key => $val): ?>
<option value="<?php echo $key; ?>" <?php echo (in_array($key, $record_genre)) ? "selected" : ''; ?>
<?php echo set_select('record_genre', $val); ?>
>
<?php echo $val; ?>
</option>
<?php endforeach;?>
</select>
</div>
So far so good. The items are being loaded correctly and until this point everything works great. The issue is that when the form is submitted only the last value selected is the one that is available, so if I selected multiple items I'm getting just one:
["record_genre"]=> string(1) "1"
Here's my JS setup:
$('.multi-selectize').each(function(){
//console.log($(this))
$(this).selectize({})
})
Any suggestions?
Thanks.
My mistake. The name of the select item should be record_genre[] since it is declared as a multiple select instead of just record_genre.

Populate Dropdown based on another Dropdown Using Ajax, jQuery and Codeigniter on Update

I have created a dropdown that populates another dropdown.
I have created a modal for update in my application and I want the selected value of the dropdown to be the name taken from the database. It shows the name, but the problem is it doesnt show the other names which should be included.
(Note that the names show up depending on the first dropdown)
Here is my Model
function get_agents($campaign_id)
{
$campaign_id1 = mysqli_real_escape_string($this->db->conn_id,trim($campaign_id));
$query = $this->db->query("SELECT tbl_employee.emp_id, CONCAT(tbl_applicant.fname, ' ', tbl_applicant.lname) AS fullname FROM tbl_applicant INNER JOIN tbl_employee ON tbl_employee.apid=tbl_applicant.apid INNER JOIN tbl_account ON tbl_employee.acc_id=tbl_account.acc_id WHERE tbl_account.acc_id='".$campaign_id1."' ORDER BY tbl_applicant.fname ASC");
return $query->result();
}
Here is my Controller
public function getAgents()
{
$campaign_id = $this->input->post('campaign_id');
$data = $this->KudosModel->get_agents($campaign_id);
echo "<option value=''>-- Select Ambassador Name --</option>";
foreach($data as $a)
{
echo "<option value='".$a->emp_id."'>".$a->fullname."</option>";
}
}
Here is my View
<div class="form-group" style="height: auto; overflow: auto;">
<label class="col-sm-3 control-label float-left">Ambassador Name</label>
<div class="col-sm-9">
<select class="form-control" id="agentNames<?php echo $val->kudos_id; ?>" required="true" data-trigger="change" value="<?php echo $val->ambassador; ?>">
<option selected="" value="">-- Select Ambassador Name --</option>
<option selected="selected" value=""><?php echo $val->ambassador;?></option>
<?php
foreach($name2 as $row)
{
if($val->campaign==$row->acc_name)
echo '<'; if($val->ambassador==$row->fullname){
echo 'selected=selected';
}echo'option value="'.$row->emp_id.'">'.$row->fullname.'</option>';
}
?>
</select>
</div>
Here is my JQuery
$('#addCampaign<?php echo $val->kudos_id; ?>').on('change', function(){
$.ajax({
type : 'POST',
data : 'campaign_id='+ $('#addCampaign<?php echo $val->kudos_id; ?>').val(),
url : "<?php echo base_url(); ?>index.php/Kudos/getAgents/",
success : function(data){
//data returns your name, iterate through it and add the name to another select
$('#agentNames<?php echo $val->kudos_id; ?>').html(data);
}
});
});

Retrieving data from databse using the dropdown selected list in php and mysql

I have texbox and dropdown list which is populated from mysql database. I want to retrieve data from database and wants to display in textbox using dropdown selected list, without refreshing the page. Here is my code and Thanks in Advance.
<select name="select1" class="form-control" id="dropdownlist1">
<option id="0">-- Select the Company --</option>
<?php
require("dbcon.php");
$getallcompanies = mysql_query("SELECT * FROM ifcandetails6");
while($viewallcompanies = mysql_fetch_array($getallcompanies)){
?>
<option id="<?php echo $viewallcompanies['tcuid']; ?>"><?php echo $viewallcompanies['tcname'] ?></option>
<?php
}
?>
</select>
Input Textbox:
<input type="text" id="field1" value="<?php echo $viewallcompanies['tccontact']?>" disabled/>
Separate things out like this:
<?php
require("dbcon.php");
$query = mysql_query("SELECT tcuid, tcname, tccontact FROM ifcandetails6");
while($row = mysql_fetch_array($query)){
$contacts[] = $row['tccontact'];
$companies[] = $row;
}
?>
<select name="select1" class="form-control" id="dropdownlist1">
<option id="0">-- Select the Company --</option>
<?php foreach($companies as $company) { ?>
<option id="<?= $company['tcuid']; ?>"><?= $company['tcname'] ?></option>
<?php } ?>
</select>
<?php foreach($contacts as $contact) { ?>
<input type="text" id="field1" value="<?= $contact['tccontact']?>"/>
<?php } ?>

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